double linked list header file code#include iostream#include.pdf
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This document contains C++ code for implementing a priority queue using a doubly linked skip list. It includes class definitions for a Node and SkipList that make up the skip list, and a PriorityQueue class that uses the skip list to store and retrieve elements based on priority. The main() function creates a PriorityQueue and SkipList, adds some sample elements, and calls the Process() method to iteratively remove and output elements by highest priority. However, the code is not fully implementing the Process() method and is not outputting the processed data as intended.
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![SkipList(int maxLevels) : MAXIMUM_ALLOWED_LEVELS(maxLevels), level(0) {
head = new Node(INT_MIN, MAXIMUM_ALLOWED_LEVELS);
tail = new Node(INT_MAX, MAXIMUM_ALLOWED_LEVELS);
for (int i = 0; i <= MAXIMUM_ALLOWED_LEVELS; i++) {
head->next[i] = tail;
tail->prev[i] = head;
}
}
int RandomLevel() {
float probability = (float)rand() / RAND_MAX;
int lvl = 0;
while (probability < 0.5 && lvl < MAXIMUM_ALLOWED_LEVELS) {
lvl++;
probability = (float)rand() / RAND_MAX;
}
return lvl;
}
Node* CreateNode(int value, int level) {
return new Node(value, level);
}
void InsertElement(int value) {
Node* current = head;
vector update(MAXIMUM_ALLOWED_LEVELS + 1, nullptr);
for (int i = level; i >= 0; i--) {
while (current->next[i]->value < value) {](https://image.slidesharecdn.com/doublelinkedlistheaderfilecodeincludeiostreaminclude-231006120015-f75c915e/85/double-linked-list-header-file-code-include-iostream-include-pdf-2-320.jpg)
![current = current->next[i];
}
update[i] = current;
}
current = current->next[0];
if (current->value != value) {
int ranLevel = RandomLevel();
if (ranLevel > level) {
for (int i = level + 1; i <= ranLevel; i++) {
update[i] = head;
}
level = ranLevel;
}
Node* n = CreateNode(value, ranLevel);
for (int i = 0; i <= ranLevel; i++) {
n->next[i] = update[i]->next[i];
n->prev[i] = update[i];
update[i]->next[i]->prev[i] = n;
update[i]->next[i] = n;
}
}
}
void Delete(int value) {
if (!Search(value)) {
cout << value << " does not exist" << endl;
return;
}
Node* current = head;
vector update(MAXIMUM_ALLOWED_LEVELS + 1, nullptr);](https://image.slidesharecdn.com/doublelinkedlistheaderfilecodeincludeiostreaminclude-231006120015-f75c915e/85/double-linked-list-header-file-code-include-iostream-include-pdf-3-320.jpg)
![for (int i = level; i >= 0; i--) {
while (current->next[i]->value < value) {
current = current->next[i];
}
update[i] = current;
}
current = current->next[0];
for (int i = 0; i <= level; i++) {
if (update[i]->next[i] == current) {
update[i]->next[i] = current->next[i];
current->next[i]->prev[i] = update[i];
}
}
delete current;
}
bool Search(int value) {
Node* current = head;
for (int i = level; i >= 0; i--) {
while (current->next[i]->value < value) {
current = current->next[i];
}
}
current = current->next[0];](https://image.slidesharecdn.com/doublelinkedlistheaderfilecodeincludeiostreaminclude-231006120015-f75c915e/85/double-linked-list-header-file-code-include-iostream-include-pdf-4-320.jpg)
![return current->value == value;
}
void Show() {
for (int i = 0; i <= level; i++) {
Node* node = head->next[i];
cout << "Level " << i << ": ";
while (node != tail) {
cout << node->value << " -> ";
node = node->next[i];
}
cout << "Tail" << endl;
}
}
void ShowBackwards() {
Node* currTail = tail;
for (int i = 0; i <= level; i++) {
Node* node = currTail->prev[i];
cout << "Level " << i << ": ";
while (node != head) {
cout << node->value << " <- ";
node = node->prev[i];
}
cout << "Head" << endl;
}
}
};
#endif
Priority Queue header file code
#ifndef PRIORITYQ_H](https://image.slidesharecdn.com/doublelinkedlistheaderfilecodeincludeiostreaminclude-231006120015-f75c915e/85/double-linked-list-header-file-code-include-iostream-include-pdf-5-320.jpg)
![tail = new Node(INT_MAX, 0);
head->next.resize(MAXIMUM_ALLOWED_LEVELS + 1, tail);
tail->prev.resize(MAXIMUM_ALLOWED_LEVELS + 1, head);
}
~PriorityQueue() {
Node* current = head;
while (current) {
Node* nextNode = current->next[0];
delete current;
current = nextNode;
}
}
void Enqueue(int data, int priority) {
Node* node = new Node(data, priority);
Node* current = head;
for (int i = MAXIMUM_ALLOWED_LEVELS; i >= 0; i--) {
while (current->next[i]->priority < priority) {
current = current->next[i];
}
}
for (int i = 0; i <= priority; i++) {
node->next[i] = current->next[i];
node->prev[i] = current;
current->next[i]->prev[i] = node;
current->next[i] = node;
}
}
int Dequeue() {
if (IsEmpty()) {
cout << "PriorityQueue is empty." << endl;
return INT_MIN; // or any other sentinel value
}](https://image.slidesharecdn.com/doublelinkedlistheaderfilecodeincludeiostreaminclude-231006120015-f75c915e/85/double-linked-list-header-file-code-include-iostream-include-pdf-7-320.jpg)
![// Find and remove the highest priority item
Node* current = head->next[MAXIMUM_ALLOWED_LEVELS];
int data = current->data;
for (int i = current->priority; i >= 0; i--) {
current->prev[i]->next[i] = current->next[i];
current->next[i]->prev[i] = current->prev[i];
delete current;
}
return data;
}
bool IsEmpty() const {
return head->next[0] == tail;
}
// Add this member function to the PriorityQueue class
vector Process(SkipList& skipList) {
vector processedData;
// Process items from highest priority to lowest
for (int priority = MAXIMUM_ALLOWED_LEVELS; priority >= 0; priority--) {
Node* current = head->next[priority];
while (current->data != INT_MAX) {
int data = current->data;
// Process the item by removing it from the SkipList
skipList.Delete(data);](https://image.slidesharecdn.com/doublelinkedlistheaderfilecodeincludeiostreaminclude-231006120015-f75c915e/85/double-linked-list-header-file-code-include-iostream-include-pdf-8-320.jpg)
![// Remove the item from the PriorityQueue
Node* temp = current;
current = current->next[priority];
for (int i = temp->priority; i >= 0; i--) {
temp->prev[i]->next[i] = temp->next[i];
temp->next[i]->prev[i] = temp->prev[i];
}
delete temp;
// Add the processed data to the result
processedData.push_back(data);
}
}
// Display the SkipList from highest level to lowest level
skipList.ShowBackwards();
return processedData;
}
};
#endif
main.cpp code file below
#include
#include
#include
#include "PriorityQ.h"
#include "doublyskiplist.h"
int main(){
srand(static_cast(time(nullptr)));
PriorityQueue queue(3);
SkipList q(3);](https://image.slidesharecdn.com/doublelinkedlistheaderfilecodeincludeiostreaminclude-231006120015-f75c915e/85/double-linked-list-header-file-code-include-iostream-include-pdf-9-320.jpg)
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Double linked list header file below for FYI#include iostream.pdf
Double linked list header file below for FYI#include iostream.pdffacevenky Double linked list header file below for FYI
#include
#include
#include
#include
#ifndef DOUBLYSKIPLIST_H
#define DOUBLYSKIPLIST_H
using namespace std;
class Node {
public:
int value;
int level;
vector next;
vector prev;
Node(int val, int lvl) : value(val), level(lvl) {
next.resize(lvl + 1, nullptr);
prev.resize(lvl + 1, nullptr);
}
};
class SkipList {
public:
int level;
Node* head;
Node* tail;
int MAXIMUM_ALLOWED_LEVELS;
SkipList(int maxLevels) : MAXIMUM_ALLOWED_LEVELS(maxLevels), level(0) {
head = new Node(INT_MIN, MAXIMUM_ALLOWED_LEVELS);
tail = new Node(INT_MAX, MAXIMUM_ALLOWED_LEVELS);
for (int i = 0; i <= MAXIMUM_ALLOWED_LEVELS; i++) {
head->next[i] = tail;
tail->prev[i] = head;
}
}
int RandomLevel() {
float probability = (float)rand() / RAND_MAX;
int lvl = 0;
while (probability < 0.5 && lvl < MAXIMUM_ALLOWED_LEVELS) {
lvl++;
probability = (float)rand() / RAND_MAX;
}
return lvl;
}
Node* CreateNode(int value, int level) {
return new Node(value, level);
}
void InsertElement(int value) {
Node* current = head;
vector update(MAXIMUM_ALLOWED_LEVELS + 1, nullptr);
for (int i = level; i >= 0; i--) {
while (current->next[i]->value < value) {
current = current->next[i];
}
update[i] = current;
}
current = current->next[0];
if (current->value != value) {
int ranLevel = RandomLevel();
if (ranLevel > level) {
for (int i = level + 1; i <= ranLevel; i++) {
update[i] = head;
}
level = ranLevel;
}
Node* n = CreateNode(value, ranLevel);
for (int i = 0; i <= ranLevel; i++) {
n->next[i] = update[i]->next[i];
n->prev[i] = update[i];
update[i]->next[i]->prev[i] = n;
update[i]->next[i] = n;
}
}
}
void Delete(int value) {
if (!Search(value)) {
cout << value << " does not exist" << endl;
return;
}
Node* current = head;
vector update(MAXIMUM_ALLOWED_LEVELS + 1, nullptr);
for (int i = level; i >= 0; i--) {
while (current->next[i]->value < value) {
current = current->next[i];
}
update[i] = current;
}
current = current->next[0];
for (int i = 0; i <= level; i++) {
if (update[i]->next[i] == current) {
update[i]->next[i] = current->next[i];
current->next[i]->prev[i] = update[i];
}
}
delete current;
}
bool Search(int value) {
Node* current = head;
for (int i = level; i >= 0; i--) {
while (current->next[i]->value < value) {
current = current->next[i];
}
}
current = current->next[0];
return current->value == value;
}
void Show() {
for (int i = 0; i <= level; i++) {
Node* node = head->next[i];
cout << "Level " << i << ": ";
while (node != tail) {
cout << node->value << " -> ";
node = node->next[i];
}
cout << "Tail" << endl;
}
}
void ShowBackwards() {
Node* currTail = tail;
for (int i = 0; i <= level; i++) {
Node* node = currTail->prev[i];
cout << "Level " << i << ": ";
while (node != head) {
cout << node->value << " <- ";
node = node->prev[i];
}
cout << "Head" << endl;
}
}
};
#endif
PriorityQueue header file code below
#ifndef PRIORITYQ_H
#define PRIORITYQ_H
#include
#include
#include // for INT_MAX
#include // for rand()
#include
using namespace std;
class Node {
public:
.
double Skiplist code below#include iostream#include vector.pdf
double Skiplist code below#include iostream#include vector.pdftxkev double Skiplist code below
#include
#include
#include
#include
#include
#include
#include "Node.h"
#ifndef SKIPLIST_H
#define SKIPLIST_H
using namespace std;
class SkipList{
public:
// Maximum number of levels allowed for this skip list
int MAXIMUM_ALLOWED_LEVELS;
// current maximum level amongst the inserted nodes
int level;
// the head node's next links are connected to the first node at every level
Node *head;
SkipList(int maxLevels){
MAXIMUM_ALLOWED_LEVELS = maxLevels;
// initially we have the bottom-most level only
level = 0;
// create the header node, value is irrelevant (as long as it doesn't match an inserted value -
NO REPEATS), number of next links is important (this node is connected to the first node at
every level)
head = new Node(INT_MIN, MAXIMUM_ALLOWED_LEVELS);
}
int RandomLevel(){
float probablity = (float)rand()/RAND_MAX; // flip a coin
int lvl = 0;
/*Olog(n) */while (probablity < 0.5 && lvl < MAXIMUM_ALLOWED_LEVELS){
lvl++; // landed heads so increase level by 1
probablity = (float)rand()/RAND_MAX; // flip a coin again
}
return lvl;
}
Node* CreateNode(int value, int level){
// create a new node with next links for every level that this node will be part of
// it will use these links to connect to the next node at each level
return new Node(value, level);
}
void InsertElement(int value)/*Olog(n) becuase all the functions in it are Olog(n) */{
/**
* THIS CODE HAS A BUG,
*
* ***********FIND THE BUG,
* *************EXPLAIN THE WHY THE BUG EXIST
* AND
* **********************SUGGEST A FIX *
*
*/
//w
Node *current = head; // start at head node at the toppest level
/*Olog(n)*/vector update(MAXIMUM_ALLOWED_LEVELS+1, nullptr); // this will hold
the nodes that need updating at every level after the insert takes place
/*BIG Olog(n)*/for (int i = level; i >= 0; i--){ //level is the current maximum level
// for level i, if value is to be inserted here then find out where (i.e. after which node)
/*O(1) constant */ while (current->next[i] != nullptr && current->next[i]->value <
value){ //the while loop is saying keep moving right until null or the current.value > value
current = current->next[i];
}
// found the node after which the value is to be placed at level i
update[i] = current;
}
//if
current = current->next[0]; // current moves bcoz we need to check if the value exists
if (current == nullptr || current->value != value){
/*Olog(n) */int ranLevel = RandomLevel(); // choose a random level upto where the new
node will be placed
if (ranLevel > level){
// if random level for current node is higher than the current maximum level for the
existing nodes then set updates for each level over current maximum to head (since there are no
nodes at these levels yet).
/*Olog(n)*/for (int i=level+1;i<=ranLevel;i++){
update[i] = head;
}
// also change the current maximum level for the existing nodes
level = ranLevel;
}
// create new node with next links for every level from ranLevel to zero
/*Olog(n) */Node* n = CreateNode(value, ranLevel);
// placi.
