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Physics Helpline
L K Satapathy
Inverse Trigonometry 5
Inverse Trigonometry 5
Physics Helpline
L K Satapathy
Question :
Answer
2
1 1
2 2
11 2tan sin cos , 1, 0, 1
2 1 1
yxFind the value of x y xy
x y
  
    
  
2
1 1
2 2
11 2tan sin cos
2 1 1
yx
x y
  
 
  
1 11tan [sin (sin 2 ) cos (cos2 )]
2
  
 
tan tan1tan (2 2 ) tan( )
2 1 tan .tan 1
[ ]
x y
xy
Ans
 
   
 

     
 
2
1 1
2 2
1 tan1 2tantan sin cos
2 1 tan 1 tan

 
  
  
  
Putting x = tan and y = tan
Inverse Trigonometry 5
Physics Helpline
L K Satapathy
Question :
Answer
   1 cos, tan , ,
1 sin 4 2 2 2
x xProve that x
x
  
   

 
2 2
1 1
2 2
cos sin
cos 2 2tan tan
1 sin cos sin 2sin cos
2 2 2 2
x x
xLHS
x x x x x
 
 
 
      
 
 
2 2
1 1
2
cos sin cos sin
2 2 2 2tan tan
cos sincos sin 2 22 2
x x x x
x xx x
 
       
    
       
 1 1
tan tan
4 2tan tan tan
4 2 4 21 tan tan
[ ]
4 2
x
x RHx S
x

 

 
 
            
 

Physics Helpline
L K Satapathy
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Inverse Trigonometry QA 5

  • 1. Physics Helpline L K Satapathy Inverse Trigonometry 5
  • 2. Inverse Trigonometry 5 Physics Helpline L K Satapathy Question : Answer 2 1 1 2 2 11 2tan sin cos , 1, 0, 1 2 1 1 yxFind the value of x y xy x y            2 1 1 2 2 11 2tan sin cos 2 1 1 yx x y         1 11tan [sin (sin 2 ) cos (cos2 )] 2      tan tan1tan (2 2 ) tan( ) 2 1 tan .tan 1 [ ] x y xy Ans                  2 1 1 2 2 1 tan1 2tantan sin cos 2 1 tan 1 tan             Putting x = tan and y = tan
  • 3. Inverse Trigonometry 5 Physics Helpline L K Satapathy Question : Answer    1 cos, tan , , 1 sin 4 2 2 2 x xProve that x x           2 2 1 1 2 2 cos sin cos 2 2tan tan 1 sin cos sin 2sin cos 2 2 2 2 x x xLHS x x x x x                  2 2 1 1 2 cos sin cos sin 2 2 2 2tan tan cos sincos sin 2 22 2 x x x x x xx x                         1 1 tan tan 4 2tan tan tan 4 2 4 21 tan tan [ ] 4 2 x x RHx S x                        
  • 4. Physics Helpline L K Satapathy For More details: www.physics-helpline.com Subscribe our channel: youtube.com/physics-helpline Follow us on Facebook and Twitter: facebook.com/physics-helpline twitter.com/physics-helpline