can you add a delete button and a add button to the below program. j.pdf
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The document describes a Java program that implements a linked list of Car objects. It includes classes for the Car object with attributes like make, model, year, and color, and a NuLinkedList class that implements basic linked list functionality for adding, removing, and accessing Car elements. The program reads a file of cars into an ArrayList and provides buttons to navigate between cars, displaying the current car details. The request is to add delete and add buttons to allow removing and adding cars to the linked list from the GUI.
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![BufferedReader reader = new BufferedReader(new FileReader("cars.txt"));
String line;
while ((line = reader.readLine()) != null) {
cars.add(line);
}
reader.close();
}
private void updateCarLabel(Label label) {
label.setText(cars.get(currentIndex));
}
public static void main(String[] args) {
launch(args);
}
}
package nusoft.utils;
import java.util.NoSuchElementException;
import nusoft.Car;
public class NuLinkedList {
private Node head;
private Node tail;
private int size;
private static class Node {
E element;
Node prev;
Node next;
Node(E element, Node prev, Node next) {
this.element = element;
this.prev = prev;
this.next = next;
}
}
public boolean contains(E e) {
return indexOf(e) != -1;
}](https://image.slidesharecdn.com/canyouaddadeletebuttonandaaddbuttontothebelowprogram-230401115206-28f3d941/85/can-you-add-a-delete-button-and-a-add-button-to-the-below-program-j-pdf-4-320.jpg)
![private E remove(Node node) {
if (node == head) {
head = node.next;
} else {
node.prev.next = node.next;
}
if (node == tail) {
tail = node.prev;
} else {
node.next.prev = node.prev;
}
size--;
return node.element;
}
@Override
public String toString() {
StringBuilder sb = new StringBuilder("[");
for (Node node = head; node != null; node = node.next) {
if (node != head) {
sb.append(", ");
}
sb.append(node.element);
}
sb.append("]");
return sb.toString();
}
public void remove(Car lastCar) {
// TODO Auto-generated method stub
}
}
( import java. io. BufferedReader;](https://image.slidesharecdn.com/canyouaddadeletebuttonandaaddbuttontothebelowprogram-230401115206-28f3d941/85/can-you-add-a-delete-button-and-a-add-button-to-the-below-program-j-pdf-8-320.jpg)
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Rewrite this code so it can use a generic type instead of integers. .pdf
Rewrite this code so it can use a generic type instead of integers. .pdfalphaagenciesindia Rewrite this code so it can use a generic type instead of integers. This means we can use any data
type with it.
For example:
LinkedList = new LinkedLIst<>();
public class Main {
public static void main(String[] args) {
/*
* Expected output:
*
* The list: 8 -> 1 -> 5 -> 3 -> 6
* Size: 5
* Head: 8
* Tail: 6
* Removeing 1...
* The list: 8 -> 5 -> 3 -> 6
* Size: 4
* Head: 8
* Tail: 6
* Removeing head...
* The list: 5 -> 3 -> 6
* Size: 3
* Head: 5
* Tail: 6
* Removeing tail...
* The list: 5 -> 3
* Size: 2
* Head: 5
* Tail: 3
*/
LinkedList list = new LinkedList();
list.append(5);
list.append(3);
list.append(6);
list.prepend(1);
list.prepend(8);
printListDetails(list);
System.out.println("Removeing 1...");
list.removeByValue(1);
printListDetails(list);
System.out.println("Removeing head...");
list.removeHead();
printListDetails(list);
System.out.println("Removeing tail...");
list.removeTail();
printListDetails(list);
}
public static void printListDetails(LinkedList list) {
System.out.println("The list: " + list.toString());
System.out.println("Size: " + list.size());
System.out.println("Head: " + list.getHead());
System.out.println("Tail: " + list.getTail());
}
}
________________________________________
public class LinkedList {
private Node head;
private Node tail;
private int size;
public LinkedList() {
head = null;
tail = null;
size = 0;
}
public void append(int data) {
Node newNode = new Node(data);
if (head == null) {
head = newNode;
} else {
tail.next = newNode;
}
tail = newNode;
size++;
}
public void prepend(int data) {
Node newNode = new Node(data);
if (head == null) {
head = newNode;
tail = newNode;
} else {
newNode.next = head;
head = newNode;
}
size++;
}
public int getHead() {
return head.data;
}
public int getTail() {
return tail.data;
}
public int size() {
return size;
}
public void removeByValue(int data) {
Node current = head;
while (current.next != null && current.next.data != data) {
current = current.next;
}
if (current.next != null) {
current.next = current.next.next;
size--;
if (current.next == null) {
tail = current;
}
}
}
public int removeHead() {
int removedData = head.data;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return removedData;
}
public int removeTail() {
int removedData = tail.data;
if (head == tail) {
head = null;
tail = null;
} else {
Node current = head;
while (current.next != tail) {
current = current.next;
}
tail = current;
tail.next = null;
}
size--;
return removedData;
}
@Override
public String toString() {
StringBuilder builder = new StringBuilder();
Node current = head;
while (current != null) {
builder.append(current.data);
if (current.next != null) {
builder.append(" -> ");
}
current = current.next;
}
return builder.toString();
}
private class Node {
public Node next;
public int data;
public Node(int data) {
this.data = data;
}
}
}.
Given below is the completed implementation of MyLinkedList class. O.pdf
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modified and remain same as in question - MyList, MyAbstractList, TestMyLinkedList.
The output of TestMyLinkedList is shown below. Please don\'t forget to rate the answer if it
helped. Thank you very much.
Since the MyList is not completely pasted in the question ... giving the complete class file below
MyList.java
public interface MyList> extends java.lang.Iterable
{
// Add a new element at the end of this list
public void add (E e);
// Add a new element at specified index in this list
public void add (int index, E e);
// Return true if this list contains the element
public boolean contains (E e);
// Return the element at the specified index
public E get (int index);
// Return the index of the first matching element
// Return -1 if no match.
public int indexOf (E e);
// Return the index of the last matching element
// Return -1 if no match.
public int lastIndexOf (E e);
E remove(int index);
void clear();
E set(int index, E e);
}
MyLinkedList.java
public class MyLinkedList> extends MyAbstractList
implements Comparable>
{
private Node head, tail; // head and tail pointers
// Create a default list
public MyLinkedList()
{
}
public int size()
{
return size;
}
// Need this for implementing Comparable
public int compareTo (MyLinkedList e)
{
return(size() - e.size());
}
// Create a list from an array of objects
public MyLinkedList (E[] objects)
{
super(objects); // Passes the array up to abstract parent
}
// Return the head element in the list
public E getFirst()
{
if (size == 0)
{
return null;
}
else
{
return head.element;
}
}
// Return the last element in the list
public E getLast()
{
if (size == 0)
{
return null;
}
else
{
return tail.element;
}
}
// Add an element to the beginning of the list
public void addFirst (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // new node is only node
{
tail = head;
}
}
// Add an element to the end of the list
public void addLast (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
if (tail == null)
{
head = tail = newNode; // new node is only node
}
else
{
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
// Remove the head node and
// return the object from the removed node
public E removeFirst()
{
if (size == 0)
{
return null;
}
else
{
Node temp = head;
head = head.next;
size--;
if (head == null)
{
tail = null;
}
return temp.element;
}
}
// Remove the last node and return the object from it
public E removeLast()
{
if (size == 0)
{
return null;
}
else if (size == 1)
{
Node temp = head;
head = tail = null;
size = 0;
return temp.element;
}
else
{
Node current = head;
for (int i = 0; i < size - 2; i++)
{
current = current.next;
}
Node temp = tail;
tai.
STAGE 2 The Methods 65 points Implement all the methods t.pdf
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Exercise. The Driver program only works when you have done all the methods. I have added the
template of all the methods with a placeholder value as return types of the methods. For example,
return 0 if method returns an int value.
List of the methods left as exercise are as follows: /** Create a list from an array of objects */
@SuppressWarnings("unchecked") public MyLinkedList(E[] objects) /** Add a new element at the
specified index in this list in ascending order */ public void addInOrder(E e) /** Check to see if this
list contains element e */ public boolean contains(E e) /** Remove all the occurrences of the
element e * from this list. Return true if the element is * removed. */ public boolean removeAll(E e)
/** Remove the first occurrence of the element e * from this list. Return true if the element is *
removed. */ public boolean remove(E e) /** Return the element at the specified index */ public E
get(int index) /** Return the index of the head matching element in * this list. Return -1 if no match.
*/ public int indexOf(Object e) /** Return the index of the last matching element in * this list. Return
-1 if no match. */ public int lastIndexOf(E e) /** Replace the element at the specified position * in
this list with the specified element. */ public E set(int index, E e) /** Print this list using recursion */
public void printList() /** Returns an array containing all of the elements * in this collection; * the
runtime type of the returned array is that of * the specified array. */ public <E> E[] toArray(E[]
array) /** Split the original list in half. The original * list will continue to reference the * front half of
the original list and the method * returns a reference to a new list that stores the * back half of the
original list.
public class MyLinkedList<E extends Comparable<E>> {
private Node<E> head, tail;
private int size = 0; // Number of elements in the list
public MyLinkedList() {
head=tail=null;
size=0;
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node<E> newNode = new Node<>(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node<E> newNode = new Node<>(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = newNode; // tail now points to the last node
}
size++; // Incr.
PLEASE MAKE SURE THE PROGRAM IS ASKING FOR INPUT FROM USER TO ADD OR.pdf
PLEASE MAKE SURE THE PROGRAM IS ASKING FOR INPUT FROM USER TO ADD OR.pdfmallik3000 PLEASE MAKE SURE THE PROGRAM IS ASKING FOR INPUT FROM USER TO ADD
OR REMOVE NAME. DO NOT HARD CODE NAME. AGAIN MAKE SURE THE
PROGRAM IS ASKING FOR INPUT FROM USER TO ADD OR REMOVE NAME. PLEASE
MAKE SURE THE CODE RUNS WITHOUT ANY ERRORS.
Write a class that maintains the scores for a game application. Implement the addition and
removal function to update the database. The gamescore.txt contains player’ name and score data
record fields separated by comma. For Removal function, uses the name field to select record to
remove the game score record.
Use the List.java, LList.java, Dlink.java, GameEntry.java and gamescore.txt found below
Read gamescore.txt to initialize the Linked list in sorted order by score.
Ask the user to add or remove users to update the sorted linked list.
Display “Name exist” when add an exist name to the list.
Display “Name does not exist” when remove a name not on the list.
List.java File:
/** Source code example for \"A Practical Introduction to Data
Structures and Algorithm Analysis, 3rd Edition (Java)\"
by Clifford A. Shaffer
Copyright 2008-2011 by Clifford A. Shaffer
*/
/** List ADT */
public interface List
{
/**
* Remove all contents from the list, so it is once again empty. Client is
* responsible for reclaiming storage used by the list elements.
*/
public void clear();
/**
* Insert an element at the current location. The client must ensure that
* the list\'s capacity is not exceeded.
*
* @param item
* The element to be inserted.
*/
public void insert(E item);
/**
* Append an element at the end of the list. The client must ensure that
* the list\'s capacity is not exceeded.
*
* @param item
* The element to be appended.
*/
public void append(E item);
/**
* Remove and return the current element.
*
* @return The element that was removed.
*/
public E remove();
/** Set the current position to the start of the list */
public void moveToStart();
/** Set the current position to the end of the list */
public void moveToEnd();
/**
* Move the current position one step left. No change if already at
* beginning.
*/
public void prev();
/**
* Move the current position one step right. No change if already at end.
*/
public void next();
/** @return The number of elements in the list. */
public int length();
/** @return The position of the current element. */
public int currPos();
/**
* Set current position.
*
* @param pos
* The position to make current.
*/
public void moveToPos(int pos);
/** @return The current element. */
public E getValue();
}
LList.java File:
/**
* Source code example for \"A Practical Introduction to Data Structures and
* Algorithm Analysis, 3rd Edition (Java)\" by Clifford A. Shaffer Copyright
* 2008-2011 by Clifford A. Shaffer
*/
// Doubly linked list implementation
class LList implements List
{
private DLink head; // Pointer to list header
private DLink tail; // Pointer to last element in list
protected DLink curr; // Pointer ahead of current element
int cnt; // Size of list
// Constructors
LList(int size)
{
th.
import java-util--- public class MyLinkedList{ public static void.pdf
import java-util--- public class MyLinkedList{ public static void.pdfasarudheen07 import java.util.*; public class MyLinkedList{ public static void main(String[] args){ } } //copy
MyList to here interface MyList extends Collection { /* MyList will inherite all methods from
Collection public boolean add(E e); public boolean addAll(Collection extends E> c); public void
clear(); public boolean contains(Object o); public boolean containsAll(Collection> c); public
boolean isEmpty(); public boolean remove(Object o); public boolean removeAll(Collection> c);
public boolean retainAll(Collection> c); public int size(); public Object[] toArray(); public T[]
toArray(T[] arr); */ //abstract method public void add(int index, E e); public E get(int index);
public int indexOf(Object e); public int lastIndexOf(E e); public E remove(int index); public E
set(int index, E e); //default method @Override public default boolean add(E e){ add(size(), e);
return true; } @Override public default boolean isEmpty(){ return size()==0; } @Override
public default boolean remove(Object e){ if(indexOf(e) >= 0){ remove(indexOf(e)); return true;
} else{ return false; } } @Override public default boolean containsAll(Collection> c){
for(Object e : c){ if(!contains(e)){ return false; } } return true; } @Override public default
boolean addAll( Collection extends E> c){ for(E e : c){ add(e); } return true; } /* removeAll:
this[1,1,2,3] c[1,2,4] this.removeAll(c) [3] */ @Override public default boolean removeAll(
Collection> c){ for(Object e : c){ while(contains(e)){ this.remove(e); } } return true; } /*
retainAll this[1,1,2,3] c[1,2,4] this.retainAll(c) [1,1,2] */ @Override public default boolean
retainAll( Collection> c){ for(E e : this){ if(!c.contains(e)){ this.remove(e); } } return true; }
@Override public default Object[] toArray(){ Object[] results = new Object[size()]; int i = 0;
for(E e : this){ results[i++] = e; } return results; } /* T[] array */ @Override public default T[]
toArray(T[] array){ int i = 0; for(E e : this){ array[i++] = (T)e; } return array; } } class
TwoWayLinkedList implements MyList { //inner static class Node public class Node { E
element; Node next; Node previous; public Node(E e){ element = e; } } private Node head, tail;
private int size = 0; public TwoWayLinkedList(){ /* head = null; tail = null; size = 0; */ } public
TwoWayLinkedList(E[] objects){ } public E getFirst(){ return null; } public E getLast(){ return
null; } public void addFirst(E e){ } public void addLast(E e){ } public E removeFirst(){ return
null; } public E removeLast(){ return null; } @Override public void add(int index, E e){ }
@Override public E remove(int index){ return null; } @Override public void clear(){ }
@Override public boolean contains(Object e){ return false; } @Override public E get(int index){
return null; } @Override public int indexOf(Object e){ return -1; } @Override public int
lastIndexOf(Object e){ return -1; } @Override public E set(int index, E e){ return null; }
@Override public int size(){ return size; } //toString() @Override public String.
public class MyLinkedListltE extends ComparableltEgtg.pdf
public class MyLinkedListltE extends ComparableltEgtg.pdfaccostinternational public class MyLinkedList<E extends Comparable<E>> {
private Node<E> head, tail;
private int size = 0; // Number of elements in the list
public MyLinkedList() {
head=tail=null;
size=0;
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node<E> newNode = new Node<>(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node<E> newNode = new Node<>(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = newNode; // tail now points to the last node
}
size++; // Increase size
}
public void add(int index, E e) {
if (index == 0) {
addFirst(e);
}
else if (index >= size) {
addLast(e);
}
else {
Node<E> current = head;
for (int i = 1; i < index; i++) {
current = current.next;
}
Node<E> temp = current.next;
current.next = new Node<>(e);
(current.next).next = temp;
size++;
}
}
//Add e to the end of this linkedlist
public void add(E e) {
// Left as Exercise
}
/** Remove the head node and
* return the object that is contained in the removed node. */
public E removeFirst() {
if (size == 0) {
return null;
}
else {
E temp = head.element;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return temp;
}
}
/** Remove the last node and
* return the object that is contained in the removed node. */
public E removeLast() {
if (size == 0) {
return null;
}
else if (size == 1) {
E temp = head.element;
head = tail = null;
size = 0;
return temp;
}
else {
Node<E> current = head;
for (int i = 0; i < size - 2; i++) {
current = current.next;
}
E temp = tail.element;
tail = current;
tail.next = null;
size--;
return temp;
}
}
/** Remove the element at the specified position in this
* list. Return the element that was removed from the list. */
public E remove(int index) {
if (index < 0 || index >= size) {
return null;
}
else if (index == 0) {
return removeFirst();
}
else if (index == size - 1) {
return removeLast();
}
else {
Node<E> previous = head;
for (int i = 1; i < index; i++) {
previous = previous.next;
}
Node<E> current = previous.next;
previous.next = current.next;
size--;
return current.element;
}
}
/** Clear the list */
public void clear() {
size = 0;
head = tail = null;
}
/** Override toString() to return elements in the list in [] separated by , */
public String toString() {
StringBuilder result = new StringBuilder("[");
Node<E> current = head;
for (int i = 0; i < size; i++) {
result.append(current..
Please complete all the code as per instructions in Java programming.docx
Please complete all the code as per instructions in Java programming.docxcgraciela1 Please complete all the code as per instructions in Java programming import org.w3c.dom.Node; import javax.xml.crypto.NodeSetData; import java.awt.*; import java.util.Iterator; import java.util.NoSuchElementException; /** * This class implements an acyclic (non-cyclic), doubly-linked list. * @param */ public class CiscDoublyLinkedList implements CiscList { /** * A reference to the first node in the list (or null if list is empty). */ private Node head; /** * A reference to the last node int the list (or null if list is empty). */ private Node tail; /** * Number of elements in the list. */ private int size; /** * Returns the number of elements in this list. * * * @return the number of elements in this list */ @Override public int size() { return size; } /** * Returns {@code true} if this list contains no elements. * * * @return {@code true} if this list contains no elements */ @Override public boolean isEmpty() { if (size == 0){ return true; } return false; } /** * Returns {@code true} if this list contains the specified element (compared using the {@code equals} method). * * * @param o element whose presence in this list is to be tested * @return {@code true} if this list contains the specified element * @throws NullPointerException if the specified element is null */ @Override public boolean contains(Object o) { if(o == null) { throw new NullPointerException(); } Node node = head; while(node != null) { if(node.data.equals(o)){ return true; } node = node.next; } return false; } /** * Returns the index of the first occurrence of the specified element in this list, or -1 if this list does not * contain the element (compared using the {@code equals} method). * * * @param o element to search for * @return the index of the first occurrence of the specified element in this list, or -1 if this list does not * contain the element * @throws NullPointerException if the specified element is null */ @Override public int indexOf(Object o) { if (o == null){ throw new NullPointerException(); } for(int i =0; i = size){ throw new IndexOutOfBoundsException(); } return null; } /** * Appends the specified element to the end of this list. * * *
Lists may place the specified element at arbitrary locations if desired. In particular, an ordered list will * insert the specified element at its sorted location. List classes should clearly specify in their documentation * how elements will be added to the list if different from the default behavior (end of this list). * * @param e element to be appended to this list * @return {@code true} * @throws NullPointerException if the specified element is null */ @Override public boolean add(E e) { if(e == null){ throw new NullPointerException(); } return false; } /** * Replaces the element at the specified position in this list with the specified element. * * * @param index index of the element to replace * @param element element to be stored at the specified position * @return the element previously at the specified position *.