Node file code below#ifndef NODE_H#define NODE_H#include .pdf
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#ifndef NODE_H
#define NODE_H
#include
using namespace std;
// the node
class Node{
public:
int value;
// Array of pointers to the next nodes (which may be located at various levels)
// next[i] is the next link for level i
// the size of this vector determines the number of levels that the current node is part of
vector next;
vector prev; // previous links for each level the node is part of
Node(int val, int level){
value = val;
next = vector(level+1, nullptr); // initialize array of pointers to nulls
prev = vector(level+1, nullptr); // initialize array of pointers to nulls
};
};
#endif
SKIPLIST.H FILE CODE BELOW
#include
#include
#include
#include
#include
#include
#include "Node.h"
#ifndef SKIPLIST_H
#define SKIPLIST_H
using namespace std;
class SkipList{
public:
// Maximum allowed level index
int MAXIMUM_ALLOWED_LEVEL_INDEX;
// current maximum level amongst the inserted nodes
int currentHighestLevelIndex;
// the head node's next links are connected to the first node at every level
Node *head;
Node* tail; // last node at every level
SkipList(int maxLevels){
MAXIMUM_ALLOWED_LEVEL_INDEX = maxLevels;
// initially we have the bottom-most level only
currentHighestLevelIndex = 0;
// create the header node, value is irrelevant (as long as it doesn't match an inserted value -
NO REPEATS), number of next links is important (initially this node is the first node at every
level)
head = new Node(INT_MIN, MAXIMUM_ALLOWED_LEVEL_INDEX);
tail = new Node(INT_MAX, MAXIMUM_ALLOWED_LEVEL_INDEX); // last nodes at
each level
// connect head to tail at every level
for(int i = 0; i <= MAXIMUM_ALLOWED_LEVEL_INDEX; i++){
head->next[i] = tail; // head's prev is null
tail->prev[i] = head; // tail's next is null
}
}
int RandomLevel(){
float probablity = (float)rand()/RAND_MAX; // flip a coin
int lvl = 0;
while (probablity < 0.5 && lvl < MAXIMUM_ALLOWED_LEVEL_INDEX){
lvl++; // landed heads so increase level by 1
probablity = (float)rand()/RAND_MAX; // flip a coin again
}
return lvl;
}
Node* CreateNode(int value, int level){
// create a new node with next links for every level that this node will be part of
// it will use these links to connect to the next node at each level
return new Node(value, level);
}
void InsertElement(int value){
Node *current = head; // start at head node
vector update(MAXIMUM_ALLOWED_LEVEL_INDEX+1, nullptr); // this will hold the
nodes that need updating at every level after the insert takes place
for (int i = currentHighestLevelIndex; i >= 0; i--){ // start at the highest level and move
down so that more nodes may be skipped
// for level i, if value is to be inserted here then find out where (i.e. after which node)
while (current->next[i] != nullptr && current->next[i]->value < value){
current = current->next[i];
}
// found the node after which the value is to be placed at level i
update[i] = current;
// move down a level, if possible
}
// at level 0, where current is pointing to by the end of the preceding loop, move over.
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- When finding the insertion point, you need to traverse all levels from MAXIMUM_ALLOWED_LEVELS down to 0, not just level 0.
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Recursive Linked List Operations
Write a C++ to manage a list of string elements. Besides the basic operations expected of a
linked list (add an element, remove an element, check for empty list, report size (number) of
elements in the list, and print out the content of the list), the linked list class also needs to have a
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implement the sort and reverse operations
Solution
#include
#include
#include
#include
struct node //declaring node
{
int info;
struct node *next;
}*start;
class single_llist //declaring class
{
public:
node* create_node(int);
void insert_begin();
void insert_pos();
void insert_last();
void delete_pos();
void sort();
void reverse();
void display();
single_llist()
{
start = NULL;
}
};
main()
{
int choice, nodes, position, i;
char str[100];
single_llist sl;
start = NULL;
while (1)
{
cout<>choice;
switch(choice)
{
case 1:
cout<<\"Inserting Node at Beginning: \"<info = value;
temp->next = NULL;
return temp;
}
}
/*
* Inserting element in beginning
*/
void single_llist::insert_begin()
{
int value;
cout<<\"Enter the value to be inserted: \";
cin>>value;
struct node *temp, *p;
temp = create_node(value);
if (start == NULL)
{
start = temp;
start->next = NULL;
}
else
{
p = start;
start = temp;
start->next = p;
}
cout<<\"Element Inserted at beginning\"<>value;
struct node *temp, *s;
temp = create_node(value);
s = start;
while (s->next != NULL)
{
s = s->next;
}
temp->next = NULL;
s->next = temp;
cout<<\"Element Inserted at last\"<>value;
struct node *temp, *s, *ptr;
temp = create_node(value);
cout<<\"Enter the postion at which node to be inserted: \";
cin>>pos;
int i;
s = start;
while (s != NULL)
{
s = s->next;
counter++;
}
if (pos == 1)
{
if (start == NULL)
{
start = temp;
start->next = NULL;
}
else
{
ptr = start;
start = temp;
start->next = ptr;
}
}
else if (pos > 1 && pos <= counter)
{
s = start;
for (i = 1; i < pos; i++)
{
ptr = s;
s = s->next;
}
ptr->next = temp;
temp->next = s;
}
else
{
cout<<\"Positon out of range\"<next;s !=NULL;s = s->next)
{
if (strcmp(ptr->info > s->info))
{
value = ptr->info;
ptr->info = s->info;
s->info = value;
}
}
ptr = ptr->next;
}
}
void single_llist::delete_pos() //delete element from given position
{
int pos, i, counter = 0;
if (start == NULL)
{
cout<<\"List is empty\"<>pos;
struct node *s, *ptr;
s = start;
if (pos == 1)
{
start = s->next;
}
else
{
while (s != NULL)
{
s = s->next;
counter++;
}
if (pos > 0 && pos <= counter)
{
s = start;
for (i = 1;i < pos;i++)
{
ptr = s;
s = s->next;
}
ptr->next = s->next;
}
else
{
cout<<\"Position out of range\"<next == NULL)
{
return;
}
ptr1 = start;
ptr2 = ptr1->next;
ptr3 = ptr2->next;
ptr1->next = NULL;
ptr2->next = ptr1;
while (ptr3 != NULL)
{
ptr1 = ptr2;
ptr2.
implement the ListLinked ADT (the declaration is given in ListLinked.pdf
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exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the
number is removed from the list and true is returned. Uncomment the commented-out part in
main() that reads a second input line and removes numbers from the list. Test in develop mode to
ensure that insertion and removal both work properly, then submit code for grading. Ex: If input
is 84 72 19 61 19 84 then output is: List after inserting 84: 84 List after inserting 72: 72 84 List
after inserting 19: 19 72 84 List after inserting 61: 19 61 72 84 List after removing 19: 61 72 84
List after removing 84: 61 72
main.cpp
#include
#include
#include
#include "Node.h"
#include "SortedNumberList.h"
using namespace std; void PrintList(SortedNumberList& list); vector SpaceSplit(string source);
int main(int argc, char *argv[]) { // Read the line of input numbers string inputLine; getline(cin,
inputLine); // Split on space character vector terms = SpaceSplit(inputLine); // Insert each value
and show the sorted list's contents after each insertion SortedNumberList list; for (auto term :
terms) { double number = stod(term); cout << "List after inserting " << number << ": " << endl;
list.Insert(number); PrintList(list); } /* // Read the input line with numbers to remove getline(cin,
inputLi.
Help I keep getting the same error when running a code. Below is the.pdf
Help I keep getting the same error when running a code. Below is the.pdfmail931892 Help I keep getting the same error when running a code. Below is the code and the instructions
about the code.
import java.util.Arrays;
public class Album implements Comparable {
private final int id;
private final String[] artists;
private final int numSongs;
public Album(int id, String title, String[] artists, int numSongs) {
this.id = id;
this.artists = new String[]{Arrays.toString(artists)};
this.numSongs = numSongs;
}
public int getId() {
return id;
}
@Override
public int compareTo(Album other) {
return Integer.compare(this.numSongs, other.numSongs);
}
@Override
public String toString() {
StringBuilder artistNames = new StringBuilder();
for (String artist : artists) {
artistNames.append(artist).append(", ");
}
artistNames.delete(artistNames.length() - 2, artistNames.length());
return "ID: " + id + " -- " + numSongs + " songs -- [" + artistNames + "]";
}
}
import java.util.Random;
public class DoublyLinkedList {
private static class Node {
T data;
Node prev;
Node next;
Node(T data) {
this.data = data;
}
}
private Node head;
private Node tail;
private int size;
public DoublyLinkedList() {
head = null;
tail = null;
size = 0;
}
public Node append(T data) {
Node newNode = new Node<>(data);
if (head == null) {
head = newNode;
} else {
tail.next = newNode;
newNode.prev = tail;
}
tail = newNode;
size++;
return newNode;
}
public Node insert(int location, T data) {
if (location < 0 || location > size) {
throw new IllegalArgumentException("Invalid location");
}
Node newNode = new Node<>(data);
if (location == 0) {
newNode.next = head;
if (head != null) {
head.prev = newNode;
}
head = newNode;
if (tail == null) {
tail = newNode;
}
} else if (location == size) {
tail.next = newNode;
newNode.prev = tail;
tail = newNode;
} else {
Node current = head;
for (int i = 0; i < location; i++) {
current = current.next;
}
newNode.prev = current.prev;
newNode.next = current;
current.prev.next = newNode;
current.prev = newNode;
}
size++;
return newNode;
}
public Node delete(int location) {
if (location < 0 || location >= size) {
throw new IllegalArgumentException("Invalid location");
}
Node deletedNode;
if (location == 0) {
deletedNode = head;
head = head.next;
if (head != null) {
head.prev = null;
} else {
tail = null;
}
} else if (location == size - 1) {
deletedNode = tail;
tail = tail.prev;
tail.next = null;
} else {
Node current = head;
for (int i = 0; i < location; i++) {
current = current.next;
}
deletedNode = current;
current.prev.next = current.next;
current.next.prev = current.prev;
}
size--;
return deletedNode;
}
public int getIndex(T data) {
Node current = head;
for (int i = 0; i < size; i++) {
if (current.data.equals(data)) {
return i;
}
current = current.next;
}
return -1;
}
@Override
public String toString() {
StringBuilder result = new StringBuilder();
Node current = head;
while (current != null) {
result.append(current.data).append(" -> ");
current = current.next;
}
result.append("NULL");
return result.toString();
}
public Node shuffle() {
Random r.
Linkedlist
LinkedlistMasud Parvaze Linked lists are a data structure where each node contains a pointer to the next node in the list. Each node contains data and a pointer to the next node. The last node's pointer is set to NULL. Linked lists can dynamically grow and shrink during program execution. Nodes are implemented as structs containing data and a pointer. The head pointer points to the first node. Linked lists allow traversing the list by following node pointers until NULL is reached.
Ds 2 cycle
Ds 2 cycleChaitanya Kn The document discusses the implementation of a binary search tree (BST) using both recursive and non-recursive traversal methods. It defines a BST node structure with left and right child pointers. Functions are included to insert nodes, perform inorder, preorder and postorder traversals recursively and non-recursively using stacks. Main inserts sample nodes into the tree and calls the various traversal functions to output the node values in the specified orders.
#ifndef LINKED_LIST_ #define LINKED_LIST_ templateclass It.pdf
#ifndef LINKED_LIST_ #define LINKED_LIST_ templateclass It.pdfangelsfashion1 #ifndef LINKED_LIST_
#define LINKED_LIST_
template
class LinkedList {
private:
std::shared_ptr> headPtr; // Pointer to first node in the chain;
// (contains the first entry in the list)
int itemCount; // Current count of list items
std::shared_ptr> getNodeAt(int position) const;
public:
LinkedList();
LinkedList(const LinkedList& aList);
virtual ~LinkedList();
bool isEmpty() const;
int getLength() const;
bool insert(int newPosition, const ItemType& newEntry);
bool remove(int position);
void clear();
/** throw PrecondViolatedExcept if position < 1 or
position > getLength(). */
ItemType getEntry(int position) const throw(PrecondViolatedExcept);
/** throw PrecondViolatedExcept if position < 1 or
position > getLength(). */
void replace(int position, const ItemType& newEntry)
throw(PrecondViolatedExcept);
// Operator Overloading
void operator = (const LinkedList& arg);
friend std::ostream& operator << (std::ostream& os, const LinkedList& arg)
{
os << \"There are \" << arg.getLength() << \" values in the list:\" << std::endl;
for (int i{ 1 }; i <= arg.getLength(); i++) {
os << arg.getEntry(i) << std::endl;
}
os << std::endl << std::endl << std::endl << std::endl;
return os;
}
};
// Returns a pointer to the Node at the given position.
template
std::shared_ptr> LinkedList::getNodeAt (int position) const {
std::shared_ptr> currPtr{ headPtr };
for (int i{ 1 }; i < position; i++)
currPtr = currPtr->getNext();
return currPtr;
}
// Default constructor.
template
LinkedList::LinkedList() {
headPtr = nullptr;
itemCount = 0;
}
// Copy constructor.
template
LinkedList::LinkedList(const LinkedList& aList) {
itemCount = aList.getLength();
auto currPtr{ aList.headPtr };
auto newNodePtr{ headPtr = std::make_shared>(currPtr->getItem()) };
auto prevNodePtr{ newNodePtr };
currPtr = currPtr->getNext();
for (int i{ 2 }; i <= itemCount; i++) {
newNodePtr = std::make_shared>(currPtr->getItem());
prevNodePtr->setNext(newNodePtr);
prevNodePtr = newNodePtr;
currPtr = currPtr->getNext();
}
}
// Destructor.
template
LinkedList::~LinkedList() {
headPtr = nullptr;
itemCount = 0;
}
// Accessor/Info Functions.
template
bool LinkedList::isEmpty() const {
return (itemCount > 0)?0:1;
}
template
int LinkedList::getLength() const {
return itemCount;
}
// Places a Node at a given position (element at the same position is now pos+1).
template
bool LinkedList::insert(const int newPosition,
const ItemType& newEntry)
{
bool ableToInsert{ (newPosition >= 1) &&
(newPosition <= itemCount + 1) };
if (ableToInsert)
{
// Create a new node containing the new entry
auto newNodePtr{ std::make_shared>(newEntry) };
// Attach new node to chain
if (newPosition == 1)
{
// Insert new node at beginning of chain
newNodePtr->setNext(headPtr);
headPtr = newNodePtr;
}
else
{
// Find node that will be before new node
auto prevPtr{ getNodeAt(newPosition - 1) };
// Insert new node after node to which prevPtr points
newNodePtr->setNext(prevPtr->getNext());
prevPtr->setNext(newNodePtr);
} // end if
itemCount++; // .
