Microprocessor square wave

LABORATORY MANUAL
PROGRAMME: B.Tech
SEMESTER /YEAR: 3rd year 5th Semester
SUBJECT CODE: BM0313
SUBJECT NAME: Microprocessor & Microcontroller Lab

Prepared By:
Name: A Bhargavi Haripriya
Designation: Assistant Professor (OG)

DEPARTMENT OF BIOMEDICAL ENGINEERING
SCHOOL OF BIOENGINEERING,
FACULTY OF ENGINEERING & TECHNOLOGY

SRM UNIVERSITY
(UNDER SECTION 3 of UGC ACT 1956)

KATTANKULATHUR-603203
Tamil Nadu, India

Microprocessor & Microcontroller Lab Manual

Contents
• 8085 Pin Diagram
• 8085 Instruction Set
• 8085 Programs
1.

To perform 8-bit addition using accumulator

2.

8 bit addition using memory register

3.

8 bit subtraction using accumulator

4.

8-bit subtraction using memory register

5.

Addition of BCD number

6.

16-bit addition using accumulator

7.

16-bit addition using register pair

8.

16-bit subtraction using accumulator

9.

BCD subtraction

10. 8-bit multiplication using memory register
11. Hexadecimal division
12. Adding an array of data
13. Smallest element in an array
14. Largest element in an array
15.

Fibonacci series

16. Arrange elements in ascending order
17. Arrange elements in descending order

• I/O Interfacing
Department of Biomedical Engineering , SRM University, Kattankulathur


• Interfacing Programs
18. Generation of Saw tooth waveform
19. Generation of Triangular waveform
20. Generation of Square waveform
21. Generation of Sine waveform8086 Pin Diagram

• 8086 Programs
22. 16-bit addition using 8086 microprocessor
23. Move contents of array
24. Sum of ‘n’ consecutive numbers
25. Conversion of BCD number to decimal
26. Separating Odd and Even numbers


• 8051 Programs
27. Addition of 8-bit numbers using 8051
28. Subtraction of 8-bit numbers using 8051



8085 Pin Diagram
---------------------------------------------------------------|
|
|
_________
_________
|
|
_|
__/
|_
|
|
--> X1 |_|1
40|_| Vcc (+5V)
|
|
_|
|_
|
|
--> X2 |_|2
39|_| HOLD <-|
|
_|
|_
|
|
<-- RESET OUT |_|3
38|_| HLDA -->
|
|
_|
|_
|
|
<-- SOD |_|4
37|_| CLK (OUT) -->
|
|
_|
|_ ________
|
|
--> SID |_|5
36|_| RESET IN <-|
|
_|
|_
|
|
--> TRAP |_|6
35|_| READY <-|
|
_|
|_
_
|
|
--> RST 7.5 |_|7
34|_| IO/M -->
|
|
_|
|_
|
|
--> RST 6.5 |_|8
33|_| S1 -->
|
|
_|
|_ __
|
|
--> RST 5.5 |_|9
32|_| RD -->
|
|
_|
|_ __
|
|
--> INTR |_|10
8085A
31|_| WR -->
|
|
____ _|
|_
|
|
<-- INTA |_|11
30|_| ALE -->
|
|
_|
|_
|
|
<--> AD0 |_|12
29|_| S0 -->
|
|
_|
|_
|
|
<--> AD1 |_|13
28|_| A15 -->
|
|
_|
|_
|
|
<--> AD2 |_|14
27|_| A14 -->
|
|
_|
|_
|
|
<--> AD3 |_|15
26|_| A13 -->
|
|
_|
|_
|
|
<--> AD4 |_|16
25|_| A12 -->
|
|
_|
|_
|
|
<--> AD5 |_|17
24|_| A11 -->
|
|
_|
|_
|
|
<--> AD6 |_|18
23|_| A10 -->
|
|
_|
|_
|
|
<--> AD7 |_|19
22|_| A9 -->
|
|
_|
|_
|
|
(Gnd) Vss |_|20
21|_| A8 -->
|
|
|______________________|
|
|
|
|
|
|
|
|
Copyright (C) J.P.Bowen 1985|



8085 Instruction Set
Instructions can be categorized according to their method of addressing the
hardware registers and/or memory.
Implied Addressing:
The addressing mode of certain instructions is implied by the instruction’s
function. For example, the STC (set carry flag) instruction deals only with the
carry flag, the DAA (decimal adjust accumulator) instruction deals with the
accumulator.
Register Addressing:
Quite a large set of instructions call for register addressing. With these instructions,
you must specify one of the registers A through E, H or L as well as the operation
code. With these instructions, the accumulator is implied as a second operand. For
example, the instruction CMP E may be interpreted as 'compare the contents of the
E register with the contents of the accumulator.
Immediate Addressing:
Instructions that use immediate addressing have data assembled as a part of the
instruction itself. For example, the instruction CPI 'C' may be interpreted as
‘compare the contents of the accumulator with the letter C. When assembled, this
instruction has the hexadecimal value FE43. Hexadecimal 43 is the internal
representation for the letter C. When this instruction is executed, the processor
fetches the first instruction byte and determines that it must fetch one more byte.
The processor fetches the next byte into one of its internal registers and then
performs the compare operation.

Direct Addressing:
Jump instructions include a 16-bit address as part of the instruction. For example,
the instruction JMP 1000H causes a jump to the hexadecimal address 1000 by
replacing the current contents of the program counter with the new value 1000H.
Instructions that include a direct address require three bytes of storage: one for the
instruction code, and two for the 16-bit address



Register Indirect Addressing:
Register indirect instructions reference memory via a register pair. Thus, the
instruction MOV M,C moves the contents of the C register into the memory
address stored in the H and L register pair. The instruction LDAX B loads the
accumulator with the byte of data specified by the address in the B and C register
pair.
Combined Addressing Modes:
Some instructions use a combination of addressing modes. A CALL instruction,
for example, combines direct addressing and register indirect addressing. The
direct address in a CALL instruction specifies the address of the desired
subroutine; the register indirect address is the stack pointer. The CALL instruction
pushes the current contents of the program counter into the memory location
specified by the stack pointer.
Timing Effects of Addressing Modes:
Addressing modes affect both the amount of time required for executing an
instruction and the amount of memory required for its storage. For example,
instructions that use implied or register addressing, execute very quickly since they
deal directly with the processor’s hardware or with data already present in
hardware registers. Most important, however is that the entire instruction can be
fetched with a single memory access. The number of memory accesses required is
the single greatest factor in determining execution timing. More memory accesses
therefore require more execution time. A CALL instruction for example, requires
five memory accesses: three to access the entire instruction and two more to push
the contents of the program counter onto the stack.
The processor can access memory once during each processor cycle. Each cycle
comprises a variable number of states. (See below and the appendix of “USING
THE SDK-85 MICROPROCESSOR TRAINER”). The length of a state depends
on the clock frequency specified for your system, and may range from 480
nanoseconds to 2 microseconds. Thus, the timing for a four state instruction may
range from 1.920 microseconds through 8 microseconds. (The 8085 have a
maximum clock frequency of 5 MHz and therefore a minimum state length of 200
nanoseconds.)


Instruction Naming Conventions:
The mnemonics assigned to the instructions are designed to indicate the function of
the instruction. The instructions fall into the following functional categories:
Data Transfer Group:
The data transfer instructions move data between registers or between memory and
registers.
MOV
MVI
LDA
STA
LHLD
SHLD

Move
Move Immediate
Load Accumulator Directly from Memory
Store Accumulator Directly in Memory
Load H & L Registers Directly from Memory
Store H & L Registers Directly in Memory

An 'X' in the name of a data transfer instruction implies that it deals with a register
pair (16-bits);
LXI
LDAX
STAX
XCHG
XTHL

Load Register Pair with Immediate data
Load Accumulator from Address in Register Pair
Store Accumulator in Address in Register Pair
Exchange H & L with D & E
Exchange Top of Stack with H & L

Arithmetic Group:
The arithmetic instructions add, subtract, increment, or decrement data in registers
or memory.
ADD
ADI
ADC
ACI
SUB
SUI
SBB
SBI

Add to Accumulator
Add Immediate Data to Accumulator
Add to Accumulator Using Carry Flag
Add Immediate data to Accumulator Using Carry
Subtract from Accumulator
Subtract Immediate Data from Accumulator
Subtract from Accumulator Using Borrow (Carry) Flag
Subtract Immediate from Accumulator Using Borrow (Carry)
Flag



INR
DCR
INX
DCX
DAD

Increment Specified Byte by One
Decrement Specified Byte by One
Increment Register Pair by One
Decrement Register Pair by One
Double Register Add; Add Content of Register
Pair to H & L Register Pair

Logical Group:
This group performs logical (Boolean) operations on data in registers and memory
and on condition flags.
The logical AND, OR, and Exclusive OR instructions enable you to set specific
bits in the accumulator ON or OFF.
ANA
ANI
ORA
OR
XRA
XRI

Logical AND with Accumulator
Logical AND with Accumulator Using Immediate Data
Logical OR with Accumulator
Logical OR with Accumulator Using Immediate Data
Exclusive Logical OR with Accumulator
Exclusive OR Using Immediate Data

The Compare instructions compare the content of an 8-bit value with the contents
of the accumulator;
CMP
CPI

Compare
Compare Using Immediate Data

The rotate instructions shift the contents of the accumulator one bit position to the
left or right:
RLC
RRC
RAL
RAR

Rotate Accumulator Left
Rotate Accumulator Right
Rotate Left Through Carry
Rotate Right Through Carry

Complement and carry flag instructions:


CMA
CMC
STC

Complement Accumulator
Complement Carry Flag
Set Carry Flag

Branch Group:
The branching instructions alter normal sequential program flow, either
unconditionally or conditionally. The unconditional branching instructions are as
follows:
JMP
CALL
RET

Jump
Call
Return

Conditional branching instructions examine the status of one of four condition
flags to determine whether the specified branch is to be executed. The conditions
that may be specified are as follows:
NZ
Z
NC
C
PO
PE
P
M

Not Zero (Z =
Zero (Z = 1)
No Carry (C =
Carry (C = 1)
Parity Odd (P
Parity Even (P
Plus (S = 0)
Minus (S = 1)

0)
0)
= 0)
= 1)

Thus, the conditional branching instructions are specified as follows:
Jumps
JC
INC
JZ
JNZ
JP
JM
JPE
JP0

Calls
CC
CNC
CZ
CNZ
CP
CM
CPE
CPO

Returns
RC
RNC
RZ
RNZ
RP
RM
RPE
RPO

(Carry)
(No Carry)
(Zero)
(Not Zero)
(Plus)
(Minus)
(Parity Even)
(Parity Odd)



Two other instructions can affect a branch by replacing the contents or the program
counter:
PCHL
RST

Move H & L to Program Counter
Special Restart Instruction Used
with Interrupts

Stack I/O, and Machine Control Instructions:
The following instructions affect the Stack and/or Stack Pointer:
PUSH
POP
XTHL
SPHL

Push Two bytes of Data onto the Stack
Pop Two Bytes of Data off the Stack
Exchange Top of Stack with H & L
Move content of H & L to Stack Pointer

The I/0 instructions are as follows:
IN
OUT

Initiate Input Operation
Initiate Output Operation

The Machine Control instructions are as follows:
EI
Enable Interrupt System
DI
Disable Interrupt System
HLT
Halt
NOP
No Operation



