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This document contains C++ code to implement a linked list program that performs the following tasks: 1. Inputs 10 integers into a linked list while sorting them as they are inserted 2. Prints the sorted list and computes the average of the values 3. Deletes nodes from the list with values less than the average 4. Creates a second list of 10 sorted integers 5. Merges the two lists together, eliminating duplicates, and prints the final list
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How do you solve QUESTION #4 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *firs.
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HELP FIXING THIS CODE?
THIS IS THE PROBLEM
Write a program that allows the user to enter two positive integers and outputs their sum. Sounds
simple? Here\'s the catch: The numbers may be any size! They may be way too large to store in a
single variable. You may not assume any particular maximum number of digits.
HERE IS THE CODE
#include
#include
struct node /* Linked list node*/
{
int data;
struct node* next;
};
struct node *newNode(int data) /* Function to create a new node with giving the data*/
{
struct node *new_node = (struct node *) malloc(sizeof(struct node));
new_node->data = data;
new_node->next = NULL;
return new_node;
}
void push(struct node** head_ref, int new_data) /* Function to insert a node at the beginning of
the Doubly Linked List*/
{
struct node* new_node = newNode(new_data); /*allocate a node*/
new_node->next = (*head_ref); /* link the old list off to the new node*/
(*head_ref) = new_node; /*move the head to point to the new node*/
}
/* Adding the contents of two linked lists and return the head node of resultant list*/
struct node* addTwoLists (struct node* first, struct node* second)
{
struct node* res = NULL; /* res is head node of the resultant list*/
struct node *temp, *prev = NULL;
int carry = 0, sum;
while (first != NULL || second != NULL) /*while both the lists exists*/
{
/* Calculate value of next digit in resultant list.
// The next digit is sum of following things
// (i) Carry
// (ii) Next digit of first list (if there is a next digit)
// (ii) Next digit of second list (if there is a next digit)*/
sum = carry + (first? first->data: 0) + (second? second->data: 0);
carry = (sum >= 10)? 1 : 0; /* update carry for next calulation*/
sum = sum % 10; /*update sum if it is greater than 10*/
temp = newNode(sum); /*Create a new node with sum as data*/
if(res == NULL) /*if this is the first node then set it as head of the resultant list*/
res = temp;
else /* If this is not the first node then connect it to the rest.*/
prev->next = temp;
prev = temp; /* Set prev for next insertion*/
if (first) first = first->next; /* Move first pointers to next node*/
if (second) second = second->next; /*Move second pointer to the next node*/
}
if (carry > 0)
temp->next = newNode(carry);
return res; /* return head of the resultant list*/
}
void printList(struct node *node) /* function to print a linked list*/
{
while(node != NULL)
{
printf(\"%d \", node->data);
node = node->next;
}
printf(\"\ \");
}
int main(void) /* program to test above function*/
{
struct node* res = NULL;
struct node* first = NULL;
struct node* second = NULL;
printf(\"Enter first positive integer: \");
scanf(\"%d\",&first);
printList(first);
printf(\"Enter second positive integer: \");
scanf(\"%d\",&second);
printList(second);
/*Add the two lists and see result*/
res = addTwoLists(first, second);
printf(\"Sum is: %d\");
printList(res);
return 0;
}
Solution
#include
#include
typedef struct Node
{
int da.
C++ Doubly-Linked ListsThe goal of the exercise is to implement a.pdf
C++ Doubly-Linked ListsThe goal of the exercise is to implement a.pdfpoblettesedanoree498 C++: Doubly-Linked Lists
The goal of the exercise is to implement a class List of doubly- linked lists.
My goal is to implement the class in a file doubly-linked.cpp.
The class List implements lists using the following structures for list ele- ments:
struct Node { int val ;
Node next;
Node prev; };
Each Node contains a value (an integer) and two pointers: one meant to point to the next element
of the list and one meant to point to the previous element in the list. The class provides the
following methods that you need to implement:
• A constructor and a destructor, with no arguments;
• void insert(int n): insert an integer at the end of the list;
• void reverse(): reverse the list;
• void print(): print the list to cout in the same format as the input (i.e. integers separated by
spaces);
doubly-linked.h
#ifndef __dll__
#define __dll__
#include
using namespace std;
// Basic structure to store elements of a list
struct Node {
int val; // contains the value
Node * next; // pointer to the next element in the list
Node * prev; // pointer to the previous element in the list
};
// Class List
class List {
public:
List(void); // Constructor
~List(void); // Destructor
void insert(int n); // This should insert n in the list
void reverse(void); // This should reverse the list
void print(void); // This shoiuld print the list
private:
Node * first; // Pointer to the first (if any) element in the list
};
#endif
main.cpp
#include
#include \"doubly-linked.h\"
using namespace std;
int main(void){
List l;
int n;
while(cin >> n){
l.insert(n);
}
// Print list as read from cin
l.print();
// Reverse the list and print it
l.reverse();
l.print();
// Reverse again and print it
l.reverse();
l.print();
return 0;
}
Solution
#include
using namespace std;
/* Linked list structure */
struct list {
struct list *prev;
int data;
struct list *next;
} *node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL;
class linkedlist {
public:
/* Function for create/insert node at the beginning of Linked list */
void insrt_frnt() {
list *addBeg = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addBeg->data;
if(first == NULL) {
addBeg->prev = NULL;
addBeg->next = NULL;
first = addBeg;
last = addBeg;
cout << \"Linked list Created!\" << endl;
}
else {
addBeg->prev = NULL;
first->prev = addBeg;
addBeg->next = first;
first = addBeg;
cout << \"Data Inserted at the beginning of the Linked list!\" << endl;
}
}
/* Function for create/insert node at the end of Linked list */
void insrt_end() {
list *addEnd = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addEnd->data;
if(first == NULL) {
addEnd->prev = NULL;
addEnd->next = NULL;
first = addEnd;
last = addEnd;
cout << \"Linked list Created!\" << endl;
}
else {
addEnd->next = NULL;
last->next = addEnd;
addEnd->prev = last;
last = addEnd;
cout << \"Data Inserted at the end of the Linked list!\" << endl;
}
}
/* Function for Display Linked list */
void display() {
node = first;
cout << \"List of data in L.
could you implement this function please, im having issues with it..pdf
could you implement this function please, im having issues with it..pdfferoz544 could you implement this function please, im having issues with it.
void makeList (const ListNode::value_type [],const size_t& count)
class ListNode
{
public:
typedef int value_type;
ListNode (value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum () const { return datum; }
ListNode const* getNext () const { return next; }
//Mutator
void setDatum (const value_type& d) {datum = d; }
ListNode* getNext () { return next; }
void setNext (ListNode* new_link) {next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList ();
virtual ~LinkedList ();
void insertItem (ListNode::value_type);
void makeList (const ListNode::value_type [],const size_t& count);
void deleteList ();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
This is the pseudocode, but i still have a hard time undertanding it.
Creating a List (makeList(const ListNode::value_type [],const size_t& count)) This function
receives an array in the order that we want to add it to the linkedlist. Index 0 will be the head
node, index n will be the last node.
First, create a node initialized with a data value and a NULL pointer. Set the \"head\" to point to
the first node. Set up a current-pointer to the first node (or \"head\"). Get a data value for the next
node. While more nodes to add { Create a new node initialized with the data value and a NULL
pointer. Set the current-pointer link member (\"next\") to the new node. Set the current-pointer to
point to the new node. Get a data value for the next node. }
Thanks.