#includeiostream #includecstdio #includecstdlib using na.pdf
#includeiostream #includecstdio #includecstdlib using na.pdfharihelectronicspune #include
#include
#include
using namespace std;
struct node
{
int val;
struct node *next;
}*startNode;
// declaring class
class LinkedList
{
public:
node* create_node(int);
void insert_last();
void sort();
void search();
void reverse();
void display();
LinkedList()
{
startNode = NULL;
}
};
// main
main()
{
int userChoice, linkedListNodes, i;
LinkedList LinkList;
startNode = NULL;
while (1)
{
// displaying menu
cout<<\" 1)Insert\";
cout<<\"2) Remove\";
cout<<\"3) Search\";
cout<<\"4) Display\";
cout<<\"5) Reverse\";
cout<<\"6) Exit \";
// reading user choice
cout<<\"Enter your userChoice : \";
cin>>userChoice;
switch(userChoice)
{
case 1:
cout<<\"Inserting node to linked list: \";
LinkList.insert_begin();
cout;
break;
case 2:
cout<<\"Delete element from linked list: \";
LinkList.delete();
break;
case 3:
cout<<\"Searching data in linked list: \";
LinkList.search();
cout;
break;
case 4:
cout<<\"Displaying linked list data: \";
LinkList.display();
cout;
break;
case 5:
cout<<\"Linked list reversing: \";
LinkList.reverse();
cout;
break;
case 6:
cout<<\"Exiting...\";
exit(1);
break;
default:
cout<<\"Enter correct userChoice\";
}
}
}
// node creating to store into list
node *LinkedList::create_node(int val)
{
struct node *tempNode, *tempNode;
tempNode = new(struct node);
if (tempNode == NULL)
{
cout<<\"No memory allocated \";
return 0;
}
else
{
tempNode->val = val;
tempNode->next = NULL;
return tempNode;
}
}
/*
* Inserting Node at last
*/
void LinkedList::insert_last()
{
int val;
cout<<\"Enter the val to be inserted: \";
cin>>val;
struct node *tempNode, *tempNode;
tempNode = create_node(val);
tempNode = startNode;
while (tempNode->next != NULL)
{
tempNode = tempNode->next;
}
tempNode->next = NULL;
tempNode->next = tempNode;
cout<<\"Element Inserted\";
}
// deleting element
void LinkedList::delete()
{
int position, i, count = 0;
if (startNode == NULL)
{
cout<<\"Linkedlist empty\"<>position;
struct node *tempNode, *ptr;
tempNode = startNode;
if (position == 1)
{
startNode = tempNode->next;
}
else
{
while (tempNode != NULL)
{
tempNode = tempNode->next;
count++;
}
if (position > 0 && position <= count)
{
tempNode = startNode;
for (i = 1;i < position;i++)
{
ptr = tempNode;
tempNode = tempNode->next;
}
ptr->next = tempNode->next;
}
else
{
cout<<\"Enter correct position\";
}
}
}
// search data in linked list
void LinkedList::search()
{
int val, position = 0;
bool flagValue = false;
if (startNode == NULL)
{
cout<<\"List is empty\";
return;
}
cout<<\"Enter the val to search: \";
cin>>val;
struct node *tempNode;
tempNode = startNode;
while (tempNode != NULL)
{
position++;
if (tempNode->val == val)
{
flagValue = true;
cout<<\"Data \"<next;
}
if (!flagValue)
cout<<\"data not found\";
}
// linkedlist reverese
void LinkedList::reverse()
{
struct node *pointer1, *pointer2, *pointer3;
if (startNode == NULL)
{
cout<<\"List is empty\"<next == NULL)
{
return;
}
pointer1 = startNode;
pointer2 = pointer1->next;
pointer3 = pointer2->next;
pointer1->next = NULL;
pointer2->.
Lecture 4 data structures and algorithms
Lecture 4 data structures and algorithmsAakash deep Singhal The document discusses linked lists as an alternative to arrays for storing data. It provides 3 key points:
1. Linked lists store data in nodes that are linked together using pointers, rather than in a fixed contiguous block of memory like arrays. Each node contains a data field and a pointer to the next node.
2. Common linked list operations like insertion, deletion, and searching have time complexities of O(1) or O(n) depending on the position in the list, which can be more efficient than arrays that require shifting elements.
3. The document presents a simple C++ implementation of a linked list using Node and List classes to demonstrate how to implement basic linked list functions like insertion, deletion
In the class we extensively discussed a node class called IntNode in.pdf
In the class we extensively discussed a node class called IntNode in.pdfarjunstores123 In the class we extensively discussed a node class called IntNode in which each linked list node
contains an integer and each node is linked forward to the next element in the list. Implement a
node class called DoublyIntNode in which each node contains an integer number and each node
is linked not only forward to the next element in the list but also backward to the previous
element in the list. Your implementation of DoublyIntNode should adapt and implement all the
methods of IntNode including the following methods:
Constructor for DoublyIntNode
addNodeAfter, removeNodeAfter
getData, setData
getForeLink, setForeLink
getBackLink, setBackLink
listCopy
listCopyWithTail
listLength
listPart
listPosition
listSearch
IntNode and Node classes:
public class IntNode{
private int data;
private IntNode link;
// methods here
}
public class Node {
private E data;
private Node link;
// methods here
}
Solution
program
#include
using namespace std;
struct list
{
struct list *prev;
int data;
struct list *next;
}
*node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL;
class Dlist
{
public:
void insert_beg() {
list *addBeg = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addBeg->data;
if(first == NULL) {
addBeg->prev = NULL;
addBeg->next = NULL;
first = addBeg;
last = addBeg;
cout << \"Linked list Created!\" << endl;
}
else {
addBeg->prev = NULL;
first->prev = addBeg;
addBeg->next = first;
first = addBeg;
cout << \"Data Inserted at the beginning of the Linked list!\" << endl;
}
}
void insert_end() {
list *addEnd = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addEnd->data;
if(first == NULL) {
addEnd->prev = NULL;
addEnd->next = NULL;
first = addEnd;
last = addEnd;
cout << \"Linked list Created!\" << endl;
}
else {
addEnd->next = NULL;
last->next = addEnd;
addEnd->prev = last;
last = addEnd;
cout << \"Data Inserted at the end of the Linked list!\" << endl;
}
}
void display() {
node = first;
cout << \"List of data in Linked list in Ascending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->next;
}
node = last;
cout << \"List of data in Linked list in Descending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->prev;
}
}
void del()
{
int count = 0, number, i;
node = node1 = node2 = first;
for(node = first; node != NULL; node = node->next)
cout << \"Enter value for the node:\" << endl;
count++;
display();
cout << count << \" nodes available here!\" << endl;
cout << \"Enter the node number which you want to delete:\" << endl;
cin >> number;
if(number != 1)
{
if(number < count && number > 0)
{
for(i = 2; i <= number; i++)
node = node->next;
for(i = 2; i <= number-1; i++)
node1 = node1->next;
for(i = 2; i <= number+1; i++)
node2 = node2->next;
node2->prev = node1;
node1->next = node2;
node->prev = NULL;
node->next = NULL;
node = NULL;
}
else if(number == count)
{
node = last;
last = node->prev;
last->next = NULL;
node = NULL;
}
else
cout << \"Invalid node.
ISCP internal.pdf
ISCP internal.pdfGANDHAMKUMAR2 The document contains code for multiple programming problems across different sets. The first problem in Set 1 (Program 1) deals with checking if the sums of three stacks are equal. It takes three stacks as input, calculates their sums by traversing them in reverse order and pushing elements to additional stacks, and returns the common sum if the sums are equal at any point as the stacks are traversed. The second problem (Program 2) checks if a binary tree is complete by doing a level order traversal using a queue - it returns false if any null child node is encountered when a non-null node is still in the queue.
Please refer this solution. This is working file for IntegersHeade.pdf
Please refer this solution. This is working file for IntegersHeade.pdfsooryasalini Please refer this solution. This is working file for Integers
Header file :-
-----------------------------------
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
struct node{
void * data;
node * next;
};
class LinkedList
{
private:
node* head ;
int size;
public:
LinkedList();
//method to create a node
node * create(void* data);
//method to append
void append(node * item);
//method to prepend
void prepend(node * item);
//insert in ascending order
void insertAscend(node * item);
//insert in ascending order
void insertDescend(node * item);
//display all nodes
void display();
//free the list
void freeUp();
};
#endif // LINKEDLIST_H
Source file :-
----------------------------------
#include \"linkedlist.h\"
#include
#include
#include
LinkedList::LinkedList()
{
//head = (node *)malloc(sizeof(node));
size = 0;
head = NULL;
}
//method to create a node
node * LinkedList::create(void* data){
node * newNode = (node *)malloc(sizeof(node));
newNode->data = malloc(sizeof(data));
memcpy(newNode->data,data,sizeof(data));
newNode->next = NULL;
return newNode;
}
//method to append
void LinkedList::append(node * item){
if(head == NULL){
head = item;
size++;
return;
}
node* current;
current = head;
while (current->next!=NULL )
{
current = current->next;
}
current->next = item ;
size++;
}
//method to prepend
void LinkedList::prepend(node * item){
if(head == NULL){
head = item;
size++;
return;
}
item->next = head;
head = item;
size++;
}
//insert in ascending order
void LinkedList::insertAscend(node * item){
if(head == NULL){
head = item;
size++;
return;
}
node* current;
current = head;
node * prev = NULL;
bool found = false;
while (current !=NULL){
int *current_data = static_cast(current->data);
int *item_data = static_cast(item->data);
if(*item_data < *current_data){
if(prev == NULL){
item->next = current;
if(current == head){
head = item;
}
}
else{
prev->next = item;
item->next = current;
}
found = true;
break;
}
prev = current;
current = current->next;
}
if(!found){
prev->next = item;
}
size++;
}
//insert in Descending order
void LinkedList::insertDescend(node * item){
if(head == NULL){
head = item;
size++;
return;
}
node* current;
current = head;
node * prev = NULL;
bool found = false;
while (current !=NULL){
int *current_data = static_cast(current->data);
int *item_data = static_cast(item->data);
if(*item_data > *current_data){
if(prev == NULL){
item->next = current;
if(current == head){
head = item;
}
}
else{
prev->next = item;
item->next = current;
}
found = true;
break;
}
prev = current;
current = current->next;
}
if(!found){
prev->next = item;
}
size++;
}
//display all nodes
void LinkedList::display(){
int idx = 0;
node* current;
current = head;
while (current != NULL ){
idx++;
int *data = static_cast(current->data);
printf(\"data for item ::%dis :: %d\ \",idx,*data);
current = current->next;
}
}
//free the list
void LinkedList::freeUp(){
node* current;
current = head;
while (current->next!=NULL ){
head = current->next;
delete current;
current = head;
}
}
Main f.
Revisiting a data structures in detail with linked list stack and queue
Revisiting a data structures in detail with linked list stack and queuessuser7319f8 This document discusses various data structures including arrays, stacks, queues, and linked lists. It provides code examples for creating and manipulating each type of data structure. Specifically, it shows code for inserting and deleting elements from arrays and linked lists. It also includes algorithms and code for common stack and queue operations like push, pop, enqueue, and dequeue. The document provides a detailed overview of linear and non-linear data structures.
Given the following codepackage data1;import java.util.;p.pdf
Given the following codepackage data1;import java.util.;p.pdfillyasraja7 Given the following code
package data1;
import java.util.*;
/*public class BST> implementing a set ADT and containing the following:
* private inner class BinaryNode representing a node with a (possibly) left child and a (possibly)
right child
** instance fields BinaryNode root, int size
* contains/insert/remove method - w/ O(height) complexity
** size O(1), isEmpty O(1), clear O(1),
*** findMin, findMax, findHeight methods - w/ O(height) complexity
**** toString() method printing set (in-order traversal) and the tree (BFS traversal)
**
*/
publicclass BST> {
private BinaryNode root;
privateint size;
//Search opertion of Set ADT
publicboolean contains(E value) {
return contains(root, value);
}
//Insert opertion of Set ADT
publicvoid insert(E value) {
root = insert(root, value);
size++;
}
//Remove operation of Set ADT
publicvoid remove(E value){
root = remove(root, value);
size--;
}
publicint size(){
return size;
}
publicboolean isEmpty(){
return root == null;
}
publicvoid clear(){
root = null;
size = 0;
}
public E findMin(){
return findMin(root);
}
public E findMax(){
return findMax(root);
}
publicint findHeight(){
return root.height();
}
public String toString(){
if(root == null)
return "set {} stored in an empty tree.\n";
String elements = root.inOrder().toString();
return "set {" + elements.substring(1,elements.length()-1) + "} stored in tree \n" + root;
}
private E findMin(BinaryNode node){
if(node == null)
returnnull;
if(node.left == null)
return node.element;
return findMin(node.left);
}
private E findMax(BinaryNode node){
if(node == null)
returnnull;
if(node.right == null)
return node.element;
return findMax(node.right);
}
privateboolean contains(BinaryNode node, E value) {
if (node == null)//node represents an empty substree
returnfalse;
int comparisonResult = value.compareTo(node.element);
if(comparisonResult < 0)//if value is less than root's value
return contains(node.left, value);
if(comparisonResult > 0)//if value is greater than root's value
return contains(node.right, value);
returntrue;//successful search
}
private BinaryNode insert(BinaryNode node, E value) {
if (node == null)//base case: empty tree
returnnew BinaryNode<>(value);
if (value.compareTo(node.element) < 0)
node.left = insert(node.left, value);//insert recursively to left-subtree
elseif (value.compareTo(node.element) > 0)
node.right = insert(node.right, value);//insert recursively to right-subtree
else {//duplicate value cannot be inserted in a BST implementing the Set ADT
size--;//insertion failed!
//System.out.print("BST.insert: Warning: " + value + " is already stored in the tree \n" + node);
}
return node;
}
private BinaryNode remove(BinaryNode node, E value) {
if (node == null) {//base case: empty tree
System.out.println("BST.remove: Warning: " + value + " doesn't exist in the tree.");
size++;//removal failed!
return node;
}
if (value.compareTo(node.element) < 0)
node.left = remove(node.left, value);
elseif (value.compareTo(node.element) > 0)
node.right = remov.
17 linkedlist (1)
17 linkedlist (1)Himadri Sen Gupta This document discusses linked lists and their implementation in C. It begins by describing the differences between array-based and linked list implementations. Specifically, it notes that linked lists use dynamic memory allocation and pointers to connect nodes rather than contiguous memory blocks. The document then covers creating and traversing linked lists using nodes with data fields and next pointers. It provides code examples for inserting, finding, deleting and destroying nodes in a singly linked list. Finally, it briefly lists some other common linked list operations like sorting, reversing and finding min/max elements.
#include stdafx.h #include iostream using namespace std;vo.docx
#include stdafx.h #include iostream using namespace std;vo.docxajoy21 This document contains C++ code to implement a linked list program that performs the following tasks:
1. Inputs 10 integers into a linked list while sorting them as they are inserted
2. Prints the sorted list and computes the average of the values
3. Deletes nodes from the list with values less than the average
4. Creates a second list of 10 sorted integers
5. Merges the two lists together, eliminating duplicates, and prints the final list
Doublylinklist
Doublylinklistritu1806 This document presents information on doubly linked lists including their representation, initialization, node creation, and various operations like insertion, deletion, and traversal. It discusses inserting and deleting nodes at the beginning or end of the list, as well as inserting before or after a specified node. Code examples are provided for initializing a doubly linked list and performing each operation.
Write a Java Class to Implement a Generic Linked ListYour list mus.pdf
Write a Java Class to Implement a Generic Linked ListYour list mus.pdfrozakashif85 Write a Java Class to Implement a Generic Linked List
Your list must be implemented as a singly-linked list of generic nodes, where each Node object
has two instance variables: an object of the “type variable” class, and a pointer to the next node
on the list.
Your class will contain separate methods to handle each of the operations read from a data file
(see II., below)
Your class will also override toString() to return the objects on the list in the order in which they
occur.
Write a Test Class for Your LinkedList Class
Your main method will read list operation instructions from a data file, until end-of-file and call
the appropriate LinkedList method to execute each one.
After each operation is executed, print out the operation and the updated list.