---------------------------------------------------------------|Mnemonic |Op|SZAPC|~s|Description
|Notes
|
|---------+--+-----+--+--------------------------+-------------|
|ACI n
|CE|*****| 7|Add with Carry Immediate |A=A+n+CY
|
|ADC r
|8F|*****| 4|Add with Carry
|A=A+r+CY(21X)|
|ADC M
|8E|*****| 7|Add with Carry to Memory |A=A+[HL]+CY |
|ADD r
|87|*****| 4|Add
|A=A+r
(20X)|
|ADD M
|86|*****| 7|Add to Memory
|A=A+[HL]
|
|ADI n
|C6|*****| 7|Add Immediate
|A=A+n
|
|ANA r
|A7|****0| 4|AND Accumulator
|A=A&r
(24X)|
|ANA M
|A6|****0| 7|AND Accumulator and Memory|A=A&[HL]
|
|ANI n
|E6|**0*0| 7|AND Immediate
|A=A&n
|
|CALL a
|CD|-----|18|Call unconditional
|-[SP]=PC,PC=a|
|CC a
|DC|-----| 9|Call on Carry
|If CY=1(18~s)|
|CM a
|FC|-----| 9|Call on Minus
|If S=1 (18~s)|
|CMA
|2F|-----| 4|Complement Accumulator
|A=~A
|
|CMC
|3F|----*| 4|Complement Carry
|CY=~CY
|
|CMP r
|BF|*****| 4|Compare
|A-r
(27X)|
|CMP M
|BF|*****| 7|Compare with Memory
|A-[HL]
|
|CNC a
|D4|-----| 9|Call on No Carry
|If CY=0(18~s)|
|CNZ a
|C4|-----| 9|Call on No Zero
|If Z=0 (18~s)|
|CP a
|F4|-----| 9|Call on Plus
|If S=0 (18~s)|
|CPE a
|EC|-----| 9|Call on Parity Even
|If P=1 (18~s)|
|CPI n
|FE|*****| 7|Compare Immediate
|A-n
|
|CPO a
|E4|-----| 9|Call on Parity Odd
|If P=0 (18~s)|
|CZ a
|CC|-----| 9|Call on Zero
|If Z=1 (18~s)|
|DAA
|27|*****| 4|Decimal Adjust Accumulator|A=BCD format |
|DAD B
|09|----*|10|Double Add BC to HL
|HL=HL+BC
|
|DAD D
|19|----*|10|Double Add DE to HL
|HL=HL+DE
|
|DAD H
|29|----*|10|Double Add HL to HL
|HL=HL+HL
|
|DAD SP
|39|----*|10|Double Add SP to HL
|HL=HL+SP
|
|DCR r
|3D|****-| 4|Decrement
|r=r-1
(0X5)|
|DCR M
|35|****-|10|Decrement Memory
|[HL]=[HL]-1 |
|DCX B
|0B|-----| 6|Decrement BC
|BC=BC-1
|
|DCX D
|1B|-----| 6|Decrement DE
|DE=DE-1
|
|DCX H
|2B|-----| 6|Decrement HL
|HL=HL-1
|
|DCX SP
|3B|-----| 6|Decrement Stack Pointer
|SP=SP-1
|
|DI
|F3|-----| 4|Disable Interrupts
|
|
|EI
|FB|-----| 4|Enable Interrupts
|
|
|HLT
|76|-----| 5|Halt
|
|
|IN p
|DB|-----|10|Input
|A=[p]
|
|INR r
|3C|****-| 4|Increment
|r=r+1
(0X4)|
|INR M
|3C|****-|10|Increment Memory
|[HL]=[HL]+1 |
|INX B
|03|-----| 6|Increment BC
|BC=BC+1
|
|INX D
|13|-----| 6|Increment DE
|DE=DE+1
|
|INX H
|23|-----| 6|Increment HL
|HL=HL+1
|
|INX SP
|33|-----| 6|Increment Stack Pointer
|SP=SP+1
|
|JMP a
|C3|-----| 7|Jump unconditional
|PC=a
|
|JC a
|DA|-----| 7|Jump on Carry
|If CY=1(10~s)|
|JM a
|FA|-----| 7|Jump on Minus
|If S=1 (10~s)|
|JNC a
|D2|-----| 7|Jump on No Carry
|If CY=0(10~s)|
|JNZ a
|C2|-----| 7|Jump on No Zero
|If Z=0 (10~s)|
|JP a
|F2|-----| 7|Jump on Plus
|If S=0 (10~s)|



|JPE a
|EA|-----| 7|Jump on Parity Even
|If P=1 (10~s)|
|JPO a
|E2|-----| 7|Jump on Parity Odd
|If P=0 (10~s)|
|JZ a
|CA|-----| 7|Jump on Zero
|If Z=1 (10~s)|
|LDA a
|3A|-----|13|Load Accumulator direct
|A=[a]
|
|LDAX B
|0A|-----| 7|Load Accumulator indirect |A=[BC]
|
|LDAX D
|1A|-----| 7|Load Accumulator indirect |A=[DE]
|
|LHLD a
|2A|-----|16|Load HL Direct
|HL=[a]
|
|LXI B,nn |01|-----|10|Load Immediate BC
|BC=nn
|
|LXI D,nn |11|-----|10|Load Immediate DE
|DE=nn
|
|LXI H,nn |21|-----|10|Load Immediate HL
|HL=nn
|
|LXI SP,nn|31|-----|10|Load Immediate Stack Ptr |SP=nn
|
|MOV r1,r2|7F|-----| 4|Move register to register |r1=r2
(1XX)|
|MOV M,r |77|-----| 7|Move register to Memory
|[HL]=r (16X)|
|MOV r,M |7E|-----| 7|Move Memory to register
|r=[HL] (1X6)|
|MVI r,n |3E|-----| 7|Move Immediate
|r=n
(0X6)|
|MVI M,n |36|-----|10|Move Immediate to Memory |[HL]=n
|
|NOP
|00|-----| 4|No Operation
|
|
|ORA r
|B7|**0*0| 4|Inclusive OR Accumulator |A=Avr
(26X)|
|ORA M
|B6|**0*0| 7|Inclusive OR Accumulator |A=Av[HL]
|
|ORI n
|F6|**0*0| 7|Inclusive OR Immediate
|A=Avn
|
|OUT p
|D3|-----|10|Output
|[p]=A
|
|PCHL
|E9|-----| 6|Jump HL indirect
|PC=[HL]
|
|POP B
|C1|-----|10|Pop BC
|BC=[SP]+
|
|POP D
|D1|-----|10|Pop DE
|DE=[SP]+
|
|POP H
|E1|-----|10|Pop HL
|HL=[SP]+
|
|POP PSW |F1|-----|10|Pop Processor Status Word |{PSW,A}=[SP]+|
------------------------------------------------------------------------------------------------------------------------------|Mnemonic |Op|SZAPC|~s|Description
|Notes
|
|---------+--+-----+--+--------------------------+-------------|
|PUSH B
|C5|-----|12|Push BC
|-[SP]=BC
|
|PUSH D
|D5|-----|12|Push DE
|-[SP]=DE
|
|PUSH H
|E5|-----|12|Push HL
|-[SP]=HL
|
|PUSH PSW |F5|-----|12|Push Processor Status Word|-[SP]={PSW,A}|
|RAL
|17|----*| 4|Rotate Accumulator Left
|A={CY,A}<|
|RAR
|1F|----*| 4|Rotate Accumulator Righ
|A=->{CY,A}
|
|RET
|C9|-----|10|Return
|PC=[SP]+
|
|RC
|D8|-----| 6|Return on Carry
|If CY=1(12~s)|
|RIM
|20|-----| 4|Read Interrupt Mask
|A=mask
|
|RM
|F8|-----| 6|Return on Minus
|If S=1 (12~s)|
|RNC
|D0|-----| 6|Return on No Carry
|If CY=0(12~s)|
|RNZ
|C0|-----| 6|Return on No Zero
|If Z=0 (12~s)|
|RP
|F0|-----| 6|Return on Plus
|If S=0 (12~s)|
|RPE
|E8|-----| 6|Return on Parity Even
|If P=1 (12~s)|
|RPO
|E0|-----| 6|Return on Parity Odd
|If P=0 (12~s)|
|RZ
|C8|-----| 6|Return on Zero
|If Z=1 (12~s)|
|RLC
|07|----*| 4|Rotate Left Circular
|A=A<|
|RRC
|0F|----*| 4|Rotate Right Circular
|A=->A
|
|RST z
|C7|-----|12|Restart
(3X7)|-[SP]=PC,PC=z|
|SBB r
|9F|*****| 4|Subtract with Borrow
|A=A-r-CY
|
|SBB M
|9E|*****| 7|Subtract with Borrow
|A=A-[HL]-CY |
|SBI n
|DE|*****| 7|Subtract with Borrow Immed|A=A-n-CY
|
|SHLD a
|22|-----|16|Store HL Direct
|[a]=HL
|



|SIM
|30|-----| 4|Set Interrupt Mask
|mask=A
|
|SPHL
|F9|-----| 6|Move HL to SP
|SP=HL
|
|STA a
|32|-----|13|Store Accumulator
|[a]=A
|
|STAX B
|02|-----| 7|Store Accumulator indirect|[BC]=A
|
|STAX D
|12|-----| 7|Store Accumulator indirect|[DE]=A
|
|STC
|37|----1| 4|Set Carry
|CY=1
|
|SUB r
|97|*****| 4|Subtract
|A=A-r
(22X)|
|SUB M
|96|*****| 7|Subtract Memory
|A=A-[HL]
|
|SUI n
|D6|*****| 7|Subtract Immediate
|A=A-n
|
|XCHG
|EB|-----| 4|Exchange HL with DE
|HL<->DE
|
|XRA r
|AF|**0*0| 4|Exclusive OR Accumulator |A=Axr
(25X)|
|XRA M
|AE|**0*0| 7|Exclusive OR Accumulator |A=Ax[HL]
|
|XRI n
|EE|**0*0| 7|Exclusive OR Immediate
|A=Axn
|
|XTHL
|E3|-----|16|Exchange stack Top with HL|[SP]<->HL
|
|------------+-----+--+----------------------------------------|
| PSW
|-*01 | |Flag unaffected/affected/reset/set
|
| S
|S
| |Sign (Bit 7)
|
| Z
| Z
| |Zero (Bit 6)
|
| AC
| A | |Auxilary Carry (Bit 4)
|
| P
|
P | |Parity (Bit 2)
|
| CY
|
C| |Carry (Bit 0)
|
|---------------------+----------------------------------------|
| a p
|Direct addressing
|
| M z
|Register indirect addressing
|
| n nn
|Immediate addressing
|
| r
|Register addressing
|
|---------------------+----------------------------------------|
|DB n(,n)
|Define Byte(s)
|
|DB 'string'
|Define Byte ASCII character string
|
|DS nn
|Define Storage Block
|
|DW nn(,nn)
|Define Word(s)
|
|---------------------+----------------------------------------|
| A B C D E H L |Registers (8-bit)
|
| BC DE HL
|Register pairs (16-bit)
|
| PC
|Program Counter register (16-bit)
|
| PSW
|Processor Status Word (8-bit)
|
| SP
|Stack Pointer register (16-bit)
|
|---------------------+----------------------------------------|
| a nn
|16-bit address/data (0 to 65535)
|
| n p
|8-bit data/port (0 to 255)
|
| r
|Register (X=B,C,D,E,H,L,M,A)
|
| z
|Vector (X=0H,8H,10H,18H,20H,28H,30H,38H)|
|---------------------+----------------------------------------|
| + |Arithmetic addition/subtraction
|
| & ~
|Logical AND/NOT
|
| v x
|Logical inclusive/exclusive OR
|
| <- ->
|Rotate left/right
|
| <->
|Exchange
|
| [ ]
|Indirect addressing
|
| [ ]+ -[ ]
|Indirect address auto-inc/decrement
|
| { }
|Combination operands
|
| ( X )
|Octal op code where X is a 3-bit code
|
| If ( ~s)
|Number of cycles if condition true
|