Solution
//linkedList.h
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
#include
#include
class ListNode
{
public:
typedef int value_type;
ListNode(value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum() const { return datum; }
ListNode const* getNext() const { return next; }
//Mutator
void setDatum(const value_type& d) { datum = d; }
ListNode* getNext() { return next; }
void setNext(ListNode* new_link) { next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList();
virtual ~LinkedList();
void insertItem(ListNode::value_type);
void makeList(const ListNode::value_type[], const size_t& count);
void deleteList();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
#endif
-------------------------------------------------------------
//linkedList.cpp
#include \"linkedlist.h\"
LinkedList::LinkedList()
{
head = NULL;
}
LinkedList::~LinkedList()
{
ListNode *tmp = head;
while (tmp != NULL)
{
head = head->getNext();
delete tmp;
tmp = head;
}
}
void LinkedList::insertItem(ListNode::value_type item)
{
ListNode *newNode,*cur = head;
newNode = new ListNode;
newNode->setDatum(item);
newNode->setNext(NULL);.
In the class we extensively discussed a node class called IntNode in.pdf
In the class we extensively discussed a node class called IntNode in.pdfarjunstores123 In the class we extensively discussed a node class called IntNode in which each linked list node
contains an integer and each node is linked forward to the next element in the list. Implement a
node class called DoublyIntNode in which each node contains an integer number and each node
is linked not only forward to the next element in the list but also backward to the previous
element in the list. Your implementation of DoublyIntNode should adapt and implement all the
methods of IntNode including the following methods:
Constructor for DoublyIntNode
addNodeAfter, removeNodeAfter
getData, setData
getForeLink, setForeLink
getBackLink, setBackLink
listCopy
listCopyWithTail
listLength
listPart
listPosition
listSearch
IntNode and Node classes:
public class IntNode{
private int data;
private IntNode link;
// methods here
}
public class Node {
private E data;
private Node link;
// methods here
}
Solution
program
#include
using namespace std;
struct list
{
struct list *prev;
int data;
struct list *next;
}
*node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL;
class Dlist
{
public:
void insert_beg() {
list *addBeg = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addBeg->data;
if(first == NULL) {
addBeg->prev = NULL;
addBeg->next = NULL;
first = addBeg;
last = addBeg;
cout << \"Linked list Created!\" << endl;
}
else {
addBeg->prev = NULL;
first->prev = addBeg;
addBeg->next = first;
first = addBeg;
cout << \"Data Inserted at the beginning of the Linked list!\" << endl;
}
}
void insert_end() {
list *addEnd = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addEnd->data;
if(first == NULL) {
addEnd->prev = NULL;
addEnd->next = NULL;
first = addEnd;
last = addEnd;
cout << \"Linked list Created!\" << endl;
}
else {
addEnd->next = NULL;
last->next = addEnd;
addEnd->prev = last;
last = addEnd;
cout << \"Data Inserted at the end of the Linked list!\" << endl;
}
}
void display() {
node = first;
cout << \"List of data in Linked list in Ascending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->next;
}
node = last;
cout << \"List of data in Linked list in Descending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->prev;
}
}
void del()
{
int count = 0, number, i;
node = node1 = node2 = first;
for(node = first; node != NULL; node = node->next)
cout << \"Enter value for the node:\" << endl;
count++;
display();
cout << count << \" nodes available here!\" << endl;
cout << \"Enter the node number which you want to delete:\" << endl;
cin >> number;
if(number != 1)
{
if(number < count && number > 0)
{
for(i = 2; i <= number; i++)
node = node->next;
for(i = 2; i <= number-1; i++)
node1 = node1->next;
for(i = 2; i <= number+1; i++)
node2 = node2->next;
node2->prev = node1;
node1->next = node2;
node->prev = NULL;
node->next = NULL;
node = NULL;
}
else if(number == count)
{
node = last;
last = node->prev;
last->next = NULL;
node = NULL;
}
else
cout << \"Invalid node.
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main() that reads a second input line and removes numbers from the list. Test in develop mode to
ensure that insertion and removal both work properly, then submit code for grading. Ex: If input
is 84 72 19 61 19 84 then output is: List after inserting 84: 84 List after inserting 72: 72 84 List
after inserting 19: 19 72 84 List after inserting 61: 19 61 72 84 List after removing 19: 61 72 84
List after removing 84: 61 72
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#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std; void PrintList(SortedNumberList& list); vector SpaceSplit(string source);
int main(int argc, char *argv[]) { // Read the line of input numbers string inputLine; getline(cin,
inputLine); // Split on space character vector terms = SpaceSplit(inputLine); // Insert each value
and show the sorted list's contents after each insertion SortedNumberList list; for (auto term :
terms) { double number = stod(term); cout << "List after inserting " << number << ": " << endl;
list.Insert(number); PrintList(list); } /* // Read the input line with numbers to remove getline(cin,
inputLi.
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needed
//TODO in ListNodecpp.h file
public: ListNode(T idata, ListNode<T> * newNext);
public: void setNext(ListNode<T> * newNext);
public: void setData(T newData);
// TODO in main program
void remove(ListNode<int> * &front,int value)
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# The driver is given ListNodeMain.cpp is given to you that does the following
tests
1. Declares a pointer called front to point to a ListNode of datatype integer
2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked
list.
3. Inserts ListNode with data 3 to the list
4. Removes node 1 and adds it back to test removing and adding the first
element
5. Removes node 3 to test removing a middle node
6. Removes node 4 to test removing the last node
7. Attempt to remove a non existent node
8. Remove all existing nodes to empty the list
9. Insert node 4 and then node 1 to test if insertions preserve order
10.Print the list
Main.cpp
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#include "ListNodecpp.h"
// REMEMBER each ListNode has two parts : a data field
// and an address field. The address is either null or points to the next node
//in the chain
//Requires: integer value for searching, address of front
//Effects: traverses the list node chain starting from front until the end comparing search value
with listnode getData. Returns the original search value if found, if not adds +1 to indicate not
found
//Modifies: Nothing
int search(ListNode<int> * front, int value);
//Requires: integer value for inserting, address of front
//Effects: creates a new ListNode with value and inserts in proper position (increasing order)in
the chain. If chain is empty, adds to the beginning
//Modifies: front, if node is added at the beginning.
//Also changes the next pointer of the previous node to point to the
//newly inserted list node. the next pointer of the newly inserted pointer
//points to what was the next of the previous node.
//This way both previous and current links are adjusted
//******** NOTE the use of & in passing pointer to front as parameter -
// Why do you think this is needed ?**********
void insert(ListNode<int> * &fr.
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c++ code:
Here is the list class:
#ifndef LIN_J_LIST
#define LIN_J_LIST
typedef unsigned int uint;
#include
#include
using namespace std;
/**
* a simplified generic singly linked list class to illustrate C++ concepts
* @author Jerry Lin
* @version 2/17/17
*/
template< typename Object >
class List
{
private:
/**
* A class to store data and provide a link to the next node in the list
*/
class Node
{
public:
/**
* The constructor
* @param data the data to be stored in this node
*/
explicit Node( const Object & data )
: data{ data }, next{ nullptr } {}
Object data;
Node * next;
};
public:
/**
* The constructor for an empty list
*/
List()
: size{ 0 }, first{ nullptr }, last{ nullptr } {}
/**
* the copy constructor-creates and copy the list
*/
List( List && rhs ) = delete;
List( const List & rhs )
{
count = 0;
size = 0;
if(rhs.size != 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first;
size++;
while(current->next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op.