The data file to be used is on the class web site and the operations are:
APPEND X - Append object X to the end of the list
ADD N X - Insert object X as the new Nth element in the list, increasing the size of the list by 1
E.g. Suppose the list is:
head -> 1 -> 2 -> 3 -> 4->null
After ADD 3 7 it would be:
head -> 1 -> 2 -> 7 -> 3 -> 4->null
DELETE N – Remove the Nth object from the list
SWAP M N - Interchange the positions of the Mth and Nth
objects on the list
For credit, the two nodes must actually \"trade places\" in the list, and not merely swap their data
values
REVERSE - Reverse the order of the objects on the list
This must be done by reversing the order of the nodes themselves, rather than by swapping the
data stored
To get credit for your reverse() method, it must use either one of these 2 algorithms:
For each node on the list except the current “head”
node, delete the node and insert it as the new head
Use your swap() method
6. CLEAR – Clear the list (make it empty)
No credit will be given for programs that use any additional data structures – either from the Java
API or programmer defined -, other than your own LinkedList class
txt file:
Solution
//Java Program to Implement Singly Linked List
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
/* Class Node */
class Nodes
{
protected Object data;
protected Nodes next;
/* Constructor */
public Nodes()
{
next = null;
data = null;
}
/* Constructor */
public Nodes(Object d,Nodes n)
{
data = d;
next = n;
}
/* Function to set link to next Node */
public void setLink(Nodes n)
{
next = n;
}
/* Function to set data to current Node */
public void setData(Object d)
{
data = d;
}
/* Function to get link to next node */
public Nodes getLink()
{
return next;
}
/* Function to get data from current Node */
public Object getData()
{
return data;
}
}
/* Class linkedList */
class linkList
{
protected Nodes start;
protected Nodes end ;
public int size ;
/* Constructor */
public linkList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isEmpty()
{
return start == null;
}
/* Function to get size of list */
public int getSize()
{
return .
Implement of c & its coding programming by sarmad baloch
Implement of c & its coding programming by sarmad balochSarmad Baloch The C program implements a singly linked list with functions to insert and delete nodes, print the list, find a node by key, sort the list by data, and reverse the list. It demonstrates using the functions to create a list, delete all nodes, find and delete a node, sort the list, and reverse it, printing the list after each operation.
Data Structures and Agorithm: DS 05 Doubly Linked List.pptx
Data Structures and Agorithm: DS 05 Doubly Linked List.pptxRashidFaridChishti Data Structures and Agorithm: DS 05 Doubly Linked List.pptx
3.linked list
3.linked listChandan Singh This document discusses linked lists as a solution to problems with arrays. It provides definitions and examples of linked lists, including:
- Each node contains a data element and a pointer to the next node
- A linked list is a series of connected nodes with a head pointer pointing to the first node
- Operations like insertion, deletion, and searching have linear time complexity of O(n) in the worst case
- Variations include circular and doubly linked lists
Here is the editable codeSolutionimport java.util.NoSuchEleme.pdf
Here is the editable codeSolutionimport java.util.NoSuchEleme.pdfarrowmobile Here is the editable code:
Solution
import java.util.NoSuchElementException;
public class DoublyLinkedListImpl {
private Node head;
private Node tail;
private int size;
public DoublyLinkedListImpl() {
size = 0;
}
private class Node {
E element;
Node next;
Node prev;
public Node(E element, Node next, Node prev) {
this.element = element;
this.next = next;
this.prev = prev;
}
}
public int size() { return size; }
public boolean isEmpty() { return size == 0; }
public void addFirst(E element) {
Node tmp = new Node(element, head, null);
if(head != null ) {head.prev = tmp;}
head = tmp;
if(tail == null) { tail = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
/**
* adds element at the end of the linked list
* @param element
*/
public void addLast(E element) {
Node tmp = new Node(element, null, tail);
if(tail != null) {tail.next = tmp;}
tail = tmp;
if(head == null) { head = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void iterateForward(){
System.out.println(\"iterating forward..\");
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.next;
}
}
/**
* this method walks backward through the linked list
*/
public void iterateBackward(){
System.out.println(\"iterating backword..\");
Node tmp = tail;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.prev;
}
}
public E removeFirst() {
if (size == 0) throw new NoSuchElementException();
Node tmp = head;
head = head.next;
head.prev = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public E removeLast() {
if (size == 0) throw new NoSuchElementException();
Node tmp = tail;
tail = tail.prev;
tail.next = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public static void main(String a[]){
DoublyLinkedListImpl dll = new DoublyLinkedListImpl();
dll.addFirst(10);
dll.addFirst(34);
dll.addLast(56);
dll.addLast(364);
dll.iterateForward();
dll.removeFirst();
dll.removeLast();
dll.iterateBackward();
}
}
import java.util.Scanner;
/* Class Node */
class Node
{
protected int data;
protected Node next, prev;
/* Constructor */
public Node()
{
next = null;
prev = null;
data = 0;
}
/* Constructor */
public Node(int d, Node n, Node p)
{
data = d;
next = n;
prev = p;
}
/* Function to set link to next node */
public void setLinkNext(Node n)
{
next = n;
}
/* Function to set link to previous node */
public void setLinkPrev(Node p)
{
prev = p;
}
/* Funtion to get link to next node */
public Node getLinkNext()
{
return next;
}
/* Function to get link to previous node */
public Node getLinkPrev()
{
return prev;
}
/* Function to set data to node */
public void setData(int d)
{
data = d;
}
/* Function to get data from node */
public int getData()
{
return data;
}
}
/* Class linkedList */
class linkedList
{
protected Node start;
protected Node end ;
public int size;
/* Constructor */
public linkedList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isE.
Flag question Question 9Question 91 ptsMarty is a creative proble.pdf
Flag question Question 9Question 91 ptsMarty is a creative proble.pdffacevenky Flag question: Question 9Question 91 pts
Marty is a creative problem-solver with strong critical thinking skills. She is highly loyal to her
leader and eager to take on additional responsibilities. What type of follower is Marty?
Group of answer choices
effective
indifferent
alienated
conformist
Flag question: Question 10Question 101 pts
Viktor is a creative problem-solver with strong critical thinking skills, but he shies away from
increased responsibilities and doesnt share ideas with his leader or his team. What type of
follower is Viktor?
Group of answer choices
alienated
conformist
indifferent
effective
Flag question: Question 11Question 111 pts
Soo is a director in a marketing company. When he tries to emphasize a particular behavioral
style as a leader, what should he consider?
Group of answer choices
the nature of the people he is trying to lead
which style typically works best with most people
the style most common among leaders
which style works best for him as a follower
Flag question: Question 12Question 121 pts
Deion, a very-task oriented leader, has recently taken on a management role at a technology
company. He is running into conflict with his team, and some team members have begun
ignoring orders. Deion holds a meeting reiterating the importance of doing things the way he
says, and he warns that there will consequences for those who refuse to follow orders. This is an
example of _______ leadership.
Group of answer choices
inflexible
flexible
facilitative
participative
Flag question: Question 13Question 131 pts
An inflexible leadership approach would be most appropriate in which situation?
Group of answer choices
the context is static
the followers are inexperienced
the leader has a small team
the leader has a people-oriented style
Flag question: Question 14Question 141 pts
In the path-goal approach to leadership, the relationship between leaders and followers is about
_______.
Group of answer choices
transactions
conflict avoidance
communication
trust
Flag question: Question 15Question 151 pts
Hilmi is new to his position and unfamiliar with the tasks required of him. According to the path-
goal approach to leadership, what leadership style would be most useful for him?
Group of answer choices
directive
supportive
participative
achievement-oriented
Flag question: Question 16Question 161 pts
Kajsas team is running behind to meet a deadline for an important client. According to the path-
goal approach to leadership, what leadership style should she use in this situation?
Group of answer choices
directive
supportive
participative
achievement-oriented
Flag question: Question 17Question 171 pts
Svetlana would like to be more involved in the decision making for her team and would like to
take on more responsibilities. According to the path-goal approach to leadership, what leadership
style might allow Svetlana a sense of control and to make sure her needs are met?
Group of answer choices
participative
supportive
directive
achieveme.
Exercise 3 You are to code some simple music player application .pdf
Exercise 3 You are to code some simple music player application .pdffacevenky Exercise 3:
You are to code some simple music player application making appropriate use of doubly linked
lists with head and tail, as described hereafter.
Create a doubly linked list for a music playlist.
Adding and deleting songs (#1-2) should update the playlist accordingly. Adding a song places it
at the end of the list.
Playing a song (#3) will prompt the user to enter the title of the song and will set the currentSong
pointer to that location in the playlist before printing both the title and singer (e.g., Now playing
by ) . Use the eraseInDLL function definition to implement delete.
Skipping forward or backward (#4-5) will jump to the previous song or the next song,
respectively, and display its title and singer (as per above). Skip forward on the last song takes
you to the beginning of the list. Skip backward on the first song takes you to the last song of the
list.
Exit will quit the program.
*You may use provided main function in Ex3.cpp file to continue.
Sample Output:
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 1
Enter song title: Trouble
Enter singer: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 6
Printing playlist...
Title: Staying Alive
Artist: Bee Gees
Title: Hotel California
Artist: The Eagles
Title: Saturnalia
Artist: Marilyn Manson
Title: Potions
Artist: Puscifer
Title: Trouble
Artist: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 3
Enter the title of the song to play: Trouble
Enter singer: Taylor Swift
Now playing...
Title: Trouble
Artist: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 4
Now Playing...
Title: Staying Alive
Artist: Bee Gees
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 5
Now Playing...
Title: Trouble
Artist: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 1
Enter song title: Lavender Haze
Enter singer: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 4
Now Playing...
Title: Lavender Haze
Artist: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 6
Printing playlist...
Title: Staying Alive
Artist: Bee Gees
Title: Hotel California
Artist: The Eagles
Title: Saturnalia
Artist: Marilyn Manson
Title: Potions
Artist: Puscifer
Title: Trouble
Artist: Taylor Swift
Title: Lavender Haze
Artist: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 2
Enter the title of the song to delete: Lavender Haze
Enter singer: Taylor Swift
Deleted!
1. Add a Song
2. Delete a Song
3. Pl.
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Similar to double linked list header file code#include iostream#include.pdf (20)
Help I keep getting the same error when running a code. Below is the.pdf
Help I keep getting the same error when running a code. Below is the.pdfmail931892 Help I keep getting the same error when running a code. Below is the code and the instructions
about the code.
import java.util.Arrays;
public class Album implements Comparable {
private final int id;
private final String[] artists;
private final int numSongs;
public Album(int id, String title, String[] artists, int numSongs) {
this.id = id;
this.artists = new String[]{Arrays.toString(artists)};
this.numSongs = numSongs;
}
public int getId() {
return id;
}
@Override
public int compareTo(Album other) {
return Integer.compare(this.numSongs, other.numSongs);
}
@Override
public String toString() {
StringBuilder artistNames = new StringBuilder();
for (String artist : artists) {
artistNames.append(artist).append(", ");
}
artistNames.delete(artistNames.length() - 2, artistNames.length());
return "ID: " + id + " -- " + numSongs + " songs -- [" + artistNames + "]";
}
}
import java.util.Random;
public class DoublyLinkedList {
private static class Node {
T data;
Node prev;
Node next;
Node(T data) {
this.data = data;
}
}
private Node head;
private Node tail;
private int size;
public DoublyLinkedList() {
head = null;
tail = null;
size = 0;
}
public Node append(T data) {
Node newNode = new Node<>(data);
if (head == null) {
head = newNode;
} else {
tail.next = newNode;
newNode.prev = tail;
}
tail = newNode;
size++;
return newNode;
}
public Node insert(int location, T data) {
if (location < 0 || location > size) {
throw new IllegalArgumentException("Invalid location");
}
Node newNode = new Node<>(data);
if (location == 0) {
newNode.next = head;
if (head != null) {
head.prev = newNode;
}
head = newNode;
if (tail == null) {
tail = newNode;
}
} else if (location == size) {
tail.next = newNode;
newNode.prev = tail;
tail = newNode;
} else {
Node current = head;
for (int i = 0; i < location; i++) {
current = current.next;
}
newNode.prev = current.prev;
newNode.next = current;
current.prev.next = newNode;
current.prev = newNode;
}
size++;
return newNode;
}
public Node delete(int location) {
if (location < 0 || location >= size) {
throw new IllegalArgumentException("Invalid location");
}
Node deletedNode;
if (location == 0) {
deletedNode = head;
head = head.next;
if (head != null) {
head.prev = null;
} else {
tail = null;
}
} else if (location == size - 1) {
deletedNode = tail;
tail = tail.prev;
tail.next = null;
} else {
Node current = head;
for (int i = 0; i < location; i++) {
current = current.next;
}
deletedNode = current;
current.prev.next = current.next;
current.next.prev = current.prev;
}
size--;
return deletedNode;
}
public int getIndex(T data) {
Node current = head;
for (int i = 0; i < size; i++) {
if (current.data.equals(data)) {
return i;
}
current = current.next;
}
return -1;
}
@Override
public String toString() {
StringBuilder result = new StringBuilder();
Node current = head;
while (current != null) {
result.append(current.data).append(" -> ");
current = current.next;
}
result.append("NULL");
return result.toString();
}
public Node shuffle() {
Random r.
Linkedlist
LinkedlistMasud Parvaze Linked lists are a data structure where each node contains a pointer to the next node in the list. Each node contains data and a pointer to the next node. The last node's pointer is set to NULL. Linked lists can dynamically grow and shrink during program execution. Nodes are implemented as structs containing data and a pointer. The head pointer points to the first node. Linked lists allow traversing the list by following node pointers until NULL is reached.
Ds 2 cycle
Ds 2 cycleChaitanya Kn The document discusses the implementation of a binary search tree (BST) using both recursive and non-recursive traversal methods. It defines a BST node structure with left and right child pointers. Functions are included to insert nodes, perform inorder, preorder and postorder traversals recursively and non-recursively using stacks. Main inserts sample nodes into the tree and calls the various traversal functions to output the node values in the specified orders.
#ifndef LINKED_LIST_ #define LINKED_LIST_ templateclass It.pdf
#ifndef LINKED_LIST_ #define LINKED_LIST_ templateclass It.pdfangelsfashion1 #ifndef LINKED_LIST_
#define LINKED_LIST_
template
class LinkedList {
private:
std::shared_ptr> headPtr; // Pointer to first node in the chain;
// (contains the first entry in the list)
int itemCount; // Current count of list items
std::shared_ptr> getNodeAt(int position) const;
public:
LinkedList();
LinkedList(const LinkedList& aList);
virtual ~LinkedList();
bool isEmpty() const;
int getLength() const;
bool insert(int newPosition, const ItemType& newEntry);
bool remove(int position);
void clear();
/** throw PrecondViolatedExcept if position < 1 or
position > getLength(). */
ItemType getEntry(int position) const throw(PrecondViolatedExcept);
/** throw PrecondViolatedExcept if position < 1 or
position > getLength(). */
void replace(int position, const ItemType& newEntry)
throw(PrecondViolatedExcept);
// Operator Overloading
void operator = (const LinkedList& arg);
friend std::ostream& operator << (std::ostream& os, const LinkedList& arg)
{
os << \"There are \" << arg.getLength() << \" values in the list:\" << std::endl;
for (int i{ 1 }; i <= arg.getLength(); i++) {
os << arg.getEntry(i) << std::endl;
}
os << std::endl << std::endl << std::endl << std::endl;
return os;
}
};
// Returns a pointer to the Node at the given position.
template
std::shared_ptr> LinkedList::getNodeAt (int position) const {
std::shared_ptr> currPtr{ headPtr };
for (int i{ 1 }; i < position; i++)
currPtr = currPtr->getNext();
return currPtr;
}
// Default constructor.
template
LinkedList::LinkedList() {
headPtr = nullptr;
itemCount = 0;
}
// Copy constructor.
template
LinkedList::LinkedList(const LinkedList& aList) {
itemCount = aList.getLength();
auto currPtr{ aList.headPtr };
auto newNodePtr{ headPtr = std::make_shared>(currPtr->getItem()) };
auto prevNodePtr{ newNodePtr };
currPtr = currPtr->getNext();
for (int i{ 2 }; i <= itemCount; i++) {
newNodePtr = std::make_shared>(currPtr->getItem());
prevNodePtr->setNext(newNodePtr);
prevNodePtr = newNodePtr;
currPtr = currPtr->getNext();
}
}
// Destructor.
template
LinkedList::~LinkedList() {
headPtr = nullptr;
itemCount = 0;
}
// Accessor/Info Functions.
template
bool LinkedList::isEmpty() const {
return (itemCount > 0)?0:1;
}
template
int LinkedList::getLength() const {
return itemCount;
}
// Places a Node at a given position (element at the same position is now pos+1).
template
bool LinkedList::insert(const int newPosition,
const ItemType& newEntry)
{
bool ableToInsert{ (newPosition >= 1) &&
(newPosition <= itemCount + 1) };
if (ableToInsert)
{
// Create a new node containing the new entry
auto newNodePtr{ std::make_shared>(newEntry) };
// Attach new node to chain
if (newPosition == 1)
{
// Insert new node at beginning of chain
newNodePtr->setNext(headPtr);
headPtr = newNodePtr;
}
else
{
// Find node that will be before new node
auto prevPtr{ getNodeAt(newPosition - 1) };
// Insert new node after node to which prevPtr points
newNodePtr->setNext(prevPtr->getNext());
prevPtr->setNext(newNodePtr);
} // end if
itemCount++; // .
