MO 2020 DS Applications of Linked List 1 AB.ppt

Programming and Data Structures
Lecture #1
Applications of Linked List

Given two polynomial numbers represented by a linked list. Write a function that
add these lists means add the coefficients who have same variable powers
Example:
Input:
1st number = 5x^2 + 4x^1 + 2x^0
2nd number = 5x^1 + 5x^0
Output: 5x^2 + 9x^1 + 7x^0
Input:
1st number = 5x^3 + 4x^2 + 2x^0
2nd number = 5x^1 + 5x^0
Output: 5x^3 + 4x^2 + 5x^1 + 7x^0
2
Adding two polynomials using Linked List
Courtesy: https://www.geeksforgeeks.org/circular-linked-list/

// C++ program for addition of two polynomials
// using Linked Lists
#include<bits/stdc++.h>
using namespace std;
// Node structure containing power and coefficient of variable
struct Node
{
int coeff;
int pow;
struct Node *next;
}; 4

// Function to create new node
void create_node(int x, int y, struct Node **temp)
{
struct Node *r, *z;
z = *temp;
if(z == NULL)
{
r =(struct Node*)malloc(sizeof(struct Node));
r->coeff = x;
r->pow = y;
*temp = r;
r->next = (struct Node*)malloc(sizeof(struct Node));
r = r->next;
r->next = NULL; }
else
{
r->coeff = x;
r->pow = y;
r->next = (struct Node*)malloc(sizeof(struct Node));
r = r->next;
r->next = NULL; }
}
5

// Function Adding two polynomial numbers
void polyadd(struct Node *poly1, struct Node *poly2, struct Node *poly)
{
while(poly1->next && poly2->next)
{
// If power of 1st polynomial is greater then 2nd, then store 1st as it is and move its pointer
if(poly1->pow > poly2->pow)
{
poly->pow = poly1->pow;
poly->coeff = poly1->coeff;
poly1 = poly1->next;
}
// If power of 2nd polynomial is greater then 1st, then store 2nd as it is and move its pointer
else if(poly1->pow < poly2->pow)
{
}
6

// If power of both polynomial numbers is same then add their
coefficients
else
{
poly->coeff = poly1->coeff+poly2->coeff;
}
// Dynamically create new node
poly->next = (struct Node *)malloc(sizeof(struct Node));
poly = poly->next;
poly->next = NULL;
} 7

while(poly1->next || poly2->next)
{
if(poly1->next)
{
}
if(poly2->next)
{
}
poly->next = (struct Node *)malloc(sizeof(struct Node));
poly = poly->next;
poly->next = NULL;
}
}
8

// Display Linked list
void show(struct Node *node)
{
while(node->next != NULL)
{
printf("%dx^%d", node->coeff, node->pow);
node = node->next;
if(node->next != NULL)
printf(" + ");
}
}
9

// Driver program
int main()
{ struct Node *poly1 = NULL, *poly2 = NULL, *poly = NULL;
// Create first list of 5x^2 + 4x^1 + 2x^0
create_node(5,2,&poly1);
// Create second list of 5x^1 + 5x^0
printf("1st Number: ");
show(poly1);
printf("n2nd Number: ");
show(poly2);
poly = (struct Node *)malloc(sizeof(struct Node)); 10

// Function add two polynomial numbers
polyadd(poly1, poly2, poly);
// Display resultant List
printf("nAdded polynomial: ");
show(poly);
return 0;
}
Output:
1st Number: 5x^2 + 4x^1 + 2x^0
2nd Number: 5x^1 + 5x^0
Added polynomial: 5x^2 + 9x^1 + 7x^0
Time Complexity: O(m + n) where m and n are number of nodes in first and second lists
respectively. 11

A matrix is a two-dimensional data object made of m rows and n columns, thus
having total m x n values. If most of the elements of the matrix have 0 value, then
it is called a sparse matrix
Why to use Sparse Matrix instead of simple matrix ?
Storage: There are lesser non-zero elements than zeros and thus lesser memory
can be used to store only those elements.
Computing time: Computing time can be saved by logically designing a data
structure traversing only non-zero elements..
12
Sparse Matrix and its representations
using Arrays and Linked List

Example:
0 0 3 0 4
0 0 5 7 0
0 0 0 0 0
0 2 6 0 0
Representing a sparse matrix by a 2D array leads to wastage of lots of memory as
zeroes in the matrix are of no use in most of the cases. So, instead of storing zeroes
with non-zero elements, we only store non-zero elements. This means storing non-
zero elements with triples- (Row, Column, value).
Sparse Matrix Representations can be done in many ways following are two common
representations:
Array representation
Linked list representation 13

Example:
0 0 3 0 4
0 0 5 7 0
0 0 0 0 0
0 2 6 0 0
Representing a sparse matrix by a 2D array leads to wastage of lots of memory as
zeroes in the matrix are of no use in most of the cases. So, instead of storing zeroes
with non-zero elements, we only store non-zero elements. This means storing non-
zero elements with triples- (Row, Column, value).
Sparse Matrix Representations can be done in many ways following are two common
representations:
Array representation
Linked list representation 14

Method 1: Using Arrays
2D array is used to represent a sparse matrix in which there are three rows named
as
• Row: Index of row, where non-zero element is located
• Column: Index of column, where non-zero element is located
• Value: Value of the non zero element located at index – (row,column)
15

Method 2: Using Linked Lists
In linked list, each node has four fields. These four fields are defined as:
• Row: Index of row, where non-zero element is located
• Column: Index of column, where non-zero element is located
• Value: Value of the non zero element located at index –
(row,column)
• Next node: Address of the next node
16

MO 2020 DS Applications of Linked List 1 AB.ppt

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MO 2020 DS Applications of Linked List 1 AB.ppt