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode->next;
size++;
}
}
// you document and implement this method
}
/**
* the operator= method-copies the list
*/
List & operator=( List && rhs) = delete;
List & operator=( const List & rhs )
{
count = 0;
size = 0;
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
if(rhs.size!= 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first; //create a temporary to store
size++;
while(current -> next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode -> next;
size++;
}
}
return *this;
// you document and implement this method
}
/**
* accessor
* @return count
*/
int get_count() const
{
return count;
}
/**
* The destructor that gets rid of everything that\'s in the list and
* resets it to empty. If the list is already empty, do nothing.
*/
~List()
{
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
}
/**
* Put a new element onto the beginning of the list
* @param item the data the new element will contain
*/
void push_front( const Object& item )
{
Node * new_node = new Node( item );//basic op.
if(is_empty())
{
last = new_node;
}
else
{
new_node->next = first;
}
first = new_node;
size++;
/* you complete the rest */
}
/**
* Remove the element that\'s at the front of the list. Causes an
* assertion error if the list is empty.
*/
void pop_front()
{
assert( !is_empty() );
Node * temp = first;
if( first == last )
{
first = last = nullptr;
}
else
{
first = first->next;
}
delete temp;
size--;
}
/**
* Accessor to return the da.
Assignment is Page 349-350 #4 and #5 Use the Linked Lis.pdf
Assignment is Page 349-350 #4 and #5 Use the Linked Lis.pdfformicreation Assignment is :
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Do not work
together; no two people should have identical work!?!? Turn in .cpp file AND Turn in a \"print-
screen\' of your output (press \"print-screen\' on keyboard, then \'paste\' in MS-Word)\"
How do you solve QUESTION #5 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void dele.
C++ Please write the whole code that is needed for this assignment- wr.docx
C++ Please write the whole code that is needed for this assignment- wr.docxBrianGHiNewmanv Brianca plans to save $5,000, $1,000, and $42,000 a year over the next three years, respectively. How much would you need to deposit in one lump sum today to have the same amount as Brianca three years from now if you both earn 10.9 percent, compounded annually? $36,115 $35,192 $43,282 $41,635 $35,372
.
#include iostream using namespace std; const int nil = 0; cl.docx
#include iostream using namespace std; const int nil = 0; cl.docxajoy21 The program implements a binary search tree to store 20 integers input by the user. It performs level order, preorder, inorder and postorder traversals of the tree, printing the value and level of each node. It also outputs the number of leaf nodes, nodes with one child, and nodes with two children. Finally, it calculates and prints the maximum and minimum leaf levels and checks if the tree is balanced.
in C++ , Design a linked list class named IntegerList to hold a seri.pdf
in C++ , Design a linked list class named IntegerList to hold a seri.pdfeyewaregallery in C++ , Design a linked list class named IntegerList to hold a series of integers. The class must
have public member functions for appending , inserting, deleting and displaying nodes. The
append function must append a node to the end of the list. The insert function must insert node in
ascending order. The delete function must delete the node with the given value. The display
function should display the list from head to tail. The IntegerList class should also have a
destructor that destroys the list and release memory. The list node must be declared as a structure
using keyword struct. This structure is a private member of IntegerList. You should also store the
head of the list as a private member.
Write a test program to test the implementation your IntegerList class works properly.
Solution
Here is the code for the above scenario:
#include
using namespace std;
struct ListNode
{
float value;
ListNode *next;
};
ListNode *head;
class LinkedList
{
public:
int insertNode(float num);
int appendNode(float num);
void deleteNode(float num);
void destroyList();
void displayList();
LinkedList(void) {head = NULL;}
~LinkedList(void) {destroyList();}
};
int LinkedList::appendNode(float num)
{
ListNode *newNode, *nodePtr = head;
newNode = new ListNode;
if(newNode == NULL)
{
cout << \"Error allocating memory for new list member!\ \";
return 1;
}
newNode->value = num;
newNode->next = NULL;
if(head == NULL)
{
cout << \"List was empty - \" << newNode->value;
cout << \" is part of list\'s first node.\ \";
head = newNode;
}
else
{
while(nodePtr->next != NULL)
nodePtr = nodePtr->next;
nodePtr->next = newNode;
}
return 0;
}
int LinkedList::insertNode(float num)
{
struct ListNode *newNode, *nodePtr = head, *prevNodePtr = NULL;
newNode = new ListNode;
if(newNode == NULL)
{
cout << \"Error allocating memory for new list member!\ \";
return 1;
}
newNode->value = num;
newNode->next = NULL;
if(head==NULL) {
cout << \"List was empty - \" << newNode->value;
cout << \" is part of list\'s first node.\ \";
head = newNode;
}
else
{
while((nodePtr != NULL) && (nodePtr->value < num)) {
prevNodePtr = nodePtr;
nodePtr = nodePtr->next;
}
if(prevNodePtr==NULL)
newNode->next = head;
else
newNode->next = nodePtr; prevNodePtr->next = newNode;
}
return 0;
}
void LinkedList::deleteNode(float num)
{
struct ListNode *nodePtr = head, *prevNodePtr = NULL;
if(head==NULL) {
cout << \"The list was empty!\ \";
return;
}
if(head->value == num) {
head = nodePtr->next;
delete [] nodePtr;
}
else
{
while((nodePtr!= NULL)&&(nodePtr->value != num)) {
prevNodePtr = nodePtr;
nodePtr = nodePtr->next;
}
if(nodePtr==NULL)
cout << \"The value \" << num << \" is not in this list!\ \";
else {
prevNodePtr->next = nodePtr->next;
delete [] nodePtr;
}
}
}
void LinkedList::destroyList()
{
struct ListNode *nodePtr = head, *nextNode = nodePtr;
if(head==NULL) {
cout << \"The list is empty!\ \";
return;
}
while (nodePtr != NULL) {
nextNode = nodePtr->next;
delete [] nodePtr;
nodePtr = nextNode;
}
}
void LinkedList.
DSA(1).pptx
DSA(1).pptxDaniyalAli81 The document summarizes key concepts about linked lists including different types like singly linked lists, doubly linked lists, and circular linked lists. It provides code examples for creating nodes and performing operations like insertion, deletion, and traversal for each type of linked list. Specifically, it shows code for inserting nodes at the head, tail, and middle of singly, doubly, and circular linked lists. It also includes code for deleting nodes from singly, doubly, and circular linked lists.
In C++ please, do not alter node.hStep 1 Inspect the Node.h file.pdf
In C++ please, do not alter node.hStep 1 Inspect the Node.h file.pdfstopgolook In C++ please, do not alter node.h
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new
node with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
77 15 -42 63.5
then output is:
List after inserting 77:
77 List after inserting 15:
15 77
List after inserting -42:
-42 15 77
List after inserting 63.5:
-42 15 63.5 77
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
84 72 19 61 19 84
then output is:
List after inserting 84:
84
List after inserting 72:
72 84
List after inserting 19:
19 72 84
List after inserting 61:
19 61 72 84
List after removing 19:
61 72 84
List after removing 84:
61 72
Code below:
main.cpp
#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = Space.
C code on linked list #include stdio.h #include stdlib.h.pdf
C code on linked list #include stdio.h #include stdlib.h.pdfdeepua8 The C code defines functions to create and manipulate a linked list. It takes 5 user-input values, inserts them into an empty linked list, prints the list, takes another input value and inserts it, then prints the final list.