Help please!!(Include your modified DList.java source code file in.pdf
Help please!!(Include your modified DList.java source code file in.pdfjyothimuppasani1 Help please!!
(Include your modified DList.java source code file in your homework solution zip archive)
Using
whatever Java IDE you prefer, create a project and add DList.java and DListTest.java to it (these
files are provided
in the Week 6 Source zip archive). Modify DList to implement a method that removes all
occurrences of a specific
integer from the list. Here is the pseudocode:
Method removeAll(In: Integer pData) Returns Nothing
Define index variable i and initialize i to 0
While i < the size of this Dlist Do
If get(i) equals pData Then
remove(i)
Else
Increment i
End If
End While
End Method removeAll
Next, modify DListTest() to add test case 21 which tests that removeAll() works correctly.
WHat more do i need to provide to get help on this???
Solution
/* DListNode.java */
/**
* A DListNode is a node in a DList (doubly-linked list).
*/
class DListNode {
/**
* item references the item stored in the current node.
* prev references the previous node in the DList.
* next references the next node in the DList.
*
* DO NOT CHANGE THE FOLLOWING FIELD DECLARATIONS.
*/
public Object item;
protected DListNode prev;
protected DListNode next;
/**
* DListNode() constructor.
* @param i the item to store in the node.
* @param p the node previous to this node.
* @param n the node following this node.
*/
DListNode(Object i, DListNode p, DListNode n) {
item = i;
prev = p;
next = n;
}
}
/* DList.java */
/**
* A DList is a mutable doubly-linked list ADT. Its implementation is
* circularly-linked and employs a sentinel (dummy) node at the head
* of the list.
*
* DO NOT CHANGE ANY METHOD PROTOTYPES IN THIS FILE.
*/
class DList {
/**
* head references the sentinel node.
* size is the number of items in the list. (The sentinel node does not
* store an item.)
*
* DO NOT CHANGE THE FOLLOWING FIELD DECLARATIONS.
*/
protected DListNode head;
protected int size;
/* DList invariants:
* 1) head != null.
* 2) For any DListNode x in a DList, x.next != null.
* 3) For any DListNode x in a DList, x.prev != null.
* 4) For any DListNode x in a DList, if x.next == y, then y.prev == x.
* 5) For any DListNode x in a DList, if x.prev == y, then y.next == x.
* 6) size is the number of DListNodes, NOT COUNTING the sentinel,
* that can be accessed from the sentinel (head) by a sequence of
* \"next\" references.
*/
/**
* newNode() calls the DListNode constructor. Use this class to allocate
* new DListNodes rather than calling the DListNode constructor directly.
* That way, only this method needs to be overridden if a subclass of DList
* wants to use a different kind of node.
* @param item the item to store in the node.
* @param prev the node previous to this node.
* @param next the node following this node.
*/
protected DListNode newNode(Object item, DListNode prev, DListNode next) {
return new DListNode(item, prev, next);
}
/**
* DList() constructor for an empty DList.
*/
public DList() {
// Your solution here.
head = newNode(null, head, head);
head.prev = head;
head.next = head;
si.
For the following questions, you will implement the data structure to.pdf
For the following questions, you will implement the data structure to.pdfarjunhassan8 For the following questions, you will implement the data structure to store information used by a
local car dealer. Each car has some information and stored in a text files called cars: Write a
main program for all questions to let the user enter, delete, search for information, and print
current cars stored in the data structure. Cars formatted so car records separated by a blank line.
Each record contains (in order, each in a single line): Make (manufacturer). Model, Year,
Mileage, Price. Implement a double linked-list to store cars data. Write a double linked-list class
including search, delete, append (to the head and tail), and remove (from the head and tail).
Implement a FIFO queue of car data using the double linked-list. You can use the double linked
list you wrote in Q1. Implement a max-heap of cars data that can extract the car with the highest
price. Write a max-heap class including heapify, build heap, extract, and insertion. Implement a
binary search tree of car data. Write a BST class including search, insertion, and deletion.
Solution
Cars.java
package pacages;
public class Cars {
String make;
String model;
int year;
double mileage;
double price;
// Setters and getters for the Cars member variables
public String getMake() {
return make;
}
public void setMake(String make) {
this.make = make;
}
public String getModel() {
return model;
}
public void setModel(String model) {
this.model = model;
}
public int getYear() {
return year;
}
public void setYear(int year) {
this.year = year;
}
public double getMileage() {
return mileage;
}
public void setMileage(double mileage) {
this.mileage = mileage;
}
public double getPrice() {
return price;
}
public void setPrice(double price) {
this.price = price;
}
public String toString()
{
return \"Make: \"+getMake()+ \" Model: \"+getModel()+ \" Year: \"+getYear() + \"
Mileage: \"+getMileage() + \" Price: \"+getPrice();
}
}
DoublyLinkedList.java
package pacages;
class Node
{
protected Cars data;
protected Node next, prev;
/* Constructor */
public Node()
{
next = null;
prev = null;
data = null;
}
/* Constructor */
public Node(Cars d, Node n, Node p)
{
data = d;
next = n;
prev = p;
}
/* Function to set link to next node */
public void setLinkNext(Node n)
{
next = n;
}
/* Function to set link to previous node */
public void setLinkPrev(Node p)
{
prev = p;
}
/* Funtion to get link to next node */
public Node getLinkNext()
{
return next;
}
/* Function to get link to previous node */
public Node getLinkPrev()
{
return prev;
}
/* Function to set data to node */
public void setData(Cars d)
{
data = d;
}
/* Function to get data from node */
public Cars getData()
{
return data;
}
}
/* Class linkedList */
public class DoublyLinkedList
{
protected Node start;
protected Node end ;
public int size;
/* Constructor */
public DoublyLinkedList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isEmpty()
{
return start == null;
}
/* Function to get size of list */
public.
Implement the interface you wrote for Lab B (EntryWayListInterface)..pdf
Implement the interface you wrote for Lab B (EntryWayListInterface)..pdfrishabjain5053 This document describes implementing an EntryWayListInterface using either an array or linked nodes. It provides the interface methods that must be implemented which include insertHead, insertTail, deleteHead, deleteTail, display, contains, isEmpty, and isFull. It also describes creating a driver program to test the implementation by adding and removing elements from the list and checking for elements. A second class is to implement the interface using an AList or LList object instead of an array or linked nodes.
Hi,I have added the methods and main class as per your requirement.pdf
Hi,I have added the methods and main class as per your requirement.pdfannaelctronics Hi,
I have added the methods and main class as per your requirement. it is working fine now.
Highlighted the code changes.
MyLinkedListTest.java
public class MyLinkedListTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
MyLinkedList list = new MyLinkedList();
list.addFirst(\"AAAAA\");
list.add(\"1\");
list.add(\"2\");
list.add(\"3\");
list.addLast(\"ZZZZZ\");
System.out.println(\"Linked List Elements : \"+list.toString());
System.out.println(\"First element: \"+list.getFirst());
System.out.println(\"Second element: \"+list.getLast());
System.out.println(\"Removed First Element: \"+list.removeFirst());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed Last Element: \"+list.removeLast());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed all element: \");
list.removeAll();
System.out.println(\"Now Linked List Elements : \"+list.toString());
}
}
MyLinkedList.java
public class MyLinkedList extends MyAbstractList {
private Node head, tail;
/** Create a default list */
public MyLinkedList() {
}
/** Create a list from an array of objects */
public MyLinkedList(E[] objects) {
super(objects);
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return (E)head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return (E)tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node newNode = new Node(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node newNode = new Node(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
/** Add a new element at the specified index in this list
* The index of the head element is 0 */
public void add(int index, E e) {
if (index == 0) {
addFirst(e);
}
else if (index >= size) {
addLast(e);
}
else {
Node current = head;
for (int i = 1; i < index; i++) {
current = current.next;
}
Node temp = current.next;
current.next = new Node(e);
(current.next).next = temp;
size++;
}
}
/** Remove the head node and
* return the object that is contained in the removed node. */
public E removeFirst() {
if (size == 0) {
return null;
}
else {
Node temp = head;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return (E)temp.element;
}
}
/** Remove all elements from list */
public void removeAll() {
while(true) {
if (size == 0) {
break;
}
else {
Node temp = head;
head =.
Write a Java Class to Implement a Generic Linked ListYour list mus.pdf
Write a Java Class to Implement a Generic Linked ListYour list mus.pdfrozakashif85 Write a Java Class to Implement a Generic Linked List
Your list must be implemented as a singly-linked list of generic nodes, where each Node object
has two instance variables: an object of the “type variable” class, and a pointer to the next node
on the list.
Your class will contain separate methods to handle each of the operations read from a data file
(see II., below)
Your class will also override toString() to return the objects on the list in the order in which they
occur.
Write a Test Class for Your LinkedList Class
Your main method will read list operation instructions from a data file, until end-of-file and call
the appropriate LinkedList method to execute each one.
After each operation is executed, print out the operation and the updated list.
The data file to be used is on the class web site and the operations are:
APPEND X - Append object X to the end of the list
ADD N X - Insert object X as the new Nth element in the list, increasing the size of the list by 1
E.g. Suppose the list is:
head -> 1 -> 2 -> 3 -> 4->null
After ADD 3 7 it would be:
head -> 1 -> 2 -> 7 -> 3 -> 4->null
DELETE N – Remove the Nth object from the list
SWAP M N - Interchange the positions of the Mth and Nth
objects on the list
For credit, the two nodes must actually \"trade places\" in the list, and not merely swap their data
values
REVERSE - Reverse the order of the objects on the list
This must be done by reversing the order of the nodes themselves, rather than by swapping the
data stored
To get credit for your reverse() method, it must use either one of these 2 algorithms:
For each node on the list except the current “head”
node, delete the node and insert it as the new head
Use your swap() method
6. CLEAR – Clear the list (make it empty)
No credit will be given for programs that use any additional data structures – either from the Java
API or programmer defined -, other than your own LinkedList class
txt file:
Solution
//Java Program to Implement Singly Linked List
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
/* Class Node */
class Nodes
{
protected Object data;
protected Nodes next;
/* Constructor */
public Nodes()
{
next = null;
data = null;
}
/* Constructor */
public Nodes(Object d,Nodes n)
{
data = d;
next = n;
}
/* Function to set link to next Node */
public void setLink(Nodes n)
{
next = n;
}
/* Function to set data to current Node */
public void setData(Object d)
{
data = d;
}
/* Function to get link to next node */
public Nodes getLink()
{
return next;
}
/* Function to get data from current Node */
public Object getData()
{
return data;
}
}
/* Class linkedList */
class linkList
{
protected Nodes start;
protected Nodes end ;
public int size ;
/* Constructor */
public linkList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isEmpty()
{
return start == null;
}
/* Function to get size of list */
public int getSize()
{
return .
package ex2- public class Exercise2-E- { private static class N.pdf
package ex2- public class Exercise2-E- { private static class N.pdfarcellzone package ex2;
public class Exercise2<E> {
private static class Node<E> {
private E element;
private Node<E> prev;
private Node<E> next;
public Node(E e, Node<E> p, Node<E> n) {
element = e;
prev = p;
next = n;
}
public E getElement() { return element; }
public Node<E> getPrev() { return prev; }
public Node<E> getNext() { return next; }
public void setPrev(Node<E> p) { prev = p; }
public void setNext(Node<E> n) { next = n; }
}
private Node<E> header;
private Node<E> trailer;
private int size = 0;
public Exercise2() {
header = new Node<>(null, null, null);
trailer = new Node<>(null, header, null);
header.setNext(trailer);
}
public int size() { return size; }
public boolean isEmpty() { return size == 0; }
public E first() {
if (isEmpty()) return null;
return header.getNext().getElement();
}
public E last() {
if (isEmpty()) return null;
return trailer.getPrev().getElement();
}
public void addFirst(E e) {
addBetween(e, header, header.getNext());
}
public void addLast(E e) {
addBetween(e, trailer.getPrev(), trailer);
}
public E removeFirst() {
if (isEmpty()) return null;
return remove(header.getNext());
}
public E removeLast() {
if (isEmpty()) return null;
return remove(trailer.getPrev());
}
private void addBetween(E e, Node<E> predecessor, Node<E> successor) {
if (predecessor == header && successor == trailer) {
// skip creation of new node for header/trailer
header.setNext(new Node<>(e, header, trailer));
trailer.setPrev(header.getNext());
} else {
Node<E> newest = new Node<>(e, predecessor, successor);
predecessor.setNext(newest);
successor.setPrev(newest);
}
size++;
}
private E remove(Node<E> node) {
Node<E> predecessor = node.getPrev();
Node<E> successor = node.getNext();
predecessor.setNext(successor);
successor.setPrev(predecessor);
size--;
return node.getElement();
}
public String toString() {
StringBuilder sb = new StringBuilder("(");
Node<E> walk = header;
while (walk != null) {
sb.append(walk.getElement());
walk = walk.getNext();
if (walk != null) {
sb.append(", ");
}
}
sb.append(")");
return sb.toString();
}
public void reverseList() {
Node<E> current = header;
header = trailer.getPrev();
trailer = current.getNext();
while (current != null) {
Node<E> temp = current.getNext();
current.setNext(current.getPrev());
current.setPrev(temp);
current = temp;
}
}
public static void main(String[] args)
{
Exercise2<String> list = new Exercise2<String>();
list.addFirst("MSP");
list.addLast("ATL");
list.addLast("BOS");
list.addFirst("LAX");
System.out.println(list);
list.reverseList();
System.out.println(list);
}
}
Here's my code, the output should reverse the list, but I'm keep getting errors, anyone mind to
help me to get a proper output?
.
Submit1) Java Files2) Doc file with the following contents.pdf
Submit1) Java Files2) Doc file with the following contents.pdfakaluza07 Submit:
1) Java Files
2) Doc file with the following contents:
//************************** SLL.java *********************************
// a generic singly linked list class
public class SLL {
private class SLLNode {
private T info;
private SLLNode next;
public SLLNode() {
this(null,null);
}
public SLLNode(T el) {
this(el,null);
}
public SLLNode(T el, SLLNode ptr) {
info = el; next = ptr;
}
}
protected SLLNode head, tail;
public SLL() {
head = tail = null;
}
public boolean isEmpty() {
return head == null;
}
public void addToHead(T el) {
head = new SLLNode(el,head);
if (tail == null)
tail = head;
}
public void addToTail(T el) {
if (!isEmpty()) {
tail.next = new SLLNode(el);
tail = tail.next;
}
else head = tail = new SLLNode(el);
}
public T deleteFromHead() { // delete the head and return its info;
if (isEmpty())
return null;
T el = head.info;
if (head == tail) // if only one node on the list;
head = tail = null;
else head = head.next;
return el;
}
public T deleteFromTail() { // delete the tail and return its info;
if (isEmpty())
return null;
T el = tail.info;
if (head == tail) // if only one node in the list;
head = tail = null;
else { // if more than one node in the list,
SLLNode tmp; // find the predecessor of tail;
for (tmp = head; tmp.next != tail; tmp = tmp.next);
tail = tmp; // the predecessor of tail becomes tail;
tail.next = null;
}
return el;
}
public void delete(T el) { // delete the node with an element el;
if (!isEmpty())
if (head == tail && el.equals(head.info)) // if only one
head = tail = null; // node on the list;
else if (el.equals(head.info)) // if more than one node on the list;
head = head.next; // and el is in the head node;
else { // if more than one node in the list
SLLNode pred, tmp;// and el is in a nonhead node;
for (pred = head, tmp = head.next;
tmp != null && !tmp.info.equals(el);
pred = pred.next, tmp = tmp.next);
if (tmp != null) { // if el was found;
pred.next = tmp.next;
if (tmp == tail) // if el is in the last node;
tail = pred;
}
}
}
@Override
public String toString() {
if(head == null)
return "[ ]";
String str = "[ ";
SLLNode tmp = head;
while(tmp != null){
str += tmp.info + " ";
tmp = tmp.next;
}
return str+"]";
}
public boolean contains(T el) {
if(head == null)
return false;
SLLNode tmp = head;
while(tmp != null){
if(tmp.info.equals(el))
return true;
tmp = tmp.next;
}
return false;
}
public int size(){
if(head == null)
return 0;
int count = 0;
SLLNode p = head;
while(p != null) {
count++;
p = p.next;
}
return count;
}
}
public class SLL_Driver {
public static void main(String[] args) {
SLL myList = new SLL();
String[] cityNames = {"Jubail", "Riyadh", "Abha", "Dammam", "Taif"};
for(int i = 0; i < cityNames.length; i++)
myList.addToHead(cityNames[i]);
System.out.println("The list is: " + myList);
System.out.println("It is " + myList.contains("Dammam") + " that the list contains
Dammam.");
System.out.println("It is " + myList.contains("Jeddah") + " that the list contains Jeddah.");
}
}
// Java program to implem.
import java.util.Iterator; import java.util.NoSuchElementException; .pdf
import java.util.Iterator; import java.util.NoSuchElementException; .pdfdeepakangel import java.util.Iterator; import java.util.NoSuchElementException; /** * An implementation
of MyList with a linked list (a longer exercise would be to * implement the List interface as is
done in the class java.util.LinkedList: * the source of the LinkedList class is available from Sun.
Check it out). */ public class MyLinkedList implements MyList { // A private class to
represent a Node in the linked list private class Node { public E item;
public Node next; // a convenient constructor public Node(E o) {
this.item = o; this.next = null; } } // The start of the linked
list private Node head; // The last Node in the linked list private Node tail;
// Number of elements in the list private int size; /** * Creates an empty list (this
constructor is not necessary) */ public MyLinkedList() { } /** *
Returns the number of elements in this list. */ public int size() { return size;
} /** * Returns true if this list contains no elements. */ public boolean
isEmpty() { return size == 0; } /** * Appends the specified element to
the end of this list */ public boolean add(E o) { Node n = new Node(o);
// If this is the first element in the list if (head == null) { head = n;
} else { // If the list is not empty, use tail tail.next = n;
} // update tail tail = n; // update size size++;
return true; } /** * Empties this List */ public void clear() {
// update head, tail and size head = tail = null; size = 0; } /**
* Returns the element at the specified position in this list. */ public E get(int index) {
if (index < 0 || index >= size) { throw new
IndexOutOfBoundsException(\"index = \" + index); } // Find it
Node n = head; for (int i = 0; i < index; i++) { n = n.next; }
return n.item; } /** * Returns the index of the specified element (-1 if
there is no match) */ public int indexOf(Object o) { // If o is null
int index = 0; Node p = head; if (o == null) // look for a null element in the
list { while (p != null) { if (p.item == null) {
return index; } index++;
p = p.next; } } else // o is an object (use equals) {
while (p != null) { if (o.equals(p.item)) { return
index; } index++; p = p.next;
} } // if we get here, o is not in the list return -1; }
/** * Returns true if this list contains the specified element. */ public boolean
contains(Object o) { // easy with indexOf return indexOf(o) != -1; }
/** * Removes the element in the List at position index */ public boolean
remove(int index) { if (index < 0 || index >= size) { throw new
IndexOutOfBoundsException(\"index = \" + index); } // Find the
corresponding node Node prev = null, p = head; for (int i = 0; i < index; i++)
{ prev = p; p = p.next; } // Remove it
// Special case for the first node if (p == head) { head = head.next;
} else { prev.next = p.next; } // If the last node has been
removed, update tail if (p == tail) { tail = prev; } //
update size size--; return true; } /** * Removes the element
in the List at position index */ public boolean remove(Object o) { // easy
with indexOf and remove int index = i.
