ch05.ppt

Chapter 5: Selection Statements
1
Chapter 5
Selection Statements
WEEK 5
Lecturer: Hamid Milton Mansaray
Phone#: +23276563575
Email: hmmansaray@ccmtsl.com

Statements
• So far, we’ve used return statements and
expression statements.
• Most of C’s remaining statements fall into three
categories:
– Selection statements: if and switch
– Iteration statements: while, do, and for
– Jump statements: break, continue, and goto.
(return also belongs in this category.)
• Other C statements:
– Compound statement
– Null statement
2

Logical Expressions
• Several of C’s statements must test the value of an
expression to see if it is “true” or “false.”
• For example, an if statement might need to test
the expression i < j; a true value would indicate
that i is less than j.
• In many programming languages, an expression
such as i < j would have a special “Boolean” or
“logical” type.
• In C, a comparison such as i < j yields an
integer: either 0 (false) or 1 (true).
3

Relational Operators
• C’s relational operators:
< less than
> greater than
<= less than or equal to
>= greater than or equal to
• These operators produce 0 (false) or 1 (true) when
used in expressions.
• The relational operators can be used to compare
integers and floating-point numbers, with
operands of mixed types allowed.
4

• The precedence of the relational operators is lower
than that of the arithmetic operators.
– For example, i + j < k - 1 means (i + j) < (k - 1).
• The relational operators are left associative.
5

• The expression
i < j < k
is legal, but does not test whether j lies between i
and k.
• Since the < operator is left associative, this
expression is equivalent to
(i < j) < k
The 1 or 0 produced by i < j is then compared to k.
• The correct expression is i < j && j < k.
6

Equality Operators
• C provides two equality operators:
== equal to
!= not equal to
• The equality operators are left associative and produce
either 0 (false) or 1 (true) as their result.
• The equality operators have lower precedence than the
relational operators, so the expression
i < j == j < k
is equivalent to
(i < j) == (j < k)
7

Logical Operators
• More complicated logical expressions can be built
from simpler ones by using the logical operators:
! logical negation
&& logical and
|| logical or
• The ! operator is unary, while && and || are
binary.
• The logical operators produce 0 or 1 as their result.
• The logical operators treat any nonzero operand as
a true value and any zero operand as a false value.
8

Logical Operators
• Behavior of the logical operators:
!expr has the value 1 if expr has the value 0.
expr1 && expr2 has the value 1 if the values of expr1 and
expr2 are both nonzero.
expr1 || expr2 has the value 1 if either expr1 or expr2 (or
both) has a nonzero value.
• In all other cases, these operators produce the
value 0.
9

Logical Operators
• Both && and || perform “short-circuit” evaluation:
they first evaluate the left operand, then the right one.
• If the value of the expression can be deduced from the
left operand alone, the right operand isn’t evaluated.
• Example:
(i != 0) && (j / i > 0)
(i != 0) is evaluated first. If i isn’t equal to 0, then
(j / i > 0) is evaluated.
• If i is 0, the entire expression must be false, so there’s
no need to evaluate (j / i > 0). Without short-circuit
evaluation, division by zero would have occurred.
10

Logical Operators
• Thanks to the short-circuit nature of the && and
|| operators, side effects in logical expressions
may not always occur.
• Example:
i > 0 && ++j > 0
If i > 0 is false, then ++j > 0 is not evaluated, so
j isn’t incremented.
• The problem can be fixed by changing the
condition to ++j > 0 && i > 0 or, even better, by
incrementing j separately.
11

Logical Operators
• The ! operator has the same precedence as the
unary plus and minus operators.
• The precedence of && and || is lower than that
of the relational and equality operators.
– For example, i < j && k == m means (i < j) &&
(k == m).
• The ! operator is right associative; && and ||
are left associative.
12

The if Statement
• The if statement allows a program to choose
between two alternatives by testing an expression.
• In its simplest form, the if statement has the form
if ( expression ) statement
• When an if statement is executed, expression is
evaluated; if its value is nonzero, statement is
executed.
• Example:
if (line_num == MAX_LINES)
line_num = 0;
13

The if Statement
• Confusing == (equality) with = (assignment) is
perhaps the most common C programming error.
• The statement
if (i == 0) …
tests whether i is equal to 0.
• The statement
if (i = 0) …
assigns 0 to i, then tests whether the result is
nonzero.
14

The if Statement
• Often the expression in an if statement will test
whether a variable falls within a range of values.
• To test whether 0  i < n:
if (0 <= i && i < n) …
• To test the opposite condition (i is outside the
range):
if (i < 0 || i >= n) …
15