Experiment No:

8-BIT ADDITION USING ACCUMULATOR
AIM: To perform 8-bit Addition of two hexadecimal numbers using
accumulator in 8085
PROGRAM:
Address Program

Explanation

LDA 9000
MOV B,A

Shift contents of accumulator to register B

LDA 9001

Load contents of address 9001(Input 2) into the accumulator

ADD B

Add data in B to accumulator & store in the accumulator

STA 9002

Store the (Result) contents of accumulator to address 9002

JC Loc1

Jump to Loc1 if carry is 1

MVI A,00

Store value 00 in accumulator

STA 9003

Store the (Carry) contents of accumulator to address 9003

HLT

End of Program

MVI A,01

Store value 01 in accumulator

STA 9003

Store the (Carry) contents of accumulator to address 9003

HLT

Loc 1:

Load contents of address 9000 (Input 1) into the
accumulator

End of Program



FLOWCHART
START

GET DATA1 INTO
ACCUMULATOR

MOVE CONTENTS
OF A TO B

GET DATA2 INTO
ACCUMULATOR

ADD B TO A

STORE RESULT

IF
CARRY=1

no

yes
A=01

STORE CARRY

STOP

A=00


MNEMONICS:
ADDRESS

OPCODE

OPERAND

LOCATION COMMAND

8000

3A

00 90

8003

47

8004

3A

8007

80

8008

32

02 90

STA 9002

800B

DA

14 80

JC Loc1

800E

3E

00

MVI A,00

8010

32

03 90

STA 9003

8013

76

8014

3E

01

8016

32

03 90

8019

76

LDA 9000
MOV B,A

01 90

LDA 9001
ADD B

HLT
Loc 1


MVI A,01
STA 9003
HLT


INPUT & OUTPUT:
Location

Values

9000

INPUT 1

42

9001

INPUT 2

35

9002

RESULT

77

9003

CARRY

00

Location

Values

9000

INPUT 1

A8

9001

INPUT 2

F6

9002

RESULT

9E

9003

CARRY

01



CALCULATION:
i) Data 1
Data 2
Sum
Carry
ii) Data 1
Data 2
Sum
Carry

: 42 - 0100 0010
: 35 - 0011 0101
: 77
– 0111 0111
: 00
: A8
- 1010 1000
: 35 - 1111 0110
: 9E
- 1001 1110
: 01

RESULT: The program for adding two 8-bit hexadecimal numbers using
accumulator & registers has been performed with different sets of data.



Date:
Experiment No:

8-BIT ADDITION WITH MEMORY POINTER
AIM: To perform 8-bit Addition of two hexadecimal numbers using
memory pointer in 8085
PROGRAM:
Address Program

Explanation

LXI H, 8201
MVI C, 00

Clearing register C for carry

MOV A, M

Getting Data 1 into the accumulator from memory

INX H

Increment pointer to the next memory location

ADD M

Add second data to Accumulator and store it in
accumulator

JNC Ahead

If carry is '0' , go to location 'Ahead'

INR C

If carry is '1' , Increment register C to 1

INX H


MOV M,A

Store Sum in memory

INX H


MOV M,C

Store Carry in memory

HLT

Ahead

Setting pointer for getting data

End of Program



FLOWCHART
START
SET CARRY ‘C’ TO 00
SET POINTER TO GET DATA
FROM MEMORY

GET DATA1 INTO
ACCUMULATOR

INCREMENT
POINTER

ADD DATA 2 IN
MEMORY TO A

IF
CARRY==1
YES
NO

C=01

STORE SUM

STORE CARRY

STOP


MNEMONICS:
ADDRESS

OPCODE OPERAND

LOCATION COMMAND

8000

21

01 82

LXI H, 8201

8003

0E

00

MVI C, 00

8005

7E

MOV A, M

8006

23

INX H

8007

86

ADD M

8008

D2

800B

0C

800C

23

800D

77

MOV M,A

800E

23

INX H

800F

71

MOV M,C

8010

76

HLT

0C 80

JNC Ahead
INR C
Ahead


INX H


INPUT & OUTPUT:
Location

Values

8200

INPUT 1

54

8201

INPUT 2

A1

8202

RESULT

F5

8203

CARRY

00

Location

Values

8200

INPUT 1

B3

8201

INPUT 2

69

8202

RESULT

1C

8203

CARRY

01



CALCULATION:
i) Data 1
Data 2
Sum
Carry

: 54 - 0101 0100
: A1 - 1010 0001
: F5 - 1111 0101
: 00

ii) Data 1
Data 2
Sum
Carry

: B3 - 1011 0011
: 69 - 0110 1001
: 1C - 0001 1100
: 01

RESULT: The program for adding two 8-bit hexadecimal numbers using
memory pointer has been performed with different sets of data.



Date:
Experiment No:

8-BIT SUBTRACTION USING ACCUMULATOR
AIM: To perform 8-bit Subtraction of two hexadecimal numbers using
accumulator in 8085
PROGRAM:
LDA 8201

Load the first data in the accumulator

MOV B, A

Move contents of Accumulator to B

LDA 8200

Load the second data in the accumulator

MVI C, 00

Set C = '0' for carry

SUB B

Subtract B from Accumulator & Store in
Accumulator

JNC Ahead

If carry is not set go Ahead

INR C

if carry = '1' , increment register C to 01

CMA

Get 2's complement for Accumulator

ADD 01

Add one to accumulator

Ahead STA 8202

Store result in given location

MOV A,C

Move carry to Accumulator

STA 8203

Store Carry in given location

HLT

End of Program



FLOWCHART

START

GET DATA1 INTO
ACCUMULATOR

MOVE CONTENTS
OF A TO B

GET DATA2 INTO
ACCUMULATOR

SET REGISTER C
FOR CARRY
SUBTRACT DATA2
FROM DATA 1

IF
CARRY=0

YES

STORE RESULT IN
MEMORY

NO

SET CARRY AS
01
GET 2’S
COMPLEMENT OF
RESULT

STORE CARRY IN
MEMORY
STOP


MNEMONICS:
ADDRESS

OPCODE OPERAND LOCATION COMMAND

8000

3A

8003

47

8004

3A

00 82

LDA 8200

8007

0E

0

MVI C, 00

8009

90

800A

D2

800D

0C

INR C

800E

2F

CMA

800F

C6

1

8011

32

02 82

8014

79

8015

32

8018

76

01 82

LDA 8201
MOV B, A

SUB B
11 80

JNC Ahead

ADD 01
Ahead

MOV A,C
03 82


STA 8202

STA 8203
HLT


INPUT & OUTPUT:
i)
8200

55

8201

INPUT 2

32

8202
ii)

INPUT 1

DIFFERENCE 23

8203

BORROW

0

8200

INPUT 1

11

8201

INPUT 2

AA

8202

DIFFERENCE 99

8203

BORROW

1



CALCULATION:
i) Data 1
:
Data 2 :
Difference:
Borrow:
ii) Data 1
:
Data 2 :
Difference:
Borrow:

55
32
23
00
11
AA
99
01

-0101 0101
-0011 0010
-0010 0011
-0001 0001
-1010 1010
-1001 1001

RESULT: The program for subtracting two 8-bit hexadecimal numbers
using 8085 was executed.



Date:
Experiment No:

8-BIT SUBTRACTION WITH MEMORY POINTER
AIM: To perform 8-bit Subtraction of two hexadecimal numbers using
memory pointer in 8085

PROGRAM:
Address Program

Explanation

LXI H, 8201
MVI C, 00

Clear register C to account for Carry

MOV A, M

Get Data 1 into Accumulator

INX H

Increment the memory pointer

SUB M

Subtract Data 2 from Data 1 and store in
Accumulator

JNC Ahead

If carry==0 , go Ahead

INR C

If carry==1, Increment register C by 1

CMA

Get 2's complement for Accumulator
data

ADI 01
Ahead

Setting pointer for data

Add 1 to accumulator content

INX H




MOV M,A

Store Accumulator content (Result) to
memory

INX H


MOV M,C

Store Register C (Carry) content to
memory

HLT

End of program



FLOWCHART

START
SET CARRY ‘C’ TO 00
SET POINTER TO GET DATA
FROM MEMORY

GET DATA1 INTO
ACCUMULATOR

INCREMENT
POINTER

SUBTRACT DATA2
FROM DATA 1

IF
CARRY=0

YES

NO

SET CARRY AS
01
GET 2’S
COMPLEMENT OF
RESULT

STORE RESULT IN
MEMORY
STORE CARRY IN
MEMORY
STOP

SET CARRY AS
01


MNEMONICS:
ADDRESS OPCODE OPERAND LOCATION COMMAND
8000

21

01 82

LXI H, 8201

8003

0E

00

MVI C, 00

8005

7E

MOV A, M

8006

23

INX H

8007

96

SUB M

8008

D2

800B

0C

INR C

800C

2F

CMA

800D

C6

800F

23

8010

77

MOV M,A

8011

23

INX H

8012

71

MOV M,C

8013

76

HLT

0F 80

JNC Ahead

01

ADI 01
Ahead


INX H


INPUT & OUTPUT:
i)
8200

INPUT 1

11

8201

INPUT 2

11

8202

DIFFERENCE 00

8203

BORROW

00

8200

INPUT 1

33

8201

INPUT 2

55

8202

DIFFERENCE 22

8203

BORROW

ii)

01

CALCULATION:
i)

Data 1

:

11

-0001 0001

Data 2

:

11

-0001 0001

Difference:

00

-0010 0011

Borrow:

00



ii)

Data 1

:

33

-0011 0011

Data 2

:

55

-0101 0101

2’ complement of 55: 1010 1010
+ 1 : 1010 1011
+ Data 1 (0011 0011): 1101 1110
2’s complement of the above number : 0010 0001
+ 01 :
Difference:

22

Borrow:

0010 0010 = 22

-0010 0010

01

RESULT: The program for subtracting two 8-bit hexadecimal numbers
using memory pointer in 8085 was executed.