This is the assignmentOBJECTIVESAfter finishing this lab, stude.pdf
This is the assignmentOBJECTIVESAfter finishing this lab, stude.pdfbharatchawla141 Sustainability: Sustainability is an important consideration for any nation. Discuss what countries
do to sustain their economy and help its people.
Solution
Sustainable development is a crucial subject to affix downward since it beset so many
contrasting stuff.Due to the complication of this accountable it is big to attention at the big in a
holistic action that approaches affair intelligently.The authority for sustainab;e development at
the civil level that is for the difficult mosaic is a mixture of economic,political that precondition
be bring combine under a particular set of circumstances.Any changes in the people life style
makes a economic atmosphere and candid of championship and business will make a country
effort easy..
Note- Can someone help me with the private E get(int index- int curren (1).docx
Note- Can someone help me with the private E get(int index- int curren (1).docxVictorzH8Bondx Note: Can someone help me with the private E get(int index, int currentIndex, Node n)method. The code is not running. Also I need help with the public void add(int index, E element) method too. Please use the parameters provided with the code to solve. package edu.ust.cisc; import java.util.Iterator; import java.util.NoSuchElementException; public class CiscSortedLinkedList > implements CiscList { /** * A reference to this list's dummy node. Its next reference should refer to the node containing the first element * in this list, or it should refer to itself if the list is empty. The next reference within the node containing * the last element in this list should refer to dummy, thus creating a cyclic list. */ private Node dummy; /** * Number of elements in the list. */ private int size; /** * Constructs an empty CiscSortedLinkedList instance with a non-null dummy node whose next reference refers to * itself. */ public CiscSortedLinkedList() { dummy = new Node<>(null, null); dummy.next = dummy; } /** * Returns the number of elements in this list. * * @return the number of elements in this list */ @Override public int size() { return size; } /** * Returns {@code true} if this list contains no elements. * * @return {@code true} if this list contains no elements */ @Override public boolean isEmpty() { return size==0; } /** * Returns {@code true} if this list contains the specified element (compared using the {@code equals} method). * This implementation should stop searching as soon as it is able to determine that the specified element is not * present. * * @param o element whose presence in this list is to be tested * @return {@code true} if this list contains the specified element * @throws NullPointerException if the specified element is null */ @Override public boolean contains(Object o) { if(o==null){ throw new NullPointerException(); } return containsHelper(o,dummy.next); } private boolean containsHelper(Object o, Node node){ if(node== dummy){ return false; } else if(o.equals(node.data)){ return true; } else{ return containsHelper(o,node.next); } } /** * Returns an iterator over the elements in this list in proper sequence. * * @return an iterator over the elements in this list in proper sequence */ @Override public Iterator iterator() { //return new Iterator (){ //private Node curr = dummy.next; //private Node prev = dummy; //private boolean canRemove = false; return null; } /** * Returns an array containing all of the elements in this list in proper sequence (from first to last element). *
The returned array will be "safe" in that no references to it are maintained by this list. (In other words, * this method must allocate a new array even if this list is backed by an array). The caller is thus free to modify * the returned array. * * @return an array containing all of the elements in this list in proper sequence */ @Override public Object[] toArray() { Object[] arr = new Object[size]; int i = 0; for(Node current = dummy;current!=null;cur.
So I have this code(StackInAllSocks) and I implemented the method but.pdf
So I have this code(StackInAllSocks) and I implemented the method but.pdfaksahnan So I have this code( StackInAllSocks ) and I implemented the method but I can't seem to figure
out why there isn't anything showing up on the console. It should pop,peek and push b using the
methods from the class called ArrayListTen . The ArrayListTen works fine and compiles the
tested code of Rigth# but for StackInAllSocks it doesn't complete at all. note that file
VodeDodeis not to be changed is just a Node storage area of the array list.
Did I implement the method on StackInAllSocks correctly? if so, should I not use the method
from the ArrayListTen .?
__________________________________________________________________________
: the code is : VodeDodeis
class VodeDode<T> {
private T data;
private VodeDode<T> next;
private VodeDode<T> prev;
public VodeDode(T data) {
this.data = data;
this.next = null;
this.prev = null;}
public T getData() {
return data;}
public void setData(T data) {
this.data = data;}
public VodeDode<T> getNext() {
return this.next;}
public void setNext(VodeDode<T> next) {
this.next = next;}
public VodeDode<T> getPrev() {
return this.prev;}
public void setPrev(VodeDode<T> prev) {
this.prev = prev;}
@Override
public String toString() {
return data.toString();}}
_________________________________________________________________________
CODE that works fine called ArrayListTen:
import java.util.Iterator;
public class ArrayListTen<T> implements Iterable<T> {
private VodeDode<T> head; //beginning of list
private VodeDode<T> tail; //end of list
private int size;
private VodeDode<T> new_item;
public ArrayListTen( ){
this.head = null;
this.tail = null;
this.size = 0;}
public int lenght() {
return size ;}
public T getBegin() {
if (this.head != null) {
return head.getData();}
else { return null;}}
public void addBegin(T value) {
VodeDode<T> newVodeDode =new VodeDode<T>(value);
if (this.head== null) {
head = newVodeDode;
tail =newVodeDode;}
else {VodeDode<T> temp = head;
head = newVodeDode;
head.setNext(temp);}
size++;}
public T removeBegin() {
if(this.head == null) {
return null;}
else {T current = head.getData();
if (tail == head) {
tail = null;
head = null;
} else {
head = head.getNext();
head.setPrev(null);}size--;
return current;}}
public T getEnd() {
if (tail != null) {
return tail.getData();
} else {
return null;}}
public void addEnd(T value) {
VodeDode<T> newVodeDode = new VodeDode<T>(value);
if (this.tail == null) {
head = newVodeDode;
tail = newVodeDode;
} else {
newVodeDode.setPrev(tail);
tail.setNext(newVodeDode);
tail = newVodeDode;}
size++;}
public T removeEnd() {
if(this.tail == null) {
return null;}
else {
T current = tail.getData();//was head.
if (head == tail) {
head = null;
tail = null;
} else {
tail = tail.getPrev();
tail.setNext(null);}
size--;
return current;}}
public T removeBN(T value) {
VodeDode<T> currVodeDode = head;
VodeDode<T> prevVodeDode = null;
while(currVodeDode != null){
if(currVodeDode.getData().equals(value)){
if(prevVodeDode != null){
prevVodeDode.setNext(currVodeDode.getNext());}
else{
head = curr.
Here is the editable codeSolutionimport java.util.NoSuchEleme.pdf
Here is the editable codeSolutionimport java.util.NoSuchEleme.pdfarrowmobile Here is the editable code:
Solution
import java.util.NoSuchElementException;
public class DoublyLinkedListImpl {
private Node head;
private Node tail;
private int size;
public DoublyLinkedListImpl() {
size = 0;
}
private class Node {
E element;
Node next;
Node prev;
public Node(E element, Node next, Node prev) {
this.element = element;
this.next = next;
this.prev = prev;
}
}
public int size() { return size; }
public boolean isEmpty() { return size == 0; }
public void addFirst(E element) {
Node tmp = new Node(element, head, null);
if(head != null ) {head.prev = tmp;}
head = tmp;
if(tail == null) { tail = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
/**
* adds element at the end of the linked list
* @param element
*/
public void addLast(E element) {
Node tmp = new Node(element, null, tail);
if(tail != null) {tail.next = tmp;}
tail = tmp;
if(head == null) { head = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void iterateForward(){
System.out.println(\"iterating forward..\");
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.next;
}
}
/**
* this method walks backward through the linked list
*/
public void iterateBackward(){
System.out.println(\"iterating backword..\");
Node tmp = tail;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.prev;
}
}
public E removeFirst() {
if (size == 0) throw new NoSuchElementException();
Node tmp = head;
head = head.next;
head.prev = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public E removeLast() {
if (size == 0) throw new NoSuchElementException();
Node tmp = tail;
tail = tail.prev;
tail.next = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public static void main(String a[]){
DoublyLinkedListImpl dll = new DoublyLinkedListImpl();
dll.addFirst(10);
dll.addFirst(34);
dll.addLast(56);
dll.addLast(364);
dll.iterateForward();
dll.removeFirst();
dll.removeLast();
dll.iterateBackward();
}
}
import java.util.Scanner;
/* Class Node */
class Node
{
protected int data;
protected Node next, prev;
/* Constructor */
public Node()
{
next = null;
prev = null;
data = 0;
}
/* Constructor */
public Node(int d, Node n, Node p)
{
data = d;
next = n;
prev = p;
}
/* Function to set link to next node */
public void setLinkNext(Node n)
{
next = n;
}
/* Function to set link to previous node */
public void setLinkPrev(Node p)
{
prev = p;
}
/* Funtion to get link to next node */
public Node getLinkNext()
{
return next;
}
/* Function to get link to previous node */
public Node getLinkPrev()
{
return prev;
}
/* Function to set data to node */
public void setData(int d)
{
data = d;
}
/* Function to get data from node */
public int getData()
{
return data;
}
}
/* Class linkedList */
class linkedList
{
protected Node start;
protected Node end ;
public int size;
/* Constructor */
public linkedList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isE.
Note- Can someone help me with the Public boolean add(E value) method.pdf
Note- Can someone help me with the Public boolean add(E value) method.pdfStewart29UReesa Note: Can someone help me with the Public boolean add(E value) method and Private void
add(E value,Node n) method. I have everything but it is not working. Also need help with the
remove methods. Both public and private methods for remove. package edu.ust.cisc; import
java.util.Iterator; import java.util.NoSuchElementException; public class CiscSortedLinkedList
> implements CiscList { /** * A reference to this list's dummy node. Its next reference should
refer to the node containing the first element * in this list, or it should refer to itself if the list is
empty. The next reference within the node containing * the last element in this list should refer to
dummy, thus creating a cyclic list. */ private Node dummy; /** * Number of elements in the list.
*/ private int size; /** * Constructs an empty CiscSortedLinkedList instance with a non-null
dummy node whose next reference refers to * itself. */ public CiscSortedLinkedList() { dummy
= new Node<>(null, null); dummy.next = dummy; } /** * Returns the number of elements in
this list. * * @return the number of elements in this list */ @Override public int size() { return
size; } /** * Returns {@code true} if this list contains no elements. * * @return {@code true} if
this list contains no elements */ @Override public boolean isEmpty() { return size==0; } /** *
Returns {@code true} if this list contains the specified element (compared using the {@code
equals} method). * This implementation should stop searching as soon as it is able to determine
that the specified element is not * present. * @param o element whose presence in this list is to
be tested * @return {@code true} if this list contains the specified element * @throws
NullPointerException if the specified element is null */ @Override public boolean
contains(Object o) { if(o==null){ throw new NullPointerException(); } return
containsHelper(o,dummy.next); } private boolean containsHelper(Object o, Node node){
if(node== dummy){ return false; } else if(o.equals(node.data)){ return true; } else{ return
containsHelper(o,node.next); } } /** * Returns an iterator over the elements in this list in proper
sequence. * * @return an iterator over the elements in this list in proper sequence */ @Override
public Iterator iterator() { //return new Iterator (){ //private Node curr = dummy.next; //private
Node prev = dummy; //private boolean canRemove = false; return new CiscLinkedListIterator();
} /** * Returns an array containing all of the elements in this list in proper sequence (from first
to last element). * *
The returned array will be "safe" in that no references to it are maintained by this list. (In other
words, * this method must allocate a new array even if this list is backed by an array). The caller
is thus free to modify * the returned array. * * @return an array containing all of the elements in
this list in proper sequence */ @Override public Object[] toArray() { Object[] arr = new
Object[size]; int i = 0; for(Node current = dummy;curren.
Use the singly linked list class introduced in the lab to implement .pdf
Use the singly linked list class introduced in the lab to implement .pdfsales87 Use the singly linked list class introduced in the lab to implement integers of unlimited size.
Each node of the list should store one digit of the integer. You are to implement the addition,
subtraction and multiplication operations. Please note that any additional data structure to be
used in solving this problem has to be taken from the ones introduced in the ICS 202 lab. In
addition, provide a test class that will do the following: It will keep asking the user to enter two
integers, choose one of the operations (addition, subtraction, multiplication) and then display the
result. The program will stop upon entering the # character (without the double quotes).
this singly linked list class:
public class SLL {
private class SLLNode {
private T info;
private SLLNode next;
int value;
public SLLNode() {
this(null, null);
}
public SLLNode(T el) {
this(el, null);
}
public SLLNode(T el, SLLNode ptr) {
info = el;
next = ptr;
}
}
protected SLLNode head, tail;
public SLL() {
head = tail = null;
}
public boolean isEmpty() {
return head == null;
}
public void addToHead(T el) {
head = new SLLNode(el, head);
if (tail == null)
tail = head;
}
public void addToTail(T el) {
if (!isEmpty()) {
tail.next = new SLLNode(el);
tail = tail.next;
} else
head = tail = new SLLNode(el);
}
public T deleteFromHead() { // delete the head and return its info;
if (isEmpty())
return null;
T el = head.info;
if (head == tail) // if only one node on the list;
head = tail = null;
else
head = head.next;
return el;
}
public T deleteFromTail() { // delete the tail and return its info;
if (isEmpty())
return null;
T el = tail.info;
if (head == tail) // if only one node in the list;
head = tail = null;
else { // if more than one node in the list,
SLLNode tmp; // find the predecessor of tail;
for (tmp = head; tmp.next != tail; tmp = tmp.next)
;
tail = tmp; // the predecessor of tail becomes tail;
tail.next = null;
}
return el;
}
public void delete(T el) { // delete the node with an element el;
if (!isEmpty())
if (head == tail && el.equals(head.info)) // if only one
head = tail = null; // node on the list;
else if (el.equals(head.info)) // if more than one node on the list;
head = head.next; // and el is in the head node;
else { // if more than one node in the list
SLLNode pred, tmp;// and el is in a nonhead node;
for (pred = head, tmp = head.next; tmp != null
&& !tmp.info.equals(el); pred = pred.next, tmp = tmp.next)
;
if (tmp != null) { // if el was found;
pred.next = tmp.next;
if (tmp == tail) // if el is in the last node;
tail = pred;
}
}
}
@Override
public String toString() {
if (head == null)
return "[ ]";
String str = "[ ";
SLLNode tmp = head;
while (tmp != null) {
str += tmp.info + " ";
tmp = tmp.next;
}
return str + "]";
}
public boolean contains(T el) {
if (head == null)
return false;
SLLNode tmp = head;
while (tmp != null) {
if (tmp.info.equals(el))
return true;
tmp = tmp.next;
}
return false;
}
public int size() {
if (head == null)
return 0;
int count = 0;
SLLNode p = head;
w.
Copy your completed LinkedList class from Lab 3 into the LinkedList..pdf
Copy your completed LinkedList class from Lab 3 into the LinkedList..pdffacevenky Copy your completed LinkedList class from Lab 3 into the LinkedList.java file below.
During this lab we will add more constructors, an equals method and more challenging methods
as listed below.
Also inspect the LabProgram.java file and notice that the main() method of the LabProgram
copies and compares two linked lists. The main() method also calls the more challenging
methods. Use Develop mode to test your LinkedList iterator code as you develop it.
In Submit mode you will need to complete all lab steps to pass all automatic tests.
Step 2: Implement clear()
Method clear() re-sets the LinkedList to empty as if the default constructor had just been called.
Constructor LinkedList(T[] array) converts the given array into a LinkedList.
Constructor LinkedList(LinkedList original) instantiates a new LinkedList by copying another
List.
Method equals() determines whether the given Object is another LinkedList, containing the same
data in the same order, returning whether there is equality.
Method spinList(int numMoves) moves all nodes in the list towards the end of the list the
number of times specified. Any node that falls off the end of the list as it moves forward will be
placed at the front of the list.
Method altLists() splices together two LinkedLists to create a third List which contains
alternating values from the original list and the given parameter.
*Below is my Lab3 LinkedList.class.
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
public T getFirst() throws NoSuchElementException {
if (first == null) throw new NoSuchElementException();
return first.data;
}
public T getLast() throws NoSuchElementException {
if (last == null) throw new NoSuchElementException();
return last.data;
}
public T getIterator() throws NullPointerException {
if (iterator == null) {
throw new NullPointerException("Iterator is off end.");
}
return iterator.data;
}
public int getLength() {
return length;
}
public boolean isEmpty() {
return length == 0;
}
public boolean offEnd() {
return iterator == null;
}
public void addFirst(T data) {
Node newNode = new Node(data);
if (length == 0) {
first = newNode;
last = newNode;
} else .
In this lab, we will write an application to store a deck of cards i.pdf
In this lab, we will write an application to store a deck of cards i.pdfcontact41 In this lab, we will write an application to store a deck of cards in a linked list, and then write
methods to sort and shuffle the deck.
Copy your completed LinkedList class from Lab 4 into the LinkedList.java file below.
Complete all methods of the Card class as described by the Javadoc comments. The class
contains both a suit and a rank. A suit is one of the categories into which the cards of a deck are
divided. The rank is the relative importance of the card within its suit.
Note that the Card constructor must convert any rank and suit letters to uppercase.
For the equals() method, be sure to follow the steps outlined in Lesson 4. How to implement the
compareTo() method is also covered in Lesson 4.
Note that you are not allowed to add any additional methods or member variables to this class or
you will not receive credit for this assignment.
Complete all methods of the CardApp class in the CardApp.java file as described by the Javadoc
comments.
You may add as many methods as you would like to this file, but are not allowed to add any
additional member variables.
The CardApp program must prompt for and allow the user to enter the name of any input file as
shown in the Example output below.
Implement the shuffle() method as specified in the comments for shuffle(). After you have
shuffled the deck of cards, write the result into a file named shuffled.txt.
Implement the sort() method using bubble sort from Lesson 4. First sort by suit in alphabetical
order and then by rank from 2 to A. The pseudocode for bubble sort is as follows:
After you have sorted the deck of cards, write the result to a file named sorted.txt.
The CardApp.java file also contains the main() method of the application. Use Develop mode to
test your CardApp code along with your Card and LinkedList code.
All input and output files must contain a list of cards, with each card stored on its own line. See
the example files cards1.txt and cards2.txt for example file formats.
[[[cards1.txt]]]
2H
3H
4H
5H
6H
7H
8H
9H
10H
JH
[[[cards2.txt]]]
AS
2S
3S
4S
5S
6S
7S
8S
9S
10S
JS
QS
KS
AC
2C
3C
4C
5C
6C
7C
8C
9C
10C
JC
QC
KC
AH
2H
3H
4H
5H
6H
7H
8H
9H
10H
JH
QH
KH
AD
2D
3D
4D
5D
6D
7D
8D
9D
10D
JD
QD
KD
[[[CardApp.java]]]
/**
* CardApp.java
* @author Your name
* @author Partner's name
* CIS 22C, Applied Lab 1
*/
public class CardApp {
private LinkedList list;
/**
* User interface prompts user, reads and writes files.