Compound Statements
• In the if statement template, notice that statement
is singular, not plural:
if ( expression ) statement
• To make an if statement control two or more
statements, use a compound statement.
• A compound statement has the form
{ statements }
• Putting braces around a group of statements forces
the compiler to treat it as a single statement.
16

Compound Statements
• Example:
{ line_num = 0; page_num++; }
• A compound statement is usually put on multiple
lines, with one statement per line:
{
line_num = 0;
page_num++;
}
• Each inner statement still ends with a semicolon,
but the compound statement itself does not.
17

Compound Statements
• Example of a compound statement used inside an
if statement:
if (line_num == MAX_LINES) {
line_num = 0;
page_num++;
}
• Compound statements are also common in loops
and other places where the syntax of C requires a
single statement.
18

The else Clause
• An if statement may have an else clause:
if ( expression ) statement else statement
• The statement that follows the word else is
executed if the expression has the value 0.
• Example:
if (i > j)
max = i;
else
max = j;
19

The else Clause
• When an if statement contains an else clause,
where should the else be placed?
• Many C programmers align it with the if at the
beginning of the statement.
• Inner statements are usually indented, but if
they’re short they can be put on the same line as
the if and else:
if (i > j) max = i;
else max = j;
20

The else Clause
• It’s not unusual for if statements to be nested inside
other if statements:
if (i > j)
if (i > k)
max = i;
else
max = k;
else
if (j > k)
max = j;
else
max = k;
• Aligning each else with the matching if makes the
nesting easier to see.
21

The else Clause
• To avoid confusion, don’t hesitate to add braces:
if (i > j) {
if (i > k)
max = i;
else
max = k;
} else {
if (j > k)
max = j;
else
max = k;
}
22

The else Clause
• Some programmers use as many braces as possible
inside if statements:
if (i > j) {
if (i > k) {
max = i;
} else {
max = k;
}
} else {
if (j > k) {
max = j;
} else {
max = k;
}
}
23

The else Clause
• Advantages of using braces even when they’re not
required:
– Makes programs easier to modify, because more
statements can easily be added to any if or else
clause.
– Helps avoid errors that can result from forgetting to use
braces when adding statements to an if or else
clause.
24

Cascaded if Statements
• A “cascaded” if statement is often the best way
to test a series of conditions, stopping as soon as
one of them is true.
• Example:
if (n < 0)
printf("n is less than 0n");
else
if (n == 0)
printf("n is equal to 0n");
else
printf("n is greater than 0n");
25

• Although the second if statement is nested inside
the first, C programmers don’t usually indent it.
• Instead, they align each else with the original
if:
if (n < 0)
printf("n is less than 0n");
else if (n == 0)
printf("n is equal to 0n");
else
printf("n is greater than 0n");
26

• This layout avoids the problem of excessive
indentation when the number of tests is large:
if ( expression )
statement
else if ( expression )
statement
…
else if ( expression )
statement
else
statement
27

Program: Calculating a Broker’s Commission
• When stocks are sold or purchased through a broker, the
broker’s commission often depends upon the value of the
stocks traded.
• Suppose that a broker charges the amounts shown in the
following table:
Transaction size Commission rate
Under $2,500 $30 + 1.7%
$2,500–$6,250 $56 + 0.66%
$6,250–$20,000 $76 + 0.34%
$20,000–$50,000 $100 + 0.22%
$50,000–$500,000 $155 + 0.11%
Over $500,000 $255 + 0.09%
• The minimum charge is $39.
28

Program: Calculating a Broker’s Commission
• The broker.c program asks the user to enter the
amount of the trade, then displays the amount of
the commission:
Enter value of trade: 30000
Commission: $166.00
• The heart of the program is a cascaded if
statement that determines which range the trade
falls into.
29

broker.c
/* Calculates a broker's commission */
#include <stdio.h>
int main(void)
{
float commission, value;
printf("Enter value of trade: ");
scanf("%f", &value);
if (value < 2500.00f)
commission = 30.00f + .017f * value;
else if (value < 6250.00f)
else
30

if (commission < 39.00f)
commission = 39.00f;
printf("Commission: $%.2fn", commission);
return 0;
}
31

The “Dangling else” Problem
• When if statements are nested, the “dangling else”
problem may occur:
if (y != 0)
if (x != 0)
result = x / y;
else
printf("Error: y is equal to 0n");
• The indentation suggests that the else clause belongs
to the outer if statement.
• However, C follows the rule that an else clause
belongs to the nearest if statement that hasn’t already
been paired with an else.
32