C program to insert a node in doubly linked list
C program to insert a node in doubly linked listSourav Gayen This C program implements functions to create and manipulate a doubly linked list. It allows the user to choose from a menu to create a list, insert nodes at the beginning, end, or a specified position, and display the list. Functions are defined to create a list by dynamically allocating nodes and linking them together, insert nodes at different positions by updating next and prev pointers, and display the list by traversing from head to tail.
Help I keep getting the same error when running a code. Below is the.pdf
Help I keep getting the same error when running a code. Below is the.pdfmail931892 Help I keep getting the same error when running a code. Below is the code and the instructions
about the code.
import java.util.Arrays;
public class Album implements Comparable {
private final int id;
private final String[] artists;
private final int numSongs;
public Album(int id, String title, String[] artists, int numSongs) {
this.id = id;
this.artists = new String[]{Arrays.toString(artists)};
this.numSongs = numSongs;
}
public int getId() {
return id;
}
@Override
public int compareTo(Album other) {
return Integer.compare(this.numSongs, other.numSongs);
}
@Override
public String toString() {
StringBuilder artistNames = new StringBuilder();
for (String artist : artists) {
artistNames.append(artist).append(", ");
}
artistNames.delete(artistNames.length() - 2, artistNames.length());
return "ID: " + id + " -- " + numSongs + " songs -- [" + artistNames + "]";
}
}
import java.util.Random;
public class DoublyLinkedList {
private static class Node {
T data;
Node prev;
Node next;
Node(T data) {
this.data = data;
}
}
private Node head;
private Node tail;
private int size;
public DoublyLinkedList() {
head = null;
tail = null;
size = 0;
}
public Node append(T data) {
Node newNode = new Node<>(data);
if (head == null) {
head = newNode;
} else {
tail.next = newNode;
newNode.prev = tail;
}
tail = newNode;
size++;
return newNode;
}
public Node insert(int location, T data) {
if (location < 0 || location > size) {
throw new IllegalArgumentException("Invalid location");
}
Node newNode = new Node<>(data);
if (location == 0) {
newNode.next = head;
if (head != null) {
head.prev = newNode;
}
head = newNode;
if (tail == null) {
tail = newNode;
}
} else if (location == size) {
tail.next = newNode;
newNode.prev = tail;
tail = newNode;
} else {
Node current = head;
for (int i = 0; i < location; i++) {
current = current.next;
}
newNode.prev = current.prev;
newNode.next = current;
current.prev.next = newNode;
current.prev = newNode;
}
size++;
return newNode;
}
public Node delete(int location) {
if (location < 0 || location >= size) {
throw new IllegalArgumentException("Invalid location");
}
Node deletedNode;
if (location == 0) {
deletedNode = head;
head = head.next;
if (head != null) {
head.prev = null;
} else {
tail = null;
}
} else if (location == size - 1) {
deletedNode = tail;
tail = tail.prev;
tail.next = null;
} else {
Node current = head;
for (int i = 0; i < location; i++) {
current = current.next;
}
deletedNode = current;
current.prev.next = current.next;
current.next.prev = current.prev;
}
size--;
return deletedNode;
}
public int getIndex(T data) {
Node current = head;
for (int i = 0; i < size; i++) {
if (current.data.equals(data)) {
return i;
}
current = current.next;
}
return -1;
}
@Override
public String toString() {
StringBuilder result = new StringBuilder();
Node current = head;
while (current != null) {
result.append(current.data).append(" -> ");
current = current.next;
}
result.append("NULL");
return result.toString();
}
public Node shuffle() {
Random r.
FP 201 - Unit 6
FP 201 - Unit 6rohassanie Pointer variables store memory addresses and can be used to indirectly access other variables. Pointers allow values to be passed by reference into functions rather than by value. Arrays can be accessed using pointers by treating the array name as a pointer to its first element. Dynamic memory allocation with new/delete operators allows pointers to reference variables in heap memory.
Implement the unsorted single linked list as we did in the class and .pdf
Implement the unsorted single linked list as we did in the class and .pdfarihantstoneart Implement the unsorted single linked list as we did in the class and implement the following
operations: 1.DeletelastDuplicat(): For any element in the linked list, if there are multiple copies
(> = 2 copies), delete the last copy. DeleteSecondlastDuplicat(): For any element in the linked
list, if there are multiple copies (> = 2 copies), delete the second last copy Test your program
with the following operations: a)insert 5 b)Insert 7 c)Insert 11 d)Insert 5 e)Insert f) Insert 5 g)
Print out the list h) Delete the last duplicate of 5 i)Print out the list i) Delete the last duplicate
of 11 k) Print out the list I) Insert 11 m) Insert 7 n) Print out the list O) Delete the second last
duplicate of 5 p) Print out the list q) Delete the second last duplicate of 7 r) Print out the list
Solution
#include
#include
#include
using namespace std;
struct node
{
int data;
struct node *next;
}*start;
class LinkedList
{
public:
node* create_node(int);
void insert_begin();
void insert_pos();
void insert_last();
void delete_pos(int);
void delete_lastdup();
void delete_seclast();
int search(int);
void display();
int get_count(int);
LinkedList()
{
start = NULL;
}
};
int main()
{
int choice, pos, value, res=0;
LinkedList sl;
start = NULL;
while (1)
{
cout<>choice;
switch(choice)
{
case 1:
cout<<\"Inserting Node at Beginning: \"<>pos;
sl.delete_pos(pos);
break;
case 5:
cout<<\"Search element in Link List: \"<>value;
res=sl.search(value);
cout<<\"Element \"<data = value;
temp->next = NULL;
return temp;
}
}
//function to insert element at beginning
void LinkedList::insert_begin()
{
int value;
cout<<\"Enter the value to be inserted: \";
cin>>value;
struct node *temp, *p;
temp = create_node(value);
if (start == NULL)
{
start = temp;
start->next = NULL;
}
else
{
p = start;
start = temp;
start->next = p;
}
cout<<\"Element Inserted at beginning\"<next != NULL)
{
if(s->data == value)
count++;
s = s->next;
}
return count;
}
//function to insert node at last
void LinkedList::insert_last()
{
int value;
cout<<\"Enter the value to be inserted: \";
cin>>value;
struct node *temp, *s;
temp = create_node(value);
s = start;
while (s->next != NULL)
{
s = s->next;
}
temp->next = NULL;
s->next = temp;
cout<<\"Element Inserted at last\"<>value;
struct node *temp, *s, *ptr;
temp = create_node(value);
cout<<\"Enter the postion at which node to be inserted: \";
cin>>pos;
int i;
s = start;
while (s != NULL)
{
s = s->next;
counter++;
}
if (pos == 1)
{
if (start == NULL)
{
start = temp;
start->next = NULL;
}
else
{
ptr = start;
start = temp;
start->next = ptr;
}
}
else if (pos > 1 && pos <= counter)
{
s = start;
for (i = 1; i < pos; i++)
{
ptr = s;
s = s->next;
}
ptr->next = temp;
temp->next = s;
}
else
{
cout<<\"Positon out of range\"<>value;
c=get_count(value);
if(c<2)
{
cout<<\"duplicate does not exist\"<>value;
c=get_count(value);
x=c-1;
if(c<2)
{
cout<<\"duplicate does not exist\"<data == value)
{
f++;
res=pos;
if(f==x)
break;
}
s = s->next;
}
delete_pos(res);
}
}
//delete element at p.