*/
public static void main(String[] args) {
}
/**
* Default constructor to initialize the deck
*/
public CardApp() {
}
/**
* Inserts a new Card into the deck
* @param card a playing Card
*/
public void addCard(Card card) {
}
/**
* Shuffles cards following this algorithm:
* First swaps first and last card
* Next, swaps every even card with the card 3
* nodes away from that card. Stops when it
* reaches the 3rd to last node
* Then, swaps ALL cards with the card that is
* 2 nodes away from it, starting at the 2nd card
* and stopping stopping at the 3rd to last node
*/
public vo.
Create a new java class called ListNode. Implement ListNode as a gen.pdf
Create a new java class called ListNode. Implement ListNode as a gen.pdfmohamednihalshahru Create a new java class called ListNode. Implement ListNode as a generic version of IntNode.
public class ListNode { }
Create a generic class called Queue, which is a linked list implementation of a queue data type.
Queue must have the following methods:
• public void enqueue(T value){} This method should add a new node to the back of the queue.
• public T dequeue(){} This method should remove a node from the front of the queue and return
its value
• public T peek(){} This method should return the value of the front node without removing it
from the queue
Create a new generic class called Stack, which is a linked list implementation of a stack data
type. Stack must have the following methods:
• public void push(T value){} This method should add a new node to the top of the stack.
• public T pop(){} This method should remove a node from the top of the stack and return its
integer value
• public T peek(){} This method should return the integer value of the top node without
removing it from the stack
Solution
import java.util.Iterator;
public class LinkedList extends AbstractList {
private ListNode front; // refers to first node in list (null if empty)
public LinkedList() {
front = null; // null front means empty
}
public void add(int index, E value) {
if (index == 0) {
// insert at the front
front = new ListNode(value, front);
} else {
ListNode current = goTo(index - 1);
ListNode newNode = new ListNode(value, current.next);
current.next = newNode;
}
}
public E get(int index) {
ListNode current = goTo(index);
return current.data;
}
public int indexOf(E value) {
int index = 0;
ListNode current = front;
while (current != null) {
if (current.data == value) {
return index;
}
index++;
current = current.next;
}
return -1;
}
public Iterator iterator() {
return new LinkedListIterator();
}
public void remove(int index) {
if (index == 0) {
// removing from the front
front = front.next;
} else {
ListNode current = goTo(index - 1);
current.next = current.next.next; // deletes the node
}
}
public void set(int index, E value) {
ListNode current = goTo(index);
current.data = value;
}
public int size() {
int count = 0;
ListNode current = front;
while (current != null) {
current = current.next;
count++;
}
return count;
}
public String toString() {
if (front == null) {
return \"[]\";
} else {
String result = \"[\" + front.data;
ListNode current = front.next;
while (current != null) {
result += \", \" + current.data;
current = current.next;
}
result += \"]\";
return result;
}
}
private ListNode goTo(int index) {
ListNode current = front;
for (int i = 0; i < index; i++) {
current = current.next;
}
return current;
}
public class ListNode {
public E data;
public ListNode next;
public ListNode(E data) {
this.data = data;
this.next = null;
}
public ListNode(E data, ListNode next) {
this.data = data;
this.next = next;
}
}
private class LinkedListIterator implements Iterator {
private ListNode current; // current position in list
public LinkedListIterator() {
current = f.
Class DiagramIn the Assignment #10, you are given three files Ass.pdf
Class DiagramIn the Assignment #10, you are given three files Ass.pdfxlynettalampleyxc Class Diagram:
In the Assignment #10, you are given three files Assignment10.java, LinkedList.java, and
ListIterator.java. You will need to add additional methods in the LinkedList class in the
LinkedList.java file. The LinkedList will be tested using strings only.
Specifically, the following methods must be implemented in the LinkedList class:
(You should utilize listIterator() method already defined in the LinkedList class to obtain its
LinkedListIterator object, and use the methods in the LinkedListIterator class to traverse from
the first element to the last element of the linked list to define the following methods.)
1.
public String toString()
The toString method should concatenate strings in the linked list, and return a string of the
following format:
{ Apple Banana Melon Orange }
Thus it starts with \"{\" and ends with \"}\", and there is a space between strings and \"{\" or
\"}\". If the list is empty, it returns \"{ }\" with a space in between.
2.
public boolean isEmpty()
The isEmpty method returns true of the linked list is empty, false otherwise.
3.
public void addElement(Object element)
The addElement adds the parameter element at the parameter in the linked list in alphabetical
order. For instance, if the linked list contains {Apple, Banana, Grape}, and a user tries to add
\"Carrot\", then it should be added as:
{Apple, Banana, Carrot, Grape}.
4.
public Object removeElement(int index)
The removeElement removes the string (Object) at the parameter index and returns it. Note that
this index starts with 0 just like array indices. For instance, if the linked list contains {Apple,
Banana, Carrot, Grape} and the parameter index is 3, then \"Grape\" should be remove. If the
parameter index is larger or smaller than the existing indices, it should throw an object of the
IndexOutOfBoundsException class (and the content of the linked list should remain unchanged).
5.
public Object getElement(int index)
The getElement searches the string (Object) at the parameter index and returns it. Note that this
index starts with 0 just like array indices. For instance, if the linked list contains {Apple, Banana,
Carrot, Grape} and the parameter index is 3, then \"Grape\" will be returned. If the parameter
index is larger or smaller than the existing indices, it should throw an object of the
IndexOutOfBoundsException class (and the content of the linked list should remain unchanged).
6.
public void searchAndReplace(Object oldString, Object newString)
The searchAndReplace method searches all occurrences of the first parameter string (object) in
the list, and replaces them with the second parameter string (object). If the parameter string does
not exist in the linked list, then the linked list content will not change.
7.
public int indexOfLast(Object searchString)
The indexOfLast searches the parameter string (object) with the largest index, and returns its
index. If the parameter string does not exist in the linked list, then it should return -1.
For i.
Note Given Code modified as required and required met.pdf
Note Given Code modified as required and required met.pdfAnkitchhabra28 Note:
Given Code modified as required and required methods added.
Code:
// class node
class Node
{
// declare the required variable
String data;
Node next;
// constructor
Node(){}
// constructor with arguments
Node(String data)
{
this.data = data;
next = null;
}
// method to get the data
public String getData()
{
return data;
}
// method to set the data
public void setData(String data)
{
this.data = data;
}
// method to get the next data
public Node getNext()
{
return next;
}
// method to set the next data
public void setNext(Node next)
{
this.next = next;
}
}
// class for a linked list
class MyLInkedList
{
Node head;alue into a list
// method to add the v
public void add(String num)
{
if (head == null)
{
head = new Node(num);
}
else{
Node temp = new Node(num);
Node current = head;
if (current != null) {
while (current.getNext() != null) {
current = current.getNext();
}
current.setNext(temp);
}
}
}
// method to search a value from a list
public void search(String num)
{
Node current = head;
boolean flag=true;
if (current != null)
{
while (current != null)
{
if(current.getData() == num)
{
System.out.println(\"Search value \"+
current.getData()+\" is available\");
flag=false;
}
current = current.getNext();
}
if (flag==true)
{
System.out.println(\"Search value \"+
current.getData()+\" is not available\");
}
}
else
{
System.out.println(\"Linked list is empty\");
}
}
// method to delete a value from a list
public void delete(String num)
{
//Node current = head;
boolean flag=true;
if (head == null)
{
System.out.println(\"Can\'t Delete, Linked list is
empty\");
return;
}
if(head.getData() == num)
{
head=head.getNext();
return;
}
Node temp = new Node(num);
Node cr = head;
Node prev=null;
while ((cr != null) && !(cr.getData() == num))
{
prev=cr;
cr = cr.getNext();
}
prev.setNext(cr.getNext());
}
// method to print the list
public void print()
{
Node current = head;
if (current != null) {
while (current != null) {
System.out.println(current.getData());
current = current.getNext();
}
}
}
}
// method to test the class
public class MyLInkedListTester
{
// main method to perform the linked list operatrions
public static void main(String args[])
{
MyLInkedList llist = new MyLInkedList();
// insert the values into list
llist.add(\"1\");
llist.add(\"2\");
llist.add(\"3\");
llist.add(\"4\");
// print the list values
llist.print();
// sear the values in a list
llist.search(\"1\");
llist.print();
// delete the value from a list
llist.delete(\"4\");
System.out.println(\"List after deletion:\");
llist.print();
}
}
Result:
1
2
3
4
Search value 1 is available
1
2
3
4
List after deletion:
1
2
3
Solution
Note:
Given Code modified as required and required methods added.
Code:
// class node
class Node
{
// declare the required variable
String data;
Node next;
// constructor
Node(){}
// constructor with arguments
Node(String data)
{
this.data = data;
next = null;
}
// method to get the data
public String getData()
{
return data;
}
// method to set the data
public void se.
hi i have to write a java program involving link lists. i have a pro.pdf
hi i have to write a java program involving link lists. i have a pro.pdfarchgeetsenterprises hi i have to write a java program involving link lists. i have a problem with the nodes, as it is
posting errors with the nodes.
please help me with this problem. thank you.
public class LinkLists {
/* only need to store a single pointer to the node at the head
* of the list.
* The pointer is null if the list is empty.
* Also record the size of the list.
*/
protected Node head;
/* invariant: size is the number of nodes in the list pointed to by head */
protected int size;
/* no-arguments default constructor creates an empty list */
public LinkLists() {
head = null; // start with an empty list
size = 0;
}
/* accessor method */
public int size() {
return size;
}
/* value to add to the end of the list
*/
public void add(T value) {
head = addAtEnd(head, value);
size++;
}
/* node of the list to which the value should be added
* value to add to the end of the list
*/
private Node addAtEnd(Node node, T value) {
if (node == null) { // special case
return new Node(value, null);
} else if (node.getNext() == null) { // other special case
node.setNext(new Node(value, null));
} else {
addAtEnd(node.getNext(), value);
}
return node;
}
/* iterative implementation of the same method
* value to add to the end of the list
*/
public void add2(T value) {
if (head == null) {
head = new Node(value, null);
} else {
Node node = head; // guaranteed not to be null initially
while (node.getNext() != null) {
node = node.getNext(); // guaranteed not to be null here
}
// now, node.getNext() is guaranteed to be null
// similar to the second special case in addAtEnd
node.setNext(new Node(value, null));
}
size++;
}
public void remove(int position) throws BadItemCountException {
if ((position < 1) || (position > size)) {
throw new
BadItemCountException(\"invalid position \" + position +
\", only 1..\" + size + \" available\");
}
if (position == 1) {
head = head.getNext();
} else {
Node node = head;
for (int i = 2; i < position; i++) {
node = node.getNext();
}
node.setNext(node.getNext().getNext());
}
size--; // one less item
}
public String toString() {
return toString(head);
}
private String toString(Node node) {
if (node == null) {
return \"\";
} else {
return node.getValue() + \"\ \" + toString(node.getNext());
}
}
public static void main(String[] args) {
/* create two empty lists, make sure they print out correctly */
LinkLists list1 = new LinkLists();
LinkLists list2 = new LinkLists();
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* insert some items, keep checking */
list1.add(\"hello\");
list1.add(\"world\");
list2.add(\"foo\");
list2.add(\"bar\");
list2.add(\"baz\");
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* remove an item at an invalid position */
boolean caught = false;
try {
list2.remove(4);
} catch .
Caso de empresa Hamburguesa In-N-Out el valor del cliente a la an.pdf
Caso de empresa Hamburguesa In-N-Out el valor del cliente a la an.pdfsales88 Caso de empresa
Hamburguesa In-N-Out: el valor del cliente a la antigua usanza
En 1948, Harry y Esther Snyder abrieron la primera hamburguesa In-N-Out en Baldwin Park,
California.
Era una configuracin simple de doble servicio de autoservicio con la cocina entre dos carriles de
servicio, un acceso sin ascensor
ventana y asientos al aire libre. El men consista en hamburguesas, batidos, refrescos y papas
fritas. Este
El formato era comn para el perodo de tiempo. De hecho, otra hamburguesera que se ajusta a
este mismo
description abri el mismo ao a solo 45 minutos de la primera In-N-Out Burger. l
se llamaba McDonald's. Hoy, McDonald's cuenta con ms de 34,000 tiendas en todo el mundo
que traen
ms de $ 88 mil millones cada ao. In-N-Out tiene solo 281 tiendas en cinco estados, bueno para
un
estimada en 625 millones de dlares al ao. Con base en los resultados, parecera que McDonald's
ha
sali el claro vencedor.
Pero In-N-Out nunca quiso ser otro McDonald's. Y a pesar de su tamao ms pequeoo
tal vez por eso: a los clientes de In-N-Out les gusta la cadena regional tal como es. Cuando
cuando se trata de la satisfaccin del cliente, In-N-Out le gana a McDonald's. Publica
regularmente la
puntajes ms altos de satisfaccin del cliente de cualquier restaurante de comida rpida en sus reas
de mercado. En comparacin con
A los clientes de McDonald's, los clientes de In-N-Out realmente les "encanta". Casi cualquier
persona que tenga
estado en un In-N-Out cree que es la mejor hamburguesa que han probado. No es ninguna
sorpresa, entonces,
que las ventas promedio por tienda de In-N-Out eclipsan las de McDonald's y son el doble de las
promedio industrial.
Rompiendo todas las reglas
Segn Stacy Perman, autora de un libro definitivo sobre In-N-Out, la empresa ha logrado
xito inequvoco al romper todas las reglas. Por reglas, la Sra. Perman se refiere a la norma
prcticas comerciales para la industria de comida rpida e incluso para el comercio minorista en
general. In-N-Out ha mantenido
un enfoque tenaz en el bienestar del cliente, pero lo ha hecho haciendo lo impensable: no
cambiando. La filosofa original de la compaa sigue vigente hoy en da y es la que mejor ilustra la
base
por romper las reglas de la compaa: Ofrezca a los clientes los alimentos ms frescos y de la ms
alta calidad que pueda comprar
y brindarles un servicio amable en un ambiente limpio y reluciente. Los grandes gigantes de las
hamburguesas
podra objetar la idea de que no estn brindando el mismo enfoque en el cliente. pero vamos
eche un vistazo ms de cerca a lo que significan estas cosas para In-N-Out.
Para empezar, en In-N-Out, comida de calidad significa comida fresca. Las hamburguesas estn
hechas de 100
% de carne de res pura, sin aditivos, rellenos ni conservantes. In-N-Out posee y opera su propio
comisarios que hacen hamburguesas, asegurndose de que cada hamburguesa sea fresca y nunca
congelada. Las verduras son
loncheados y troceados a mano en todos los restaurantes. Las papas fritas incluso se hacen con
.
CASO 6.2 Algunos ciudadanos preocupados hicieron una cita para reu.pdf
CASO 6.2 Algunos ciudadanos preocupados hicieron una cita para reu.pdfsales88 CASO 6.2
Algunos ciudadanos preocupados hicieron una cita para reunirse con el jefe de polica en
Anytown, EE. UU. Les preocupa la productividad del departamento de polica de su ciudad.
Tambin les preocupa la falta de coordinacin entre los residentes de la ciudad y el departamento
de polica.
El Sr. Smith es un residente que mencion en la reunin que hay algunos lugares, conocidos como
puntos crticos de delincuencia, que son la mayor preocupacin para los residentes. Todos los
siguientes se consideran focos potenciales de delincuencia, excepto:
Barras.
Depsitos de autobuses.
centros comerciales
Escuelas.
Barras.
Depsitos de autobuses.
centros comerciales
Escuelas..
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current cars stored in the data structure. Cars formatted so car records separated by a blank line.
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price. Write a max-heap class including heapify, build heap, extract, and insertion. Implement a
binary search tree of car data. Write a BST class including search, insertion, and deletion.
Solution
Cars.java
package pacages;
public class Cars {
String make;
String model;
int year;
double mileage;
double price;
// Setters and getters for the Cars member variables
public String getMake() {
return make;
}
public void setMake(String make) {
this.make = make;
}
public String getModel() {
return model;
}
public void setModel(String model) {
this.model = model;
}
public int getYear() {
return year;
}
public void setYear(int year) {
this.year = year;
}
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return mileage;
}
public void setMileage(double mileage) {
this.mileage = mileage;
}
public double getPrice() {
return price;
}
public void setPrice(double price) {
this.price = price;
}
public String toString()
{
return \"Make: \"+getMake()+ \" Model: \"+getModel()+ \" Year: \"+getYear() + \"
Mileage: \"+getMileage() + \" Price: \"+getPrice();
}
}
DoublyLinkedList.java
package pacages;
class Node
{
protected Cars data;
protected Node next, prev;
/* Constructor */
public Node()
{
next = null;
prev = null;
data = null;
}
/* Constructor */
public Node(Cars d, Node n, Node p)
{
data = d;
next = n;
prev = p;
}
/* Function to set link to next node */
public void setLinkNext(Node n)
{
next = n;
}
/* Function to set link to previous node */
public void setLinkPrev(Node p)
{
prev = p;
}
/* Funtion to get link to next node */
public Node getLinkNext()
{
return next;
}
/* Function to get link to previous node */
public Node getLinkPrev()
{
return prev;
}
/* Function to set data to node */
public void setData(Cars d)
{
data = d;
}
/* Function to get data from node */
public Cars getData()
{
return data;
}
}
/* Class linkedList */
public class DoublyLinkedList
{
protected Node start;
protected Node end ;
public int size;
/* Constructor */
public DoublyLinkedList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isEmpty()
{
return start == null;
}
/* Function to get size of list */
public.
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MyLinkedListTest.java
public class MyLinkedListTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
MyLinkedList list = new MyLinkedList();
list.addFirst(\"AAAAA\");
list.add(\"1\");
list.add(\"2\");
list.add(\"3\");
list.addLast(\"ZZZZZ\");
System.out.println(\"Linked List Elements : \"+list.toString());
System.out.println(\"First element: \"+list.getFirst());
System.out.println(\"Second element: \"+list.getLast());
System.out.println(\"Removed First Element: \"+list.removeFirst());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed Last Element: \"+list.removeLast());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed all element: \");
list.removeAll();
System.out.println(\"Now Linked List Elements : \"+list.toString());
}
}
MyLinkedList.java
public class MyLinkedList extends MyAbstractList {
private Node head, tail;
/** Create a default list */
public MyLinkedList() {
}
/** Create a list from an array of objects */
public MyLinkedList(E[] objects) {
super(objects);
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return (E)head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return (E)tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node newNode = new Node(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node newNode = new Node(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
/** Add a new element at the specified index in this list
* The index of the head element is 0 */
public void add(int index, E e) {
if (index == 0) {
addFirst(e);
}
else if (index >= size) {
addLast(e);
}
else {
Node current = head;
for (int i = 1; i < index; i++) {
current = current.next;
}
Node temp = current.next;
current.next = new Node(e);
(current.next).next = temp;
size++;
}
}
/** Remove the head node and
* return the object that is contained in the removed node. */
public E removeFirst() {
if (size == 0) {
return null;
}
else {
Node temp = head;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return (E)temp.element;
}
}
/** Remove all elements from list */
public void removeAll() {
while(true) {
if (size == 0) {
break;
}
else {
Node temp = head;
head =.