Date:
Experiment No:

8-BIT BCD ADDITION
AIM: To perform addition of two 8-bit BCD numbers using 8085
microprocessor.
PROGRAM:
Address Program

Explanation

LDA 8200
MOV B,A

Move Accumulator contents to Register B

LDA 8201

Load Data 2 into accumulator

MVI C, 00


ADD B

Add Data 2 to Data 1 and store in
Accumulator

DAA

Convert the accumulator value to BCD
value

JNC Ahead


INR C


STA 8203

Store Accumulator content (Result) to
memory

MOV A,C

Ahead

Load Data 1 into accumulator

Move contents of Register C to
Accumulator



STA 8204

Store Register C (Carry) content to memory

HLT

End of program



START

FLOWCHART
GET DATA1 INTO
ACCUMULATOR

MOVE CONTENTS
OF A TO B

GET DATA2 INTO
ACCUMULATOR

SET REGISTER C
FOR CARRY
ADD DATA 1 TO DATA 2, AND
STORE IN ACCUMULATOR

CONVERT
ACCUMULATOR
CONTENT TO BCD

IF
CARRY=0

YES

NO
STORE RESULT IN
MEMORY
STORE CARRY IN
MEMORY
STOP


SET CARRY AS
01


MNEMONICS:
ADDRESS


8000

3A

8003

47

8004

3A

01 82

LDA 8201

8007

0E

0

MVI C, 00

8009

86

ADD B

800A

27

DAA

800B

D2

800E

0C

800F

32

8012

79

8013

32

8016

76

00 82

LDA 8200
MOV B,A

0F 80

JNC Ahead
INR C

02 82

Ahead

MOV A,C
03 82


STA 8203

STA 8204
HLT


INPUT & OUTPUT:
i)
8200

13

8201

INPUT 2

4A

8202
ii)

INPUT 1

SUM

63

8203

CARRY

0

8200

INPUT 1

13

8201

INPUT 2

16

8202

SUM

29

8203

CARRY

0



CALCULATION:
i) Data 1:
Data 2:

13 0001 0011
4A 0100 1010
Gives
0101 1101
After adding 06 0000 0110
Result:
63 0110 0011
Carry:
00
Note: If hexadecimal number is in units place 06 is added, if
hexadecimal is in tens place 60 is added to sum by the DAA command.

RESULT: Program to add two BCD 8-bit numbers was performed using
DAA command with 8085 microprocessor


Date:

Experiment No:

16 BIT ADDITION USING ACCUMULATOR
AIM: To add two 16 bit numbers ( 4 digits) using the accumulator with
8085 microprocessor.
PROGRAM:
Address

Program

Explanation

LDA 8201

Get Data 1 (lower byte) into accumulator

MOV B,A

Move Data to Register B from Accumulator

LDA 8203

Get Data 2 (lower byte) into accumulator

ADD B

Add Lower Bytes of Data 1 & Data 2

STA 8205

Store content of Accumulator , Lower Byte
Result in Memory

MVI C, 00

Set C = '0' for carry

LDA 8202

Get Data 1 (higher byte) into accumulator

MOV B,A

Move Data to Register B from Accumulator

LDA 8204

Get Data 2 (higher byte) into accumulator

ADC B

Add Higher Bytes of Data 1 & Data 2 with
carry of Lower Bytes

STA 8206

Store content of Accumulator , Lower Byte



Result in Memory
JNC Ahead
INR C

if carry = '1' , increment register C to 01

MOV A,C

Accumulator

STA 8207


HLT

Ahead


End of program



START

FLOWCHART

GET LOWER BYTE OF DATA1 INTO ACCUMULATOR
MOVE CONTENTS OF A TO B


ADD LOWER BYTES OF DATA 1 TO DATA 2, AND
STORE IN ACCUMULATOR
STORE RESULT IN MEMORY
SET REGISTER C FOR CARRY
GET HIGHER BYTE OF DATA1 INTO ACCUMULATOR

ADD HIGHER BYTES OF DATA 1 TO DATA 2 WITH CARRY OF
LOWER BYTE ADDITION AND STORE IN ACCUMULATOR

IF CARRY=0

NO

YES
STORE CARRY IN MEMORY
STOP

SET CARRY AS
01


MNEMONICS:
ADDRESS


8000

3A

8003

47

8004

3A

8007

80

8008

32

05 82

STA 8205

800B

0E

0

MVI C, 00

800D

3A

02 82

LDA 8202

8010

47

8011

3A

8014

88

8015

32

06 82

STA 8206

8018

D2

1C 80

JNC Ahead

801B

0C

801C

79

801D

32

8020

76

01 82

LDA 8201
MOV B,A

03 82

LDA 8203
ADD B

MOV B,A
04 82

LDA 8204
ADC B

INR C
Ahead
07 82


MOV A,C
STA 8207
HLT


INPUT & OUTPUT:
i) INPUT 1 4283
INPUT 2
2931
SUM
6BB4
CARRY 00
8201
83
Lower Byte of Data 1
8202

42

Higher Byte of Data 1

8203

31


8204

29


8205

B4

Lower Byte of Sum

8206

6B

Higher Byte of Sum

8207

0

Carry

ii)
INPUT 1
INPUT 2
SUM
CARRY

9312
8856
1B68
1


8201

12


8202

93


8203

56


8204

88



Lower Byte of Sum

8205

68

Higher Byte of Sum

8206

1B

Carry

8207

1

CALCULATION:
Lower Byte of Data 1:
Lower Byte of Data 2:
Lower Byte of Sum :
Higher Byte of Data 1:
Higher Byte of Data 2:
Higher Byte of Sum :
Carry: 00

83
31
B4
42
29
6B

1000 0011
0011 0001
1011 0100
0100 0010
0010 1001
0110 1011

RESULT: Program to add two 16 bit numbers (4 digits) using the
accumulator with 8085 microprocessor was executed



Date:
Experiment No:

16 BIT ADDITION USING REGISTER PAIR
AIM: To add two 16 bit numbers (4 digits) using the register pairs in
8085 microprocessor.

PROGRAM:
Address

Explanation

LHLD 8201

Load HL register pair with data in 8201
& 8202

XCHG

Exchange contents of HL with DE
Register Pair

LHLD 8203

Load HL register pair with data in 8203
& 8204

MVI A, 00

Set Accumulator , A = '0' for carry

DAD D

Double Addition

JNC Ahead


INR A
Ahead

Program

if carry = '1' , increment Accumulator to
01

SHLD 8205

Store contents of HL Register pair in
Memory



STA 8207

Store Register C (Carry) content to
memory

HLT

End of program



FLOWCHART

START

GET DATA1 INTO HL REGISTER PAIR

EXCHANGE : MOVE DATA 1 TO DE
REGISTER PAIR

GET DATA2 INTO HL REGISTER PAIR

SET ACCUMULATOR FOR CARRY

DOUBLE ADDITION OF DATA 1 WITH DATA 2

IF CARRY==0

NO

YES

INCEMENT CARRY

STORE CONTENT OF HL REGISTER PAIR ( RESULT ) IN
MEMORY

STORE ACCUMULATOR CONTENT (CARRY)
TO MEMORY

STOP


MNEMONICS:
ADDRESS


8000

2A

8003

E3

8004

2A

03 82

LHLD 8203

8007

3E

0

MVI A, 00

8009

19

800A

D2

800D

3C

800E

22

05 82

8011

32

07 82

8014

76

01 82

LHLD 8201
XCHG

DAD D
0E 80

JNC Ahead
INR A
Ahead

STA 8207
HLT

INPUT & OUTPUT:
INPUT 1
INPUT 2
SUM
CARRY

9437
7259
0690
01


8201

37


SHLD 8205



8202

94


8203

59


8204

72

Lower Byte of Sum

8205

90

Higher Byte of Sum

8206

6

Carry

8207

1

RESULT: Program to add two 16 bit numbers (4 digits) using the
Register pairs in 8085 microprocessor was executed



Date:
Experiment No:

16 BIT HEXADECIMAL SUBTRACTION
AIM: To subtract two 16-bit hexadecimal numbers using Accumulator
with 8085 Microprocessor

PROGRAM:
Program

Explanation

LDA 8202

Load contents of Accumulator with Lower byte of
Data 2

MOV B,A

Move contents of Accumulator to Register B

LDA 8200

Load contents of Accumulator with Lower byte of
Data 1

SUB B

Subtract contents of B from Accumulator

STA 8204

Store Accumulator content (Lower byte of
difference) to Memory

LDA 8203

Load contents of Accumulator with Higher byte of
Data 2

MOV B,A


LDA 8201

Load contents of Accumulator with Higher byte of
Data 1



SBB B

Subtract contents of B from Accumulator along
with Borrow, if any

STA 8205

Store Accumulator content (Higher byte of
difference) to Memory

HLT

End of Program



FLOWCHART

START




SUBTRACT LOWER BYTES OF DATA 1 TO DATA 2,
AND STORE DIFFERENCE IN ACCUMULATOR

STORE DIFFERENCE IN MEMORY




SUBTRACT HIGHER BYTE OF DATA 1 AND DATA 2 WITH
BORROW OF LOWER BYTE AND STORE IN ACCUMULATOR


STOP


MNEMONICS:
ADDRESS

OPCODE

OPERAND

COMMAND

8000

3A

02 82

LDA 8202

8003

47

8004

3A

8007

90

8008

32

04 82

STA 8204

800B

3A

03 82

LDA 8203

800E

47

800F

3A

8012

98

8013

32

8016

76

MOV B,A
00 82

LDA 8200
SUB B

MOV B,A
01 82

LDA 8201
SBB B

05 82

STA 8205
HLT

INPUT & OUTPUT:
i) INPUT 1 4398
INPUT 2
2931
Difference
5522
BORROW
00


8200

98


8201

43


8202

21


8203

46


8204

22

Lower Byte of Difference

8205

55

Higher Byte of Sum

8206

0

BORROW

ii)
INPUT 1
INPUT 2
SUM
BORROW

4531
9576
AFB7
00


8200

31


8201

45


8202

76


8203

95

Lower Byte of

8204

B8

Higher Byte of Difference

8205

AF

BORROW

8206

01

Difference



CALCULATION:
Lower Byte of Difference
Higher Byte of Difference
Borrow : 00

:
:
:
:
:
:

43
21
22
98
46
55

0100 0011
0010 0001
0010 0010
1001 1000
0100 0110
0101 0101

RESULT: Program to subtract two 16 bit numbers (4 digits) using the
accumulator with 8085 microprocessor was executed



Date:
Experiment No:

8 BIT MULTIPLICATION
AIM: To multiply two 8-bit hexadecimal numbers using memory pointer
with 8085 microprocessor

PROGRAM:
Address Program

Explanation

LXI H, 8201
MVI C, 00

Set Accumulator to '0' to account for
product

MOV B,M

Move Data 1 to Register B from Memory

INX H


MOV D,M

Move Data 2 to Register D from Memory

ADD D

Add contents of Register D to Accumulator

JNC Ahead


INR C


DCR B

Decrement Register B content by 1

JNZ Repeat

Ahead


XRA A

Repeat


If B is not Zero, got back to Repeat



INX H


MOV M,A

Store Accumulator content (Product) to
memory

INX H


MOV M,C


HTL

End of program



FLOWCHART

START
SETTING MEMORY POINTER FOR DATA
GATHERING AND STORAGE
SET REGISTER C FOR CARRY
CLEAR ACCUMULATOR
MOVE DATA1 FROM MEMORY TO B
INCREMENT POINTER
MOVE DATA2 FROM MEMORY TO D

ADD Reg D TO REGISTER B

IF CARRY=0

NO

YES
YES

DECREMENT REGISTER B

IF ZERO FLAG SET
NO
INCREMENT POINTER
STORE RPODUCT IN MEMORY
INCREMENT POINTER
STORE QUOTIENT IN MEMORY
STOP


INCREMENT C


MNEMONICS:
ADDRESS

OPCODE OPERAND

LOCATION COMMAND

8000

21

01 82

LXI H, 8201

8003

0E

0

MVI C, 00

8005

AF

XRA A

8006

46

MOV B,M

8007

23

INX H

8008

56

MOV D,M

8009

82

800A

D2

800D

0C

800E

5

800F

C2

8012

23

INX H

8013

77

MOV M,A

8014

23

INX H

8015

71

MOV M,C

8016

76

HLT

Repeat
0E 80

JNC Ahead
INR C
Ahead

09 80


ADD D

DCR B
JNZ Repeat


INPUT & OUTPUT:
8201

INPUT 1

5

8202

INPUT 2

3

8203

PRODUCT

F

8204

CARRY

0



CALCULATION:
05

- 0000 0101

05

-0000 0101

----- 0A

- 0000 1010

+

05

-0000 0101

=

0F

- 0000 1111

+

RESULT: The program to multiply two 8-bit hexadecimal numbers
using 8085 was executed.