#includeiostream #includecstdio #includecstdlib using na.pdf
#includeiostream #includecstdio #includecstdlib using na.pdfharihelectronicspune #include
#include
#include
using namespace std;
struct node
{
int val;
struct node *next;
}*startNode;
// declaring class
class LinkedList
{
public:
node* create_node(int);
void insert_last();
void sort();
void search();
void reverse();
void display();
LinkedList()
{
startNode = NULL;
}
};
// main
main()
{
int userChoice, linkedListNodes, i;
LinkedList LinkList;
startNode = NULL;
while (1)
{
// displaying menu
cout<<\" 1)Insert\";
cout<<\"2) Remove\";
cout<<\"3) Search\";
cout<<\"4) Display\";
cout<<\"5) Reverse\";
cout<<\"6) Exit \";
// reading user choice
cout<<\"Enter your userChoice : \";
cin>>userChoice;
switch(userChoice)
{
case 1:
cout<<\"Inserting node to linked list: \";
LinkList.insert_begin();
cout;
break;
case 2:
cout<<\"Delete element from linked list: \";
LinkList.delete();
break;
case 3:
cout<<\"Searching data in linked list: \";
LinkList.search();
cout;
break;
case 4:
cout<<\"Displaying linked list data: \";
LinkList.display();
cout;
break;
case 5:
cout<<\"Linked list reversing: \";
LinkList.reverse();
cout;
break;
case 6:
cout<<\"Exiting...\";
exit(1);
break;
default:
cout<<\"Enter correct userChoice\";
}
}
}
// node creating to store into list
node *LinkedList::create_node(int val)
{
struct node *tempNode, *tempNode;
tempNode = new(struct node);
if (tempNode == NULL)
{
cout<<\"No memory allocated \";
return 0;
}
else
{
tempNode->val = val;
tempNode->next = NULL;
return tempNode;
}
}
/*
* Inserting Node at last
*/
void LinkedList::insert_last()
{
int val;
cout<<\"Enter the val to be inserted: \";
cin>>val;
struct node *tempNode, *tempNode;
tempNode = create_node(val);
tempNode = startNode;
while (tempNode->next != NULL)
{
tempNode = tempNode->next;
}
tempNode->next = NULL;
tempNode->next = tempNode;
cout<<\"Element Inserted\";
}
// deleting element
void LinkedList::delete()
{
int position, i, count = 0;
if (startNode == NULL)
{
cout<<\"Linkedlist empty\"<>position;
struct node *tempNode, *ptr;
tempNode = startNode;
if (position == 1)
{
startNode = tempNode->next;
}
else
{
while (tempNode != NULL)
{
tempNode = tempNode->next;
count++;
}
if (position > 0 && position <= count)
{
tempNode = startNode;
for (i = 1;i < position;i++)
{
ptr = tempNode;
tempNode = tempNode->next;
}
ptr->next = tempNode->next;
}
else
{
cout<<\"Enter correct position\";
}
}
}
// search data in linked list
void LinkedList::search()
{
int val, position = 0;
bool flagValue = false;
if (startNode == NULL)
{
cout<<\"List is empty\";
return;
}
cout<<\"Enter the val to search: \";
cin>>val;
struct node *tempNode;
tempNode = startNode;
while (tempNode != NULL)
{
position++;
if (tempNode->val == val)
{
flagValue = true;
cout<<\"Data \"<next;
}
if (!flagValue)
cout<<\"data not found\";
}
// linkedlist reverese
void LinkedList::reverse()
{
struct node *pointer1, *pointer2, *pointer3;
if (startNode == NULL)
{
cout<<\"List is empty\"<next == NULL)
{
return;
}
pointer1 = startNode;
pointer2 = pointer1->next;
pointer3 = pointer2->next;
pointer1->next = NULL;
pointer2->.
Lecture 4 data structures and algorithms
Lecture 4 data structures and algorithmsAakash deep Singhal The document discusses linked lists as an alternative to arrays for storing data. It provides 3 key points:
1. Linked lists store data in nodes that are linked together using pointers, rather than in a fixed contiguous block of memory like arrays. Each node contains a data field and a pointer to the next node.
2. Common linked list operations like insertion, deletion, and searching have time complexities of O(1) or O(n) depending on the position in the list, which can be more efficient than arrays that require shifting elements.
3. The document presents a simple C++ implementation of a linked list using Node and List classes to demonstrate how to implement basic linked list functions like insertion, deletion
In the class we extensively discussed a node class called IntNode in.pdf
In the class we extensively discussed a node class called IntNode in.pdfarjunstores123 In the class we extensively discussed a node class called IntNode in which each linked list node
contains an integer and each node is linked forward to the next element in the list. Implement a
node class called DoublyIntNode in which each node contains an integer number and each node
is linked not only forward to the next element in the list but also backward to the previous
element in the list. Your implementation of DoublyIntNode should adapt and implement all the
methods of IntNode including the following methods:
Constructor for DoublyIntNode
addNodeAfter, removeNodeAfter
getData, setData
getForeLink, setForeLink
getBackLink, setBackLink
listCopy
listCopyWithTail
listLength
listPart
listPosition
listSearch
IntNode and Node classes:
public class IntNode{
private int data;
private IntNode link;
// methods here
}
public class Node {
private E data;
private Node link;
// methods here
}
Solution
program
#include
using namespace std;
struct list
{
struct list *prev;
int data;
struct list *next;
}
*node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL;
class Dlist
{
public:
void insert_beg() {
list *addBeg = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addBeg->data;
if(first == NULL) {
addBeg->prev = NULL;
addBeg->next = NULL;
first = addBeg;
last = addBeg;
cout << \"Linked list Created!\" << endl;
}
else {
addBeg->prev = NULL;
first->prev = addBeg;
addBeg->next = first;
first = addBeg;
cout << \"Data Inserted at the beginning of the Linked list!\" << endl;
}
}
void insert_end() {
list *addEnd = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addEnd->data;
if(first == NULL) {
addEnd->prev = NULL;
addEnd->next = NULL;
first = addEnd;
last = addEnd;
cout << \"Linked list Created!\" << endl;
}
else {
addEnd->next = NULL;
last->next = addEnd;
addEnd->prev = last;
last = addEnd;
cout << \"Data Inserted at the end of the Linked list!\" << endl;
}
}
void display() {
node = first;
cout << \"List of data in Linked list in Ascending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->next;
}
node = last;
cout << \"List of data in Linked list in Descending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->prev;
}
}
void del()
{
int count = 0, number, i;
node = node1 = node2 = first;
for(node = first; node != NULL; node = node->next)
cout << \"Enter value for the node:\" << endl;
count++;
display();
cout << count << \" nodes available here!\" << endl;
cout << \"Enter the node number which you want to delete:\" << endl;
cin >> number;
if(number != 1)
{
if(number < count && number > 0)
{
for(i = 2; i <= number; i++)
node = node->next;
for(i = 2; i <= number-1; i++)
node1 = node1->next;
for(i = 2; i <= number+1; i++)
node2 = node2->next;
node2->prev = node1;
node1->next = node2;
node->prev = NULL;
node->next = NULL;
node = NULL;
}
else if(number == count)
{
node = last;
last = node->prev;
last->next = NULL;
node = NULL;
}
else
cout << \"Invalid node.
ISCP internal.pdf
ISCP internal.pdfGANDHAMKUMAR2 The document contains code for multiple programming problems across different sets. The first problem in Set 1 (Program 1) deals with checking if the sums of three stacks are equal. It takes three stacks as input, calculates their sums by traversing them in reverse order and pushing elements to additional stacks, and returns the common sum if the sums are equal at any point as the stacks are traversed. The second problem (Program 2) checks if a binary tree is complete by doing a level order traversal using a queue - it returns false if any null child node is encountered when a non-null node is still in the queue.
Please refer this solution. This is working file for IntegersHeade.pdf
Please refer this solution. This is working file for IntegersHeade.pdfsooryasalini Please refer this solution. This is working file for Integers
Header file :-
-----------------------------------
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
struct node{
void * data;
node * next;
};
class LinkedList
{
private:
node* head ;
int size;
public:
LinkedList();
//method to create a node
node * create(void* data);
//method to append
void append(node * item);
//method to prepend
void prepend(node * item);
//insert in ascending order
void insertAscend(node * item);
//insert in ascending order
void insertDescend(node * item);
//display all nodes
void display();
//free the list
void freeUp();
};
#endif // LINKEDLIST_H
Source file :-
----------------------------------
#include \"linkedlist.h\"
#include
#include
#include
LinkedList::LinkedList()
{
//head = (node *)malloc(sizeof(node));
size = 0;
head = NULL;
}
//method to create a node
node * LinkedList::create(void* data){
node * newNode = (node *)malloc(sizeof(node));
newNode->data = malloc(sizeof(data));
memcpy(newNode->data,data,sizeof(data));
newNode->next = NULL;
return newNode;
}
//method to append
void LinkedList::append(node * item){
if(head == NULL){
head = item;
size++;
return;
}
node* current;
current = head;
while (current->next!=NULL )
{
current = current->next;
}
current->next = item ;
size++;
}
//method to prepend
void LinkedList::prepend(node * item){
if(head == NULL){
head = item;
size++;
return;
}
item->next = head;
head = item;
size++;
}
//insert in ascending order
void LinkedList::insertAscend(node * item){
if(head == NULL){
head = item;
size++;
return;
}
node* current;
current = head;
node * prev = NULL;
bool found = false;
while (current !=NULL){
int *current_data = static_cast(current->data);
int *item_data = static_cast(item->data);
if(*item_data < *current_data){
if(prev == NULL){
item->next = current;
if(current == head){
head = item;
}
}
else{
prev->next = item;
item->next = current;
}
found = true;
break;
}
prev = current;
current = current->next;
}
if(!found){
prev->next = item;
}
size++;
}
//insert in Descending order
void LinkedList::insertDescend(node * item){
if(head == NULL){
head = item;
size++;
return;
}
node* current;
current = head;
node * prev = NULL;
bool found = false;
while (current !=NULL){
int *current_data = static_cast(current->data);
int *item_data = static_cast(item->data);
if(*item_data > *current_data){
if(prev == NULL){
item->next = current;
if(current == head){
head = item;
}
}
else{
prev->next = item;
item->next = current;
}
found = true;
break;
}
prev = current;
current = current->next;
}
if(!found){
prev->next = item;
}
size++;
}
//display all nodes
void LinkedList::display(){
int idx = 0;
node* current;
current = head;
while (current != NULL ){
idx++;
int *data = static_cast(current->data);
printf(\"data for item ::%dis :: %d\ \",idx,*data);
current = current->next;
}
}
//free the list
void LinkedList::freeUp(){
node* current;
current = head;
while (current->next!=NULL ){
head = current->next;
delete current;
current = head;
}
}
Main f.
Revisiting a data structures in detail with linked list stack and queue
Revisiting a data structures in detail with linked list stack and queuessuser7319f8 This document discusses various data structures including arrays, stacks, queues, and linked lists. It provides code examples for creating and manipulating each type of data structure. Specifically, it shows code for inserting and deleting elements from arrays and linked lists. It also includes algorithms and code for common stack and queue operations like push, pop, enqueue, and dequeue. The document provides a detailed overview of linear and non-linear data structures.
Given the following codepackage data1;import java.util.;p.pdf
Given the following codepackage data1;import java.util.;p.pdfillyasraja7 Given the following code
package data1;
import java.util.*;
/*public class BST> implementing a set ADT and containing the following:
* private inner class BinaryNode representing a node with a (possibly) left child and a (possibly)
right child
** instance fields BinaryNode root, int size
* contains/insert/remove method - w/ O(height) complexity
** size O(1), isEmpty O(1), clear O(1),
*** findMin, findMax, findHeight methods - w/ O(height) complexity
**** toString() method printing set (in-order traversal) and the tree (BFS traversal)
**
*/
publicclass BST> {
private BinaryNode root;
privateint size;
//Search opertion of Set ADT
publicboolean contains(E value) {
return contains(root, value);
}
//Insert opertion of Set ADT
publicvoid insert(E value) {
root = insert(root, value);
size++;
}
//Remove operation of Set ADT
publicvoid remove(E value){
root = remove(root, value);
size--;
}
publicint size(){
return size;
}
publicboolean isEmpty(){
return root == null;
}
publicvoid clear(){
root = null;
size = 0;
}
public E findMin(){
return findMin(root);
}
public E findMax(){
return findMax(root);
}
publicint findHeight(){
return root.height();
}
public String toString(){
if(root == null)
return "set {} stored in an empty tree.\n";
String elements = root.inOrder().toString();
return "set {" + elements.substring(1,elements.length()-1) + "} stored in tree \n" + root;
}
private E findMin(BinaryNode node){
if(node == null)
returnnull;
if(node.left == null)
return node.element;
return findMin(node.left);
}
private E findMax(BinaryNode node){
if(node == null)
returnnull;
if(node.right == null)
return node.element;
return findMax(node.right);
}
privateboolean contains(BinaryNode node, E value) {
if (node == null)//node represents an empty substree
returnfalse;
int comparisonResult = value.compareTo(node.element);
if(comparisonResult < 0)//if value is less than root's value
return contains(node.left, value);
if(comparisonResult > 0)//if value is greater than root's value
return contains(node.right, value);
returntrue;//successful search
}
private BinaryNode insert(BinaryNode node, E value) {
if (node == null)//base case: empty tree
returnnew BinaryNode<>(value);
if (value.compareTo(node.element) < 0)
node.left = insert(node.left, value);//insert recursively to left-subtree
elseif (value.compareTo(node.element) > 0)
node.right = insert(node.right, value);//insert recursively to right-subtree
else {//duplicate value cannot be inserted in a BST implementing the Set ADT
size--;//insertion failed!