Write a Java Class to Implement a Generic Linked ListYour list mus.pdf
Write a Java Class to Implement a Generic Linked ListYour list mus.pdfrozakashif85 Write a Java Class to Implement a Generic Linked List
Your list must be implemented as a singly-linked list of generic nodes, where each Node object
has two instance variables: an object of the “type variable” class, and a pointer to the next node
on the list.
Your class will contain separate methods to handle each of the operations read from a data file
(see II., below)
Your class will also override toString() to return the objects on the list in the order in which they
occur.
Write a Test Class for Your LinkedList Class
Your main method will read list operation instructions from a data file, until end-of-file and call
the appropriate LinkedList method to execute each one.
After each operation is executed, print out the operation and the updated list.
The data file to be used is on the class web site and the operations are:
APPEND X - Append object X to the end of the list
ADD N X - Insert object X as the new Nth element in the list, increasing the size of the list by 1
E.g. Suppose the list is:
head -> 1 -> 2 -> 3 -> 4->null
After ADD 3 7 it would be:
head -> 1 -> 2 -> 7 -> 3 -> 4->null
DELETE N – Remove the Nth object from the list
SWAP M N - Interchange the positions of the Mth and Nth
objects on the list
For credit, the two nodes must actually \"trade places\" in the list, and not merely swap their data
values
REVERSE - Reverse the order of the objects on the list
This must be done by reversing the order of the nodes themselves, rather than by swapping the
data stored
To get credit for your reverse() method, it must use either one of these 2 algorithms:
For each node on the list except the current “head”
node, delete the node and insert it as the new head
Use your swap() method
6. CLEAR – Clear the list (make it empty)
No credit will be given for programs that use any additional data structures – either from the Java
API or programmer defined -, other than your own LinkedList class
txt file:
Solution
//Java Program to Implement Singly Linked List
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
/* Class Node */
class Nodes
{
protected Object data;
protected Nodes next;
/* Constructor */
public Nodes()
{
next = null;
data = null;
}
/* Constructor */
public Nodes(Object d,Nodes n)
{
data = d;
next = n;
}
/* Function to set link to next Node */
public void setLink(Nodes n)
{
next = n;
}
/* Function to set data to current Node */
public void setData(Object d)
{
data = d;
}
/* Function to get link to next node */
public Nodes getLink()
{
return next;
}
/* Function to get data from current Node */
public Object getData()
{
return data;
}
}
/* Class linkedList */
class linkList
{
protected Nodes start;
protected Nodes end ;
public int size ;
/* Constructor */
public linkList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isEmpty()
{
return start == null;
}
/* Function to get size of list */
public int getSize()
{
return .
package ex2- public class Exercise2-E- { private static class N.pdf
package ex2- public class Exercise2-E- { private static class N.pdfarcellzone package ex2;
public class Exercise2<E> {
private static class Node<E> {
private E element;
private Node<E> prev;
private Node<E> next;
public Node(E e, Node<E> p, Node<E> n) {
element = e;
prev = p;
next = n;
}
public E getElement() { return element; }
public Node<E> getPrev() { return prev; }
public Node<E> getNext() { return next; }
public void setPrev(Node<E> p) { prev = p; }
public void setNext(Node<E> n) { next = n; }
}
private Node<E> header;
private Node<E> trailer;
private int size = 0;
public Exercise2() {
header = new Node<>(null, null, null);
trailer = new Node<>(null, header, null);
header.setNext(trailer);
}
public int size() { return size; }
public boolean isEmpty() { return size == 0; }
public E first() {
if (isEmpty()) return null;
return header.getNext().getElement();
}
public E last() {
if (isEmpty()) return null;
return trailer.getPrev().getElement();
}
public void addFirst(E e) {
addBetween(e, header, header.getNext());
}
public void addLast(E e) {
addBetween(e, trailer.getPrev(), trailer);
}
public E removeFirst() {
if (isEmpty()) return null;
return remove(header.getNext());
}
public E removeLast() {
if (isEmpty()) return null;
return remove(trailer.getPrev());
}
private void addBetween(E e, Node<E> predecessor, Node<E> successor) {
if (predecessor == header && successor == trailer) {
// skip creation of new node for header/trailer
header.setNext(new Node<>(e, header, trailer));
trailer.setPrev(header.getNext());
} else {
Node<E> newest = new Node<>(e, predecessor, successor);
predecessor.setNext(newest);
successor.setPrev(newest);
}
size++;
}
private E remove(Node<E> node) {
Node<E> predecessor = node.getPrev();
Node<E> successor = node.getNext();
predecessor.setNext(successor);
successor.setPrev(predecessor);
size--;
return node.getElement();
}
public String toString() {
StringBuilder sb = new StringBuilder("(");
Node<E> walk = header;
while (walk != null) {
sb.append(walk.getElement());
walk = walk.getNext();
if (walk != null) {
sb.append(", ");
}
}
sb.append(")");
return sb.toString();
}
public void reverseList() {
Node<E> current = header;
header = trailer.getPrev();
trailer = current.getNext();
while (current != null) {
Node<E> temp = current.getNext();
current.setNext(current.getPrev());
current.setPrev(temp);
current = temp;
}
}
public static void main(String[] args)
{
Exercise2<String> list = new Exercise2<String>();
list.addFirst("MSP");
list.addLast("ATL");
list.addLast("BOS");
list.addFirst("LAX");
System.out.println(list);
list.reverseList();
System.out.println(list);
}
}
Here's my code, the output should reverse the list, but I'm keep getting errors, anyone mind to
help me to get a proper output?
.
Submit1) Java Files2) Doc file with the following contents.pdf
Submit1) Java Files2) Doc file with the following contents.pdfakaluza07 Submit:
1) Java Files
2) Doc file with the following contents:
//************************** SLL.java *********************************
// a generic singly linked list class
public class SLL {
private class SLLNode {
private T info;
private SLLNode next;
public SLLNode() {
this(null,null);
}
public SLLNode(T el) {
this(el,null);
}
public SLLNode(T el, SLLNode ptr) {
info = el; next = ptr;
}
}
protected SLLNode head, tail;
public SLL() {
head = tail = null;
}
public boolean isEmpty() {
return head == null;
}
public void addToHead(T el) {
head = new SLLNode(el,head);
if (tail == null)
tail = head;
}
public void addToTail(T el) {
if (!isEmpty()) {
tail.next = new SLLNode(el);
tail = tail.next;
}
else head = tail = new SLLNode(el);
}
public T deleteFromHead() { // delete the head and return its info;
if (isEmpty())
return null;
T el = head.info;
if (head == tail) // if only one node on the list;
head = tail = null;
else head = head.next;
return el;
}
public T deleteFromTail() { // delete the tail and return its info;
if (isEmpty())
return null;
T el = tail.info;
if (head == tail) // if only one node in the list;
head = tail = null;
else { // if more than one node in the list,
SLLNode tmp; // find the predecessor of tail;
for (tmp = head; tmp.next != tail; tmp = tmp.next);
tail = tmp; // the predecessor of tail becomes tail;
tail.next = null;
}
return el;
}
public void delete(T el) { // delete the node with an element el;
if (!isEmpty())
if (head == tail && el.equals(head.info)) // if only one
head = tail = null; // node on the list;
else if (el.equals(head.info)) // if more than one node on the list;
head = head.next; // and el is in the head node;
else { // if more than one node in the list
SLLNode pred, tmp;// and el is in a nonhead node;
for (pred = head, tmp = head.next;
tmp != null && !tmp.info.equals(el);
pred = pred.next, tmp = tmp.next);
if (tmp != null) { // if el was found;
pred.next = tmp.next;
if (tmp == tail) // if el is in the last node;
tail = pred;
}
}
}
@Override
public String toString() {
if(head == null)
return "[ ]";
String str = "[ ";
SLLNode tmp = head;
while(tmp != null){
str += tmp.info + " ";
tmp = tmp.next;
}
return str+"]";
}
public boolean contains(T el) {
if(head == null)
return false;
SLLNode tmp = head;
while(tmp != null){
if(tmp.info.equals(el))
return true;
tmp = tmp.next;
}
return false;
}
public int size(){
if(head == null)
return 0;
int count = 0;
SLLNode p = head;
while(p != null) {
count++;
p = p.next;
}
return count;
}
}
public class SLL_Driver {
public static void main(String[] args) {
SLL myList = new SLL();
String[] cityNames = {"Jubail", "Riyadh", "Abha", "Dammam", "Taif"};
for(int i = 0; i < cityNames.length; i++)
myList.addToHead(cityNames[i]);
System.out.println("The list is: " + myList);
System.out.println("It is " + myList.contains("Dammam") + " that the list contains
Dammam.");
System.out.println("It is " + myList.contains("Jeddah") + " that the list contains Jeddah.");
}
}
// Java program to implem.
import java.util.Iterator; import java.util.NoSuchElementException; .pdf
import java.util.Iterator; import java.util.NoSuchElementException; .pdfdeepakangel import java.util.Iterator; import java.util.NoSuchElementException; /** * An implementation
of MyList with a linked list (a longer exercise would be to * implement the List interface as is
done in the class java.util.LinkedList: * the source of the LinkedList class is available from Sun.
Check it out). */ public class MyLinkedList implements MyList { // A private class to
represent a Node in the linked list private class Node { public E item;
public Node next; // a convenient constructor public Node(E o) {
this.item = o; this.next = null; } } // The start of the linked
list private Node head; // The last Node in the linked list private Node tail;
// Number of elements in the list private int size; /** * Creates an empty list (this
constructor is not necessary) */ public MyLinkedList() { } /** *
Returns the number of elements in this list. */ public int size() { return size;
} /** * Returns true if this list contains no elements. */ public boolean
isEmpty() { return size == 0; } /** * Appends the specified element to
the end of this list */ public boolean add(E o) { Node n = new Node(o);
// If this is the first element in the list if (head == null) { head = n;
} else { // If the list is not empty, use tail tail.next = n;
} // update tail tail = n; // update size size++;
return true; } /** * Empties this List */ public void clear() {
// update head, tail and size head = tail = null; size = 0; } /**
* Returns the element at the specified position in this list. */ public E get(int index) {
if (index < 0 || index >= size) { throw new
IndexOutOfBoundsException(\"index = \" + index); } // Find it
Node n = head; for (int i = 0; i < index; i++) { n = n.next; }
return n.item; } /** * Returns the index of the specified element (-1 if
there is no match) */ public int indexOf(Object o) { // If o is null
int index = 0; Node p = head; if (o == null) // look for a null element in the
list { while (p != null) { if (p.item == null) {
return index; } index++;
p = p.next; } } else // o is an object (use equals) {
while (p != null) { if (o.equals(p.item)) { return
index; } index++; p = p.next;
} } // if we get here, o is not in the list return -1; }
/** * Returns true if this list contains the specified element. */ public boolean
contains(Object o) { // easy with indexOf return indexOf(o) != -1; }
/** * Removes the element in the List at position index */ public boolean
remove(int index) { if (index < 0 || index >= size) { throw new
IndexOutOfBoundsException(\"index = \" + index); } // Find the
corresponding node Node prev = null, p = head; for (int i = 0; i < index; i++)
{ prev = p; p = p.next; } // Remove it
// Special case for the first node if (p == head) { head = head.next;
} else { prev.next = p.next; } // If the last node has been
removed, update tail if (p == tail) { tail = prev; } //
update size size--; return true; } /** * Removes the element
in the List at position index */ public boolean remove(Object o) { // easy
with indexOf and remove int index = i.
This is the assignmentOBJECTIVESAfter finishing this lab, stude.pdf
This is the assignmentOBJECTIVESAfter finishing this lab, stude.pdfbharatchawla141 Sustainability: Sustainability is an important consideration for any nation. Discuss what countries
do to sustain their economy and help its people.
Solution
Sustainable development is a crucial subject to affix downward since it beset so many
contrasting stuff.Due to the complication of this accountable it is big to attention at the big in a
holistic action that approaches affair intelligently.The authority for sustainab;e development at
the civil level that is for the difficult mosaic is a mixture of economic,political that precondition
be bring combine under a particular set of circumstances.Any changes in the people life style
makes a economic atmosphere and candid of championship and business will make a country
effort easy..
Note- Can someone help me with the private E get(int index- int curren (1).docx
Note- Can someone help me with the private E get(int index- int curren (1).docxVictorzH8Bondx Note: Can someone help me with the private E get(int index, int currentIndex, Node n)method. The code is not running. Also I need help with the public void add(int index, E element) method too. Please use the parameters provided with the code to solve. package edu.ust.cisc; import java.util.Iterator; import java.util.NoSuchElementException; public class CiscSortedLinkedList > implements CiscList { /** * A reference to this list's dummy node. Its next reference should refer to the node containing the first element * in this list, or it should refer to itself if the list is empty. The next reference within the node containing * the last element in this list should refer to dummy, thus creating a cyclic list. */ private Node dummy; /** * Number of elements in the list. */ private int size; /** * Constructs an empty CiscSortedLinkedList instance with a non-null dummy node whose next reference refers to * itself. */ public CiscSortedLinkedList() { dummy = new Node<>(null, null); dummy.next = dummy; } /** * Returns the number of elements in this list. * * @return the number of elements in this list */ @Override public int size() { return size; } /** * Returns {@code true} if this list contains no elements. * * @return {@code true} if this list contains no elements */ @Override public boolean isEmpty() { return size==0; } /** * Returns {@code true} if this list contains the specified element (compared using the {@code equals} method). * This implementation should stop searching as soon as it is able to determine that the specified element is not * present. * * @param o element whose presence in this list is to be tested * @return {@code true} if this list contains the specified element * @throws NullPointerException if the specified element is null */ @Override public boolean contains(Object o) { if(o==null){ throw new NullPointerException(); } return containsHelper(o,dummy.next); } private boolean containsHelper(Object o, Node node){ if(node== dummy){ return false; } else if(o.equals(node.data)){ return true; } else{ return containsHelper(o,node.next); } } /** * Returns an iterator over the elements in this list in proper sequence. * * @return an iterator over the elements in this list in proper sequence */ @Override public Iterator iterator() { //return new Iterator (){ //private Node curr = dummy.next; //private Node prev = dummy; //private boolean canRemove = false; return null; } /** * Returns an array containing all of the elements in this list in proper sequence (from first to last element). *
The returned array will be "safe" in that no references to it are maintained by this list. (In other words, * this method must allocate a new array even if this list is backed by an array). The caller is thus free to modify * the returned array. * * @return an array containing all of the elements in this list in proper sequence */ @Override public Object[] toArray() { Object[] arr = new Object[size]; int i = 0; for(Node current = dummy;current!=null;cur.
So I have this code(StackInAllSocks) and I implemented the method but.pdf
So I have this code(StackInAllSocks) and I implemented the method but.pdfaksahnan So I have this code( StackInAllSocks ) and I implemented the method but I can't seem to figure
out why there isn't anything showing up on the console. It should pop,peek and push b using the
methods from the class called ArrayListTen . The ArrayListTen works fine and compiles the
tested code of Rigth# but for StackInAllSocks it doesn't complete at all. note that file
VodeDodeis not to be changed is just a Node storage area of the array list.
Did I implement the method on StackInAllSocks correctly? if so, should I not use the method
from the ArrayListTen .?
__________________________________________________________________________
: the code is : VodeDodeis
class VodeDode<T> {
private T data;
private VodeDode<T> next;
private VodeDode<T> prev;
public VodeDode(T data) {
this.data = data;
this.next = null;
this.prev = null;}
public T getData() {
return data;}
public void setData(T data) {
this.data = data;}
public VodeDode<T> getNext() {
return this.next;}
public void setNext(VodeDode<T> next) {
this.next = next;}
public VodeDode<T> getPrev() {
return this.prev;}
public void setPrev(VodeDode<T> prev) {
this.prev = prev;}
@Override
public String toString() {
return data.toString();}}
_________________________________________________________________________
CODE that works fine called ArrayListTen:
import java.util.Iterator;
public class ArrayListTen<T> implements Iterable<T> {
private VodeDode<T> head; //beginning of list
private VodeDode<T> tail; //end of list
private int size;
private VodeDode<T> new_item;
public ArrayListTen( ){
this.head = null;
this.tail = null;
this.size = 0;}
public int lenght() {
return size ;}
public T getBegin() {
if (this.head != null) {
return head.getData();}
else { return null;}}
public void addBegin(T value) {
VodeDode<T> newVodeDode =new VodeDode<T>(value);
if (this.head== null) {
head = newVodeDode;
tail =newVodeDode;}
else {VodeDode<T> temp = head;
head = newVodeDode;
head.setNext(temp);}
size++;}
public T removeBegin() {
if(this.head == null) {
return null;}
else {T current = head.getData();
if (tail == head) {
tail = null;
head = null;
} else {
head = head.getNext();
head.setPrev(null);}size--;
return current;}}
public T getEnd() {
if (tail != null) {
return tail.getData();
} else {
return null;}}
public void addEnd(T value) {
VodeDode<T> newVodeDode = new VodeDode<T>(value);
if (this.tail == null) {
head = newVodeDode;
tail = newVodeDode;
} else {
newVodeDode.setPrev(tail);
tail.setNext(newVodeDode);
tail = newVodeDode;}
size++;}
public T removeEnd() {
if(this.tail == null) {
return null;}
else {
T current = tail.getData();//was head.
if (head == tail) {
head = null;
tail = null;
} else {
tail = tail.getPrev();
tail.setNext(null);}
size--;
return current;}}
public T removeBN(T value) {
VodeDode<T> currVodeDode = head;
VodeDode<T> prevVodeDode = null;
while(currVodeDode != null){
if(currVodeDode.getData().equals(value)){
if(prevVodeDode != null){
prevVodeDode.setNext(currVodeDode.getNext());}
else{
head = curr.
Here is the editable codeSolutionimport java.util.NoSuchEleme.pdf
Here is the editable codeSolutionimport java.util.NoSuchEleme.pdfarrowmobile Here is the editable code:
Solution
import java.util.NoSuchElementException;
public class DoublyLinkedListImpl {
private Node head;
private Node tail;
private int size;
public DoublyLinkedListImpl() {
size = 0;
}
private class Node {
E element;
Node next;
Node prev;
public Node(E element, Node next, Node prev) {
this.element = element;
this.next = next;
this.prev = prev;
}
}
public int size() { return size; }
public boolean isEmpty() { return size == 0; }
public void addFirst(E element) {
Node tmp = new Node(element, head, null);
if(head != null ) {head.prev = tmp;}
head = tmp;
if(tail == null) { tail = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
/**
* adds element at the end of the linked list
* @param element
*/
public void addLast(E element) {
Node tmp = new Node(element, null, tail);
if(tail != null) {tail.next = tmp;}
tail = tmp;
if(head == null) { head = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void iterateForward(){
System.out.println(\"iterating forward..\");
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.next;
}
}
/**
* this method walks backward through the linked list
*/
public void iterateBackward(){
System.out.println(\"iterating backword..\");
Node tmp = tail;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.prev;
}
}
public E removeFirst() {
if (size == 0) throw new NoSuchElementException();
Node tmp = head;
head = head.next;
head.prev = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public E removeLast() {
if (size == 0) throw new NoSuchElementException();
Node tmp = tail;
tail = tail.prev;
tail.next = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public static void main(String a[]){
DoublyLinkedListImpl dll = new DoublyLinkedListImpl();
dll.addFirst(10);
dll.addFirst(34);
dll.addLast(56);
dll.addLast(364);
dll.iterateForward();
dll.removeFirst();
dll.removeLast();
dll.iterateBackward();
}
}
import java.util.Scanner;
/* Class Node */
class Node
{
protected int data;
protected Node next, prev;
/* Constructor */
public Node()
{
next = null;
prev = null;
data = 0;
}
/* Constructor */
public Node(int d, Node n, Node p)
{
data = d;
next = n;
prev = p;
}
/* Function to set link to next node */
public void setLinkNext(Node n)
{
next = n;
}
/* Function to set link to previous node */
public void setLinkPrev(Node p)
{
prev = p;
}
/* Funtion to get link to next node */
public Node getLinkNext()
{
return next;
}
/* Function to get link to previous node */
public Node getLinkPrev()
{
return prev;
}
/* Function to set data to node */
public void setData(int d)
{
data = d;
}
/* Function to get data from node */
public int getData()
{
return data;
}
}
/* Class linkedList */
class linkedList
{
protected Node start;
protected Node end ;
public int size;
/* Constructor */
public linkedList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isE.