Date:
Experiment No:

8-BIT DIVISION
AIM: To divide two 8-bit hexadecimal numbers using 8085
microprocessor
PROGRAM:
Address Program

Explanation

LDA 8201

Load contents of Accumulator with Divisor
from memory

MOV B,A


LDA 8200

Load contents of Accumulator with Dividend
from memory

MVI C, 00 Clear register C to account for Carry
Again

CMP B

Compare Register B with Accumulator

JC Store

If carry==1, jump to Store

SUB B

If carry==0, subtract Register B from
Accumulator

INR C

Increment register C by 1

JMP Again Jump to Again , unconditionally
Store

STA 8203

Store Accumulator content (Reminder) to



Memory
MOV A,C

Move contents of Register C to Accumulator

STA 8202

Store Accumulator content (Quotient) to
Memory

HLT

End of Program



FLOWCHART

START

GET DIVISOR INTO ACCUMULATOR , THEN MOVE IT TO
REGISTER B

GET DIVIDEND INTO ACCUMULATOR

SET CARRY TO ‘0’

COMPARE ACCUMULATOR TO
REGISTER B
INCREMENT C

SUBTRACT B FROM
ACCUMULATOR

NO

IF CARRY=1

STORE REMINDER
YES
MOVE QUOTIENT FROM C TO

STORE QUOTIENT IN
MEMORY
STOP



MNEMONICS:
8000

3A

01 82

LDA 8201

8003

47

8004

3A

00 82

LDA 8200

8007

0E

0

MVI C, 00

8009

B8

800A

DA

800D

90

SUB B

800E

0C

INR C

800F

C3

09 80

8012

32

03 82

8015

79

8016

32

8019

76

MOV B,A

Again
12 80

JC Store

JMP Again
Store

STA 8203
MOV A,C

02 82

INPUT & OUTPUT:
i)

CMP B

STA 8202
HLT


8200

DIVIDEND

6

8201

DIVISOR

3

8202

REMINDER 2

8203

QUOTIENT 0

ii)
8200

DIVIDEND

15

8201

DIVISOR

5

8202

REMINDER 4

8203

QUOTIENT 1

CALCULATION:
i) Dividend A=06 ; Divisor B=03
A – B = 06 -03 = 03 : While A>B , C = C+1
A – B= 03 – 03=00

: C=C+1

Reminder = 0 , Carry=02

RESULT: Thus program for dividing two hexadecimal numbers using
8085 Microprocessor has been executed


Date:
Experiment No:

ADDITION OF ‘n’ NUMBERS IN ARRAY
AIM: To add ‘n’ numbers in array and find the sum of those numbers
using 8085 Microprocessor with memory pointer.

PROGRAM:
Address Program

Explanation

LXI H, 8201
MOV B,M


XRA A

Set Accumulator to '0' to account for
product

INX H


ADD M

Add Contents of Memory to Accumulator
& store in Accumulator

JNC Ahead


INR C
Ahead

Move number of data to Register B from
Memory

MVI C, 00

Repeat


Increment register C by 1, If carry ==1

DCR B




JNZ Repeat

If B is not Zero, got back to Repeat

STA 8300

Store Accumulator content (Sum) to
Memory

MOV A,C

Accumulator

STA 8301

Store Accumulator content (Carry) to
Memory

HLT

End of Program



FLOWCHART

START
SET MEMORY POINTER
MOVE THE ‘n’ VALUE TO REGISTER B
FROM MEMORY
SET C FOR CARRY

CLEAR ACCUMULATOR

INCREMENT POINTER GET NEXT DATA

ADD COMTENTS OF MEMORY TO
ACCUMULATOR

IF
CARRY=0

NO

YES
DECREMENT B
NO
B==0?
YES
STORE SUM OF N NUMBERS

STORE CARRY IN MEMORY

STOP

INCREMENT C


MNEMONICS:
8000

21

01 82

LXI H, 8201

8003

46

8004

0E

8006

AF

8007

23

8008

86

8009

D2

800C

0C

800D

5

800E

C2

780

JNZ Repeat

8011

32

00 83

STA 8300

8014

71

8015

32

8018

76

MOV B,M
0

MVI C, 00
XRA A
Repeat

ADD M
0D 80

JNC Ahead
INR C
Ahead

DCR B

MOV A,C
01 83


INX H

STA 8301
HLT


INPUT & OUTPUT:
8200

No. of Elements

6

8201

DATA 1

2

8202

DATA 2

4

8203

DATA 3

6

8204

DATA 4

8

8205

DATA 5

0A

8206

DATA 6

0C

8300

TOTAL

2A

8301

CARRY

0



CALCULATION:
DATA 1 :

02

- 0000 0010

DATA 2 :

04

- 0000 0100

+

06

- 0000 0110

DATA 3 :

06

- 0000 0110

+

0C

- 0000 1100

DATA 4 :

08

- 0000 1000

+

14

- 0001 0100

DATA 5 :

0A

- 0000 1010

+

1E

- 0001 1110

DATA 6 :

0C

- 0000 1100

TOTAL

:

2A

- 0010 1010

CARRY

:

00

RESULT: Program to add ‘n’ numbers in array and find the sum of
those numbers using 8085 Microprocessor with memory pointer was
executed.



Date:
Experiment No:

SMALLEST IN ARRAY
AIM: To find the smallest element in an array of size ‘n’ using 8085
Microprocessor.

PROGRAM:
Address

Explanation

LXI H, 8200


MOV B,M

Memory

INX H


MOV A,M

Move contents of memory to Accumulator

DCR B


INX H


CMP M

Compare contents of memory with
Accumulator

JC Ahead

If carry==1 , go Ahead i.e., number is
larger

MOV A,M

Loop

Program




Ahead

DCR B


JNZ Loop

If Register B is not equal to '0', go to Loop

STA 8300

Store Accumulator content (Smallest No)
to Memory

HLT

End of Program



START

FLOWCHART

SET MEMORY POINTER
FROM MEMORY
MOVE DATA TO AVVUMULATOR
FROM MEMORY
DECREMENT B

ACCUMULATOR

IF
CARRY=1

NO

YES
DECREMENT B
NO
B==0?
YES
STORE SMALLEST OF N
NUMBERS INTO MEMORY

STOP

MOVE CONTENT
OF M TO A


MNEMONICS:
8000

21

00 82

LXI H, 8200

8003

46

MOV B,M

8004

23

INX H

8005

7E

MOV A,M

8006

5

DCR B

8007

23

8008

BE

8009

DA

800C

7E

800D

5

800E

C2

07 80

JNZ Loop

8011

32

00 83

STA 8300

8014

76

Loop

CMP M
0D 80

JC Ahead
MOV A,M
Ahead


INX H

DCR B

HLT


INPUT & OUTPUT:
8200

No. of Elements

6

8201

DATA 1

04

8202

DATA 2

03

8203

DATA 3

01

8204

DATA 4

02

8205

DATA 5

05

8206

DATA 6

0C

8300

TOTAL

01



CALCULATION:
B =6
i) A=04
; B=5
ii) M=03 , Compare M with A: Carry=0
A=03 ; B=4
iii) M=01, Compare M with A: Carry=0
A=01; B=3
iv)M=02, Compare M with A: Carry=1, B=2
v) M=05, Compare M with A: Carry=1, B=1
vi)M=0C, Compare M with A: Carry=1, B=0
Hence, A=01 Smallest number

RESULT: Program to find the smallest element in an array of size ‘n’
using 8085 Microprocessor has been executed.



Date:
Experiment No:

LARGEST IN ARRAY
AIM: To find the Largest element in an array of size ‘n’ using 8085
Microprocessor.

PROGRAM:
Address Program

Explanation

LXI H, 8200
MOV B,M

Memory

INX H


MOV A,M


DCR B


INX H


CMP M

Compare contents of memory with
Accumulator

JNC Ahead

If carry==0, go Ahead i.e., number is
smaller

MOV A,M

Loop





Ahead

DCR B


JNZ Loop

If Register B is not equal to '0', go to Loop

STA 8300

Store Accumulator content (Sum) to
Memory

HLT

End of Program



FLOWCHART

START
SET MEMORY POINTER
FROM MEMORY
MOVE DATA TO AVVUMULATOR
FROM MEMORY
DECREMENT B

ACCUMULATOR
IF
CARRY=0

NO

YES
DECREMENT B
NO
B==0?
YES
STORE LARGEST OF N
NUMBERS INTO MEMORY

STOP

MOVE CONTENT
OF M TO A


MNEMONICS:
ADDRESS OPCODE

OPERAND LOCATION COMMAND

8000

21

00 82

8003

46

MOV B,M

8004

23

INX H

8005

7E

MOV A,M

8006

5

DCR B

8007

23

8008

BE

8009

D2

800C

7E

800D

5

800E

C2

07 80

JNZ Loop

8011

32

00 83

STA 8300

8014

76

LXI H, 8200

Loop

CMP M
0D 80

JNC Ahead
MOV A,M
Ahead


INX H

DCR B

HLT


INPUT & OUTPUT:
8200

No. of Elements

6

8201

DATA 1

04

8202

DATA 2

03

8203

DATA 3

01

8204

DATA 4

22

8205

DATA 5

05

8206

DATA 6

0C

8300

TOTAL

01



CALCULATION:
B =6
i) A=04
; B=5
ii) M=03 , Compare M with A: Carry=1 B=4
iii) M=01, Compare M with A: Carry=1 ; B=3
iv)M=22, Compare M with A: Carry=0,
A=22, B=2
v) M=05, Compare M with A: Carry=1, B=1
vi)M=0C, Compare M with A: Carry=1, B=0
Hence, A=22 Largest number

RESULT: Program to find the Largest element in an array of size ‘n’
using 8085 Microprocessor has been executed



Date:
Experiment No:

SORTING IN ASCENDING ORDER
AIM: To Sort an array of ‘n’ element in ascending order PROGRAM:
LXI H, 8200
MOV E,M

Move contents of memory(size of array) to Register E

MOV B,M

Move number of data to Register B from Memory

MOV C,E

Move register E content to Register C

INX H


DCR C

Next


Decrement Register C by 1

Compare MOV A,M


INX H
CMP M

Compare contents of memory with Accumulator

JC Ahead

Jump on Carry to Ahead

MOV D,M

Move contents of Memory to Register D

MOV M,A

Move contents of Accumulator to Memory

DCX H

Decrement the memory pointer

MOV M,D

Move contents of Register D to Memory

INX H


DCR C


JNZ Compare

If Register C is not equal to '0', go to Compare

DCR B


JNZ Next

If Register B is not equal to '0', go to Next

HLT

Ahead


End of Program



START

FLOWCHART

SET MEMORY POINTER FOR DATA
GET NUMBER OF ELEMENTS IN
ARRAY MOVE TO E B(ref)
MOV CONTENTS OF E TO C
INCREMENT POINTER FOR DATA
DECREMENT C
MOVE DATA FROM M TO A

INCREMENT POINTER FOR NEXT DATA
COMPARE M WITH ACCUMULATOR
YES

CARRY???
NO
SWAP DATA BETWEEN
MEMORY AND ACCUMUL;ATOR
DECREMENT C

C==0?