Linkedlist
LinkedlistMasud Parvaze Linked lists are a data structure where each node contains a pointer to the next node in the list. Each node contains data and a pointer to the next node. The last node's pointer is set to NULL. Linked lists can dynamically grow and shrink during program execution. Nodes are implemented as structs containing data and a pointer. The head pointer points to the first node. Linked lists allow traversing the list by following node pointers until NULL is reached.
dynamicList.ppt
dynamicList.pptssuser0be977 The document discusses implementing a sorted linked list data structure in C++. It describes how to insert a new node into the linked list in the correct sorted position by finding the previous and current nodes between which the new node should be inserted. The key steps are to create a new node, find the previous and current nodes using a while loop, and connect the new node by updating the next pointers of the previous and current nodes.
Please complete the assignment listed below.Define and explain, us.docx
Please complete the assignment listed below.Define and explain, us.docxajoy21 Please complete the assignment listed below.
Define and explain, using at least five sentence or on-task bullet notes for each. Each answer earns up to five points. For each answer, please make five different substantive points, earning one point each.
Transnational corporation
Gentrification
Renewable resources
Desertification
Photochemical smog
Biodiversity
Barriers to migration
Hierarchical diffusion
Militant fundamentalism
Urbanization
Eastern European cities
Hazardous waste
The Endangered Species Act
Subsidence
Water Quality
Deforestation
Wetlands
Central place theory
Soil degradation
Hydraulic fracturing (fracking)
Wind power
Oil sands
Models of urban form
Hinterland
Agglomeration economies
.
Please cite sources for each question. Do not use the same sources f.docx
Please cite sources for each question. Do not use the same sources f.docxajoy21 Please cite sources for each question. Do not use the same sources for each question. Minimum of 2 resources and 300 words.
Briefly contrast the views of Locke and Rousseau on how children develop.
a) What do ethologists, such as Lorenz, mean by imprinting on a parent-figure?
b) What observations led Bowlby to suggest that imprinting occurs in human infants? That is, what parallels between human infants and other species did he point to?
"For children to learn, we must praise their correct responses and correct their mistakes." Would Montessori agree? Explain.
What did Werner mean by "microgenesis" and "microgenetic mobility?" Give examples. Discuss some valuable aspects of these concepts.
Piaget's critics charge that he made development appear too slow. Discuss this criticism with respect to either: a) object permanence, b) conservation training, or c) Kamii's teaching methods. Then, describe the Piagetian approach.
Compare conventional and postconventional morality in Kohlberg's theory.
.
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This assignment and the next (#5) involve design and development of a.pdf
This assignment and the next (#5) involve design and development of a.pdfEricvtJFraserr This assignment and the next (#5) involve design and development of a sequential
non contiguous and dynamic datastructure called LinkedList. A linked list object is
a container consisting of connected ListNode objects. As before, we are not going
to use pre-fabricated classes from the c++ library, but construct the LinkedList
ADT from scratch.
The first step is construction and testing of the ListNode class. A ListNode object
contains a data field and a pointer to the next ListNode object (note the recursive
definition).
#This assignment requires you to
1. Read the Assignment 4 Notes
2. Watch the Assignment 4 Support video
3. Implement the following methods of the ListNode class
-custom constructor
-setters for next pointer and data
4. Implement the insert and remove method in the main program
5. Scan the given template to find the above //TODO and implement the code
needed
//TODO in ListNodecpp.h file
public: ListNode(T idata, ListNode<T> * newNext);
public: void setNext(ListNode<T> * newNext);
public: void setData(T newData);
// TODO in main program
void remove(ListNode<int> * &front,int value)
void insert(ListNode<int> * &front,int value)
# The driver is given ListNodeMain.cpp is given to you that does the following
tests
1. Declares a pointer called front to point to a ListNode of datatype integer
2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked
list.
3. Inserts ListNode with data 3 to the list
4. Removes node 1 and adds it back to test removing and adding the first
element
5. Removes node 3 to test removing a middle node
6. Removes node 4 to test removing the last node
7. Attempt to remove a non existent node
8. Remove all existing nodes to empty the list
9. Insert node 4 and then node 1 to test if insertions preserve order
10.Print the list
Main.cpp
#include <iostream>
#include "ListNodecpp.h"
// REMEMBER each ListNode has two parts : a data field
// and an address field. The address is either null or points to the next node
//in the chain
//Requires: integer value for searching, address of front
//Effects: traverses the list node chain starting from front until the end comparing search value
with listnode getData. Returns the original search value if found, if not adds +1 to indicate not
found
//Modifies: Nothing
int search(ListNode<int> * front, int value);
//Requires: integer value for inserting, address of front
//Effects: creates a new ListNode with value and inserts in proper position (increasing order)in
the chain. If chain is empty, adds to the beginning
//Modifies: front, if node is added at the beginning.
//Also changes the next pointer of the previous node to point to the
//newly inserted list node. the next pointer of the newly inserted pointer
//points to what was the next of the previous node.
//This way both previous and current links are adjusted
//******** NOTE the use of & in passing pointer to front as parameter -
// Why do you think this is needed ?**********
void insert(ListNode<int> * &fr.
week-13x
week-13xKITE www.kitecolleges.com The document describes a C program to create a sorted linked list from an unsorted list of numbers. It includes functions to insert nodes in sorted order, print the list, and count the number of nodes. The main function accepts user input to build the initial list, then calls the insert_sort function to sort it and other functions to output the sorted list and count of nodes.
Data Structures and Agorithm: DS 05 Doubly Linked List.pptx
Data Structures and Agorithm: DS 05 Doubly Linked List.pptxRashidFaridChishti Data Structures and Agorithm: DS 05 Doubly Linked List.pptx
Write java program using linked list to get integer from user and.docx
Write java program using linked list to get integer from user and.docxajoy21 This document provides the code for a Java program that uses a linked list to count even and odd numbers entered by the user. The program defines a Node class to create nodes for the linked list. It also defines methods to push nodes onto the front of the list, segregate the even and odd nodes, and print the list. The main method tests the program by pushing sample integers onto a linked list, segregating the even and odd nodes, and printing the modified list.
How do you stop infinite loop Because I believe that it is making a.pdf
How do you stop infinite loop Because I believe that it is making a.pdffeelinggift How do you stop infinite loop? Because I believe that it is making an infinite circular list.
c++ code:
Here is the list class:
#ifndef LIN_J_LIST
#define LIN_J_LIST
typedef unsigned int uint;
#include
#include
using namespace std;
/**
* a simplified generic singly linked list class to illustrate C++ concepts
* @author Jerry Lin
* @version 2/17/17
*/
template< typename Object >
class List
{
private:
/**
* A class to store data and provide a link to the next node in the list
*/
class Node
{
public:
/**
* The constructor
* @param data the data to be stored in this node
*/
explicit Node( const Object & data )
: data{ data }, next{ nullptr } {}
Object data;
Node * next;
};
public:
/**
* The constructor for an empty list
*/
List()
: size{ 0 }, first{ nullptr }, last{ nullptr } {}
/**
* the copy constructor-creates and copy the list
*/
List( List && rhs ) = delete;
List( const List & rhs )
{
count = 0;
size = 0;
if(rhs.size != 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first;
size++;
while(current->next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op.