Note- Can someone help me with the Public boolean add(E value) method.pdf
Note- Can someone help me with the Public boolean add(E value) method.pdfStewart29UReesa Note: Can someone help me with the Public boolean add(E value) method and Private void
add(E value,Node n) method. I have everything but it is not working. Also need help with the
remove methods. Both public and private methods for remove. package edu.ust.cisc; import
java.util.Iterator; import java.util.NoSuchElementException; public class CiscSortedLinkedList
> implements CiscList { /** * A reference to this list's dummy node. Its next reference should
refer to the node containing the first element * in this list, or it should refer to itself if the list is
empty. The next reference within the node containing * the last element in this list should refer to
dummy, thus creating a cyclic list. */ private Node dummy; /** * Number of elements in the list.
*/ private int size; /** * Constructs an empty CiscSortedLinkedList instance with a non-null
dummy node whose next reference refers to * itself. */ public CiscSortedLinkedList() { dummy
= new Node<>(null, null); dummy.next = dummy; } /** * Returns the number of elements in
this list. * * @return the number of elements in this list */ @Override public int size() { return
size; } /** * Returns {@code true} if this list contains no elements. * * @return {@code true} if
this list contains no elements */ @Override public boolean isEmpty() { return size==0; } /** *
Returns {@code true} if this list contains the specified element (compared using the {@code
equals} method). * This implementation should stop searching as soon as it is able to determine
that the specified element is not * present. * @param o element whose presence in this list is to
be tested * @return {@code true} if this list contains the specified element * @throws
NullPointerException if the specified element is null */ @Override public boolean
contains(Object o) { if(o==null){ throw new NullPointerException(); } return
containsHelper(o,dummy.next); } private boolean containsHelper(Object o, Node node){
if(node== dummy){ return false; } else if(o.equals(node.data)){ return true; } else{ return
containsHelper(o,node.next); } } /** * Returns an iterator over the elements in this list in proper
sequence. * * @return an iterator over the elements in this list in proper sequence */ @Override
public Iterator iterator() { //return new Iterator (){ //private Node curr = dummy.next; //private
Node prev = dummy; //private boolean canRemove = false; return new CiscLinkedListIterator();
} /** * Returns an array containing all of the elements in this list in proper sequence (from first
to last element). * *
The returned array will be "safe" in that no references to it are maintained by this list. (In other
words, * this method must allocate a new array even if this list is backed by an array). The caller
is thus free to modify * the returned array. * * @return an array containing all of the elements in
this list in proper sequence */ @Override public Object[] toArray() { Object[] arr = new
Object[size]; int i = 0; for(Node current = dummy;curren.
Use the singly linked list class introduced in the lab to implement .pdf
Use the singly linked list class introduced in the lab to implement .pdfsales87 Use the singly linked list class introduced in the lab to implement integers of unlimited size.
Each node of the list should store one digit of the integer. You are to implement the addition,
subtraction and multiplication operations. Please note that any additional data structure to be
used in solving this problem has to be taken from the ones introduced in the ICS 202 lab. In
addition, provide a test class that will do the following: It will keep asking the user to enter two
integers, choose one of the operations (addition, subtraction, multiplication) and then display the
result. The program will stop upon entering the # character (without the double quotes).
this singly linked list class:
public class SLL {
private class SLLNode {
private T info;
private SLLNode next;
int value;
public SLLNode() {
this(null, null);
}
public SLLNode(T el) {
this(el, null);
}
public SLLNode(T el, SLLNode ptr) {
info = el;
next = ptr;
}
}
protected SLLNode head, tail;
public SLL() {
head = tail = null;
}
public boolean isEmpty() {
return head == null;
}
public void addToHead(T el) {
head = new SLLNode(el, head);
if (tail == null)
tail = head;
}
public void addToTail(T el) {
if (!isEmpty()) {
tail.next = new SLLNode(el);
tail = tail.next;
} else
head = tail = new SLLNode(el);
}
public T deleteFromHead() { // delete the head and return its info;
if (isEmpty())
return null;
T el = head.info;
if (head == tail) // if only one node on the list;
head = tail = null;
else
head = head.next;
return el;
}
public T deleteFromTail() { // delete the tail and return its info;
if (isEmpty())
return null;
T el = tail.info;
if (head == tail) // if only one node in the list;
head = tail = null;
else { // if more than one node in the list,
SLLNode tmp; // find the predecessor of tail;
for (tmp = head; tmp.next != tail; tmp = tmp.next)
;
tail = tmp; // the predecessor of tail becomes tail;
tail.next = null;
}
return el;
}
public void delete(T el) { // delete the node with an element el;
if (!isEmpty())
if (head == tail && el.equals(head.info)) // if only one
head = tail = null; // node on the list;
else if (el.equals(head.info)) // if more than one node on the list;
head = head.next; // and el is in the head node;
else { // if more than one node in the list
SLLNode pred, tmp;// and el is in a nonhead node;
for (pred = head, tmp = head.next; tmp != null
&& !tmp.info.equals(el); pred = pred.next, tmp = tmp.next)
;
if (tmp != null) { // if el was found;
pred.next = tmp.next;
if (tmp == tail) // if el is in the last node;
tail = pred;
}
}
}
@Override
public String toString() {
if (head == null)
return "[ ]";
String str = "[ ";
SLLNode tmp = head;
while (tmp != null) {
str += tmp.info + " ";
tmp = tmp.next;
}
return str + "]";
}
public boolean contains(T el) {
if (head == null)
return false;
SLLNode tmp = head;
while (tmp != null) {
if (tmp.info.equals(el))
return true;
tmp = tmp.next;
}
return false;
}
public int size() {
if (head == null)
return 0;
int count = 0;
SLLNode p = head;
w.
Copy your completed LinkedList class from Lab 3 into the LinkedList..pdf
Copy your completed LinkedList class from Lab 3 into the LinkedList..pdffacevenky Copy your completed LinkedList class from Lab 3 into the LinkedList.java file below.
During this lab we will add more constructors, an equals method and more challenging methods
as listed below.
Also inspect the LabProgram.java file and notice that the main() method of the LabProgram
copies and compares two linked lists. The main() method also calls the more challenging
methods. Use Develop mode to test your LinkedList iterator code as you develop it.
In Submit mode you will need to complete all lab steps to pass all automatic tests.
Step 2: Implement clear()
Method clear() re-sets the LinkedList to empty as if the default constructor had just been called.
Constructor LinkedList(T[] array) converts the given array into a LinkedList.
Constructor LinkedList(LinkedList original) instantiates a new LinkedList by copying another
List.
Method equals() determines whether the given Object is another LinkedList, containing the same
data in the same order, returning whether there is equality.
Method spinList(int numMoves) moves all nodes in the list towards the end of the list the
number of times specified. Any node that falls off the end of the list as it moves forward will be
placed at the front of the list.
Method altLists() splices together two LinkedLists to create a third List which contains
alternating values from the original list and the given parameter.
*Below is my Lab3 LinkedList.class.
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
public T getFirst() throws NoSuchElementException {
if (first == null) throw new NoSuchElementException();
return first.data;
}
public T getLast() throws NoSuchElementException {
if (last == null) throw new NoSuchElementException();
return last.data;
}
public T getIterator() throws NullPointerException {
if (iterator == null) {
throw new NullPointerException("Iterator is off end.");
}
return iterator.data;
}
public int getLength() {
return length;
}
public boolean isEmpty() {
return length == 0;
}
public boolean offEnd() {
return iterator == null;
}
public void addFirst(T data) {
Node newNode = new Node(data);
if (length == 0) {
first = newNode;
last = newNode;
} else .
In this lab, we will write an application to store a deck of cards i.pdf
In this lab, we will write an application to store a deck of cards i.pdfcontact41 In this lab, we will write an application to store a deck of cards in a linked list, and then write
methods to sort and shuffle the deck.
Copy your completed LinkedList class from Lab 4 into the LinkedList.java file below.
Complete all methods of the Card class as described by the Javadoc comments. The class
contains both a suit and a rank. A suit is one of the categories into which the cards of a deck are
divided. The rank is the relative importance of the card within its suit.
Note that the Card constructor must convert any rank and suit letters to uppercase.
For the equals() method, be sure to follow the steps outlined in Lesson 4. How to implement the
compareTo() method is also covered in Lesson 4.
Note that you are not allowed to add any additional methods or member variables to this class or
you will not receive credit for this assignment.
Complete all methods of the CardApp class in the CardApp.java file as described by the Javadoc
comments.
You may add as many methods as you would like to this file, but are not allowed to add any
additional member variables.
The CardApp program must prompt for and allow the user to enter the name of any input file as
shown in the Example output below.
Implement the shuffle() method as specified in the comments for shuffle(). After you have
shuffled the deck of cards, write the result into a file named shuffled.txt.
Implement the sort() method using bubble sort from Lesson 4. First sort by suit in alphabetical
order and then by rank from 2 to A. The pseudocode for bubble sort is as follows:
After you have sorted the deck of cards, write the result to a file named sorted.txt.
The CardApp.java file also contains the main() method of the application. Use Develop mode to
test your CardApp code along with your Card and LinkedList code.
All input and output files must contain a list of cards, with each card stored on its own line. See
the example files cards1.txt and cards2.txt for example file formats.
[[[cards1.txt]]]
2H
3H
4H
5H
6H
7H
8H
9H
10H
JH
[[[cards2.txt]]]
AS
2S
3S
4S
5S
6S
7S
8S
9S
10S
JS
QS
KS
AC
2C
3C
4C
5C
6C
7C
8C
9C
10C
JC
QC
KC
AH
2H
3H
4H
5H
6H
7H
8H
9H
10H
JH
QH
KH
AD
2D
3D
4D
5D
6D
7D
8D
9D
10D
JD
QD
KD
[[[CardApp.java]]]
/**
* CardApp.java
* @author Your name
* @author Partner's name
* CIS 22C, Applied Lab 1
*/
public class CardApp {
private LinkedList list;
/**
* User interface prompts user, reads and writes files.
*/
public static void main(String[] args) {
}
/**
* Default constructor to initialize the deck
*/
public CardApp() {
}
/**
* Inserts a new Card into the deck
* @param card a playing Card
*/
public void addCard(Card card) {
}
/**
* Shuffles cards following this algorithm:
* First swaps first and last card
* Next, swaps every even card with the card 3
* nodes away from that card. Stops when it
* reaches the 3rd to last node
* Then, swaps ALL cards with the card that is
* 2 nodes away from it, starting at the 2nd card
* and stopping stopping at the 3rd to last node
*/
public vo.
Create a new java class called ListNode. Implement ListNode as a gen.pdf
Create a new java class called ListNode. Implement ListNode as a gen.pdfmohamednihalshahru Create a new java class called ListNode. Implement ListNode as a generic version of IntNode.
public class ListNode { }
Create a generic class called Queue, which is a linked list implementation of a queue data type.
Queue must have the following methods:
• public void enqueue(T value){} This method should add a new node to the back of the queue.
• public T dequeue(){} This method should remove a node from the front of the queue and return
its value
• public T peek(){} This method should return the value of the front node without removing it
from the queue
Create a new generic class called Stack, which is a linked list implementation of a stack data
type. Stack must have the following methods:
• public void push(T value){} This method should add a new node to the top of the stack.
• public T pop(){} This method should remove a node from the top of the stack and return its
integer value
• public T peek(){} This method should return the integer value of the top node without
removing it from the stack
Solution
import java.util.Iterator;
public class LinkedList extends AbstractList {
private ListNode front; // refers to first node in list (null if empty)
public LinkedList() {
front = null; // null front means empty
}
public void add(int index, E value) {
if (index == 0) {
// insert at the front
front = new ListNode(value, front);
} else {
ListNode current = goTo(index - 1);
ListNode newNode = new ListNode(value, current.next);
current.next = newNode;
}
}
public E get(int index) {
ListNode current = goTo(index);
return current.data;
}
public int indexOf(E value) {
int index = 0;
ListNode current = front;
while (current != null) {
if (current.data == value) {
return index;
}
index++;
current = current.next;
}
return -1;
}
public Iterator iterator() {
return new LinkedListIterator();
}
public void remove(int index) {
if (index == 0) {
// removing from the front
front = front.next;
} else {
ListNode current = goTo(index - 1);
current.next = current.next.next; // deletes the node
}
}
public void set(int index, E value) {
ListNode current = goTo(index);
current.data = value;
}
public int size() {
int count = 0;
ListNode current = front;
while (current != null) {
current = current.next;
count++;
}
return count;
}
public String toString() {
if (front == null) {
return \"[]\";
} else {
String result = \"[\" + front.data;
ListNode current = front.next;
while (current != null) {
result += \", \" + current.data;
current = current.next;
}
result += \"]\";
return result;
}
}
private ListNode goTo(int index) {
ListNode current = front;
for (int i = 0; i < index; i++) {
current = current.next;
}
return current;
}
public class ListNode {
public E data;
public ListNode next;
public ListNode(E data) {
this.data = data;
this.next = null;
}
public ListNode(E data, ListNode next) {
this.data = data;
this.next = next;
}
}
private class LinkedListIterator implements Iterator {
private ListNode current; // current position in list
public LinkedListIterator() {
current = f.
Class DiagramIn the Assignment #10, you are given three files Ass.pdf
Class DiagramIn the Assignment #10, you are given three files Ass.pdfxlynettalampleyxc Class Diagram:
In the Assignment #10, you are given three files Assignment10.java, LinkedList.java, and
ListIterator.java. You will need to add additional methods in the LinkedList class in the
LinkedList.java file. The LinkedList will be tested using strings only.
Specifically, the following methods must be implemented in the LinkedList class:
(You should utilize listIterator() method already defined in the LinkedList class to obtain its
LinkedListIterator object, and use the methods in the LinkedListIterator class to traverse from
the first element to the last element of the linked list to define the following methods.)
1.
public String toString()
The toString method should concatenate strings in the linked list, and return a string of the
following format:
{ Apple Banana Melon Orange }
Thus it starts with \"{\" and ends with \"}\", and there is a space between strings and \"{\" or
\"}\". If the list is empty, it returns \"{ }\" with a space in between.
2.
public boolean isEmpty()
The isEmpty method returns true of the linked list is empty, false otherwise.
3.
public void addElement(Object element)
The addElement adds the parameter element at the parameter in the linked list in alphabetical
order. For instance, if the linked list contains {Apple, Banana, Grape}, and a user tries to add
\"Carrot\", then it should be added as:
{Apple, Banana, Carrot, Grape}.
4.
public Object removeElement(int index)
The removeElement removes the string (Object) at the parameter index and returns it. Note that
this index starts with 0 just like array indices. For instance, if the linked list contains {Apple,
Banana, Carrot, Grape} and the parameter index is 3, then \"Grape\" should be remove. If the
parameter index is larger or smaller than the existing indices, it should throw an object of the
IndexOutOfBoundsException class (and the content of the linked list should remain unchanged).
5.
public Object getElement(int index)
The getElement searches the string (Object) at the parameter index and returns it. Note that this
index starts with 0 just like array indices. For instance, if the linked list contains {Apple, Banana,
Carrot, Grape} and the parameter index is 3, then \"Grape\" will be returned. If the parameter
index is larger or smaller than the existing indices, it should throw an object of the
IndexOutOfBoundsException class (and the content of the linked list should remain unchanged).
6.
public void searchAndReplace(Object oldString, Object newString)
The searchAndReplace method searches all occurrences of the first parameter string (object) in
the list, and replaces them with the second parameter string (object). If the parameter string does
not exist in the linked list, then the linked list content will not change.
7.
public int indexOfLast(Object searchString)
The indexOfLast searches the parameter string (object) with the largest index, and returns its
index. If the parameter string does not exist in the linked list, then it should return -1.
For i.
Note Given Code modified as required and required met.pdf
Note Given Code modified as required and required met.pdfAnkitchhabra28 Note:
Given Code modified as required and required methods added.
Code:
// class node
class Node
{
// declare the required variable
String data;
Node next;
// constructor
Node(){}
// constructor with arguments
Node(String data)
{
this.data = data;
next = null;
}
// method to get the data
public String getData()
{
return data;
}
// method to set the data
public void setData(String data)
{
this.data = data;
}
// method to get the next data
public Node getNext()
{
return next;
}
// method to set the next data
public void setNext(Node next)
{
this.next = next;
}
}
// class for a linked list
class MyLInkedList
{
Node head;alue into a list
// method to add the v
public void add(String num)
{
if (head == null)
{
head = new Node(num);
}
else{
Node temp = new Node(num);
Node current = head;
if (current != null) {
while (current.getNext() != null) {
current = current.getNext();
}
current.setNext(temp);
}
}
}
// method to search a value from a list
public void search(String num)
{
Node current = head;
boolean flag=true;
if (current != null)
{
while (current != null)
{
if(current.getData() == num)
{
System.out.println(\"Search value \"+
current.getData()+\" is available\");
flag=false;
}
current = current.getNext();
}
if (flag==true)
{
System.out.println(\"Search value \"+
current.getData()+\" is not available\");
}
}
else
{
System.out.println(\"Linked list is empty\");
}
}
// method to delete a value from a list
public void delete(String num)
{
//Node current = head;
boolean flag=true;
if (head == null)
{
System.out.println(\"Can\'t Delete, Linked list is
empty\");
return;
}
if(head.getData() == num)
{
head=head.getNext();
return;
}
Node temp = new Node(num);
Node cr = head;
Node prev=null;
while ((cr != null) && !(cr.getData() == num))
{
prev=cr;
cr = cr.getNext();
}
prev.setNext(cr.getNext());
}
// method to print the list
public void print()
{
Node current = head;
if (current != null) {
while (current != null) {
System.out.println(current.getData());
current = current.getNext();
}
}
}
}
// method to test the class
public class MyLInkedListTester
{
// main method to perform the linked list operatrions
public static void main(String args[])
{
MyLInkedList llist = new MyLInkedList();
// insert the values into list
llist.add(\"1\");
llist.add(\"2\");
llist.add(\"3\");
llist.add(\"4\");
// print the list values
llist.print();
// sear the values in a list
llist.search(\"1\");
llist.print();
// delete the value from a list
llist.delete(\"4\");
System.out.println(\"List after deletion:\");
llist.print();
}
}
Result:
1
2
3
4
Search value 1 is available
1
2
3
4
List after deletion:
1
2
3
Solution
Note:
Given Code modified as required and required methods added.