YES

NO
DECREMENT B
YES

B==0?
NO
STOP



MNEMONICS:
ADDRESS
8000
8003
8004
8005
8006
8007
8008
8009
800A
800B
800E
800F
8010
8011
8012
8013
8014
8017
8018
801B

OPCODE
21
5E
46
4B
23
0D
7E
23
BE
DA
56
77
2B
72
23
0D
C2
05
C2
76

OPERAND
00 82

13 80

08 80
05 80

LOCATION COMMAND
LXI H, 8200
MOV E,M
MOV B,M
Next
MOV C,E
INX H
DCR C
Compare
MOV A,M
INX H
CMP M
JC Ahead
MOV D,M
MOV M,A
DCX H
MOV M,D
INX H
Ahead
DCR C
JNZ Compare
DCR B
JNZ Next
HLT

INPUT & OUTPUT:
8200
8201
8202
8203
8204
8205
8206

No. of Elements
DATA 1
DATA 2
DATA 3
DATA 4
DATA 5
DATA 6

6
5
8
3
6
7
15

After Sorting
8201 DATA 1
3


8202
8203
8204
8205
8206

DATA 2
DATA 3
DATA 4
DATA 5
DATA 6

5
6
7
8
15

8200
8201
8202
8203
8204
8205

No. of Elements
DATA 1
DATA 2
DATA 3
DATA 4
DATA 5

05
1A
0A
5C
18
23

After Sorting
8200 No. of Elements
8201 DATA 1
8202 DATA 2
8203 DATA 3
8204 DATA 4
8205 DATA 5

05
0A
1A
18
23
5C

RESULT: Program to Sort an array of ‘n’ element in ascending order
using 8085 Microprocessor was executed.



Date:
Experiment No:

SORTING IN DESCENDING ORDER
AIM: To Sort an array of ‘n’ element in ascending order using 8085
Microprocessor

PROGRAM:
Address Program

Explanation

LXI H, 8200
MOV E,M

Move contents of memory(size of array) to Register E

MOV B,M

Move number of data to Register B from Memory

MOV C,E

Move register E content to Register C

INX H


DCR C

Next



Compare MOV A,M


INX H
CMP M

Compare contents of memory with Accumulator

JNC Ahead

Jump on NO Carry to Ahead

MOV D,M

Move contents of Memory to Register D

MOV M,A


DCX H

Decrement the memory pointer

MOV M,D

Move contents of Register D to Memory

INX H
Ahead



DCR C




JNZ Compare

If Register C is not equal to '0', go to Compare

DCR B


JNZ Next

If Register B is not equal to '0', go to Next

HLT

End of Program



START

FLOWCHART

GET NUMBER OF ELEMENTS IN
ARRAY MOVE TO E B(ref)
MOV CONTENTS OF E TO C
INCREMENT POINTER FOR DATA
DECREMENT C
MOVE DATA FROM M TO A

INCREMENT POINTER FOR NEXT DATA
COMPARE M WITH ACCUMULATOR
YES

CARRY=0?
NO
SWAP DATA BETWEEN
MEMORY AND ACCUMUL;ATOR
DECREMENT C

C==0?

YES

NO
DECREMENT B
YES

B==0?
NO
STOP



MNEMONICS:
ADDRESS
8000
8003
8004
8005
8006
8007
8008
8009
800A
800B
800E
800F
8010
8011
8012
8013
8014
8017
8018
801B

OPCODE
21
5E
46
4B
23
0D
7E
23
BE
D2
56
77
2B
72
23
0D
C2
05
C2
76

OPERAND
00 82

13 80

08 80
05 80

LOCATION COMMAND
LXI H, 8200
MOV E,M
MOV B,M
Next
MOV C,E
INX H
DCR C
Compare
MOV A,M
INX H
CMP M
JC Ahead
MOV D,M
MOV M,A
DCX H
MOV M,D
INX H
Ahead
DCR C
JNZ Compare
DCR B
JNZ Next
HLT

INPUT & OUTPUT:
8200
8201
8202
8203
8204
8205
8206

No. of
Elements
DATA 1
DATA 2
DATA 3
DATA 4
DATA 5
DATA 6

6
06
18
1B
2C
1A
15



After Sorting
8201 DATA 1
8202 DATA 2
8203 DATA 3
8204 DATA 4
8205 DATA 5
8206 DATA 6

8200
8201
8202
8203
8204
8205

2C
1B
1A
18
15
06

No. of Elements
DATA 1
DATA 2
DATA 3
DATA 4
DATA 5

05
1A
0A
5C
18
23

After Sorting
8200 No. of Elements
8201 DATA 1
8202 DATA 2
8203 DATA 3
8204 DATA 4
8205 DATA 5

05
5C
23
1A
18
0A

RESULT: Program to Sort an array of ‘n’ element in descending order
using 8085 Microprocessor was executed.



Date:
Experiment No:

FIBONACCI SERIES
AIM: To display ‘n’ elements of the Fibonacci series using 8085
Microprocessor

PROGRAM:
Address Program
LXI H, 8300
LDA 8200
CPI 00
JZ End
MOV C,A
MVI B, 01

Again

end

MVI A,00
MOV M,A
INX H
DCR C
JZ End
MOV D,A
ADD B
MOV B,D
MOV M,A
INX H
DCR C
JNZ Again
RST 1

Explanation
Setting pointer for storing/ displaying data
Load contents of Accumulator with no. of numbers to be
generated
Check if 00
If Zero , end program - no display
Move contents of Accumulator to Register C
Move '01' (second number in Fibonacci Series) to Register
B
Move '00' (First number in Fibonacci Series) to
Accumulator
If Zero , end program
Move contents of Accumulator to Register D
Add contents of Register B to Accumulator
Move contents of Register D to Register B
If Register C is not equal to '0', go to Again
Reset command



START

FLOWCHART

GET NUMBER OF ELEMENTS TO BE
DISPLAYED TO ACCUMULATOR

YES

ACCU=0?
NO

MOVE A TO C
B=01 AND ACCUMULATOR=00

MOVE ACCUMULATOR CONTENT TO MEMORY
INCREMENT MEMORY POINTER

DECREMENT C
YES

C==0
NO
SWAP DATA BETWEEN
REGISTER B & ACCUMUL;ATOR

MOVE ACCUMULATOR TO MEMORY

INCREMENT MEMORY POINTER  , DECREMENT C

C NOT ZERO

YES

NO
STOP



MNEMONICS:
ADDRESS
8000
8003
8006
8008
800B
800C
800E
8010
8011
8012
8013
8016
8017
8018
8019
801A
801B
801C
801F

OPCODE
21
3A
FE
CA
4F
0B
3E
77
23
0D
CA
57
80
42
77
23
0D
C2
CF

00 83
LXI H, 8300
00 82
LDA 8200
00
CPI 00
1F 80
JZ End
MOV C,A
01
MVI B, 01
00
MVI A,00
MOV M,A
INX H
DCR C
1F 80
JZ End
Again
MOV D,A
ADD B
MOV B,D
MOV M,A
INX H
DCR C
16 80
JNZ Again
end
RST 1

INPUT & OUTPUT:
NO. of elements (8200)=06
8201
8202
8203
8204
8205
8206

0
1
1
2
3
5



CALCULATION:
Number of Elements in Series =06
00
01
+

01
01

+

02
01

+

03
02

+

05

RESULT: Program to display ‘n’ elements of the Fibonacci series using
8085 Microprocessor was executed


I/O INTERFACING WITH 8085
I/O STRUCTURE OF A TYPICAL
MICROCOMPUTER:

There are three major types of data transfer between the
microcomputer and art I/O device. They are,
•

•

•

Programmed I/O : In programmed I/O the data
transfer is accomplished through an I/O port and
controlled by software.
Interrupt driven I/O : In interrupt driven I/O, the
I/O device will interrupt the processor, and initiate
data transfer.
Direct memory access (DMA) : In DMA, the data
transfer between memory and I/O can be performed
by bypassing the microprocessor.



INTERFACING I/O AND PERIPHERAL DEVICES:
1. For data transfer from input device to processor the
following operations are performed.
•
•
•
•

The input device will load the data to the port.
When the port receives a data, it sends message to
the processor to read the data.
The processor will read the data from the port.
After a data have been read by the processor the
input device will load the next data into the port.

2. For data transfer from processor to output device the
following operations are performed.
•
•
•
•
•

The processor will load the data to the port.
The port will send a message to the output device to
read the data.
The output device will read the data from the port.
After the data have been read by the output device
the processor can load the next data to the port.
The various INTEL 110 port devices are 8212,
8155/8156, 8255, 8355 and 8755.

8156:
•
•
•
•
•

It has two numbers of 8-bit parallel I/O port (port-A
and B)
One number of 6-bit parallel 1 port (port-C).
It has 14 bit timer (operating in 4 modes).
It has six internal addresses.
It has one chip select pin CS (low).



Fig - Internal address of 8156

8255:
•
•
•
•
•
•

It has 3 numbers of 8-bit parallel I/O ports (port A,
B and C).
Port-A can be programmed in mode-0 mode-1 or
mode-2 as input or output port.
Port-B can be programmed in mode-1 and mode-2
as 1/Oport.
When ports A and B are in mode-0, the port-C can be
used as I/O port.
One logic low chip select (CS) pin.
It requires four internal addresses

Fig - Internal address of 8255



Experiment No:

GENERATE SAWTOOTH WAVEFORM
AIM: To generate Sawtooth waveform using 8085 microprocessor

PROGRAM:
Start
Loop

MVI A,00
OUT C0
INR
JNZ Loop
JMP Start

Make Accumulator '0'
Display Accumulator content at Port
Increment Accumulator by '1'
If Accumulator is not equal to '0', go to Loop
Jump to Start unconditionally, for continuous wave form

MNEMONICS:
ADDRESS
4100
4102
4104
4105
4108

OPCODE
3E
D3
3C
C2
C3

00
Start
MVI A,00
C0
Loop
OUT C0
INR
02 41
JNZ Loop
00 41
JMP Start



FLOWCHART

START

MOVE 00 INTO ACCUMULATOR

DISPLAY VALUE AT PORT

INCREMENT A

A!=0

WAVEFORM:



CALCULATION:
Amplitude:
Time Period:

RESULT: The Sawtooth Waveform was generated and wave was
plotted.


Date:
Experiment No:

GENERATE TRIANGULAR WAVEFORM
AIM: To generate Triangular waveform using 8085 Microprocessor.