//System.out.print("BST.insert: Warning: " + value + " is already stored in the tree \n" + node);
}
return node;
}
private BinaryNode remove(BinaryNode node, E value) {
if (node == null) {//base case: empty tree
System.out.println("BST.remove: Warning: " + value + " doesn't exist in the tree.");
size++;//removal failed!
return node;
}
if (value.compareTo(node.element) < 0)
node.left = remove(node.left, value);
elseif (value.compareTo(node.element) > 0)
node.right = remov.
17 linkedlist (1)
17 linkedlist (1)Himadri Sen Gupta This document discusses linked lists and their implementation in C. It begins by describing the differences between array-based and linked list implementations. Specifically, it notes that linked lists use dynamic memory allocation and pointers to connect nodes rather than contiguous memory blocks. The document then covers creating and traversing linked lists using nodes with data fields and next pointers. It provides code examples for inserting, finding, deleting and destroying nodes in a singly linked list. Finally, it briefly lists some other common linked list operations like sorting, reversing and finding min/max elements.
#include stdafx.h #include iostream using namespace std;vo.docx
#include stdafx.h #include iostream using namespace std;vo.docxajoy21 This document contains C++ code to implement a linked list program that performs the following tasks:
1. Inputs 10 integers into a linked list while sorting them as they are inserted
2. Prints the sorted list and computes the average of the values
3. Deletes nodes from the list with values less than the average
4. Creates a second list of 10 sorted integers
5. Merges the two lists together, eliminating duplicates, and prints the final list
Doublylinklist
Doublylinklistritu1806 This document presents information on doubly linked lists including their representation, initialization, node creation, and various operations like insertion, deletion, and traversal. It discusses inserting and deleting nodes at the beginning or end of the list, as well as inserting before or after a specified node. Code examples are provided for initializing a doubly linked list and performing each operation.
Write a Java Class to Implement a Generic Linked ListYour list mus.pdf
Write a Java Class to Implement a Generic Linked ListYour list mus.pdfrozakashif85 Write a Java Class to Implement a Generic Linked List
Your list must be implemented as a singly-linked list of generic nodes, where each Node object
has two instance variables: an object of the “type variable” class, and a pointer to the next node
on the list.
Your class will contain separate methods to handle each of the operations read from a data file
(see II., below)
Your class will also override toString() to return the objects on the list in the order in which they
occur.
Write a Test Class for Your LinkedList Class
Your main method will read list operation instructions from a data file, until end-of-file and call
the appropriate LinkedList method to execute each one.
After each operation is executed, print out the operation and the updated list.
The data file to be used is on the class web site and the operations are:
APPEND X - Append object X to the end of the list
ADD N X - Insert object X as the new Nth element in the list, increasing the size of the list by 1
E.g. Suppose the list is:
head -> 1 -> 2 -> 3 -> 4->null
After ADD 3 7 it would be:
head -> 1 -> 2 -> 7 -> 3 -> 4->null
DELETE N – Remove the Nth object from the list
SWAP M N - Interchange the positions of the Mth and Nth
objects on the list
For credit, the two nodes must actually \"trade places\" in the list, and not merely swap their data
values
REVERSE - Reverse the order of the objects on the list
This must be done by reversing the order of the nodes themselves, rather than by swapping the
data stored
To get credit for your reverse() method, it must use either one of these 2 algorithms:
For each node on the list except the current “head”
node, delete the node and insert it as the new head
Use your swap() method
6. CLEAR – Clear the list (make it empty)
No credit will be given for programs that use any additional data structures – either from the Java
API or programmer defined -, other than your own LinkedList class
txt file:
Solution
//Java Program to Implement Singly Linked List
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
/* Class Node */
class Nodes
{
protected Object data;
protected Nodes next;
/* Constructor */
public Nodes()
{
next = null;
data = null;
}
/* Constructor */
public Nodes(Object d,Nodes n)
{
data = d;
next = n;
}
/* Function to set link to next Node */
public void setLink(Nodes n)
{
next = n;
}
/* Function to set data to current Node */
public void setData(Object d)
{
data = d;
}
/* Function to get link to next node */
public Nodes getLink()
{
return next;
}
/* Function to get data from current Node */
public Object getData()
{
return data;
}
}
/* Class linkedList */
class linkList
{
protected Nodes start;
protected Nodes end ;
public int size ;
/* Constructor */
public linkList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isEmpty()
{
return start == null;
}
/* Function to get size of list */
public int getSize()
{
return .
Implement of c & its coding programming by sarmad baloch
Implement of c & its coding programming by sarmad balochSarmad Baloch The C program implements a singly linked list with functions to insert and delete nodes, print the list, find a node by key, sort the list by data, and reverse the list. It demonstrates using the functions to create a list, delete all nodes, find and delete a node, sort the list, and reverse it, printing the list after each operation.
Data Structures and Agorithm: DS 05 Doubly Linked List.pptx
Data Structures and Agorithm: DS 05 Doubly Linked List.pptxRashidFaridChishti Data Structures and Agorithm: DS 05 Doubly Linked List.pptx
3.linked list
3.linked listChandan Singh This document discusses linked lists as a solution to problems with arrays. It provides definitions and examples of linked lists, including:
- Each node contains a data element and a pointer to the next node
- A linked list is a series of connected nodes with a head pointer pointing to the first node
- Operations like insertion, deletion, and searching have linear time complexity of O(n) in the worst case
- Variations include circular and doubly linked lists
Here is the editable codeSolutionimport java.util.NoSuchEleme.pdf
Here is the editable codeSolutionimport java.util.NoSuchEleme.pdfarrowmobile Here is the editable code:
Solution
import java.util.NoSuchElementException;
public class DoublyLinkedListImpl {
private Node head;
private Node tail;
private int size;
public DoublyLinkedListImpl() {
size = 0;
}
private class Node {
E element;
Node next;
Node prev;
public Node(E element, Node next, Node prev) {
this.element = element;
this.next = next;
this.prev = prev;
}
}
public int size() { return size; }
public boolean isEmpty() { return size == 0; }
public void addFirst(E element) {
Node tmp = new Node(element, head, null);
if(head != null ) {head.prev = tmp;}
head = tmp;
if(tail == null) { tail = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
/**
* adds element at the end of the linked list
* @param element
*/
public void addLast(E element) {
Node tmp = new Node(element, null, tail);
if(tail != null) {tail.next = tmp;}
tail = tmp;
if(head == null) { head = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void iterateForward(){
System.out.println(\"iterating forward..\");
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.next;
}
}
/**
* this method walks backward through the linked list
*/
public void iterateBackward(){
System.out.println(\"iterating backword..\");
Node tmp = tail;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.prev;
}
}
public E removeFirst() {
if (size == 0) throw new NoSuchElementException();
Node tmp = head;
head = head.next;
head.prev = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public E removeLast() {
if (size == 0) throw new NoSuchElementException();
Node tmp = tail;
tail = tail.prev;
tail.next = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public static void main(String a[]){
DoublyLinkedListImpl dll = new DoublyLinkedListImpl();
dll.addFirst(10);
dll.addFirst(34);
dll.addLast(56);
dll.addLast(364);
dll.iterateForward();
dll.removeFirst();
dll.removeLast();
dll.iterateBackward();
}
}
import java.util.Scanner;
/* Class Node */
class Node
{
protected int data;
protected Node next, prev;
/* Constructor */
public Node()
{
next = null;
prev = null;
data = 0;
}
/* Constructor */
public Node(int d, Node n, Node p)
{
data = d;
next = n;
prev = p;
}
/* Function to set link to next node */
public void setLinkNext(Node n)
{
next = n;
}
/* Function to set link to previous node */
public void setLinkPrev(Node p)
{
prev = p;
}
/* Funtion to get link to next node */
public Node getLinkNext()
{
return next;
}
/* Function to get link to previous node */
public Node getLinkPrev()
{
return prev;
}
/* Function to set data to node */
public void setData(int d)
{
data = d;
}
/* Function to get data from node */
public int getData()
{
return data;
}
}
/* Class linkedList */
class linkedList
{
protected Node start;
protected Node end ;
public int size;
/* Constructor */
public linkedList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isE.
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Flag question Question 9Question 91 ptsMarty is a creative proble.pdffacevenky Flag question: Question 9Question 91 pts
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alienated
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Group of answer choices
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Exercise 3 You are to code some simple music player application .pdf
Exercise 3 You are to code some simple music player application .pdffacevenky Exercise 3:
You are to code some simple music player application making appropriate use of doubly linked
lists with head and tail, as described hereafter.
Create a doubly linked list for a music playlist.
Adding and deleting songs (#1-2) should update the playlist accordingly. Adding a song places it
at the end of the list.
Playing a song (#3) will prompt the user to enter the title of the song and will set the currentSong
pointer to that location in the playlist before printing both the title and singer (e.g., Now playing
by ) . Use the eraseInDLL function definition to implement delete.
Skipping forward or backward (#4-5) will jump to the previous song or the next song,
respectively, and display its title and singer (as per above). Skip forward on the last song takes
you to the beginning of the list. Skip backward on the first song takes you to the last song of the
list.
Exit will quit the program.
*You may use provided main function in Ex3.cpp file to continue.
Sample Output:
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 1
Enter song title: Trouble
Enter singer: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 6
Printing playlist...
Title: Staying Alive
Artist: Bee Gees
Title: Hotel California
Artist: The Eagles
Title: Saturnalia
Artist: Marilyn Manson
Title: Potions
Artist: Puscifer
Title: Trouble
Artist: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 3
Enter the title of the song to play: Trouble
Enter singer: Taylor Swift
Now playing...
Title: Trouble
Artist: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 4
Now Playing...
Title: Staying Alive
Artist: Bee Gees
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 5
Now Playing...
Title: Trouble
Artist: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 1
Enter song title: Lavender Haze
Enter singer: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 4
Now Playing...
Title: Lavender Haze
Artist: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 6
Printing playlist...
Title: Staying Alive
Artist: Bee Gees
Title: Hotel California
Artist: The Eagles
Title: Saturnalia
Artist: Marilyn Manson
Title: Potions
Artist: Puscifer
Title: Trouble
Artist: Taylor Swift
Title: Lavender Haze
Artist: Taylor Swift
1. Add a Song
2. Delete a Song
3. Play a Song
4. Forward
5. Backward
6. Show Playlist
7.Exit
Choose an option: 2
Enter the title of the song to delete: Lavender Haze
Enter singer: Taylor Swift
Deleted!
1. Add a Song
2. Delete a Song
3. Pl.
Fiancial Statements. South Sea Baubles has the following (incomplete.pdf
Fiancial Statements. South Sea Baubles has the following (incomplete.pdffacevenky Fiancial Statements. South Sea Baubles has the following (incomplete) balance shet and income
statement. (103-1, 1034)
BALANCE SHEET AT END OF YEAR
(Figures In $ millions)
Assets
2021
2022
Liabilities and Shareholders Equity
2021
2022
Current assets
$ 90
$ 140
Current liabilities
$ 50
$ 60
Net fixed assets
800
900
Long-term debt
600
750
INCOME STATEMENT, 2022
(Figures In $ millions)
Revenue
Cost of goods sold
Depreciation
Interest expense
$1,950
1,030
350
240
a. What is shareholders' equity in 2021?
b. What is shareholders' equity in 2022?
c. What is net working capital in 2021?
d. What is net working capital in 2022?
e. What are taxes paid in 2022? Assume the firm pays taxes equal to 21% of taxable income.
f. What is cash provided by operations during 2022? Pay attention to changes in net working
capital, using 1 Table 3.4
g. Net fixed assets increased from $800 million to $900 million during 2022. What must have
been South Sea's gross investment fixed assets during 2022?
h. If South Sea reduced its outstanding accounts payable by $35 million during the year, what
must have happened to its other liabilities?.
Explore how the shift to digital platforms and online interactions has.pdf
Explore how the shift to digital platforms and online interactions has.pdffacevenky Explore how the shift to digital platforms and online interactions has influenced consumer
behavior. Investigate strategies for managers to adapt their approaches in light of these changes.
Introduction: Background of the topic and your research proposal: what is the purpose and
importance of your research; include the research question according to rules of a good question;
outline/contents of the proposal. (4) Research Design Section: Outline your approach to
answering your question and justify the survey method, i.e. why use a survey? Identify and show
how you operationalize your variables using a conceptual model/diagram (see slides for
examples); include your sampling strategy, administration/mode of delivery, discuss the internal
validity of your ins.
Exercise2You are to develop a simple queue system for a customer .pdf
Exercise2You are to develop a simple queue system for a customer .pdffacevenky Exercise2:
You are to develop a simple queue system for a customer service counter, based on singly linked
lists with head and tail.
Customers are processed first come, first served from the front of the queue, while new
customers join at the end of the queue. (This is known as FIFO or First In First Out.)
Implement the queue system using a singly liked list. You need to have both head and tail
pointers, to the first node (front) and last node (end), respectively, in order to manage the queue.
Your program should display a menu for the user to choose an option, as follows:
For options #1, your program should ask the user to enter a customer name (string) and add it at
the end of the queue.
Option #2, print customers name to be served and delete the customer from queue.
Option #3, print customer names waiting in the queue along with the count.
Option #4, exit the program.
Sample input and output:
#include
#include
using namespace std;
//defining single node
template
struct SingleNode
{
Object data;
SingleNode* next;
SingleNode(const Object& d = Object{}, SingleNode* n = nullptr) //constructor
initializing data to empty object and
: data{ d }, next{ n } { } //next pointer to null
};
template
SingleNode*& AddToQueue(SingleNode*& queueHead, SingleNode*& queueTail, Object
customerName)
{
SingleNode* NewCustomer = new SingleNode(customerName);
if (queueHead==nullptr) {
queueHead = queueTail = NewCustomer;
}
else {
queueTail->next = NewCustomer;
queueTail = NewCustomer;
}
return NewCustomer;
}
template
void printSLL(SingleNode* head)
{
while (head != nullptr)
{
cout << head->data << "\t";
head = head->next;
}
cout << endl;
}
template
void eraseSLL(SingleNode*& head, Object givenValue)
{
SingleNode* temp = head;
SingleNode* prev = nullptr;
while (temp != nullptr)
{
if (temp->data == givenValue)
{
if (prev == nullptr)
{
// If the value to be deleted is in the first node
head = temp->next;
delete temp;
}
else
{
prev->next = temp->next;
delete temp;
}
}
prev = temp;
temp = temp->next;
}
}
int main()
{
SingleNode* queueHead = nullptr;
SingleNode* queueTail = nullptr;
cout << "1. Stand in the Queue \n2. Serve a Customer \n3. Print Customer names waiting
\n4. Exit \nEnter your choice: ";
int choice;
string customerName, coursePreReq;
cin >> choice;
SingleNode* Queue=new SingleNode;
while (choice != 4)
{
if (choice == 1) //add
{
cout << "Enter Customer Name: ";
cin >> customerName;
Queue->next = AddToQueue(queueHead, queueTail, customerName);
}
else if (choice == 2) //delete
{
cout << "Serving " << queueHead->data << endl;
eraseSLL(Queue, queueHead->data);
}
else if (choice == 3) //print
{
printSLL(Queue);
}
cout << "1. Stand in the Queue \n2. Serve a Customer \n3. Print Customer names
waiting \n4. Exit \nEnter your choice: ";
cin >> choice;
}
return 0;
}
*You may use provided main function in Ex2Source.cpp file to continue.
