Ch19 network layer-logical add

19.1
Chapter 19
Network Layer:
Logical Addressing
Modified by Allam
AbuMwais
Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.

19.2
Introduction
 communication path through the network layer is hop-to-hop.
The packet transmitted by the sending computer may pass
through several LANs or WANs before reaching the destination
computer.
For this level of communication, we need a global addressing
scheme; we called this logical addressing IP in TCP/IP
protocol.
The Internet addresses are 32 bits in length; this gives us a
maximum of 232 addresses.
In this chapter, we will address the IPv4IPv6.

19.3
19-1 IPv4 ADDRESSES
An IPv4 address is a 32-bit address that uniquely
and universally defines the connection of a device
(for example, a computer or a router) to the Internet.
Address Space
Notations
Classful Addressing
Classless Addressing
Network Address Translation (NAT)
Topics discussed in this section:

19.4
IPv4 addresses are unique:
1. each address defines one, and only one, connection to the
Internet.
2. Two devices on the Internet can never have the same
address at the same time.
IPv4 addresses are universal:
1. the addressing system must be accepted by any host that
wants to be connected to the Internet.

19.5
The IPv4 addresses are unique
and universal.
Note
An IPv4 address is 32 bits long.
Note

19.6
The address space of IPv4 is
232 or 4,294,967,296.
Note
Address Space
A protocol such as IPv4 that defines addresses has an
address space. An address space is the total number of
addresses used by the protocol.

19.7 Figure 19.1 Dotted-decimal notation and binary notation for an IPv4 address
Notations
There are two prevalent notations to show an IPv4
address: binary notation and dotted-decimal notation.

19.8
Numbering systems are reviewed in
Appendix B.
Note

19.9
Change the following IPv4 addresses from binary
notation to dotted-decimal notation.
Example 19.1
Solution
We replace each group of 8 bits with its equivalent
decimal number (see Appendix B) and add dots for
separation.

19.10
Change the following IPv4 addresses from dotted-
decimal notation to binary notation.
Example 19.2
Solution
We replace each decimal number with its binary
equivalent (see Appendix B).

19.11
Find the error, if any, in the following IPv4 addresses.
Example 19.3
Solution
a. There must be no leading zero (045).
b. There can be no more than four numbers.
c. Each number needs to be less than or equal to 255.
d. A mixture of binary notation and dotted-decimal
notation is not allowed.

19.12
Classful Addressing
The concept of classes. This architecture is
called classful addressing.
We can find the class of an address when given
the address in binary notation or dotted-decimal
notation.

19.13
In classful addressing, the address
space is divided into five classes:
A, B, C, D, and E.
Note

19.14
Figure 19.2 Finding the classes in binary and dotted-decimal notation

19.15
Find the class of each address.
a. 00000001 00001011 00001011 11101111
b. 11000001 10000011 00011011 11111111
c. 14.23.120.8
d. 252.5.15.111
Example 19.4
Solution
a. The first bit is 0. This is a class A address.
b. The first 2 bits are 1; the third bit is 0. This is a class
C
address.
c. The first byte is 14; the class is A.
d. The first byte is 252; the class is E.

19.16
One problem with classful addressing is that each
class is divided into a fixed number of blocks with each
block having a fixed size as shown in Table.
Classes and Blocks
Table 19.1 Number of blocks and block size in classful IPv4 addressing

19.17
In classful addressing, a large part of the
available addresses were wasted.
Note

19.18
Netid and Hostid
IP address in class A, B, or C is divided into netid and
hostid. These parts are of varying lengths, depending
on the class of the address.
Table 19.2 Default masks for classful addressing

19.19
Mask
Although the length of the netid and hostid (in
bits) is predetermined in classful addressing,
we can also use a mask (also called the default
mask), a 32-bit .
Table 19.2 Default masks for classful addressing

19.20
Subnetting
During the era of classful addressing, subnetting
was introduced. If an organization was granted a
large block in class A or B, it could divide the
addresses into several contiguous groups and assign
each group to smaller networks (called subnets)

19.21
Supernetting
 …class A and class B addresses were depleted.
There was still a huge demand for midsize blocks. The
size of a class C block with a
maximum number of 256 addresses did not satisfy the
needs of most organizations.
Even a midsize organization needed more addresses. One
solution was super-netting.
Several networks are combined to create a supernetwork
or a supemet.

19.22
Classless Addressing
To overcome address depletion and give more organizations access
to the Internet, classless addressing was designed and implemented.
In this scheme, there are no classes, but the addresses are still
granted in blocks.
Restriction
1. The addresses in a block must be contiguous, one after another.
2. The number of addresses in a block must be a power of 2 (1, 2, 4, 8, .
3. The first address must be evenly divisible by the number of addresses.

