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4.1.3 Example Solution Three

T
Talia Carbis

The document calculates the electrical load and demand current for 11 circuits in a home. It groups the loads into categories like lighting, outlets, appliances, and assigns each a description, allowance, and demand calculation. The total demand current per phase is summarized at the bottom, with the highest draw of 46.5 amps on phase L3.

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4.1.3 Example Solution Three
4.1.3 Example Solution Three
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5

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4.1.3 Example Solution Three

  • 3. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
  • 4. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
  • 5. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
  • 6. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
  • 7. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
  • 8. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
  • 9. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
  • 10. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
  • 11. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
  • 12. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
  • 13. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
  • 14. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
  • 15. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5
  • 16. Demand Description Current allowance (Amps) Load Group of load per unit Calculation Circuit No (column 1) (given list) (column 2) L1 L2 L3 3 A (1st 20) 1 A (i) 13 Lighting points na 3.0 2 A (next 20) 2 A (i) 14 Lighting points 3 A (1st 20) na 3.0 3 A (i) 15 Lighting points 3 A (1st 20) na 3.0 8 + (4 x 2) = 16 8 single + socket points + 4 B (i) 10 A (1st 20) 10.0 1 (pool filter 4 double outlets pump) = 17 7 single + 7 + (5 x 2) = 5 B (i) 10 A (1st 20) 10.0 17 socket points 5 double outlets One 15 A 10 A B (ii) single phase (See note on group na 10.0 6 outlet in Table C1, B (ii)) 50% 7 C Cook top 4200/240 x 0.5 8.8 (or x 0.5) 50% 8 C Oven rating 5200/240 x 0.5 10.8 (or x 0.5) Pump rating = 4.3 A so socket outlet to be used for pump supply. 9 B (i) Pool filter pump na Socket will be part of circuit L1 so Included with circuit 4 calculations Air conditioner 75% 10 D 23.6 x 0.75 17.7 17.7 17.7 (23.6 A) (or x 0.75) 11a OPHWS F Full load current 15.0 bottom element 3600/240 11b OPHWS Included F Full load current 0.0 top element above Total demand current per phase 40.7 39.5 46.5