Mulexml java

XML – Java Conversion in Dataweave Mule
Pre-requisites:
 Anypoint Studio
 Mule ESB Runtime 3.7
 xml input file.
Input XML File
<user>
<name>Max</name>
<lastName>Mule</lastName>
</user>

<http:listener-config name="HTTP_Listener_Configuration"
host="0.0.0.0" port="8081" doc:name="HTTP Listener Configuration"/>
<flow name="testweaveFlow">
<http:listener config-ref="HTTP_Listener_Configuration" path="/"
metadata:id="cab0526f-779e-427c-9a33-be44f9b12696"
doc:name="HTTP"/>
<dw:transform-message doc:name="Transform Message">
<dw:input-payload doc:sample="json.json"/>
<dw:set-payload><![CDATA[%dw 1.0
%type user = :object { class: "testweave.User" }
%output application/java
---
{
firstName: payload.user.name,
lastName: payload.user.lastName
} as :user]]></dw:set-payload>
</dw:transform-message>
<byte-array-to-string-transformer doc:name="Byte Array to
String"/>
</flow>

In the transform code I created the Object type
in the header
“ %type user = :object { class: "testweave.User"}
”
And the payload of the transform is converted
to User Object using the transform logic as
below.
{
firstName: payload.user.name,
lastName: payload.user.lastName
} as :user

package testweave;
public class User {
private String firstName;
private String lastName;
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
@Override
public String toString() {
// TODO Auto-generated method stub
return this.firstName+" "+this.lastName;
}
}

Mulexml java

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