#include
#include
using namespace std;
//defining single node
template
struct SingleNode
{
Object data;
SingleNode *next;
SingleNode(c.
Electronic Distribution has a defined benefit pension plan. Characte.pdf
Electronic Distribution has a defined benefit pension plan. Characte.pdffacevenky Electronic Distribution has a defined benefit pension plan. Characteristics of the plan during
2024 are as follows:
The expected long-term rate of return on plan assets was 8%. There were no AOCI balances
related to pensions on January 1, 2024, but at the end of 2024, the company amended the pension
formula, creating a prior service cost of $12 million.($ millions)PBO balance, January
1$480Plan assets balance, January 1300Service cost75Interest cost45Gain from change in
actuarial assumption22Benefits paid(36)Actual return on plan assets20Contributions 202460
Calculate the pension expense for 2024 . Note: Amounts to be deducted should be indicated with
a minus sign. Enter your answers in millions (i.e., 10,000,000 should be entered as 10).
Prepare the journal entries to record (a) pension expense, (b) gains or losses, (c) prior service
cost, (d) funding, and (e) payment of benefits for 2024 . Note: If no entry is required for a
transaction/event, select "No journal entry required" in the first account field. Enter your answers
in millions (i.e., 10,000,000 should be entered as 10).
Complete this question by entering your answers in the tabs below. What amount will Electronic
Distribution report in its 2024 balance sheet as a net pension asset or net pension liability? Note:
Enter your answer in millions (i.e., 10,000,000 should be entered as 10 )..
Execution Steps of Building the Inverted Index is shown as below Exec.pdf
Execution Steps of Building the Inverted Index is shown as below Exec.pdffacevenky Execution Steps of Building the Inverted Index is shown as below: Execution Steps to Build
inverted index Eepembert1, 2019 Sonst Churg Lecturs Hates Write a Process in any language of
your choice for text processing of the log file: UnionAddressTable.csv to create an Inverted
Index Table for Term Frequency Look Up with the following Steps shown in Slide 10-13 in
Inverted Index lecture note. Import the Input File (CSV file) UnionAddressTable to create a table
in RDBMS. The input file UnionAddressTable.csv is given on the class webpage. Reads
UnionAddressTable to Parse to Create an Intermediate Table as Shown Slide 11 in Inverted
Index Lecture. Slide 11: For each record, read the whole text of the Union Address (in the last.
Elicitation TechniquesSeeking help for Elicitation plan for projec.pdf
Elicitation TechniquesSeeking help for Elicitation plan for projec.pdffacevenky Elicitation Techniques
Seeking help for Elicitation plan for project plan/design listed below. Information above should
be based off of information below this line.
Step1. Project Plan
1.1. Chosen SDLC (Software Development Life Cycle)
We will adopt the Agile SDLC for this project due to its flexibility and iterative nature, allowing
us to adapt to changing requirements, which are common in the dynamic field of sustainable
energy. Agile also encourages customer feedback, ensuring the application aligns with Toro
Tech
Solution
s evolving needs.
1.2. Project Schedule
Phase 1: Initiation and Planning (2 weeks)
Phase 2: Design and Development (8 weeks)
Phase 3: Testing and Quality Assurance (2 weeks)
Phase 4: Deployment and Monitoring (2 weeks)
Phase 5: Maintenance and Updates (Ongoing)
1.3. Plan for the Assessment of Progress
Progress will be assessed using the following methods:
Step 2. Staffing Plan
Effective communication is crucial for project success. Our communications plan will include:
Identifying and mitigating risks is essential to project success:
Risk: Changing requirements
Risk: Technical challenges
Risk: Budget overrun
Risk: Integration issues with data sources
Risk: Security and data privacy
Risk: Low user adoption.
Draw a complete ERD that depicts the data model to record the requir.pdf
Draw a complete ERD that depicts the data model to record the requir.pdffacevenky Draw a complete ERD that depicts the data model to record the required information. The data
model must be neat and professional in appearance. The assignment must be completed through
your individual efforts giving or seeking assistance from anyone other than the instructor is not
permitted. The final ERD should be in a single MS Word document and uploaded to D2L.
Southern Clinic for Abuse Rehabilitation Services (SCARS) is a specialty clinic that helps
individuals deal with substance abuse issues. They are not prepared for, and do not treat, all
mental and/or emotional disorders. Primarily, SCARS works with individuals that present
themselves for treatment; however, they also work with some COSAT (court ordered substance
abuse treatment) patients. All patients are treated on an outpatient basis. SCARS is attempting to
get government funding to support their operations so they need to improve the ease with which
they can produce a variety of reports. You have been contracted to develop a database to support
tracking the patients they work with. Your design should support the following operations.
Description of Operations: When a patient comes to SCARS, the staff will diagnose them so the
staff will know what they are working with. Each new patient is assigned an identification
number that is recorded along with the patients name, address, and whether or not he or she is a
COSAT patient. Patients come in knowing that they suffer from some kind of chemical
dependency disorder. In addition, many patients also suffer from one or more other disorders,
such as depression or paranoia, that they are not aware is a disorder. If the staff thinks a patient
suffers from a disorder that SCARS cannot deal with, then the staff refer that patient to a local
full-care hospital. Such patients will appear in SCARS system, but will not be associated with a
disorder since SCARS will not make an official diagnosis for them. Each disorder has an
identification code, a name, a general description, and a description of the pattern of family
incidence (e.g. tends to appear on the mothers side of the family, tends to appear on the fathers
side of the family, no hereditary characteristic, etc.). Each disorder is associated with symptoms
that help to identify the disorder. Each symptom has a name, a general description, and a location
on the body where it occurs. Every disorder will have one or more symptoms. Some symptoms
are common to many different disorders, but all symptoms must be associated with at least one
disorder. A patient may be diagnosed with one or more disorders. SCARS may expand their
capabilities in the future so the system should support disorders with which no patient has been
diagnosed. Whenever a patient is diagnosed with a disorder, the date of that diagnoses, the
severity of the Page 2 of 2 disorder in that patient, and a prognosis (forecast for the likely
recovery from the disorder) are recorded. For example, when Henry Peterson first came to
S.
Do the following well, read all directions, I asked this question be.pdf
Do the following well, read all directions, I asked this question be.pdffacevenky Do the following well, read all directions, I asked this question before but the person sent some
classes good but some classes wasnt right so when sending it on gradescope i only got 30/80.
That was the tavern class, so i will send the directions of the assignment, so you know what that
is, then i will send you the code i have so far, which is 30/80, and then i will tell you what do.
Note that while i got only 30/80 on gradescope, on vs code or whatever platform you use, it will
run, but it does not complete the requirements of the assignment that gradescope looks like so
please make sure you read the directions well and modify my code accordingly.
Please make sure that while the character and arraybag files are fine, it is the tavern that is the
problem so make sure you exactly check the assignment and see what they are asking for tavern
that i dont have in the code i am sending and fix it as possible.
The following are the directions for it, read this carefully
For Task 1, you have to modify the character class. A rough format of the character.cpp and
character.hpp has been given, and I will give it to you, and you have to modify that based on the
instructions given.
Character.cpp/hpp given:
Character.cpp:
#include "Character.hpp"
/**
Default constructor.
Default-initializes all private members.
Default character name: "NAMELESS".
Booleans are default-initialized to False.
Default enum value: NONE.
Default Vitality, Max Armor, and Level: 0.
*/
Character::Character():name_{"NAMELESS"},race_{NONE},vitality_{0},armor_{0},level_{0}
,enemy_{false}
{
}
/**
Parameterized constructor.
@param : The name of the character (a string in UPPERCASE)
@param : The race of the character (a string)
@param : The character's vitality (a non-negative integer) , with default value 0
@param : The character's max armor level (a non-negative integer), with default value 0
@param : The character's level (a non-negative integer), with default value 0
@param : A flag indicating whether the character is an enemy, with default value false
@post : The private members are set to the values of the corresponding parameters.
Hint: Notice the default arguments in the parameterized constructor.
If the given parameters are invalid, the default values are used instead.
*/
Character::Character(const std::string& name, const std::string& race, int vitality, int armor, int
level, bool enemy) : Character()
{
setName(name); // checks valid name
setRace(race); // checks valid race
(vitality >= 0) ? vitality_ = vitality: vitality_ = 0;
(armor >= 0) ? armor_ = armor: armor_ = 0;
(level >= 0) ? level_ = level: level_ = 0;
enemy_ = enemy;
}
/**
@param : the name of the Character
@post : sets the Character's title to the value of the parameter, in UPPERCASE. Only
alphabetical characters are allowed. For example, attempting to create a character named
"TW3EDLEDUM2" should create a character named "TWEDLEDUM".
: If the given parameter does not have any valid alphabetical characters, the char.
Digital Communication SystemsObjectives 1 To be able to demons.pdf
Digital Communication SystemsObjectives 1 To be able to demons.pdffacevenky Digital Communication Systems
Objectives
1 To be able to demonstrate the fundamental concepts of digital communication systems
including channel models, waveform design, signal modulation, transmission, and signal
detection.
2 To be able to evaluate digital communication systems under given power, spectral and error
performance constrains.
Question 1:
Question 2: Consider a digital communication link based binary symmetric wireless
communication channel. The prior probabilities of binary symbols 0 and 1 are respectively, 0.1
and 0.9 , and the flipping probability is 0.2 . Determine the posteriori probabilities.
Question 2: [CLO1.1, K1, 1 Mark] A communication channel with binary input and quaternary
output alphabet is shown in the figure. The input probabilities and the transition probabilities are
shown on the figure. a. What is the probability of Y=0 ? b. If Y=0 is received, what is the
probability that X=0 was transmitted? What is the probability the X=1 was transmitted?.
Diagonal communicationa) is the traditional flow of communication .pdf
Diagonal communicationa) is the traditional flow of communication .pdffacevenky Diagonal communication
a) is the traditional flow of communication between employees and customers.
b)occurs when individuals from different units and departments within an organization
communicate.
c) is an informal method of communication that can improve decision making within an
organization.
d) flows from lower organizational levels to higher ones.
e) occurs with communication between peers and colleagues within a department. Diagonal
communication is the traditional flow of communication between employees and customers.
occurs when individuals from different units and departments within an organization
communicate. is an informal method of communication that can improve decision making within
an organization. flows from lower organizational levels to higher ones occurs with
communication between peers and colleagues within a department..
Depicted below is footnote #5 for Boeing, Co. for FYE 2021 and 2020,.pdf
Depicted below is footnote #5 for Boeing, Co. for FYE 2021 and 2020,.pdffacevenky Depicted below is footnote #5 for Boeing, Co. for FYE 2021 and 2020, which includes
component amounts making up the net amount of accounts receivable on the balance sheet.
a. Of the components, which typically have a debit balance?
b. Of the components, which typically have a credit balance?
c. Describe how each of the five management assertions(i) existence, (ii) completeness, (iii)
valuation, (iv) rights and obligations, and (v) presentation and disclosurerelate to the components
making up the net balance sheet amount for accounts receivable for Boeing.
Note 5Accounts Receivable, net Accounts receivable at December 31 consisted of the following:
Note 1: Includes foreign military sales through the U.S. government
Note 2: Excludes U.S. government contracts
20212020U.S. Government Contracts*(Note 1)$1,180$811Commercial Airplanes27917Global
Services*(Note 2)1,4561,437Defense, Space & Security*(Note 2)111120Other514Less
Valuation Allowance(390)(444)Total$2,641$1,955.
Create a diagram for the following scenario The music streaming serv.pdf
Create a diagram for the following scenario The music streaming serv.pdffacevenky Create a diagram for the following scenario The music streaming service features different types
of users based on their access type: regular users, superusers, and system administrators. Artists
may create songs that users can listen to, some songs created by multiple artists. Each artist has a
unique Artist ID, name, and genre. Songs represent individual music tracks available on the
platform that can be added to user playlists; each song has Song ID, title, duration, and release
date. Playlists are collections of songs selected by users, each playlist have a unique Playlist ID,
name, and creation date. Users might create empty playlists. System records updated date every
time user updates playlist. Users can access multiple on-demand reports, including a monthly
usage report, favorite songs report, songs genre report, and others. Hint: Do not assume anything,
do not add unnecessary details, and do not overthink.
Create a function that will read the saved projects from localStorag.pdf
Create a function that will read the saved projects from localStorag.pdffacevenky Create a function that will read the saved projects from localStorage.
Create a table row () element and save it to a variable.
If the project is past due, give the row a class so that the row for the project will have a light red
background. If the project is due today, give the row a class so that the row will have a light
yellow background.
Create a table detail () element for each of the corresponding project fields in Task 1.
Append each element to the .
Append each to the element on the page.
Don't forget to clear the before adding all the rows.
Add a call to the function when the page loads.
Update the function responsible for capturing form data so that it calls the function for printing
the data.
Given Js:.
Dawn Company general ledger shows the following account balances amo.pdf
Dawn Company general ledger shows the following account balances amo.pdffacevenky Dawn Company general ledger shows the following account balances among others on Dec 31,
2022:
Problems:
The following transactions occurred during 2023
A) Jan 10, Issued 1,000 common shares at $25 per share for cash
B) Feb 8, Bought and canceled 200 common shares at $20 per share
C) Issued 1,000 preferred shares for $10 per share cash
D) Mar 9, Issued 200 common shares at $40 per share for cash
E) Apr 9, Bought and canceled 200 common shares at $50 per share
F) June 6, Bought and canceled 2,000 common shares at $50 per share
G) July 2 declare cash dividends amount of $3 per common share and 8% for preferred shares,
for the date of records Aug 24, payable on Oct 10.
Needed:Preferred shares, no par value, 8%, cumulative and participating, 1,000 issued &
outstanding 100,000 Common shares, no par value, 20,000 authorized, 6,000 issued, and
outstanding 270,000 Contributed Surplus-common shares
1,000 Contributed Surplus-Preferred shares
10,000 Retained earnings 145,000
Total shareholders equity 526,000.
Create a class Person with two instance variables of type String cal.pdf
Create a class Person with two instance variables of type String cal.pdffacevenky Create a class Person with two instance variables of type String called firstName and
LastName, an instance variable of type int called age, an instance variables of type int
called height (measured in inches), and an instance variable of type double called weight.
Define an appropriate constructor that takes initial values for all instance variables and
calls the corresponding set methods. Define get and set methods for all instance variables.
All set (mutator) methods should validate that reasonable data is being passed to the
object.
Then create a test application that queries the user for information and uses that
information to create an object of type Person. The application should display all
information about the object by calling the get methods and displaying the values
returned.
remember I am new to coding so make this as basic as possible.
Dave and his friend Stewart each owns 50 percent of KBS. During the .pdf
Dave and his friend Stewart each owns 50 percent of KBS. During the .pdffacevenky Dave and his friend Stewart each owns 50 percent of KBS. During the year, Dave received
$80,000 compensation for services he performed for KBS during the year. He performed a
significant amount of work for the entity, and he was heavily involved in management decisions
for the entity (he was not a passive investor in KBS). After deducting Dave's compensation, KBS
reported taxable income of $32,000. How much FICA and/or self-employment tax is Dave
required to pay on his compensation and his share of the KBS income if KBS is formed as a C
corporation, an S corporation, or a limited liability company (taxed as a partnership) (ignore the
0.9 percent additional Medicare tax)? How much FICA tax would the ent be required to pay on
the compensation paid to Dave.