19.23
Classful addressing, which is almost
obsolete, is replaced with classless
addressing.
Note

19.24
Figure 19.3 shows a block of addresses, in both binary
and dotted-decimal notation, granted to a small
business that needs 16 addresses.
We can see that the restrictions are applied to this
block. The addresses are contiguous. The number of
addresses is a power of 2 (16 = 24), and the first address
is divisible by 16. The first address, when converted to a
decimal number, is 3,440,387,360, which when divided
by 16 results in 215,024,210.
Example 19.5

19.25
Figure 19.3 A block of 16 addresses granted to a small organization

19.26
In IPv4 addressing, a block of
addresses can be defined as
x.y.z.t /n
in which x.y.z.t defines one of the
addresses and the /n defines the mask.
Note

19.27
The first address in the block can be
found by setting the rightmost
32 − n bits to 0s.
Note

19.28
A block of addresses is granted to a small organization.
We know that one of the addresses is 205.16.37.39/28.
What is the first address in the block?
Solution
The binary representation of the given address is
11001101 00010000 00100101 00100111
If we set 32−28 rightmost bits to 0, we get
11001101 00010000 00100101 0010000
or
205.16.37.32.
This is actually the block shown in Figure 19.3.
Example 19.6

19.29
The last address in the block can be
found by setting the rightmost
32 − n bits to 1s.
Note

19.30
Find the last address for the block in Example 19.6.
Solution
The binary representation of the given address is
11001101 00010000 00100101 00100111
If we set 32 − 28 rightmost bits to 1, we get
11001101 00010000 00100101 00101111
or
205.16.37.47
This is actually the block shown in Figure 19.3.
Example 19.7

19.31
The number of addresses in the block
can be found by using the formula
232−n.
Note

19.32
Find the number of addresses in Example 19.6.
Example 19.8
Solution
The value of n is 28, which means that number
of addresses is 2 32−28 or 16.

19.33
Another way to find the first address, the last address,
and the number of addresses is to represent the mask as
a 32-bit binary (or 8-digit hexadecimal) number. This is
particularly useful when we are writing a program to
find these pieces of information. In Example 19.5 the
/28 can be represented as
11111111 11111111 11111111 11110000
(twenty-eight 1s and four 0s).
Find
a. The first address
b. The last address
c. The number of addresses.
Example 19.9

19.34
Solution
a. The first address can be found by ANDing the given
addresses with the mask. ANDing here is done bit by
bit. The result of ANDing 2 bits is 1 if both bits are
1s;
the result is 0 otherwise.
Example 19.9 (continued)

19.35
b. The last address can be found by ORing the given
addresses with the complement of the mask. ORing
here is done bit by bit. The result of ORing 2 bits is 0
if
both bits are 0s; the result is 1 otherwise. The
complement of a number is found by changing each 1
to 0 and each 0 to 1.

19.36
c. The number of addresses can be found by
complementing the mask, interpreting it as a
decimal number, and adding 1 to it.

19.37
Figure 19.4 A network configuration for the block 205.16.37.32/28

19.38
The first address in a block is
normally not assigned to any device;
it is used as the network address that
represents the organization
to the rest of the world.
Note

19.39 Figure 19.5 Hierarchy in a telephone network in North America
Hierarchy

19.40
Figure 19.6 Two levels ofhierarchy in an IPv4 address
The n leftmost bits of the address x.y.z.tJn define
the network (organization network); the 32 – n
rightmost bits define the particular host
(computer or router) to the network.

19.41
Each address in the block can be
considered as a two-level
hierarchical structure:
the leftmost n bits (prefix) define
the network;
the rightmost 32 − n bits define
the host.
Note

19.42
Figure 19.8 Three-level hierarchy in an IPv4 address
An organization that is granted a large block of addresses may want
to create clusters of networks (called subnets) and divide the
addresses between the different subnets.
As an example, suppose an organization is given the block
17.12.40.0/26, which contains 64 addresses. The organization has
three offices and needs to divide the addresses into three subblocks
of 32, 16, and 16 addresses.

19.43
Figure 19.7 Configuration and addresses in a subnetted network
1. Suppose the mask for the first
subnet is n1, then 232- n1 must
be 32, which means that n1 =27.
2. Suppose the mask for the
second subnet is n2, then 232- n2
must be 16, which means that n2
= 28.
3. Suppose the mask for the
third subnet is n3, then 232- n3
must be 16, which means that n3
=28.