PROGRAM:
Start

MVI L,00

Set Register L equal to '0' -minimum

Loop 1

MOV A,L

Move contents of Register L to Accumulator

OUT C8


INR L

Increment Register L by '1'

JNZ Loop1

If Register L is not '0' jump to Loop1

MVI L,FF

Set Register L equal to 'FF' - maximum

MOV A,L

Move contents of Register L to Accumulator

OUT C8


DCR L

Decrement Register L by '1'

JNZ Loop2

If Register L is not '0' jump to Loop2

JMP Start

Jump to Start unconditionally, for continuous wave form

Loop 2



START

FLOWCHART
MOVE 00 INTO REGISTER L

MOVE CONTENT OF L INTO ACCUMULATOR


INCREMENT L

YES

L!=0

NO
MOVE ‘FF’ INTO REGISTER L

MOVE CONTENT OF L INTO ACCUMULATOR


DECREMENT L

YES

L!=0
NO



MNEMONICS:
4100

2E

0

Start

MVI L,00

4102

7D

Loop 1

MOV A,L

4103

D3

4105

2C

4106

C2

03 41

JNZ Loop1

4109

2E

FF

MVI L,FF

410B

7D

410C

D3

410E

2D

410F

C2

0C 41

JNZ Loop2

4112

C3

00 41

JMP Start

C8

OUT C8
INR L

Loop 2
C8

MOV A,L
OUT C8
DCR L

WAVEFORM:



CALCULATION:
Amplitude:
Time Period:

RESULT: The Triangular Waveform was generated and wave was
plotted.


Date:
Experiment No:

GENERATE SQUARE WAVEFORM
AIM: To generate Square waveform using 8085 Microprocessor

PROGRAM:
Start

Return

DELAY
Loop 1
Loop 2

MVI A,00
OUT C8
CALL
DELAY
MVI A,FF
OUT C8
CALL
DELAY
JMP Start

Move '0' into Accumulator
Display 0 at port
Call the DELAY subroutine
Move 'FF' into Accumulator
Display at port

MVI B,05
MVI C,FF
DCR C
JNZ Loop2
DCR B
JNZ Loop1
RET

Move 05 to Register B to give delay
Move FF to Register C
If C NOT '0' , decrement C again
Decrement Register B by 1
If B NOT '0', go to Loop1
Return to the main program

Call the DELAY subroutine
Jump to start



FLOWCHART

START

MOVE ‘0’ TO ACCUMULATOR

DISPLAY AT PORT
CALL DELAY

MOVE ‘FF’ TO ACCUMULATOR

DISPLAY AT PORT
CALL DELAY

MOVE 05 TO REGISTER B

MOVE FF TO REGISTER

DECREMENT C BY 1

NO

C==0?
YES
DECREMENT B BY 1

YES

B==0?

NO



MNEMONICS:
ADDRESS
4100
4102
4104
4107
4109
410B
410E

OPCODE
3E
D3
CD
3E
D3
CD
C3

OPERAND
0
C8
20 41
FF
C8
11 41
20 41

LOCATION
Start

4120
4122
4124
4125
4128
4129
412C

6
0E
0D
C2
5
C2
C9

5
FF

DELAY
Loop 1
Loop 2

24 41
22 41

Return

COMMAND
MVI A,00
OUT C8
CALL DELAY
MVI A,FF
OUT C8
CALL DELAY
JMP Start
MVI B,05
MVI C,FF
DCR C
JNZ Loop2
DCR B
JNZ Loop1
RET

WAVEFORM:



CALCULATION:
Amplitude:
Time Period:

RESULT: The Square Waveform was generated and wave was plotted.



Date:
Experiment No:

GENERATING SINE WAVE
AIM: To generate Sine Waveform using 8085 Microprocessor
PROGRAM:
Start

Set pointer to get data from Look-up table
Set Register C for number of data in look up
MVI C, 46
table
Loop
MOV A, M
Move contents of memory into Accumulator
OUT C0
Display out put at port
INX H
Increment memory pointer to next data
DCR C
Decrement register C
JNZ Loop
If C is not '0' , go to Loop
JMP Start
Start again
Look -Up Table : Starting Address : 4110
74
8A
BF
E7
FC
FA
E0
B5
7F
49
1D
04
07
25
53

LXI H, 4110

84
95
C8
ED
FE
F7
D9
AA
74
3F
17
01
0B
2D
5F

95
A0
D1
F2
FF
F2
D1
A0
69
36
10
00
10
36
69

A0
AA
D9
F7
FE
ED
C8
95
5F
2D
0B
01
17
3F
74

7F
B5
E0
FA
FC
E7
BF
8A
53
25
07
04
1D
49



FLOWCHART

START

SETTING POINTER FOR DATA TO
LOOK UP TABLE

MOVE 46 (ARRAY SIZE) TO
REGISTER C
MOVE CONTENT OF MEMORY TO
ACCUMULATOR

DISPLAY AT PORT

INCREMENT
MEMORY POINTER

DECREMENT C

YES

NO
C==0?



MNEMONICS:
ADDRESS

OPCODE

OPERAND

LOCATION COMMAND

4100

21

10 41

Start

4103

0E

46

4105

7E

4106

D3

4108

23

INX H

4109

0D

DCR C

410A

C2

05 41

JNZ Loop

410D

C3

00 41

JMP Start

MVI C, 46
Loop

C0

LXI H, 4110
MOV A, M
OUT C0

WAVEFORM:



CALCULATION:
Amplitude:
Time Period:

RESULT: The Sine Waveform was generated and wave was plotted.



8086 Pin Diagram



8086 Instruction Set Summary
Data Transfer Instructions
MOV
IN, OUT
LEA
LDS, LES
PUSH, POP
XCHG
XLAT

Move byte or word to register or memory
Input byte or word from port, output word to port
Load effective address
Load pointer using data segment, extra segment
Push word onto stack, pop word off stack
Exchange byte or word
Translate byte using look-up table

Logical Instructions
NOT
AND
OR
XOR
TEST

Logical NOT of byte or word (one's complement)
Logical AND of byte or word
Logical OR of byte or word
Logical exclusive-OR of byte or word
Test byte or word (AND without storing)

Shift and Rotate Instructions
SHL, SHR
SAL, SAR
ROL, ROR
RCL, RCR

Logical shift left, right byte or word by 1 or CL
Arithmetic shift left, right byte or word by 1 or CL
Rotate left, right byte or word by 1 or CL
Rotate left, right through carry byte or word by 1 or CL

Arithmetic Instructions
ADD, SUB
ADC, SBB
INC, DEC
NEG
CMP
MUL, DIV
IMUL, IDIV
CBW, CWD

Add, subtract byte or word
Add, subtract byte or word and carry (borrow)
Increment, decrement byte or word
Negate byte or word (two's complement)
Compare byte or word (subtract without storing)
Multiply, divide byte or word (unsigned)
Integer multiply, divide byte or word (signed)
Convert byte to word, word to double word (useful before
multiply/divide)



Adjustments after arithmetic operations:
AAA, AAS,
AAM, AAD
ASCII adjust for addition, subtraction, multiplication, division
(ASCII codes 30-39)
DAA, DAS
Decimal adjust for addition, subtraction (binary coded decimal
numbers)

Transfer Instructions
JMP

Unconditional jump (short 127/8, near 32K, far between segments)

Conditional jumps:
JA (JNBE)
Jump if above (not below or equal) +127, -128 range only
JAE (JNB)
Jump if above or equal(not below) +127, -128 range only
JB (JNAE)
Jump if below (not above or equal) +127, -128 range only
JBE (JNA)
Jump if below or equal (not above) +127, -128 range only
JE (JZ)
Jump if equal (zero) +127, -128 range only
JG (JNLE)
Jump if greater (not less or equal) +127, -128 range only
JGE (JNL)
Jump if greater or equal (not less) +127, -128 range only
JL (JNGE)
Jump if less (not greater nor equal) +127, -128 range only
JLE (JNG)
Jump if less or equal (not greater) +127, -128 range only
JC, JNC
Jump if carry set, carry not set +127, -128 range only
JO, JNO
Jump if overflow, no overflow +127, -128 range only
JS, JNS
Jump if sign, no sign +127, -128 range only
JNP (JPO)
Jump if no parity (parity odd) +127, -128 range only
JP (JPE)
Jump if parity (parity even) +127, -128 range only
Loop control:
LOOP
Loop unconditional, count in CX, short jump to target address
LOOPE (LOOPZ) Loop if equal (zero), count in CX, short jump to target address
LOOPNE (LOOPNZ) Loop if not equal (not zero), count in CX, short jump to
target address
JCXZ
Jump if CX equals zero (used to skip code in loop)

Subroutine and Interrupt Instructions
CALL, RET

Call, return from procedure (inside or outside current segment)



INT, INTO
IRET

Software interrupt, interrupt if overflow
Return from interrupt

String Instructions
MOVS
Move byte or word string
MOVSB, MOVSW
Move byte, word string
CMPS
Compare byte or word string
SCAS
Scan byte or word string (comparing to A or AX)
LODS, STOS
Load, store byte or word string to AL or AX
Repeat instructions (placed in front of other string operations):
REP
Repeat
REPE, REPZ
Repeat while equal, zero
REPNE, REPNZ
Repeat while not equal (zero)

Processor Control Instructions
Flag manipulation:
STC, CLC, CMC
STD, CLD
STI, CLI
LAHF, SAHF
PUSHF, POPF

Set, clear, complement carry flag
Set, clear direction flag
Set, clear interrupt enable flag
Load AH from flags, store AH into flags
Push flags onto stack, pop flags off stack

Coprocessor, multiprocessor interface:
ESC
Escape to external processor interface
LOCK
Lock bus during next instruction
Inactive states:
NOP
WAIT
HLT

No operation
Wait for TEST pin activity
Halt processor



Date:
Experiment No:

16 BIT ADDITION USING 8086
AIM: To add two 16 bit numbers (4 digits) using the 8086
microprocessor.

PROGRAM:
Program
MOV SI, 1500
LODSW
MOV AX, BX
LODSW
ADD BX, AX
MOV
DI,[1520]

Explanation
Set source index as 1500
Load data from source memory and auto increment
memory pointer
Move data from AX to BX
Load data from source memory
Add contents of AX, BX

Set Destination index as address in 1520
Move Result in BX to location pointed by Destination
MOV [DI], BX Index
INT 3
Break Point



INPUT & OUTPUT:
i)

INPUT 1
4283
INPUT 2
2931
SUM
6BB4
CARRY 00
1500
83
1501

42


1502

31


1503

29


1520

B4

Lower Byte of Sum

1521

6B

Higher Byte of Sum

RESULT: Program to add two 16 bit numbers (4 digits) with 8086
microprocessor was executed



Date:
Experiment No:

MOVE CONTENTS OF ARRAY
AIM: To move contents of array from one memory location to another
memory location.