Copy your completed LinkedList class from Lab 3 into the LinkedList..pdf
Copy your completed LinkedList class from Lab 3 into the LinkedList..pdffacevenky Copy your completed LinkedList class from Lab 3 into the LinkedList.java file below.
During this lab we will add more constructors, an equals method and more challenging methods
as listed below.
Also inspect the LabProgram.java file and notice that the main() method of the LabProgram
copies and compares two linked lists. The main() method also calls the more challenging
methods. Use Develop mode to test your LinkedList iterator code as you develop it.
In Submit mode you will need to complete all lab steps to pass all automatic tests.
Step 2: Implement clear()
Method clear() re-sets the LinkedList to empty as if the default constructor had just been called.
Constructor LinkedList(T[] array) converts the given array into a LinkedList.
Constructor LinkedList(LinkedList original) instantiates a new LinkedList by copying another
List.
Method equals() determines whether the given Object is another LinkedList, containing the same
data in the same order, returning whether there is equality.
Method spinList(int numMoves) moves all nodes in the list towards the end of the list the
number of times specified. Any node that falls off the end of the list as it moves forward will be
placed at the front of the list.
Method altLists() splices together two LinkedLists to create a third List which contains
alternating values from the original list and the given parameter.
*Below is my Lab3 LinkedList.class.
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
/**** CONSTRUCTORS ****/
/**
* Instantiates a new LinkedList with default values
* @postcondition
*/
public LinkedList() {
first = null;
last = null;
iterator = null;
length = 0;
}
/**
* Converts the given array into a LinkedList
* @param array the array of values to insert into this LinkedList
* @postcondition
*/
public LinkedList(T[] array) {
}
/**
* Instantiates a new LinkedList by copying another List
* @param original the LinkedList to copy
* @postcondition a new List object, which is an identical,
* but separate, copy of the LinkedList original
*/
public LinkedList(LinkedList original) {
}
public T getFirst() throws NoSuchElementException {
if (first == null) throw new NoSuchElementException();
return first.data;
}
public T getLast() throws NoSuchElementException {
if (last == null) throw new NoSuchElementException();
return last.data;
}
public T getIterator() throws NullPointerException {
if (iterator == null) {
throw new NullPointerException("Iterator is off end.");
}
return iterator.data;
}
public int getLength() {
return length;
}
public boolean isEmpty() {
return length == 0;
}
public boolean offEnd() {
return iterator == null;
}
public void addFirst(T data) {
Node newNode = new Node(data);
if (length == 0) {
first = newNode;
last = newNode;
} else .
Contreras article is about different reforms that have been introdu.pdf
Contreras article is about different reforms that have been introdu.pdffacevenky Contreras' article is about different reforms that have been introduced in order to bring more of
value-based care to the Medicare Program. This program helps to emphasize quality of the care
patients are receiving, not just the amount of services they can have access to. The program is
also becoming more efficient in saving money, while still bringing value-care to patients. This
value act also serves to bring care to the harder to reach patients as well as the underserved. It
also serves to assist with financials, give help to new organizations and physicians assisting those
on Medicare, and to help Medicare and Medicaid better sustainable as well as more appealing to
users and more efficient. (Contreras, 2023). This source seems to be credible, as it aligns with
what the CMS.gov website puts out on the topic to include how the Medicare Access and CHIP
Reauthorization Act (MACRA) are to be revised and assist communities better. (U.S. Centers for
Medicare & Medicaid Services, 2023).
Are these issues with Medicare and Medicaid services a common factor with phyisicians/medical
faciltiies? It seems the number one struggle for most organizations is to file claims properly in
order to remain compliant and receive full reimbursements..
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All the materials around us are made up of elements. These elements can be broadly divided into two major groups:
Metals
Non-Metals
Each group has its own unique physical and chemical properties. Let's understand them one by one.
Physical Properties
1. Appearance
Metals: Shiny (lustrous). Example: gold, silver, copper.
Non-metals: Dull appearance (except iodine, which is shiny).
2. Hardness
Metals: Generally hard. Example: iron.
Non-metals: Usually soft (except diamond, a form of carbon, which is very hard).
3. State
Metals: Mostly solids at room temperature (except mercury, which is a liquid).
Non-metals: Can be solids, liquids, or gases. Example: oxygen (gas), bromine (liquid), sulphur (solid).
4. Malleability
Metals: Can be hammered into thin sheets (malleable).
Non-metals: Not malleable. They break when hammered (brittle).
5. Ductility
Metals: Can be drawn into wires (ductile).
Non-metals: Not ductile.
6. Conductivity
Metals: Good conductors of heat and electricity.
Non-metals: Poor conductors (except graphite, which is a good conductor).
7. Sonorous Nature
Metals: Produce a ringing sound when struck.
Non-metals: Do not produce sound.
Chemical Properties
1. Reaction with Oxygen
Metals react with oxygen to form metal oxides.
These metal oxides are usually basic.
Non-metals react with oxygen to form non-metallic oxides.
These oxides are usually acidic.
2. Reaction with Water
Metals:
Some react vigorously (e.g., sodium).
Some react slowly (e.g., iron).
Some do not react at all (e.g., gold, silver).
Non-metals: Generally do not react with water.
3. Reaction with Acids
Metals react with acids to produce salt and hydrogen gas.
Non-metals: Do not react with acids.
4. Reaction with Bases
Some non-metals react with bases to form salts, but this is rare.
Metals generally do not react with bases directly (except amphoteric metals like aluminum and zinc).
Displacement Reaction
More reactive metals can displace less reactive metals from their salt solutions.
Uses of Metals
Iron: Making machines, tools, and buildings.
Aluminum: Used in aircraft, utensils.
Copper: Electrical wires.
Gold and Silver: Jewelry.
Zinc: Coating iron to prevent rusting (galvanization).
Uses of Non-Metals
Oxygen: Breathing.
Nitrogen: Fertilizers.
Chlorine: Water purification.
Carbon: Fuel (coal), steel-making (coke).
Iodine: Medicines.
Alloys
An alloy is a mixture of metals or a metal with a non-metal.
Alloys have improved properties like strength, resistance to rusting.
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With fierce competition in today’s job market, candidates need a lot more than a good CV and interview skills to stand out from the crowd.
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Structure
1. *Brain*: The insect brain is a complex structure that processes sensory information, controls behavior, and integrates information.
2. *Ventral nerve cord*: A chain of ganglia (nerve clusters) that runs along the insect's body, controlling movement and sensory processing.
3. *Peripheral nervous system*: Nerves that connect the central nervous system to sensory organs and muscles.
Functions
1. *Sensory processing*: Insects can detect and respond to various stimuli, such as light, sound, touch, taste, and smell.
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3. *Behavioral responThe *nervous system of insects* is a complex network of nerve cells (neurons) and supporting cells that process and transmit information. Here's an overview:
Structure
1. *Brain*: The insect brain is a complex structure that processes sensory information, controls behavior, and integrates information.
2. *Ventral nerve cord*: A chain of ganglia (nerve clusters) that runs along the insect's body, controlling movement and sensory processing.
3. *Peripheral nervous system*: Nerves that connect the central nervous system to sensory organs and muscles.
Functions
1. *Sensory processing*: Insects can detect and respond to various stimuli, such as light, sound, touch, taste, and smell.
2. *Motor control*: The nervous system controls movement, including walking, flying, and feeding.
3. *Behavioral responses*: Insects can exhibit complex behaviors, such as mating, foraging, and social interactions.
Characteristics
1. *Decentralized*: Insect nervous systems have some autonomy in different body parts.
2. *Specialized*: Different parts of the nervous system are specialized for specific functions.
3. *Efficient*: Insect nervous systems are highly efficient, allowing for rapid processing and response to stimuli.
The insect nervous system is a remarkable example of evolutionary adaptation, enabling insects to thrive in diverse environments.
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double linked list header file code#include iostream#include.pdf
- 1. double linked list header file code #include #include #include #include #ifndef DOUBLYSKIPLIST_H #define DOUBLYSKIPLIST_H using namespace std; class Node { public: int value; int level; vector next; vector prev; Node(int val, int lvl) : value(val), level(lvl) { next.resize(lvl + 1, nullptr); prev.resize(lvl + 1, nullptr); } }; class SkipList { public: int level; Node* head; Node* tail; int MAXIMUM_ALLOWED_LEVELS;
- 2. SkipList(int maxLevels) : MAXIMUM_ALLOWED_LEVELS(maxLevels), level(0) { head = new Node(INT_MIN, MAXIMUM_ALLOWED_LEVELS); tail = new Node(INT_MAX, MAXIMUM_ALLOWED_LEVELS); for (int i = 0; i <= MAXIMUM_ALLOWED_LEVELS; i++) { head->next[i] = tail; tail->prev[i] = head; } } int RandomLevel() { float probability = (float)rand() / RAND_MAX; int lvl = 0; while (probability < 0.5 && lvl < MAXIMUM_ALLOWED_LEVELS) { lvl++; probability = (float)rand() / RAND_MAX; } return lvl; } Node* CreateNode(int value, int level) { return new Node(value, level); } void InsertElement(int value) { Node* current = head; vector update(MAXIMUM_ALLOWED_LEVELS + 1, nullptr); for (int i = level; i >= 0; i--) { while (current->next[i]->value < value) {
- 3. current = current->next[i]; } update[i] = current; } current = current->next[0]; if (current->value != value) { int ranLevel = RandomLevel(); if (ranLevel > level) { for (int i = level + 1; i <= ranLevel; i++) { update[i] = head; } level = ranLevel; } Node* n = CreateNode(value, ranLevel); for (int i = 0; i <= ranLevel; i++) { n->next[i] = update[i]->next[i]; n->prev[i] = update[i]; update[i]->next[i]->prev[i] = n; update[i]->next[i] = n; } } } void Delete(int value) { if (!Search(value)) { cout << value << " does not exist" << endl; return; } Node* current = head; vector update(MAXIMUM_ALLOWED_LEVELS + 1, nullptr);
- 4. for (int i = level; i >= 0; i--) { while (current->next[i]->value < value) { current = current->next[i]; } update[i] = current; } current = current->next[0]; for (int i = 0; i <= level; i++) { if (update[i]->next[i] == current) { update[i]->next[i] = current->next[i]; current->next[i]->prev[i] = update[i]; } } delete current; } bool Search(int value) { Node* current = head; for (int i = level; i >= 0; i--) { while (current->next[i]->value < value) { current = current->next[i]; } } current = current->next[0];
- 5. return current->value == value; } void Show() { for (int i = 0; i <= level; i++) { Node* node = head->next[i]; cout << "Level " << i << ": "; while (node != tail) { cout << node->value << " -> "; node = node->next[i]; } cout << "Tail" << endl; } } void ShowBackwards() { Node* currTail = tail; for (int i = 0; i <= level; i++) { Node* node = currTail->prev[i]; cout << "Level " << i << ": "; while (node != head) { cout << node->value << " <- "; node = node->prev[i]; } cout << "Head" << endl; } } }; #endif Priority Queue header file code #ifndef PRIORITYQ_H
- 6. #define PRIORITYQ_H #include #include #include // for INT_MAX #include // for rand() #include #include "doublySkiplist.h" using namespace std; class Node { public: int data; int priority; // Priority is also the level in the skip list std::vector next; std::vector prev; Node(int val, int prio) : data(val), priority(prio) { // Initialize vectors based on priority next.resize(prio + 1, nullptr); prev.resize(prio + 1, nullptr); } }; class PriorityQueue { public: int MAXIMUM_ALLOWED_LEVELS; // Maximum priority/level Node* head; Node* tail; PriorityQueue(int maxLevels) : MAXIMUM_ALLOWED_LEVELS(maxLevels) { head = new Node(INT_MIN, 0);
- 7. tail = new Node(INT_MAX, 0); head->next.resize(MAXIMUM_ALLOWED_LEVELS + 1, tail); tail->prev.resize(MAXIMUM_ALLOWED_LEVELS + 1, head); } ~PriorityQueue() { Node* current = head; while (current) { Node* nextNode = current->next[0]; delete current; current = nextNode; } } void Enqueue(int data, int priority) { Node* node = new Node(data, priority); Node* current = head; for (int i = MAXIMUM_ALLOWED_LEVELS; i >= 0; i--) { while (current->next[i]->priority < priority) { current = current->next[i]; } } for (int i = 0; i <= priority; i++) { node->next[i] = current->next[i]; node->prev[i] = current; current->next[i]->prev[i] = node; current->next[i] = node; } } int Dequeue() { if (IsEmpty()) { cout << "PriorityQueue is empty." << endl; return INT_MIN; // or any other sentinel value }
- 8. // Find and remove the highest priority item Node* current = head->next[MAXIMUM_ALLOWED_LEVELS]; int data = current->data; for (int i = current->priority; i >= 0; i--) { current->prev[i]->next[i] = current->next[i]; current->next[i]->prev[i] = current->prev[i]; delete current; } return data; } bool IsEmpty() const { return head->next[0] == tail; } // Add this member function to the PriorityQueue class vector Process(SkipList& skipList) { vector processedData; // Process items from highest priority to lowest for (int priority = MAXIMUM_ALLOWED_LEVELS; priority >= 0; priority--) { Node* current = head->next[priority]; while (current->data != INT_MAX) { int data = current->data; // Process the item by removing it from the SkipList skipList.Delete(data);
- 9. // Remove the item from the PriorityQueue Node* temp = current; current = current->next[priority]; for (int i = temp->priority; i >= 0; i--) { temp->prev[i]->next[i] = temp->next[i]; temp->next[i]->prev[i] = temp->prev[i]; } delete temp; // Add the processed data to the result processedData.push_back(data); } } // Display the SkipList from highest level to lowest level skipList.ShowBackwards(); return processedData; } }; #endif main.cpp code file below #include #include #include #include "PriorityQ.h" #include "doublyskiplist.h" int main(){ srand(static_cast(time(nullptr))); PriorityQueue queue(3); SkipList q(3);
- 10. queue.Enqueue(5,0); queue.Enqueue(2,1); queue.Enqueue(3,2); //queue.Dequeue(); //queue.ShowQueue(); queue.Process(q); return 0; } l am trying to complete the below task The priority queue holds data in a skip list where each node is doubly linked at every level 1. Each node in the skip list contains an integer data, a non- negative integer priority (this will also be the level index of the node in the skiplist once inserted, default 0 because every node must be part of level 0), a vector of next links and a vector of previous links where the number of links in each vector determines how many levels the node is part of. 1. Maximum value for priority is the maximum allowed level for the skip list, minimum value is 0 Add methods Enqueue, Dequeue, Process to the Priority Queue class When new item is being enqueued set its data and priority to random integers (priority is a random integer between 0 and MAXIMUM_ALLOWED_LEVEL_INDEX which is a property of the SkipList class) Priority of a node determines its level in the skiplist (no coin tosses) When a priority queue is processed, all higher priority items are processed before lower priority items 2. Once an item is processed it is removed from the SkipList 3. The Process method must output the data values in the order they were processed
- 11. 4. Display the skip list from highest level to lowest level to check your code Can you tell me why code doesn't output anything