• A correctly indented version would look like this:
if (y != 0)
if (x != 0)
result = x / y;
else
33

• To make the else clause part of the outer if
statement, we can enclose the inner if statement
in braces:
if (y != 0) {
if (x != 0)
result = x / y;
} else
• Using braces in the original if statement would
have avoided the problem in the first place.
34

Conditional Expressions
• C’s conditional operator allows an expression to
produce one of two values depending on the value
of a condition.
• The conditional operator consists of two symbols
(? and :), which must be used together:
expr1 ? expr2 : expr3
• The operands can be of any type.
• The resulting expression is said to be a
conditional expression.
35

• The conditional operator requires three operands,
so it is often referred to as a ternary operator.
• The conditional expression expr1 ? expr2 : expr3
should be read “if expr1 then expr2 else expr3.”
• The expression is evaluated in stages: expr1 is
evaluated first; if its value isn’t zero, then expr2 is
evaluated, and its value is the value of the entire
conditional expression.
• If the value of expr1 is zero, then the value of
expr3 is the value of the conditional.
36

• Example:
int i, j, k;
i = 1;
j = 2;
k = i > j ? i : j; /* k is now 2 */
k = (i >= 0 ? i : 0) + j; /* k is now 3 */
• The parentheses are necessary, because the
precedence of the conditional operator is less than
that of the other operators discussed so far, with
the exception of the assignment operators.
37

• Conditional expressions tend to make programs
shorter but harder to understand, so it’s probably
best to use them sparingly.
• Conditional expressions are often used in return
statements:
return i > j ? i : j;
38

• Calls of printf can sometimes benefit from
condition expressions. Instead of
if (i > j)
printf("%dn", i);
else
printf("%dn", j);
we could simply write
printf("%dn", i > j ? i : j);
• Conditional expressions are also common in
certain kinds of macro definitions.
39

Boolean Values in C89
• For many years, the C language lacked a proper
Boolean type, and there is none defined in the C89
standard.
• One way to work around this limitation is to declare
an int variable and then assign it either 0 or 1:
int flag;
flag = 0;
…
flag = 1;
• Although this scheme works, it doesn’t contribute
much to program readability.
40

• To make programs more understandable, C89
programmers often define macros with names
such as TRUE and FALSE:
#define TRUE 1
#define FALSE 0
• Assignments to flag now have a more natural
appearance:
flag = FALSE;
…
flag = TRUE;
41

• To test whether flag is true, we can write
if (flag == TRUE) …
or just
if (flag) …
• The latter form is more concise. It also works
correctly if flag has a value other than 0 or 1.
• To test whether flag is false, we can write
if (flag == FALSE) …
or
if (!flag) …
42

• Carrying this idea one step further, we might even
define a macro that can be used as a type:
#define BOOL int
• BOOL can take the place of int when declaring
Boolean variables:
BOOL flag;
• It’s now clear that flag isn’t an ordinary integer
variable, but instead represents a Boolean
condition.
43

• C99 provides the _Bool type.
• A Boolean variable can be declared by writing
_Bool flag;
• _Bool is an integer type, so a _Bool variable is
really just an integer variable in disguise.
• Unlike an ordinary integer variable, however, a
_Bool variable can only be assigned 0 or 1.
• Attempting to store a nonzero value into a _Bool
variable will cause the variable to be assigned 1:
flag = 5; /* flag is assigned 1 */
44

• It’s legal (although not advisable) to perform
arithmetic on _Bool variables.
• It’s also legal to print a _Bool variable (either 0
or 1 will be displayed).
• And, of course, a _Bool variable can be tested in
an if statement:
if (flag) /* tests whether flag is 1 */
…
45

• C99’s <stdbool.h> header makes it easier to work
with Boolean values.
• It defines a macro, bool, that stands for _Bool.
• If <stdbool.h> is included, we can write
bool flag; /* same as _Bool flag; */
• <stdbool.h> also supplies macros named true
and false, which stand for 1 and 0, respectively,
making it possible to write
flag = false;
…
flag = true;
46

The switch Statement
• A cascaded if statement can be used to compare an
expression against a series of values:
if (grade == 4)
printf("Excellent");
else if (grade == 3)
printf("Good");
printf("Average");
printf("Poor");
printf("Failing");
else
printf("Illegal grade");
47

• The switch statement is an alternative:
switch (grade) {
case 4: printf("Excellent");
break;
case 3: printf("Good");
break;
case 2: printf("Average");
break;
case 1: printf("Poor");
break;
case 0: printf("Failing");
break;
default: printf("Illegal grade");
break;
}
48