19.44
An ISP is granted a block of addresses starting with
190.100.0.0/16 (65,536 addresses). The ISP needs to
distribute these addresses to three groups of customers
as follows:
a. The first group has 64 customers; each needs 256
addresses.
b. The second group has 128 customers; each needs 128
addresses.
c. The third group has 128 customers; each needs 64
addresses.
Design the subblocks and find out how many addresses
are still available after these allocations.
Example 19.10

19.45
Solution
Figure 19.9 shows the situation.
Group 1
For this group, each customer needs 256 addresses. This
means that 8 (log2 256) bits are needed to define each
host. The prefix length is then 32 − 8 = 24. The
addresses are

19.46
Group 2
means that 7 (log2 128) bits are needed to define each
host. The prefix length is then 32 − 7 = 25. The
addresses are

19.47
Group 3
means that 6 (log264) bits are needed to each host. The
prefix length is then 32 − 6 = 26. The addresses are
Number of granted addresses to the ISP: 65,536
Number of allocated addresses by the ISP: 40,960
Number of available addresses: 24,576

19.48
Figure 19.9 An example of address allocation and distribution by an ISP

19.49
Network Address Translation (NAT)
The number of home users and small businesses that
want to use the Internet is ever increasing.
many have created small networks with several hosts
and need an IP address for each host. With the
shortage of addresses, this is a serious problem.
A network address translation (NAT) is quick
solution to this problem.
NAT enables a user to have a large set of addresses
internally and one address, or a small set of addresses,
externally.

19.50
Table 19.3 Addresses for private networks
Everyone knows that these reserved addresses are for
private networks. They are unique inside the
organization, but they are not unique globally.

19.51
Figure 19.10 A NAT implementation
The private network is transparent to the rest of the
Internet; the rest of the Internet sees only the NAT router
with the address 200.24.5.8.

19.52
Address Translation
Figure 19.11 Addresses in a NAT
All the outgoing packets go through the NAT router, which replaces the source
address in the packet with the global NAT address.
 All incoming packets also pass through the NAT router, which replaces the
destination address in the packet with the appropriate private address

19.53 Figure 19.12 NAT address translation
Translation Table
How does the NAT
router know the
destination address for a
packet coming from the
Internet? There may be
tens or hundreds of
private IP The problem
is solved if the NAT
router has a translation
table.

19.54
Table 19.4 Five-column translation table

19.55
Figure 19.13 An ISP and NAT

19.56
19-2 IPv6 ADDRESSES
Despite all short-term solutions, address depletion is
still a long-term problem for the Internet. This and
other problems in the IP protocol itself have been the
motivation for IPv6.
Structure
Address Space
Topics discussed in this section:

19.57
An IPv6 address is 128 bits long.
Note

19.58
Figure 19.14 IPv6 address in binary and hexadecimal colon notation

19.59
Figure 19.15 Abbreviated IPv6 addresses

19.60
Expand the address 0:15::1:12:1213 to its original.
Example 19.11
Solution
We first need to align the left side of the double colon to
the left of the original pattern and the right side of the
double colon to the right of the original pattern to find
how many 0s we need to replace the double colon.
This means that the original address is.

19.61
Table 19.5 Type prefixes for IPv6 addresses
Address Space
The designers of IPv6 divided the address into several
categories. A few leftmost bits, called the type prefix.

19.62
Table 19.5 Type prefixes for IPv6 addresses (continued)

19.63 Figure 19.16 Prefixes for provider-based unicast address
Unicast Addresses
A unicast address defines a single computer. The packet sent to a
unicast address must be delivered to that specific computer.
 With two type geographically based and provider-based.

19.64 Figure 19.16 Prefixes for provider-based unicast address
Unicast Addresses
Type identifier. This 3-bit field defines the address as a provider-base.d
address.
 Registry identifier. This 5-bit field indicates the agency that has
registered the address. Currently three registry centers have been
defined.
Provider identifier. This variable-length field identifies the provider for
Internet access (such as an ISP). 16 bit

19.65 Figure 19.17 Multicast address in IPv6
Multicast Addresses---Anycaste
Multicast addresses are used to define a group of hosts instead of
just one.

19.66
Figure 19.18 Reserved addresses in IPv6

19.67
Figure 19.19 Local addresses in IPv6
These addresses are used when an organization wants
to use IPv6 protocol without being connected to the global
Internet.
A link local address is used in an isolated subnet; a site
local address is used in an isolated site with several
subnets.

Ch19 network layer-logical add

Recommended

More Related Content

What's hot (20)

Viewers also liked (20)

Similar to Ch19 network layer-logical add (20)

More from Mohammed Romi (7)

Recently uploaded (20)

Ch19 network layer-logical add