Code:
// class node
class Node
{
// declare the required variable
String data;
Node next;
// constructor
Node(){}
// constructor with arguments
Node(String data)
{
this.data = data;
next = null;
}
// method to get the data
public String getData()
{
return data;
}
// method to set the data
public void se.
hi i have to write a java program involving link lists. i have a pro.pdf
hi i have to write a java program involving link lists. i have a pro.pdfarchgeetsenterprises hi i have to write a java program involving link lists. i have a problem with the nodes, as it is
posting errors with the nodes.
please help me with this problem. thank you.
public class LinkLists {
/* only need to store a single pointer to the node at the head
* of the list.
* The pointer is null if the list is empty.
* Also record the size of the list.
*/
protected Node head;
/* invariant: size is the number of nodes in the list pointed to by head */
protected int size;
/* no-arguments default constructor creates an empty list */
public LinkLists() {
head = null; // start with an empty list
size = 0;
}
/* accessor method */
public int size() {
return size;
}
/* value to add to the end of the list
*/
public void add(T value) {
head = addAtEnd(head, value);
size++;
}
/* node of the list to which the value should be added
* value to add to the end of the list
*/
private Node addAtEnd(Node node, T value) {
if (node == null) { // special case
return new Node(value, null);
} else if (node.getNext() == null) { // other special case
node.setNext(new Node(value, null));
} else {
addAtEnd(node.getNext(), value);
}
return node;
}
/* iterative implementation of the same method
* value to add to the end of the list
*/
public void add2(T value) {
if (head == null) {
head = new Node(value, null);
} else {
Node node = head; // guaranteed not to be null initially
while (node.getNext() != null) {
node = node.getNext(); // guaranteed not to be null here
}
// now, node.getNext() is guaranteed to be null
// similar to the second special case in addAtEnd
node.setNext(new Node(value, null));
}
size++;
}
public void remove(int position) throws BadItemCountException {
if ((position < 1) || (position > size)) {
throw new
BadItemCountException(\"invalid position \" + position +
\", only 1..\" + size + \" available\");
}
if (position == 1) {
head = head.getNext();
} else {
Node node = head;
for (int i = 2; i < position; i++) {
node = node.getNext();
}
node.setNext(node.getNext().getNext());
}
size--; // one less item
}
public String toString() {
return toString(head);
}
private String toString(Node node) {
if (node == null) {
return \"\";
} else {
return node.getValue() + \"\ \" + toString(node.getNext());
}
}
public static void main(String[] args) {
/* create two empty lists, make sure they print out correctly */
LinkLists list1 = new LinkLists();
LinkLists list2 = new LinkLists();
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* insert some items, keep checking */
list1.add(\"hello\");
list1.add(\"world\");
list2.add(\"foo\");
list2.add(\"bar\");
list2.add(\"baz\");
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* remove an item at an invalid position */
boolean caught = false;
try {
list2.remove(4);
} catch .
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Mercados emergentes: Red Alliance de Etihad Airways
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en Aer Lingus, con sede en Dubln, Irlanda (4% de acciones); Alitalia, con sede en Roma, Italia
(49 %), la aerolnea ms grande de Italia; Air Serbia, con sede en Belgrado, Serbia (49%), la
aerolnea ms grande de Serbia, anteriormente conocida como Jat Airways; Air Seychelles, con
sede en Mahe, Seychelles (40%); Darwin Airline, con sede en Lugano, Suiza (34 %),
recientemente renombrada como Etihad Regional; Jet Airways, con sede en Mumbai, India
(24%); y Virgin Australia, con sede en Brisbane, Australia (20%).
El director ejecutivo de Etihad, James Hogan, que es australiano, es visto com.
CASO DE ESTUDIO La cl�nica Mayo es uno de los nombres m�s respetad.pdf
CASO DE ESTUDIO La cl�nica Mayo es uno de los nombres m�s respetad.pdfsales88 CASO DE ESTUDIO
La clnica Mayo es uno de los nombres ms respetados en el mundo de la medicina. Fundada en la
dcada de 1880 en Rochester, Minnesota, la clnica Mayo abraz la innovacin desde el principio. Se
cree que es la primera prctica grupal integrada de Estados Unidos, ya que emple el concepto de
atencin especializada coordinada y busc la mejor experiencia.
En el ncleo de la cultura de Mayo, desde sus inicios hasta el da de hoy, se encuentra un enfoque
de equipo y una toma de decisiones mdica arraigada en la responsabilidad compartida y la
creacin de consenso. Mayo tiene una slida tradicin de ser una organizacin dirigida por mdicos
que defiende la atencin al paciente excepcional y la investigacin mdica. Es reconocida
mundialmente por su calidad de atencin.
Hoy, la clnica Mayo est decidida a establecer un nuevo estndar en el cuidado de la salud al
eliminar el desperdicio y mejorar la eficacia. Ya ha logrado brindar una atencin ms segura que
cuesta significativamente menos que el promedio de EE. UU. A medida que la organizacin creci
y la sociedad cambi, una combinacin personalizada de herramientas y enfoques de calidad ayud a
lograr una transformacin en todo el sistema, posicionando a Mayo para lograr su objetivo de
brindar la mejor atencin mdica, sin excepcin.
A medida que la atencin mdica cambi en la dcada de 1990, Mayo comenz a abordar la calidad
con un rigor cada vez mayor, midiendo ms a fondo los resultados de sus esfuerzos con la ayuda
del instituto Juran, Mayo lanz un programa completo de mejora de la calidad. Varios lderes
siguieron la capacitacin Six Sigma y compartieron su experiencia con la organizacin. Estos
esfuerzos trajeron algunas mejoras y ayudaron a desarrollar futuros lderes clave. Pero un
conflicto entre la eficiencia y la eficacia sentido por muchas organizaciones se desarroll en
Mayo: el costo percibido de la mejora de la calidad choc con la mejora de los resultados, ya sea
necesaria o no. el programa fue descartado.
Se prob la ventaja estratgica de Mayo de ser lo mejor de lo mejor. En 1999, el instituto de
medicina emiti un informe fundamental, construyendo un sistema de salud ms seguro. Que desafi
a los proveedores de atencin mdica a reducir los errores mdicos prevenibles en un 50 por ciento
durante los siguientes cinco aos. Cruzando el abismo de la calidad: un nuevo sistema de salud
para el siglo XXI y varios otros informes influyentes siguieron.
Los informes del IOM fueron un catalizador para que Mayo aprendiera cmo estaba a la altura de
la seguridad y la atencin del paciente. Alrededor de este tiempo, el personal de la clnica reconoci
que ocurrieron algunos errores prevenibles que pusieron un rostro humano en los datos del
informe y ayudaron al liderazgo de Mato a darse cuenta de que todas las organizaciones, ya sean
buenas o malas, necesitan mejorar.
Mayo tambin enfrent el desafo de ser un proveedor de destino, ya que la mayora de los pacientes
viajaban largas distancias y esperaban completar su atencin en cuatro o.
CASO DE ESTUDIO La �pera de Sydney es uno de los edificios ic�nico.pdf
CASO DE ESTUDIO La �pera de Sydney es uno de los edificios ic�nico.pdfsales88 CASO DE ESTUDIO
La pera de Sydney es uno de los edificios icnicos ms conocidos, reconocido en todo el mundo
como un smbolo mundial de Australia. El arquitecto dans Jrn Utzon gan el concurso de
arquitectura establecido por el gobierno de Nueva Gales del Sur para el nuevo edificio en 1957, y
la construccin comenz en 1959. El proyecto estaba originalmente programado para cuatro aos,
con un presupuesto de 7 millones de dlares australianos. Termin tardando 14 aos en completarse
y cost AUS $ 102 millones. La pera de Sdney probablemente podra verse como uno de los
proyectos de construccin ms desastrosos de la historia, no solo desde el punto de vista financiero
sino tambin desde el punto de vista de la gestin en su conjunto. Analicemos las principales
razones que llevaron a ello. En primer lugar, al comienzo de cualquier proyecto, el cliente debe
definir claramente las metas y los objetivos para proporcionar una gua de lo que debe completar
el proyecto. Hay tres factores principales: tiempo, costo y calidad. En el caso de la pera de
Sdney, este ltimo fue el ms importante, ya que era un objetivo casi irrestricto del proyecto y el
motivo por el cual se puso en marcha. Tampoco se proporcionaron indicaciones sobre los lmites
de tiempo o costo para la competencia. As, a los arquitectos se les permiti total libertad en sus
diseos. Despus de que Utzon fuera seleccionado, present su "Libro rojo" en marzo de 1958, que
consista en el informe de la pera Nacional de Sydney. Comprendi algunas indicaciones como
planos, secciones, informes de consultores, etc. Los fondos provinieron casi en su totalidad de
una lotera dedicada, por lo que el proyecto no fue una carga financiera para el gobierno. En
cuanto a la planificacin del tiempo, la meta era completar la construccin a fines de 1962 y tener
la gran inauguracin a principios de 1963. El proyecto debera haber durado cuatro aos. La
principal parte interesada era el arquitecto, pero Utzon estaba mucho ms preocupado por el
aspecto del diseo que por los objetivos de tiempo y costos, lo que result ser problemtico. Durante
el proyecto, Utzon colabor con Ove Arup, quien estuvo a cargo de la estructura y la ingeniera.
Con algunos otros subcontratistas, el equipo estuvo a cargo de la mecnica, electricidad,
calefaccin y ventilacin, iluminacin y acstica. No haba un director de proyecto real, sino ms bien
una colaboracin entre Utzon y Arup.
El otro actor principal era el cliente, el estado de Nueva Gales del Sur. Esto abarc al gobierno
australiano, que lanz el concurso para el proyecto, y especialmente al primer ministro laborista,
Joe Cahill. Se cre un comit ejecutivo a tiempo parcial para supervisar el proyecto, pero los
miembros no tenan habilidades tcnicas reales. El gobierno finalmente se convirti en un obstculo
para el equipo del proyecto al inhibir los cambios durante el progreso de las operaciones y, por lo
tanto, contribuy a sobrecostos y demoras. Finalmente, el pblico era un actor indirecto porque
estaba preocupado .
Caso de estudio Despu�s de luchar con la deuda y la fuerte compete.pdf
Caso de estudio Despu�s de luchar con la deuda y la fuerte compete.pdfsales88 Caso de estudio
Despus de luchar con la deuda y la fuerte competencia de Netflix y Redbox, Blockbuster, Inc. se
declar en bancarrota en septiembre de 2010. Este fue un final triste para una empresa que haba
dominado el negocio de alquiler de pelculas en la dcada de 1990. Blockbuster Inc. fue fundada
por David Cook en 1985 con su primera tienda de alquiler en Dallas. Cook plane aprovechar un
mercado de alquiler de videos altamente fragmentado, en el que la mayora de las tiendas eran
operaciones familiares relativamente modestas que vendan una pequea seleccin de pelculas de
gran xito, principalmente debido al alto costo que cobran los distribuidores (alrededor de $ 65).
por cinta). Con 8000 cintas que cubran 6500 ttulos, Blockbuster tena un inventario mucho ms
amplio y profundo en comparacin con el de su competidor ms cercano. Las operaciones de la
tienda tambin se agilizaron en gran medida gracias a un sistema computarizado de control de
inventario y caja. La tienda fue un gran xito, lo que provoc la adicin de tres ubicaciones ms a
mediados de 1986. En 1986, debido a problemas de liquidez, Cook se vio obligado a entregar
toda la empresa a un grupo de inversores liderado por Wayne Huizenga. Entre 1987 y 1993,
Huizenga convirti a Blockbuster en un enorme xito. Durante este perodo, Blockbuster abri
tiendas en todo el mundo a razn de una cada 24 horas. En 1993, Blockbuster era el principal
proveedor mundial de entretenimiento de juegos y pelculas para el hogar, con ms de 3400 tiendas
en Amrica, Europa, Asia y Australia. Las tiendas de gran xito eran una caracterstica
omnipresente del vecindario que permaneca abierta los 365 das del ao, generalmente desde las
10 am hasta la medianoche. La seleccin, la cantidad y los formatos de la mercanca se
personalizaron a nivel de tienda para satisfacer las necesidades y preferencias de los clientes
locales. Sin embargo, a principios de la dcada de 2000, Blockbuster comenz a ver una
competencia real del floreciente mercado de alquiler en lnea a medida que los DVD comenzaron
a reemplazar las cintas. Su principal competidor era Netflix, lanzado en 1997. Adems de ser ms
baratos de comprar que las cintas, los DVD eran adecuados para el envo por correo porque eran
menos costosos de enviar y menos frgiles que las cintas. Netflix desafi a Blockbuster en dos
dimensiones clave: variedad y cargos por pagos atrasados. Mientras que las tiendas Blockbuster
generalmente vendan alrededor de 3000 ttulos, Netflix inicialmente ofreca ms de diez veces esa
cantidad. Adems, Netflix no cobr los "cargos por pagos atrasados" que tanto disgustaban a
Blockbuster, sino que permiti a los clientes conservar los ttulos todo el tiempo que quisieran. El
plan de suscripcin mensual de Netflix ofreca alquileres ilimitados por correo por $9, el costo de
dos alquileres en una tienda Blockbuster. Mientras tanto, Redbox, una unidad de Coinstar Inc.,
operaba mquinas expendedoras que alquilaban DVD por tan solo $1 por noche. A pesar de sus
mejores esf.
Caso cl�nicoSDRAPregunta 1.Dados sus s�ntomas de fatiga, disne.pdf
Caso cl�nicoSDRAPregunta 1.Dados sus s�ntomas de fatiga, disne.pdfsales88 Caso clnicoSDRA
Pregunta 1.Dados sus sntomas de fatiga, disnea, tos y fiebre, mencione 3 diagnsticos
diferenciales (incluya definiciones y caractersticas importantes de la enfermedad).
1.
2.
3..
Caso 21-3 Orden de prueba de deterioro Five Star Hotel Corporati.pdf
Caso 21-3 Orden de prueba de deterioro Five Star Hotel Corporati.pdfsales88 Caso 21-3
Orden de prueba de deterioro
Five Star Hotel Corporation (Five Star) opera dos propiedades tursticas exclusivas que operan
bajo diferentes marcas, una ubicada en los Estados Unidos y la otra en las Bermudas. Se ha
determinado que cada resort es un grupo de activos para evaluar el deterioro de los activos de
larga duracin y una unidad de informes para evaluar el deterioro de la plusvala. Five Star fue
adquirida por una compaa de inversin hace varios aos, lo que result en la inclusin de un activo
intangible de marca y un fondo de comercio en cada grupo de activos/unidad de informes.
Ambos activos intangibles de marca estn determinados a tener una vida til indefinida. En
resumen, cada grupo de activos de resort/unidad de informes tiene los siguientes tipos de activos:
Cuentas por cobrar
Inventario
Activos intangibles relacionados con el cliente (de vida finita)
Activos intangibles de marca (de vida indefinida)
Propiedad, planta y equipo
Buena voluntad
Durante el perodo de informe actual, Five Star ha determinado que ocurri un evento
desencadenante en relacin con el resort en los Estados Unidos, lo que requiere que el grupo de
activos sea probado por deterioro sobre la base de retencin y uso. Adems, durante el perodo de
informe actual, Five Star inici un proceso para disponer del resort en las Bermudas a travs de una
venta y ha determinado que se cumplen los criterios para la clasificacin como mantenido para la
venta.
Requerido:
Cul es el orden de las pruebas de deterioro para los activos en el grupo de activos de resort de
EE. UU. de Five Star cuando el grupo de activos se clasifica como mantenido y utilizado?
Cul es el orden de las pruebas de deterioro para los activos del grupo de enajenacin de
complejos tursticos de Five Star en Bermudas cuando el grupo de enajenacin se clasifica como
mantenido para la venta?.
Caso 6.2 Seguro Mar�timo Cl�usula Inchmaree Un barco pesquero c.pdf
Caso 6.2 Seguro Mar�timo Cl�usula Inchmaree Un barco pesquero c.pdfsales88 Caso 6.2 Seguro Martimo: Clusula Inchmaree
Un barco pesquero con casco de madera de cuarenta pies sufri una fuga inesperada unos das
despus de salir del puerto. A medida que entraba ms agua en la embarcacin, el motor se inundaba
y finalmente la embarcacin se hunda. La inspeccin de la embarcacin durante la fuga mostr que el
agua provena de debajo de un espacio refrigerado en la parte delantera de la embarcacin. En vista
de su estilo de construccin, la sentina debajo de la embarcacin era inaccesible. El asegurador se
neg a indemnizar al asegurado por la prdida de la embarcacin alegando que este ltimo no haba
actuado con diligencia para poner la embarcacin en condiciones de navegar antes de que se
produjera la fuga (segn lo dispuesto en la Clusula Inchmaree). El propietario/capitn del barco no
tena conocimiento de la fuga antes de que el barco comenzara su viaje.
Preguntas
1. (Caso 6.1) Es esta prdida total real o constructiva? Explica tu respuesta.
2. En el caso 6.2, piensa que la prdida est cubierta por la pliza (ver Perspectiva Internacional
6.3)?
PERSPECTIVA INTERNACIONAL 6.1
Atributos de un Sistema Logstico de Clase Mundial: Dinamarca
Dinamarca ocupa el primer puesto mundial en logstica. Su excelencia en logstica se atribuye a
una serie de factores:
Inversin en infraestructura: El aeropuerto internacional se encuentra a unos treinta minutos de
diez puertos internacionales y zonas francas. Proporciona acceso directo a la red ferroviaria y de
carreteras europea con conexiones directas a muchas ciudades europeas. Cuenta con
transportistas e integradores internacionales con instalaciones de depsito aduanero. Proporciona
una inversin sustancial para el mantenimiento y desarrollo de la infraestructura (puentes,
aeropuerto y puerto martimo). Cuenta con una eficiente instalacin de manejo de carga area. El
despacho de aduana de las mercancas se realiza antes del pago de los derechos, con un mnimo de
trmites burocrticos. La tecnologa de la informacin ayuda a agilizar los procedimientos de
exportacin o importacin y vincula a los transportistas y los consumidores.
Recursos humanos: mano de obra altamente calificada y motivada, operaciones las veinticuatro
horas del da, los siete das de la semana y buenas relaciones entre la gerencia y los trabajadores
(las huelgas o huelgas son prcticamente inexistentes).
Entorno de negocios: Disponibilidad de zonas de libre comercio y depsitos aduaneros, bajas
restricciones comerciales con un entorno econmico/poltico estable.
PERSPECTIVA INTERNACIONAL 6.2
Embalaje de exportaciones de artesanas: puntos importantes
Antes del embalaje: Saque el polvo, limpie, elimine las huellas dactilares y seque los artculos.
Principales problemas a considerar en el empaque: Deslustre, corrosin, manchas, descomposicin,
rotura.
edad, humedad.
Prevencin de la humedad: use un agente secante (gel de slice) para reducir la humedad; reducir
el rea de superficie del paquete; artculos secos; y empaque los materiales en paquetes con un
sello he.