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode->next;
size++;
}
}
// you document and implement this method
}
/**
* the operator= method-copies the list
*/
List & operator=( List && rhs) = delete;
List & operator=( const List & rhs )
{
count = 0;
size = 0;
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
if(rhs.size!= 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first; //create a temporary to store
size++;
while(current -> next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode -> next;
size++;
}
}
return *this;
// you document and implement this method
}
/**
* accessor
* @return count
*/
int get_count() const
{
return count;
}
/**
* The destructor that gets rid of everything that\'s in the list and
* resets it to empty. If the list is already empty, do nothing.
*/
~List()
{
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
}
/**
* Put a new element onto the beginning of the list
* @param item the data the new element will contain
*/
void push_front( const Object& item )
{
Node * new_node = new Node( item );//basic op.
if(is_empty())
{
last = new_node;
}
else
{
new_node->next = first;
}
first = new_node;
size++;
/* you complete the rest */
}
/**
* Remove the element that\'s at the front of the list. Causes an
* assertion error if the list is empty.
*/
void pop_front()
{
assert( !is_empty() );
Node * temp = first;
if( first == last )
{
first = last = nullptr;
}
else
{
first = first->next;
}
delete temp;
size--;
}
/**
* Accessor to return the da.
Assignment is Page 349-350 #4 and #5 Use the Linked Lis.pdf
Assignment is Page 349-350 #4 and #5 Use the Linked Lis.pdfformicreation Assignment is :
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Do not work
together; no two people should have identical work!?!? Turn in .cpp file AND Turn in a \"print-
screen\' of your output (press \"print-screen\' on keyboard, then \'paste\' in MS-Word)\"
How do you solve QUESTION #5 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void dele.
C++ Please write the whole code that is needed for this assignment- wr.docx
C++ Please write the whole code that is needed for this assignment- wr.docxBrianGHiNewmanv Brianca plans to save $5,000, $1,000, and $42,000 a year over the next three years, respectively. How much would you need to deposit in one lump sum today to have the same amount as Brianca three years from now if you both earn 10.9 percent, compounded annually? $36,115 $35,192 $43,282 $41,635 $35,372
.
#include iostream using namespace std; const int nil = 0; cl.docx
#include iostream using namespace std; const int nil = 0; cl.docxajoy21 The program implements a binary search tree to store 20 integers input by the user. It performs level order, preorder, inorder and postorder traversals of the tree, printing the value and level of each node. It also outputs the number of leaf nodes, nodes with one child, and nodes with two children. Finally, it calculates and prints the maximum and minimum leaf levels and checks if the tree is balanced.
in C++ , Design a linked list class named IntegerList to hold a seri.pdf
in C++ , Design a linked list class named IntegerList to hold a seri.pdfeyewaregallery in C++ , Design a linked list class named IntegerList to hold a series of integers. The class must
have public member functions for appending , inserting, deleting and displaying nodes. The
append function must append a node to the end of the list. The insert function must insert node in
ascending order. The delete function must delete the node with the given value. The display
function should display the list from head to tail. The IntegerList class should also have a
destructor that destroys the list and release memory. The list node must be declared as a structure
using keyword struct. This structure is a private member of IntegerList. You should also store the
head of the list as a private member.
Write a test program to test the implementation your IntegerList class works properly.
Solution
Here is the code for the above scenario:
#include
using namespace std;
struct ListNode
{
float value;
ListNode *next;
};
ListNode *head;
class LinkedList
{
public:
int insertNode(float num);
int appendNode(float num);
void deleteNode(float num);
void destroyList();
void displayList();
LinkedList(void) {head = NULL;}
~LinkedList(void) {destroyList();}
};
int LinkedList::appendNode(float num)
{
ListNode *newNode, *nodePtr = head;
newNode = new ListNode;
if(newNode == NULL)
{
cout << \"Error allocating memory for new list member!\ \";
return 1;
}
newNode->value = num;
newNode->next = NULL;
if(head == NULL)
{
cout << \"List was empty - \" << newNode->value;
cout << \" is part of list\'s first node.\ \";
head = newNode;
}
else
{
while(nodePtr->next != NULL)
nodePtr = nodePtr->next;
nodePtr->next = newNode;
}
return 0;
}
int LinkedList::insertNode(float num)
{
struct ListNode *newNode, *nodePtr = head, *prevNodePtr = NULL;
newNode = new ListNode;
if(newNode == NULL)
{
cout << \"Error allocating memory for new list member!\ \";
return 1;
}
newNode->value = num;
newNode->next = NULL;
if(head==NULL) {
cout << \"List was empty - \" << newNode->value;
cout << \" is part of list\'s first node.\ \";
head = newNode;
}
else
{
while((nodePtr != NULL) && (nodePtr->value < num)) {
prevNodePtr = nodePtr;
nodePtr = nodePtr->next;
}
if(prevNodePtr==NULL)
newNode->next = head;
else
newNode->next = nodePtr; prevNodePtr->next = newNode;
}
return 0;
}
void LinkedList::deleteNode(float num)
{
struct ListNode *nodePtr = head, *prevNodePtr = NULL;
if(head==NULL) {
cout << \"The list was empty!\ \";
return;
}
if(head->value == num) {
head = nodePtr->next;
delete [] nodePtr;
}
else
{
while((nodePtr!= NULL)&&(nodePtr->value != num)) {
prevNodePtr = nodePtr;
nodePtr = nodePtr->next;
}
if(nodePtr==NULL)
cout << \"The value \" << num << \" is not in this list!\ \";
else {
prevNodePtr->next = nodePtr->next;
delete [] nodePtr;
}
}
}
void LinkedList::destroyList()
{
struct ListNode *nodePtr = head, *nextNode = nodePtr;
if(head==NULL) {
cout << \"The list is empty!\ \";
return;
}
while (nodePtr != NULL) {
nextNode = nodePtr->next;
delete [] nodePtr;
nodePtr = nextNode;
}
}
void LinkedList.
DSA(1).pptx
DSA(1).pptxDaniyalAli81 The document summarizes key concepts about linked lists including different types like singly linked lists, doubly linked lists, and circular linked lists. It provides code examples for creating nodes and performing operations like insertion, deletion, and traversal for each type of linked list. Specifically, it shows code for inserting nodes at the head, tail, and middle of singly, doubly, and circular linked lists. It also includes code for deleting nodes from singly, doubly, and circular linked lists.
In C++ please, do not alter node.hStep 1 Inspect the Node.h file.pdf
In C++ please, do not alter node.hStep 1 Inspect the Node.h file.pdfstopgolook In C++ please, do not alter node.h
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new
node with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
77 15 -42 63.5
then output is:
List after inserting 77:
77 List after inserting 15:
15 77
List after inserting -42:
-42 15 77
List after inserting 63.5:
-42 15 63.5 77
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
84 72 19 61 19 84
then output is:
List after inserting 84:
84
List after inserting 72:
72 84
List after inserting 19:
19 72 84
List after inserting 61:
19 61 72 84
List after removing 19:
61 72 84
List after removing 84:
61 72
Code below:
main.cpp
#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = Space.
C code on linked list #include stdio.h #include stdlib.h.pdf
C code on linked list #include stdio.h #include stdlib.h.pdfdeepua8 The C code defines functions to create and manipulate a linked list. It takes 5 user-input values, inserts them into an empty linked list, prints the list, takes another input value and inserts it, then prints the final list.
