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Probability
Axioms of Probability
Let S be a finite sample space and A be an event in S. Then in the
axiomatic definition, the probability P ( A ) of the event A is a real
number assigned to A which satisfies the following three axioms:
1. Axiom 1 : P ( A )  1
2. Axiom 2 : P(S) = 1
3. Axiom 3 : P ( A  B) = P ( A ) + P(B) if A  B = 
If the sample space S is not finite, then axiom 3 must be modified as
follows:
Axiom 3*: If 𝐴1, 𝐴2 , 𝐴3, . . . is an infinite sequence of mutually
exclusive events in Sample space S (𝐴𝑖  𝐴𝑗 =  for i ≠ j), then
Elementary Properties of Probability:
By using the above axioms, the following useful properties of
probability can be obtained:
1. P(A’)= 1 – P(A)
2. P() = 0
3. P(A)  P(B) if A  B
4. 0 P(A)  1
5. P ( A  B) = P (A) + P(B) – P(A  B)
Example:
The probability of getting a white ball from the bag of balls is ¼.
What is the probability of not getting a white ball?
Solution:
Let A be the event of getting a white ball.
A’ = event of not getting a white ball.
P(A’)= 1 – P(A)
= 1 – ¼
= ¾

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Axioms of Probability

  • 2. Axioms of Probability Let S be a finite sample space and A be an event in S. Then in the axiomatic definition, the probability P ( A ) of the event A is a real number assigned to A which satisfies the following three axioms: 1. Axiom 1 : P ( A )  1 2. Axiom 2 : P(S) = 1 3. Axiom 3 : P ( A  B) = P ( A ) + P(B) if A  B = 
  • 3. If the sample space S is not finite, then axiom 3 must be modified as follows: Axiom 3*: If 𝐴1, 𝐴2 , 𝐴3, . . . is an infinite sequence of mutually exclusive events in Sample space S (𝐴𝑖  𝐴𝑗 =  for i ≠ j), then
  • 4. Elementary Properties of Probability: By using the above axioms, the following useful properties of probability can be obtained: 1. P(A’)= 1 – P(A) 2. P() = 0 3. P(A)  P(B) if A  B 4. 0 P(A)  1 5. P ( A  B) = P (A) + P(B) – P(A  B)
  • 5. Example: The probability of getting a white ball from the bag of balls is ¼. What is the probability of not getting a white ball? Solution: Let A be the event of getting a white ball. A’ = event of not getting a white ball. P(A’)= 1 – P(A) = 1 – ¼ = ¾