• A switch statement may be easier to read than a
cascaded if statement.
• switch statements are often faster than if
statements.
• Most common form of the switch statement:
switch ( expression ) {
case constant-expression : statements
…
case constant-expression : statements
default : statements
}
49

• The word switch must be followed by an integer
expression—the controlling expression—in
parentheses.
• Characters are treated as integers in C and thus can
be tested in switch statements.
• Floating-point numbers and strings don’t qualify,
however.
50

• Each case begins with a label of the form
case constant-expression :
• A constant expression is much like an ordinary
expression except that it can’t contain variables or
function calls.
– 5 is a constant expression, and 5 + 10 is a constant
expression, but n + 10 isn’t a constant expression
(unless n is a macro that represents a constant).
• The constant expression in a case label must
evaluate to an integer (characters are acceptable).
51

• After each case label comes any number of
statements.
• No braces are required around the statements.
• The last statement in each group is normally
break.
52

• Duplicate case labels aren’t allowed.
• The order of the cases doesn’t matter, and the default
case doesn’t need to come last.
• Several case labels may precede a group of statements:
switch (grade) {
case 4:
case 3:
case 2:
case 1: printf("Passing");
break;
break;
break;
}
53

• To save space, several case labels can be put on the
same line:
switch (grade) {
case 4: case 3: case 2: case 1:
printf("Passing");
break;
break;
break;
}
• If the default case is missing and the controlling
expression’s value doesn’t match any case label,
control passes to the next statement after the switch.
54

The Role of the break Statement
• Executing a break statement causes the program
to “break” out of the switch statement; execution
continues at the next statement after the switch.
• The switch statement is really a form of
“computed jump.”
• When the controlling expression is evaluated,
control jumps to the case label matching the value
of the switch expression.
• A case label is nothing more than a marker
indicating a position within the switch.
55

• Without break (or some other jump statement) at the
end of a case, control will flow into the next case.
• Example:
switch (grade) {
case 4: printf("Excellent");
case 3: printf("Good");
case 2: printf("Average");
case 1: printf("Poor");
}
• If the value of grade is 3, the message printed is
GoodAveragePoorFailingIllegal grade
56

• Omitting break is sometimes done intentionally, but
it’s usually just an oversight.
• It’s a good idea to point out deliberate omissions of
break:
switch (grade) {
case 4: case 3: case 2: case 1:
num_passing++;
/* FALL THROUGH */
case 0: total_grades++;
break;
}
• Although the last case never needs a break statement,
including one makes it easy to add cases in the future.
57

Program: Printing a Date in Legal Form
• Contracts and other legal documents are often dated in
the following way:
Dated this __________ day of __________ , 20__ .
• The date.c program will display a date in this form
after the user enters the date in month/day/year form:
Enter date (mm/dd/yy): 7/19/14
Dated this 19th day of July, 2014.
• The program uses switch statements to add “th” (or
“st” or “nd” or “rd”) to the day, and to print the month
as a word instead of a number.
58

date.c
/* Prints a date in legal form */
#include <stdio.h>
int main(void)
{
int month, day, year;
printf("Enter date (mm/dd/yy): ");
scanf("%d /%d /%d", &month, &day, &year);
printf("Dated this %d", day);
switch (day) {
case 1: case 21: case 31:
printf("st"); break;
case 2: case 22:
printf("nd"); break;
case 3: case 23:
printf("rd"); break;
default: printf("th"); break;
}
printf(" day of ");
59

switch (month) {
case 1: printf("January"); break;
case 2: printf("February"); break;
case 3: printf("March"); break;
case 4: printf("April"); break;
case 5: printf("May"); break;
case 6: printf("June"); break;
case 7: printf("July"); break;
case 8: printf("August"); break;
case 9: printf("September"); break;
case 10: printf("October"); break;
case 11: printf("November"); break;
case 12: printf("December"); break;
}
printf(", 20%.2d.n", year);
return 0;
}
60

Exercise 1
Write a program to print the corresponding Celsius to
Fahrenheit table.
• Input:
1) the range of temperature, for example: 1 ℃ to 300
℃.
2) the step of temperature increment, for example, step
= 20 ℃.
• Output:
The corresponding Fahrenheit temperature, the value
includes 2 digits after the decimal point.

Exercise 1
• Rank the student’s score by 5 levels
>= 90 points, level A
<= 80 and < 90 points, level B
<= 70 and < 80 points, level C
<= 60 and < 70 points, level D
< 60, level E
Using if {} else {} and Switch {}, separately.

ch05.ppt

More Related Content

Similar to ch05.ppt (20)

Recently uploaded (20)

ch05.ppt