C program to insert a node in doubly linked list
C program to insert a node in doubly linked listSourav Gayen This C program implements functions to create and manipulate a doubly linked list. It allows the user to choose from a menu to create a list, insert nodes at the beginning, end, or a specified position, and display the list. Functions are defined to create a list by dynamically allocating nodes and linking them together, insert nodes at different positions by updating next and prev pointers, and display the list by traversing from head to tail.
Help I keep getting the same error when running a code. Below is the.pdf
Help I keep getting the same error when running a code. Below is the.pdfmail931892 Help I keep getting the same error when running a code. Below is the code and the instructions
about the code.
import java.util.Arrays;
public class Album implements Comparable {
private final int id;
private final String[] artists;
private final int numSongs;
public Album(int id, String title, String[] artists, int numSongs) {
this.id = id;
this.artists = new String[]{Arrays.toString(artists)};
this.numSongs = numSongs;
}
public int getId() {
return id;
}
@Override
public int compareTo(Album other) {
return Integer.compare(this.numSongs, other.numSongs);
}
@Override
public String toString() {
StringBuilder artistNames = new StringBuilder();
for (String artist : artists) {
artistNames.append(artist).append(", ");
}
artistNames.delete(artistNames.length() - 2, artistNames.length());
return "ID: " + id + " -- " + numSongs + " songs -- [" + artistNames + "]";
}
}
import java.util.Random;
public class DoublyLinkedList {
private static class Node {
T data;
Node prev;
Node next;
Node(T data) {
this.data = data;
}
}
private Node head;
private Node tail;
private int size;
public DoublyLinkedList() {
head = null;
tail = null;
size = 0;
}
public Node append(T data) {
Node newNode = new Node<>(data);
if (head == null) {
head = newNode;
} else {
tail.next = newNode;
newNode.prev = tail;
}
tail = newNode;
size++;
return newNode;
}
public Node insert(int location, T data) {
if (location < 0 || location > size) {
throw new IllegalArgumentException("Invalid location");
}
Node newNode = new Node<>(data);
if (location == 0) {
newNode.next = head;
if (head != null) {
head.prev = newNode;
}
head = newNode;
if (tail == null) {
tail = newNode;
}
} else if (location == size) {
tail.next = newNode;
newNode.prev = tail;
tail = newNode;
} else {
Node current = head;
for (int i = 0; i < location; i++) {
current = current.next;
}
newNode.prev = current.prev;
newNode.next = current;
current.prev.next = newNode;
current.prev = newNode;
}
size++;
return newNode;
}
public Node delete(int location) {
if (location < 0 || location >= size) {
throw new IllegalArgumentException("Invalid location");
}
Node deletedNode;
if (location == 0) {
deletedNode = head;
head = head.next;
if (head != null) {
head.prev = null;
} else {
tail = null;
}
} else if (location == size - 1) {
deletedNode = tail;
tail = tail.prev;
tail.next = null;
} else {
Node current = head;
for (int i = 0; i < location; i++) {
current = current.next;
}
deletedNode = current;
current.prev.next = current.next;
current.next.prev = current.prev;
}
size--;
return deletedNode;
}
public int getIndex(T data) {
Node current = head;
for (int i = 0; i < size; i++) {
if (current.data.equals(data)) {
return i;
}
current = current.next;
}
return -1;
}
@Override
public String toString() {
StringBuilder result = new StringBuilder();
Node current = head;
while (current != null) {
result.append(current.data).append(" -> ");
current = current.next;
}
result.append("NULL");
return result.toString();
}
public Node shuffle() {
Random r.
FP 201 - Unit 6
FP 201 - Unit 6rohassanie Pointer variables store memory addresses and can be used to indirectly access other variables. Pointers allow values to be passed by reference into functions rather than by value. Arrays can be accessed using pointers by treating the array name as a pointer to its first element. Dynamic memory allocation with new/delete operators allows pointers to reference variables in heap memory.
Implement the unsorted single linked list as we did in the class and .pdf
Implement the unsorted single linked list as we did in the class and .pdfarihantstoneart Implement the unsorted single linked list as we did in the class and implement the following
operations: 1.DeletelastDuplicat(): For any element in the linked list, if there are multiple copies
(> = 2 copies), delete the last copy. DeleteSecondlastDuplicat(): For any element in the linked
list, if there are multiple copies (> = 2 copies), delete the second last copy Test your program
with the following operations: a)insert 5 b)Insert 7 c)Insert 11 d)Insert 5 e)Insert f) Insert 5 g)
Print out the list h) Delete the last duplicate of 5 i)Print out the list i) Delete the last duplicate
of 11 k) Print out the list I) Insert 11 m) Insert 7 n) Print out the list O) Delete the second last
duplicate of 5 p) Print out the list q) Delete the second last duplicate of 7 r) Print out the list
Solution
#include
#include
#include
using namespace std;
struct node
{
int data;
struct node *next;
}*start;
class LinkedList
{
public:
node* create_node(int);
void insert_begin();
void insert_pos();
void insert_last();
void delete_pos(int);
void delete_lastdup();
void delete_seclast();
int search(int);
void display();
int get_count(int);
LinkedList()
{
start = NULL;
}
};
int main()
{
int choice, pos, value, res=0;
LinkedList sl;
start = NULL;
while (1)
{
cout<>choice;
switch(choice)
{
case 1:
cout<<\"Inserting Node at Beginning: \"<>pos;
sl.delete_pos(pos);
break;
case 5:
cout<<\"Search element in Link List: \"<>value;
res=sl.search(value);
cout<<\"Element \"<data = value;
temp->next = NULL;
return temp;
}
}
//function to insert element at beginning
void LinkedList::insert_begin()
{
int value;
cout<<\"Enter the value to be inserted: \";
cin>>value;
struct node *temp, *p;
temp = create_node(value);
if (start == NULL)
{
start = temp;
start->next = NULL;
}
else
{
p = start;
start = temp;
start->next = p;
}
cout<<\"Element Inserted at beginning\"<next != NULL)
{
if(s->data == value)
count++;
s = s->next;
}
return count;
}
//function to insert node at last
void LinkedList::insert_last()
{
int value;
cout<<\"Enter the value to be inserted: \";
cin>>value;
struct node *temp, *s;
temp = create_node(value);
s = start;
while (s->next != NULL)
{
s = s->next;
}
temp->next = NULL;
s->next = temp;
cout<<\"Element Inserted at last\"<>value;
struct node *temp, *s, *ptr;
temp = create_node(value);
cout<<\"Enter the postion at which node to be inserted: \";
cin>>pos;
int i;
s = start;
while (s != NULL)
{
s = s->next;
counter++;
}
if (pos == 1)
{
if (start == NULL)
{
start = temp;
start->next = NULL;
}
else
{
ptr = start;
start = temp;
start->next = ptr;
}
}
else if (pos > 1 && pos <= counter)
{
s = start;
for (i = 1; i < pos; i++)
{
ptr = s;
s = s->next;
}
ptr->next = temp;
temp->next = s;
}
else
{
cout<<\"Positon out of range\"<>value;
c=get_count(value);
if(c<2)
{
cout<<\"duplicate does not exist\"<>value;
c=get_count(value);
x=c-1;
if(c<2)
{
cout<<\"duplicate does not exist\"<data == value)
{
f++;
res=pos;
if(f==x)
break;
}
s = s->next;
}
delete_pos(res);
}
}
//delete element at p.
