Infix to Prefix (Conversion, Evaluation, Code)
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The document summarizes an assignment on converting infix to prefix notation, evaluating infix expressions, and providing pseudocode to perform the conversion. It includes an example infix expression converted to prefix notation, evaluates the expression to verify the conversion is correct, and provides pseudocode that uses a stack to pop operators and operands off an infix string into a prefix notation string.
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![Arr = (Infix Expression)
Set loop_counter to length_ of_ Arr
do
character = arr[loop_counter]
if character is operator
push character to prefix_stack
if character is ‘)’
push character to stack
if character is ‘(’
do
pop character and push it to prefix_stack
until character equals ‘(‘
if character is operator
if character_precedence is greater OR is equal to stack[top]_ precedence
push to stack
else
do
pop from stack and push to prefix_stack
until condition satisfices
loop_counter = loop_counter - 1
While loop_counter IS NOT EQUAL to 0
Pop out prefix_stack and display each element](https://image.slidesharecdn.com/infixtoprefix-130421063214-phpapp02/85/Infix-to-Prefix-Conversion-Evaluation-Code-5-320.jpg)
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Infix to Postfix) Write a program that converts an infix expression into an equivalent postfix
expression. The rules to convert an infix expression into an equivalent postfix expression are as
follows:
Initialize pfx to an empty expression and also initialize the stack.
Get the next symbol, sym, from infx.
If sym is an operand, append sym to pfx.
If sym is (, push sym into the stack.
If sym is ), pop and append all of the symbols from the stack until the most recent left
parentheses. Pop and discard the left parentheses.
If sym is an operator:
Pop and append all of the operators from the stack to pfx that are above the most recent left
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everything from the stack.
In this program, you will consider the following (binary) arithmetic operators: +, -, *, and /.
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the infix and postfix strings. The class must include the following operations:
getInfix: Stores the infix expression.
showInfix: Outputs the infix expression.
showPostfix: Outputs the postfix expression.
convertToPostfix: Converts the infix expression into a postfix expression. The resulting postfix
expression is stored in pfx.
precedence: Determines the precedence between two operators. If the first operator is of higher
or equal precedence than the second operator, it returns the value true; otherwise, it returns the
value false.
A + B - C;
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Infix Expression: A+B-C;
Postfix Expression: AB+C-
Infix Expression: (A+B)*C;
Postfix Expression: AB+C*
Infix Expression: (A+B)*(C-D);
Postfix Expression: AB+CD-*
Infix Expression: A+((B+C)*(E-F)-G)/(H-I);
Postfix Expression: ABC+EF-*G-HI-/+
Infix Expression: A+B*(C+D)-E/F*G+H;
Postfix Expression: ABCD+*+EF/G*-H+
PLEASE PROVIDE FOLLOWING.
A UML diagram for your class.
The header file for your class.
The implementation file for your class.
The source code for your test program.
Solution
#include
using namespace std;
const int MAX = 50 ;
class InfixToPostfix
{
private :
char target[MAX], stack[MAX] ;
char *s, *t ;
int top ;
public :
InfixToPostfix( ) ;
void getInfix ( char *str ) ;
void showInfix () ;
void push ( char c ) ;
char pop( ) ;
void convertToPostfix( ) ;
int precedence ( char c ) ;
void showPostfix( ) ;
void Delete();
} ;
InfixToPostfix :: InfixToPostfix( )
{
top = -1 ;
strcpy ( target, \"\" ) ;
strcpy ( stack, \"\" ) ;
t = target ;
s = \"\" ;
}
void InfixToPostfix :: getInfix ( char *str )
{
s = str ;
}
void InfixToPostfix :: showInfix ( )
{
cout<<\"Infix Expression :\"<= precedence ( *s ) )
{
*t = opr ;
t++ ;
opr = pop( ) ;
}
push ( opr ) ;
push ( *s ) ;
}
else
push ( *s ) ;
s++ ;
}
if ( *s == \')\' )
{
opr = pop( ) ;
while ( ( opr ) != \.
Stacks.ppt
Stacks.pptOliverKane3 - Templates in C++ allow functions and classes to be reused for different data types through generic programming. This avoids defining multiple functions to handle the same task on different types.
- A template can be viewed as a variable that can be instantiated to any data type. Two functions min() are shown, one for ints and one for doubles, demonstrating the need for templates.
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- 2. A) CONVERSION INFIX EXPRESSION TO PREFIX. B) EVALUATION OF INFIX EXPRESSION (AND VERIFICATION). C) PSEUDO CODE TO CONVERT INFIX TO PREFIX PART A - Let have an Infix Expression ( (A+B) * (C+D) / (E-F) ) + G - Reading Expression from “right to left” character by character. - We have Input, Prefix_Stack & Stack. - Now converting this expression to Prefix. Input Prefix_Stack Stack G G (empty) + G + ) G + ) ) G + ) ) F GF + ) ) - GF + ) ) - E GFE + ) ) - ( GFE- + ) / GFE- + ) / ) GFE- + ) / ) D GFE-D + ) / ) + GFE-D + ) / ) + C GFE-DC + ) / ) +
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