Caso 3.1 Firma de contadores Moss y McAdams Bruce Palmer hab�a t.pdf
Caso 3.1 Firma de contadores Moss y McAdams Bruce Palmer hab�a t.pdfsales88 Caso 3.1
Firma de contadores Moss y McAdams
Bruce Palmer haba trabajado para Moss and McAdams (M&M) durante seis aos y acababa de
ser ascendido a gerente de cuentas. Su primera asignacin fue dirigir una auditora de Johnsonville
Trucks. Estaba bastante complacido con los cinco contadores que haban sido asignados a su
equipo, especialmente con Zeke Olds. Olds era un veterano del ejrcito que haba regresado a la
escuela para obtener una doble especializacin en contabilidad e informtica. Estaba al tanto de los
ltimos desarrollos en sistemas de informacin financiera y tena la reputacin de encontrar
soluciones innovadoras a los problemas.
M&M era una firma de contabilidad regional bien establecida con 160 empleados ubicados en
seis oficinas en Minnesota y Wisconsin. La oficina principal, donde trabajaba Palmer, estaba en
Green Bay, Wisconsin. De hecho, uno de los miembros fundadores, Seth Moss, jug brevemente
para los Packers de la NFL de su ciudad natal a fines de la dcada de 1950. Los principales
servicios de M&M eran auditoras corporativas y preparacin de impuestos. En los ltimos dos aos,
los socios decidieron incursionar de manera ms agresiva en el negocio de la consultora. M&M
proyect que la consultora representara el 40 por ciento de su crecimiento durante los prximos
cinco aos.
Pgina 98M&M operaba dentro de una estructura matricial. A medida que se reclutaban nuevos
clientes, se asignaba un administrador a la cuenta. Se podra asignar un gerente a varias cuentas,
segn el tamao y el alcance del trabajo. Esto fue especialmente cierto en el caso de los proyectos
de preparacin de impuestos, donde no era raro que un gerente fuera asignado a 8 a 12 clientes.
Asimismo, los contadores principales y de planta fueron asignados a mltiples equipos de cuentas.
Ruby Sands era la gerente de oficina responsable de asignar personal a diferentes cuentas en la
oficina de Green Bay. Hizo todo lo posible para asignar personal a mltiples proyectos bajo el
mismo gerente. Esto no siempre era posible y, a veces, los contadores tenan que trabajar en
proyectos dirigidos por diferentes gerentes.
M&M, como la mayora de las empresas de contabilidad, tena un sistema de promocin por
niveles. Nuevos CPA ingresados como contadores junior o de personal. En dos aos, se revis su
desempeo y se les pidi que se fueran o se les ascendi a contador senior. En algn momento
durante su quinto o sexto ao, se tom la decisin de ascenderlos a gerente de cuentas. Finalmente,
luego de 10 a 12 aos en la firma, el gerente fue considerado para su ascenso a socio. Esta era una
posicin muy competitiva. Durante los ltimos 5 aos, solo el 20 por ciento de los gerentes de
cuentas de M&M haban sido ascendidos a socios. Sin embargo, una vez que eran socios, tenan
prcticamente garantizado el puesto de por vida y disfrutaban de aumentos significativos en
salario, beneficios y prestigio. M&M tena la reputacin de ser una organizacin orientada a los
resultados; las promociones de los socios se basaron en el cu.
Caso 2 (TV de Alta Definici�n La Gran Alianza) (1) Seg�n el caso .pdf
Caso 2 (TV de Alta Definici�n La Gran Alianza) (1) Seg�n el caso .pdfsales88 (1) El documento describe la transición a la televisión de alta definición (HDTV) y los esfuerzos de varios países y organizaciones para establecer estándares. (2) Japón desarrolló el estándar Hi-Vision a través de NHK, mientras que Europa lanzó el Proyecto Eureka. (3) En Estados Unidos, las emisoras estaban divididas sobre HDTV, ya que requeriría inversiones pero quizás no aumentaría la audiencia.
Caso 1 (8 puntos) Miguel y Cinthia Leatch viven en Covington, Ten.pdf
Caso 1 (8 puntos) Miguel y Cinthia Leatch viven en Covington, Ten.pdfsales88 Caso 1 (8 puntos):
Miguel y Cinthia Leatch viven en Covington, Tennessee, en una casa que tienen desde 2002.
Cuando compraron la casa, haba una cantera de grava al otro lado de la calle. En 2005, el estado
convirti la gravera en un vertedero. Bajo la operacin del estado, el vertedero acept basura
domstica, recortes de csped, estircol, cadveres de animales, contenedores con advertencias de
contenido peligroso, bateras de automviles con fugas, aceite de desecho, entre otras cosas. A
pesar de las leyes ambientales federales que exigen que los depsitos de vertederos se cubran
dentro de las veinticuatro horas posteriores a su vertido, los depsitos de vertederos a menudo se
dejaban descubiertos durante semanas seguidas, atrayendo insectos, ratas y otros carroeros. Se
produjeron incendios, incluido al menos uno iniciado por un intruso que haba ingresado a la
propiedad del vertedero a travs de una puerta abierta.
Los Leatch se quejaron al estado, alegando que el relleno sanitario estaba siendo operado en
violacin de las leyes federales que estn diseadas para minimizar los riesgos de lesiones por
incendios, carroeros, contaminacin del agua subterrnea y otros peligros de contaminacin. El
estado inspeccion el vertedero, pero no se realizaron cambios operativos. Los Leatch presentaron
una demanda contra el estado por la operacin del vertedero.
Caso 1 Pregunta:
Tienen los Leatch legitimacin para demandar en estas circunstancias? Por qu o por qu no?
Explique completamente su anlisis..
Caso 1 Agmmaglobulinemia ligada al X 1. Bill fue testamento duran.pdf
Caso 1 Agmmaglobulinemia ligada al X 1. Bill fue testamento duran.pdfsales88 Caso 1: Agmmaglobulinemia ligada al X
1. Bill fue testamento durante los primeros 10 meses de esta vida. como explicas esto
2. Los pacientes con enfermedades de inmunodeficiencia nunca deben recibir vacunas virales
vivas. A varios lactantes varones con agammaglobulineia ligada al cromosoma X se les administr
la vacuna antipoliomieltica oral viva y desarrollaron poliomielitis paraltica. Qu secuencia de
eventos condujo al desarrollo de polio en estos nios?
3. Las infecciones recurrentes de Bills se debieron casi exclusivamente a las especies
Streptococcus y Haemophilus . Estas bacterias tienen una cpsula viscosa compuesta
principalmente por polmeros de polisacridos, que las protegen de todo ataque directo de los
fagocitos. Los seres humanos fabrican anticuerpos IgG2 contra estos polmeros de polisacridos.
Los anticuerpos IgG2 opsonizan a las bacterias fijando el complemento en su superficie, lo que
facilita la rpida captacin de estas bacterias por las clulas fagocticas. Qu otro defecto gentico en el
sistema inmunitario podra imitar clnicamente la agammaglobulinemia ligada al cromosoma X?.
Caso 1 Felipe R�os y Tiffany De Los Rios married filling jointl.pdf
Caso 1 Felipe R�os y Tiffany De Los Rios married filling jointl.pdfsales88 Caso 1 Felipe Ros y Tiffany De Los Rios married filling jointly
Postal direction: URB BEVERLY HILLS A-12 Guaynabo PR 00969
Date of birth Felipe Rios 08/12/1984 Tiffany Rios 12/06/1985
Felipe Rios Seguro Social: 111-21-4521 Tiffany de los Ros 222-54-8489
Telephone: 787-794-4584
Felipe w2 wages 49,844
Tax withholding 3,419
Social security tax 3,090.32
Medicare withheld 722.73
480 7a
Interest paid by borrower 6,808
Property taxes 1,800
Principal balance 212,660
Loan term 180
Tiffany de los ros withholding
Wages 37,513
Refund Expense and fringe benefits 5,778
Tax withheld 2,551
Governmental retirement 4,313
Total wages for social security number 41,860
Social security tax 2,595
Medicare 608
Dependent 1: Patrick Rios De Los Rios Jr. Son
Date of Birth 12/01/2005 Social Security: 151-56-4156
Dependent 2: Maria Rios De Los Rios Daughter
Date of Birth 06/25/2008 Social Security: 165-14-5616
Required: Complete the income tax return for 2022 form 1040 using the information provided
and considering this couple as residents of Puerto Rico. Consider Schedule CO if it suits the
taxpayer..
Case studyData Protect and PrivacyHuman beings value their priva.pdf
Case studyData Protect and PrivacyHuman beings value their priva.pdfsales88 Case study
Data Protect and Privacy
Human beings value their privacy and the protection of their personal sphere of life. They value
some control over who knows what about them. They certainly do not want their personal
information to be accessible to just anyone at any time. But recent advances in information
technology threaten privacy and have reduced the amount of control over personal data and open
up the possibility of a range of negative consequences as a result of access to personal data. In
the second half of the 20th century data protection regimes have been put in place as a response
to increasing levels of processing of personal data. The 21st century has become the century of
big data and advanced information technology (e.g. forms of deep learning), the rise of big tech
companies and the platform economy, which comes with the storage and processing of exabytes
of data. The technical capabilities to collect, store and search large quantities of data concerning
telephone conversations, internet searches and electronic payment are now in place and are
routinely used by government agencies and corporate actors alike. The rise of China and the
large scale of use and spread of advanced digital technologies for surveillance and control have
only added to the concern of many. For business firms, personal data about customers and
potential customers are now also a key asset. Source:https://plato.stanford.edu/entries/it-privacy/
As more phishing scams emerge, the more important it is for businesses and individuals to be
protected against these cyber-attacks. Discuss FIVE (5) effective techniques to keep phishing
attacks at bay?.
CASE STUDY [30 Marks] Former Tongaat Hulett bosses in court for frau.pdf![CASE STUDY [30 Marks] Former Tongaat Hulett bosses in court for frau.pdf](https://cdn.slidesharecdn.com/ss_thumbnails/casestudy30marksformertongaathulettbossesincourtforfrau-230401115215-ae09130f-thumbnail.jpg?width=560&fit=bounds)
CASE STUDY [30 Marks] Former Tongaat Hulett bosses in court for frau.pdfsales88 CASE STUDY [30 Marks] Former Tongaat Hulett bosses in court for fraud Just over two years
after charges were laid against them, former Tongaat Hulett Limited chief executive Peter Staude
and six others accused of defrauding the sugar and property giant of R2.5-billion have finally
appeared in court. The group of former executives charged over the fraud includes Deloitte audit
partner Gavin Kruger, who was responsible for auditing Tongaats books; former chief financial
officer Murray Munro; former property division head Michael Deighton, finance section head
Rory Wilkinson; legal executive Kamlasagrie Singh and finance executive Samantha Shukla.
They appeared in the Durban commercial crimes court on Thursday and were granted bail of
R30 000 each. They will appear in court again on 11 April, then the matter will be transferred to
the high court. Straude and his co-accused backdated sale agreements by Tongaats property
division to the value of R2.5-billion between March 2015 and September 2018, when the fraud
was discovered by the new Tongaat board, which appointed a forensic investigation. By inflating
the companys profits, they scored themselves millions of rand in productivity bonuses based on
the fraudulent sales, with Straude alone raking in R94-million by cooking the books. Their greed
cost nearly 8 000 workers in Tongaats sugar division and its milling operations their jobs when
the company moved to sell off assets and reduce its debt, while the firm and its suppliers
sustained huge losses. The company has gone after Staudes assets and those of Munro and
Deighton. It instituted a high court claim against them for R450-million in 2020, seeking
repayment of all the bonuses, salary payments and benefits it had paid them during their tenure.
Tongatt also wants the court to attach the accuseds pensions, which it has withheld pending the
outcome of the civil and criminal matters. According to the charge sheet, the seven had acted
with common purpose in planning to falsify sales figures and defraud the company. The group
also actively associated themselves with the common purpose, and worked together to
misrepresent the true state of the revenue brought about by sales of land by Tongaat Hulett
Development (THD), and to falsify the financial records of THD and or Tongaat Hulett Limited.
They had overstated the company revenue by R2.4-billion, an act which, once discovered,
exposed Tongaat to negative publicity and has been brought into disrepute with shareholders,
lenders, regulatory authorities and the broader public. Their fraudulent conduct cost Tongaat
R44-milion to have its financial statements restated and it was fined a further R7.5million by
local bourse the JSE and R20-million by the Financial Sector Conduct Authority. The seven
knew that material inaccurate accounting records had been compiled and maintained which were
ultimately processed and incorporated into the financial statements, the indictment said, adding:
The financial stateme.
case study Private Practice Implements Safeguards for Waiting .pdf
case study Private Practice Implements Safeguards for Waiting .pdfsales88 case study
Private Practice Implements Safeguards for Waiting Rooms
Covered Entity: Private Practice
Issue: Safeguards; Impermissible Uses and Disclosures
A staff member of a medical practice discussed HIV testing procedures with a patient in the
waiting room, thereby disclosing PHI to several other individuals. Also, computer screens
displaying patient information were easily visible to patients. Among other corrective actions to
resolve the specific issues in the case, OCR required the provider to develop and implement
policies and procedures regarding appropriate administrative and physical safeguards related to
the communication of PHI. The practice trained all staff on the newly developed policies and
procedures. In addition, OCR required the practice to reposition its computer monitors to
prevent patients from viewing information on the screens, and the practice installed computer
monitor privacy screens to prevent impermissible disclosures.
Recommendations
1. Determine and discuss specific strategies for preventing such HIPAA violations in the future.
2. What should be done and who should do it to make sure that such violations do not recur?.
Case Study Liberty and the Elderly Patient Ronald is 71 years old..pdf
Case Study Liberty and the Elderly Patient Ronald is 71 years old..pdfsales88 Case Study
Liberty and the Elderly Patient Ronald is 71 years old. A widower, he lives alone in an
apartment, but he regularly receives some assistance from a cleaning woman and a friendly
neighbor. Ronald is presently in Metropolitan hospital, because he had a fall and suffered a
broken leg. Now that he has begun to heal, he is ready to be discharged. Ronald also suffers from
arteriosclerosis, a condition that results in his experiencing periods of confusion during which he
sometimes wanders purposelessly around his apartment building and sometimes wandering
around the city. This type of behavior has run some risks for Ronald in the past, and his children
do not want him to return to his apartment. The children believe that he needs the supervised care
provided in a nursing home. Ronald, when not in a confused state, repeatedly expresses his
awareness of the problems he faces stemming from his arteriosclerosis and the resultant risks that
he runs. Nonetheless, he would rather run those risks than be confined to institutional care. The
health care professionals and Ronalds children decide that he cannot be discharged from
Metropolitan hospital until an appropriate nursing home is found. At that time, he will be sent to
the nursing home. When Ronald insists to being discharged from the hospital, the nurses sedate
him to a level sufficient to gain his compliance.
1. If Ronalds adult children decided that he is capable of returning to his apartment with his
neighbor and his cleaning lady assisting him, would the medical professionals and the social
workers at the hospital be able to detain him against Ronalds will and his childrens will? In your
opinion, would this situation similar to a battered child/ spouse scenario where the abused person
is returned to the abuser? _______
2. If Ronald is deemed to be mentally incompetent because of his medical condition, his oldest
daughter will become his legal guardian. In your own words, explain how the removal of
Ronalds self-determination and autonomy in the hospital and the nursing home have made him
more vulnerable and dependent on his children and medical care givers. (will he be better off
/worse off if someone else is making decisions for him _______
3. In your opinion, what is the best possible outcome for Ronald? Please choose 1 (A -Ronald is
allowed to go home to his apartment B- He moves into his daughters house, C - he is sent to the
County Nursing home) Explain why your solution will put Ronald at the lowest risk and Please
indicate if you agree or disagree with what has happened to Ronald so far in our case.
Case Study AMr. P tripped and broke her left hip while attempting.pdf
Case Study AMr. P tripped and broke her left hip while attempting.pdfsales88 Case Study A:
Mr. P tripped and broke her left hip while attempting to go to the bathroom in the middle of the
night. Prior to this episode, she has been living alone and spend most of her days watching
television. She last presented 3 months ago after she has had a fall at home. At that time, she had
no serious injuries.
Mrs. P was taken to surgery and underwent an ORIF for her fracture. She did well post-op and
was discharged to a rehab facility. The physician overseeing her rehab started her on alendronate
once a week in addition to calcium with vitamin D.
Youre the discharging nurse and Mrs. P has questions about her new medications. Answer each
question:
Case Study B:
Mrs. Davis presented to the clinic in December of 2010 with some concerns about osteoporosis.
She was becoming more stooped and had already lost 1 in height over the last few years. She
was 20 years postmenopausal and had never taken hormone replacement therapy. She
subsequently received a DEXA scan at that time and was placed on Fosamax 10 mg daily. Over
the next year, this seemed to be working well for her and she did not experience any side effects
from the medication. In the fall of 2011, she sustained a fracture to her 4th metacarpal on her left
hand that she suffered during a fall. She received another DEXA scan in late 2011 with no
change. She seemed fairly stable and was only seen yearly after that time. During a repeat exam
in 2013, DEXA scores continued to show progression and she was subsequently referred to an
endocrinologist to eliminate secondary causes. After a thorough work-up, no cause was found for
her worsening osteoporosis. Thyroid studies were normal as well as serum phosphorus, PTH and
urine calcium. suggestion was made to switch to weekly Fosamax; however, this was not
tolerated well and she remains on Fosamax 10 mg q.d.
1. Identify and discuss at least 6 risk factors in Mrs. Davis history that predispose her to
osteoporosis. (3 points)
2. Which of those risk factors are intrinsic and not amenable to change? Which are extrinsic and
can be modified? (2 points)
3. Evaluate her calcium intake from her diet and supplements; is it adequate for her age and
menopausal status? (1 point)
4. Formulate a recommendation for vitamin and mineral intake for Mrs. Davis, including specific
compounds, doses and directions. (2 points)
5. Evaluate Mrs. Davis level of physical activity and make any recommendations you think
necessary. (2 points).
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- 5. public E get(int index) { if (index < 0 || index >= size) { throw new IndexOutOfBoundsException(); } return getNode(index).element; } public int indexOf(E e) { int index = 0; for (Node node = head; node != null; node = node.next) { if (e == null ? node.element == null : e.equals(node.element)) { return index; } index++; } return -1; } public int lastIndexOf(E e) { int index = size - 1; for (Node node = tail; node != null; node = node.prev) { if (e == null ? node.element == null : e.equals(node.element)) { return index; } index--; } return -1; } public E set(int index, E e) { if (index < 0 || index >= size) { throw new IndexOutOfBoundsException(); } Node node = getNode(index); E oldElement = node.element; node.element = e; return oldElement; } public void add(E e) {
- 6. addLast(e); } public void add(int index, E e) { if (index < 0 || index > size) { throw new IndexOutOfBoundsException(); } if (index == size) { addLast(e); } else { addBefore(getNode(index), e); } } public void addFirst(E e) { if (size == 0) { head = tail = new Node<>(e, null, null); } else { head.prev = new Node<>(e, null, head); head = head.prev; } size++; } public void addLast(E e) { if (size == 0) { head = tail = new Node<>(e, null, null); } else { tail.next = new Node<>(e, tail, null); tail = tail.next; } size++; } public E remove(int index) { if (index < 0 || index >= size) { throw new IndexOutOfBoundsException(); } return remove(getNode(index)); }
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