Linkedlist
LinkedlistMasud Parvaze Linked lists are a data structure where each node contains a pointer to the next node in the list. Each node contains data and a pointer to the next node. The last node's pointer is set to NULL. Linked lists can dynamically grow and shrink during program execution. Nodes are implemented as structs containing data and a pointer. The head pointer points to the first node. Linked lists allow traversing the list by following node pointers until NULL is reached.
dynamicList.ppt
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References
American Nurses Association. (2010).
Nursing's social policy statement: The essence of the profession
. Nursesbooks. org.
Mason, D. J., Leavitt, J. K., & Chaffee, M. W. (2013).
Policy and Politics in Nursing and Healthcare-Revised Reprint
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1)
XYZ Company had three defined benefit plans with the following information:
12 Points
Plan 1
Plan 2
Plan 3
Expected Payment over next year
3,500,000
3,500,000
3,500,000
Fair Value of Plan Assets
5,000,000
6,000,000
3,000,000
Projected Benefit Obligation
7,000,000
5,500,000
4,500,000
Record the over/(under) funded status of each plan. Then determine the balance sheet presentation based on the over/(under) funded status. (Input an amount in each yellow cell. If zero, input zero.)
Plan 1
Plan 2
Plan 3
Over/ (Under) Funded Status
Noncurrent Asset
Current Liability**
Noncurrent Liability
** Think about the expected payment over the next year compared to the Plan Assets available.
2)
XYZ Company received the following information from its actuary team for the
10 points
year pertaining to one of its defined benefit plans:
Service Cost
120,000
Interest on Projected Benefit Obligation
55,000
Expected Return on Plan Assets
30,000
Amortization of Prior Service Cost
15,000
Amortization of Actuarial Gain
10,000
Calculate the Pension Expense for the year (show all items included in the calculation):
3)
At the end of year, XYZ Corporation had the following pension related information in addition to the above information:
12 points
12/31/X1
12/31/X2
Fair Value of Plan Assets
405,000
505,000
Projected Benefit Obligation
1,065,000
1,035,000
Funded Status
(660,000)
(530,000)
Record the Necessary Journal Entries:
Entry to record Service Cost, Interest Cost and Return on Plan Assets:
Account Name:
Debit
Credit
Amortization of Prior Service Cost and/or Actuarial Losses:
Account Name:
Debit
Credit
Amortization of Actuarial Gains:
Account Name:
Debit
Credit
4)
a) Identify a US Company that offers a Defined Benefit Plan and review the 10K information for 2016 of the identified company and provide a brief analysis based on footnotes related to the plan.
3 points
b) Include screenshots to report the Funded Status and Pension Expense information for the selected plan.
1 Points
c) Record the associated journal entries based on the screenshots for that company.
12 points
Entry to record Service Cost, Interest Cost and Return on Plan Assets:
Account Name:
Debit
Credit
Amortization of Prior Serv.
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#include stdafx.h #include iostream using namespace std;vo.docx
- 1. #include <stdafx.h> #include <iostream> using namespace std; void getdata(int& ident, int& grade_value); void sortlist(int& ident, int& grade_value); const int nil = 0; class node_type // declaration of class// { public: int id; int grade; node_type *next; }; void getdata(int& ident, int& grade_value); void sortlist(int& ident, int& grade_value); const int nil = 0; void main() { node_type *first, *p, *q, *newnode; int i, ident, grade_value; float sum, average; sum = 0; first = new node_type; p = first; getdata(ident, grade_value); (*first).id = ident; (*first).grade = grade_value; (*first).next = nil; for (i = 2; i <= 10; ++i) { getdata(ident, grade_value); newnode = new node_type; (*newnode).id = ident; (*newnode).grade = grade_value; (*newnode).next = nil;
- 2. //**********Links previous node to newnode******// (*p).next = newnode; p = newnode; } //**********Traverses list and prints out nodes in chronological order ******// q = first; cout << "The list contains "; while (q != nil) { cout << "ID is :" << (*q).id << " "; cout << "GRADE is :" << (*q).grade << " "; sum = sum + (*q).grade; q = (*q).next; } average = sum / 10; cout << " The average of the grades is " << average << " "; sortlist(ident, grade_value); } void getdata(int& ident, int& grade_value) { cout << "Enter id and grade "; cin >> ident; cout << ident << " "; cin >> grade_value; cout << grade_value << " "; } void sortlist(int& ident, int& grade_value); { if (first == nil) first = newnode; else if ((*first).next == nil) {
- 3. if ((*newnode).id > (*first).id) (*first).next == newnode; else { (*newnode).next = first; first = newnode; } } else if ((newnode).id < (*first).id) (*newnode).next = first; first = newnode; else q = first; p = (*q).next; while ((*p).id < (*newnode).id && ((*p).next != nil)) { q = p; p = (*p).next; } if ((*p).id >= (*newnode).id) (*q).next = newnode; (*newnode).next = p; } else { (*p).next = newnode; } }
- 4. Using the linked list program given in class , alter the program to input 10 integers, sorting them as they are inserted into the list. Print out the sorted list. Compute the average of the sorted values and print this out. Then delete all values from the list which are LESS than the average of the entries in the list Then create a second list of 10 integers, sorting as the list is created. Print out this list. Finally, merge the two lists together (i.e. the ORIGINAL first and second lists), eliminating any duplicates Print out the final merged list. Solution Here is the modified code: #include <stdafx.h> #include <iostream> using namespace std; void getdata(int& ident, int& grade_value); void sortlist(int& ident, int& grade_value); const int nil = 0; class node_type // declaration of class//
- 5. { public: int id; int grade; node_type *next; }; void getdata(int& ident, int& grade_value); void sortlist(int& ident, int& grade_value); const int nil = 0; void main() { const int NUM_NODES = 10 ; // number of nodes to be added int ident, grade_value; getdata(ident, grade_value); node_type* first = new node_type { ident, grade_value, nullptr } ; node_type* last = first; // last keeps track of the last ode i n the list. // right now, there is only one node and last == first for( int i = 1 ; i < NUM_NODES ; ++i ) // add (NUM_NODES-1) more nodes { getdata(ident, grade_value);
- 6. node_type* newnode = new node_type { ident, grade_value, nullptr } ; last->next = newnode; // append newnode to the end of the list: last = newnode; // and the node just added at the end becomes the last node } double sum = 0 ; std::cout << "The list contains "; for( node_type* current = first ; current != nullptr ; current = current->next ) { // print out the id and grade in the current node std::cout << "ID is : " << current->id << " GRADE is : " << current->grade << ' ' ; sum += current->grade ; // add the grade in the current node } const double average = sum / NUM_NODES ; std::cout << " The average of the grades is " << average << ' ' ; } void getdata( int& ident, int& grade_value ) { std::cout << "Enter id and grade ";
- 7. std::cin >> ident; std::cin >> grade_value; } void sortlist(int& ident, int& grade_value); { if (first == nil) first = newnode; else if ((*first).next == nil) { if ((*newnode).id > (*first).id) (*first).next == newnode; else { (*newnode).next = first; first = newnode; } } else if ((newnode).id < (*first).id) (*newnode).next = first; first = newnode; else q = first; p = (*q).next; while ((*p).id < (*newnode).id && ((*p).next != nil))
- 8. { q = p; p = (*p).next; } if ((*p).id >= (*newnode).id) (*q).next = newnode; (*newnode).next = p; } else { (*p).next = newnode; } }