PROGRAM:
Address Program
MOV CL, 08
MOV SI, 1400
MOV DI, 1450
Loop
LODSB
MOV [DI], AL
INC DI
DEC CL
JNC Loop
INT 3

Explanation
Set number of data i.e., count
Set Destination index as memory address 1500
Move content of address pointed by destination Index to
lower byte of accumulator
Increment Destination index
Decrement count
Jump if not zero to Loop
Break Point



INPUT & OUTPUT:
INPUT
1400
1401
1402
1403
1404
1405
1406
1407

11
22
33
44
21
31
41
51

OUTPUT
1500
1501
1502
1503
1504
1505
1506
1507

11
22
33
44
21
31
41
51

RESULT: Program to shift contents of an array from one location to
another was executed



Date:
Experiment No:

SUM OF N CONSECUTIVE NUMBERS
AIM: To find the sum of N consecutive numbers with 8086
microprocessor
PROGRAM:
Address Program
MOV SI, 2000

LOOP

MOV CL, [SI]
MOV AL, 00
MOV BL, 01
ADD AL, BL
INC BL
DEC CL
JNZ LOOP
MOV DI, 2002
MOV [DI], AX
INT 3

Explanation
Move content of address pointed by source index to
CL
Clear AL to store sum
Move '1' to BL , as it’s the first number
Add content of BL to AL
increment BL
Decrement the count
Move content of Register A to destination, which is
the total sum
Break Point



INPUT & OUTPUT:
INPUT
OUTPUT

2000
2002

05
0F

1+2+3+4+5 = 15 = F (HEXADECIMAL)

RESULT: Thus program for finding sum of ‘n’ consequent numbers was
executed



Date:
Experiment No:

CONVERSION OF BCD TO HEXADECIMAL
AIM: To convert a BCD number into hexadecimal with 8086
microprocessor
PROGRAM:
Program
MOV SI, 1600
MOV DI, 1500
MOV AL, [SI]
MOV AH, AL
AND AH, 0F
MOV BL, AH
AND AL, F0
MOV CL, 04
ROR AL, CL
MOV BH, 0A
MUL BH
ADD AL, BL
MOV [DI], AL
INT 3

Explanation
Load BCD number into AL register
Move content of AL to AH
Mask MSD of BCD number
Save LSD in BL register
Mask LSD of BCD number
Load 04 to counter
rotate AL by counter times
move 0A to BH register
Multiply BH register
Add AL, BL
Move result to Destination
Break Point



INPUT & OUTPUT:
INPUT
OUTPUT

1600
1500

56
38

RESULT: Thus program for converting BCD to Hexadecimal number
was executed.



Date:
Experiment No:

SEPARATE ODD & EVEN
AIM: To separate odd and even numbers using 8086 microprocessor

PROGRAM:
Address Program
MOV CL, 06
MOV SI, 1600
MOV DI, 1500
Loop
LODSB
ROR AL, 01
JB Loop
ROL AL,01
MOV [DI], AL
INC DI
DEC CL
JNZ Loop
INT 3

Explanation
Set counter in CL register
Rotate AL once to right
If bit is one Jump to Loop
Rotate AL once to left
Move result to Destination
Increment Destination index
Decrement the count
Break Point



INPUT & OUTPUT:
INPUT

OUTPUT

1600
1601
1602
1603
1604
1605
1500
1501
1503

2
5
7
6
12
15
5
7
15

RESULT: Thus program for separating Odd & Even numbers was
executed.



8051 Pin Diagram



8051 Instruction Set
ARITHMETIC OPERATIONS
Mnemonic
Description
ADD A,Rn
Add register to Accumulator
ADD A,direct
Add direct byte to Accumulator
ADD A,@Ri
Add indirect RAM to Accumulator
ADD A,#data
Add immediate data to Accumulator
ADDC A,Rn
Add register to Accumulator with Carry
ADDC A,direct
Add direct byte to Accumulator with Carry
ADDC A,@Ri
Add indirect RAM to Accumulator with Carry
ADDC A,#data
Add immediate data to Acc with Carry
SUBB A,Rn
Subtract Register from Acc with borrow
SUBB A,direct
Subtract direct byte from Acc with borrow
SUBB A,@Ri
Subtract indirect RAM from ACC with borrow
SUBB A,#data
Subtract immediate data from Acc with borrow
INC A
Increment Accumulator
INC Rn
Increment register
INC direct
Increment direct byte
INC @Ri
Increment direct RAM
DEC A
Decrement Accumulator
DEC Rn
Decrement Register
DEC direct
Decrement direct byte
DEC @Ri
Decrement indirect RAM
INC DPTR
Increment Data Pointer
MUL AB
Multiply A & B
DIV AB
Divide A by B
DA A
Decimal Adjust Accumulator
LOGICAL OPERATIONS
Mnemonic
Description
ANL A,Rn
AND Register to Accumulator
ANL A,direct
AND direct byte to Accumulator
ANL A,@Ri
AND indirect RAM to Accumulator
ANL A,#data
AND immediate data toAccumulator
ANL direct,A
AND Accumulator to direct byte


ANL direct,#data
ORL A,Rn

AND immediate data to direct byte
OR register to Accumulator

LOGICAL OPERATIONS (continued)
Mnemonic
Description
ORL A,direct
OR direct byte to Accumulator
ORL A,@Ri
OR indirect RAM to Accumulator
ORL A,#data
OR immediate data to Accumulator
ORL direct,A
OR Accumulator to direct byte
ORL direct,#data
OR immediate data to direct byte
XRL A,Rn
Exclusive-OR register to Accumulator
XRL A,direct
Exclusive-OR direct byte to Accumulator
XRL A,@Ri
Exclusive-OR indirect RAM to Accumulator
XRL A,#data
Exclusive-OR immediate data to Accumulator
XRL direct,A
Exclusive-OR Accumulator to direct byte
XRL direct,#data
Exclusive-OR immediate data to direct byte
CLR A
Clear Accumulator
CPL A
Complement Accumulator
RL A
Rotate Accumulator Left
RLC A
Rotate Accumulator Left through the Carry
RR A
Rotate Accumulator Right
RRC A
Rotate Accumulator Right through the Carry
SWAP A
Swap nibbles within the Accumulator
DATA TRANSFER
Mnemonic
MOV A,Rn
MOV A,direct
MOV A,@Ri
MOV A,#data
MOV Rn,A
MOV Rn,direct
MOV Rn,#data
MOV direct,A
MOV direct,Rn
MOV direct,direct
MOV direct,@Ri

Description
Move register to Accumulator
Move direct byte to Accumulator
Move indirect RAM to Accumulator
Move immediate data to Accumulator
Move Accumulator to register
Move direct byte to register
Move immediate data to register
Move Accumulator to direct byte
Move register to direct byte
Move direct byte to direct
Move indirect RAM to direct byte



MOV direct,#data
MOV @Ri,A
MOV @Ri,direct
MOV @Ri,#data
MOV DPTR,#data16

Move immediate data to direct byte
Move Accumulator to indirect RAM
Move direct byte to indirect RAM
Move immediate data to indirect RAM
Load Data Pointer with a 16-bit constant

DATA TRANSFER (continued)
Mnemonic
Description
MOVC A,@A+DPTR Move Code byte relative to DPTR to Acc
MOVC A,@A+PC
Move Code byte relative to PC to Acc
MOVX A,@Ri
Move External RAM (8- bit addr) to Acc
MOVX A,@DPTR
Move Exernal RAM (16- bit addr) to Acc
MOVX @Ri,A
Move Acc to External RAM (8-bit addr)
MOVX @DPTR,A
Move Acc to External RAM (16-bit addr)
PUSH direct
Push direct byte onto stack
POP direct
Pop direct byte from stack
XCH A,Rn
Exchange register with Accumulator
XCH A,direct
Exchange direct byte with Accumulator
XCH A,@Ri
Exchange indirect RAM with Accumulator
XCHD A,@Ri
Exchange low-order Digit indirect RAM with Acc
BOOLEAN VARIABLE MANIPULATION
Mnemonic
Description
CLR C
Clear Carry
CLR bit
Clear direct bit
SETB C
Set Carry
SETB bit
Set direct bit
CPL C
Complement Carry
CPL bit
Complement direct bit
ANL C,bit
AND direct bit to CARRY
ANL C,/bit
AND complement of direct bit to Carry
ORL C,bit
OR direct bit to Carry
ORL C,/bit
OR complement of direct bit to Carry
MOV C,bit
Move direct bit to Carry
MOV bit,C
Move Carry to direct bit
JC rel
Jump if Carry is set
JNC rel
Jump if Carry not set


JB bit,rel
JNB bit,rel
JBC bit,rel

Jump if direct Bit is set
Jump if direct Bit is Not set
Jump if direct Bit is set & clear bit

PROGRAM BRANCHING
Mnemonic
Description
ACALL addr11
Absolute Subroutine Call
LCALL addr16
Long Subroutine Call
RET
Return from Subroutine
PROGRAM BRANCHING(continued)
Mnemonic
Description
RETI
Return from interrupt
AJMP addr11
Absolute Jump
LJMP addr16
Long Jump
SJMP rel
Short Jump (relative addr)
JMP @A+DPTR
Jump indirect relative to the DPTR
JZ rel
Jump if Accumulator is Zero
JNZ rel
Jump if Accumulator is Not Zero
CJNE A,direct,rel
Compare direct byte to Acc and Jump if Not Equal
CJNE A,#data,rel
Compare immediate to Acc and Jump if Not Equal
CJNE Rn,#data,rel
Compare immediate to register and Jump if Not Equal
CJNE @Ri,#data,rel
Compare immediate to indirect and Jump if Not Equal
DJNZ Rn,rel
Decrement register and Jump if Not Zero
DJNZ direct,rel
Decrement direct byte and Jump if Not Zero
NOP
No Operation
Source : Atmel 8051 Microcontrollers Hardware Manual



Date:
Experiment No:

8 BIT ADDITION
AIM: To perform 8-bit addition using 8051 microcontroller
PROGRAM:
Address

Explanation

MOV a,#23

Move data 1 to a

MOV r1,#11

Move data 2 to register 1

MOV r2, #00

Set r2 for carry

ADD a,r1

Add a, r1

JNC ahead

Jump on no carry to ahead

INC r2
ahead

Program

If carry is '1' increment r2

MOV DPTR,#9200 Set datapointer to location 9200
move a contents to location pointed by data
MOVX @ DPTR,a pointer (DPTR)
INC DPTR

Increment pointer

MOV a,r2

Move r2 to a
LCALL 00BB

End



INPUT & OUTPUT:
Data 1
Data 2
9200
9201

23
11
34
0

RESULT: Thus program for adding two 8 bit numbers had been
executed.



Date:
Experiment No:

8 BIT SUBTRACTION
AIM: To perform 8-bit subtraction using 8051 microcontroller
PROGRAM:
Address

Explanation

MOV a,#23

Move data 1 to a

MOV r1,#11

Move data 2 to register 1

MOV r2, #00

Set r2 for carry

SUBB a,r1

Subtract r1 from a and store in a

JNC ahead

Jump on no carry to ahead

INC r2
ahead

Program

If carry is '1' increment r2

MOV DPTR,#9200 Set datapointer to location 9200
INC DPTR

Increment pointer

MOV a,r2

Move r2 to a
LCALL 00BB

End



INPUT & OUTPUT:
Data 1
Data 2
9200
9201

23
11
12
0

RESULT: Thus program for subtracting two 8 bit numbers had been
executed.


Microprocessor square wave

Recommended

More Related Content

What's hot (20)

Viewers also liked (20)

Similar to Microprocessor square wave (20)

Recently uploaded (20)

Microprocessor square wave