pattern-printing-in-c.pdf

Saikat Banerjee Page 1
Pattern Printing in C
Output :
* * * * *
* * * * *
* * * * *
* * * * *
* * * * *_
Program :
/* Program to print pyramid pattern in C : Pattern 1
#include <stdio.h>
#include <conio.h>
void main()
{
int i,j;
clrscr();
for(i=0; i<5; i++)
{
for(j=0; j<5; j++)
{
printf(" * ");
}
printf("n");
}
getch();
}
Output :
*
* *
* * *
* * * *
* * * * *_
Program :
#include <stdio.h>
#include <conio.h>
void main()
{
int i,j;
clrscr();
for(i=0; i<5; i++)
{
for(j=0; j<=i; j++)

{
printf(" * ");
}
printf("n");
}
getch();
}
Output :
*
* *
* * *
* * * *
* * * * *_
Program :
#include <stdio.h>
#include <conio.h>
void main()
{
int i,j,k;
clrscr();
for(i=1; i<=5; i++)
{
for(j=5; j>=i; j--)
{
printf(" ");
}
for(k=1; k<=i; k++)
{
printf("*");
}
printf("n");
}
getch();
}
Output :
* * * * *
* * * *
* * *
* *
*_
Program :

#include <stdio.h>
#include <conio.h>
void main()
{
int i,j,k,samp=1;
clrscr();
for(i=5; i>=1; i--)
{
for(k=samp; k>=0; k--)
{
printf(" "); // only 1 space
}
for(j=i; j>=1; j--)
{
printf("*");
}
samp = samp + 1;
printf("n");
}
getch();
}
or
#include <stdio.h>
#include <conio.h>
void main()
{
int i,j,k;
clrscr();
for(i=1; i<=5; i++)
{
for(j=5; j>=i; j--)
{
printf("*");
}
for(k=1; k<=i; k++)
{
printf(" ");
}
printf("n");
}
getch();
}
Output :
* * * * *
* * * *
* * *
* *
*_

Program :
#include <stdio.h>
#include <conio.h>
void main()
{
int i,j;
clrscr();
for(i=5; i>=1; i--)
{
for(j=1; j<=i; j++)
{
printf(" * ");
}
printf("n");
}
getch();
}
Output :
*
* *
* * *
* * * *
* * * * *_
Program :
#include <stdio.h>
#include <conio.h>
void main()
{
int i,j,k,t=0;
clrscr();
for(i=1; i<=5; i++)
{
for(k=t; k<5; k++)
{
printf(" ");
}
for(j=0; j< i; j++)
{
printf(" * ");
t = t + 1;
}
printf("n");
}
getch();

}
Output :
*
* *
* * *
* * * *
* * * * *
* * * *
* * *
* *
*_
Program :
Creation Date : 01:13 AM 22/11/2010
Author : www.technoexam.com [Technowell, Sangli] */
#include <stdio.h>
#include <conio.h>
void main()
{
int i,j,k,samp=1;
clrscr();
for(i=1; i<=5; i++)
{
for(k=samp; k<=5; k++)
{
printf(" ");
}
for(j=0; j< i; j++)
{
printf("*");
}
samp = samp + 1;
printf("n");
}
samp = 1;
for(i=4; i>=1; i--)
{
for(k=samp; k>=0; k--)
{
printf(" ");
}
for(j=i; j>=1; j--)
{
printf("*");
}
samp = samp + 1;
printf("n");
}
getch();

}
Output :
Enter number of rows: 5
1
2 3
4 5 6
7 8 9 10
11 12 13 14 15_
Program :
Creation Date : 02:39 PM 01/10/2011
#include <stdio.h>
#include <conio.h>
void main()
{
int rw, c, no=1 ,len;
clrscr();
printf("Enter number of rows: ");
scanf("%d," &len);
for(rw=1; rw<=len; rw++)
{
printf("n");
for(c=1; c<=rw; c++)
{
printf(" %2d ", no);
no++;
}
}
getch();
}
Output :
Enter number of rows: 5
0
1 0 1
2 1 0 1 2
3 2 1 0 1 2 3
4 3 2 1 0 1 2 3 4
5 4 3 2 1 0 1 2 3 4 5_
Program :

#include <stdio.h>
#include <conio.h>
void main()
{
int no,i,y,x=35;
clrscr();
printf("Enter number of rows: ");
scanf("%d," &no);
for(y=0;y<=no;y++)
{
goto(x,y+1);
for(i=0-y; i<=y; i++)
{
printf(" %3d ", abs(i));
x=x-3;
}
}
getch();
}
Output :
1
2 2
3 3 3
4 4 4 4
5 5 5 5 5_
Program :
#include <stdio.h>
#include <conio.h>
void main()
{
int i, j=5, k, x;
clrscr();
for(i=1;i<=5;i++)
{
for(k=1;k<=j;k++)
{
printf(" ");
}
for(x=1;x<=i;x++)

{
printf("%d",i);
printf(" ");
}
printf("n");
j=j-1;
}
getch();
}
Output :
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5_
Program :
#include <stdio.h>
#include <conio.h>
void main()
{
int rw,c,no,spc;
clrscr();
printf("Enter number of rows : ");
scanf("%d", &no);
for(rw=1; rw<=no; rw++)
{
for(spc=no; spc>=rw; spc--)
{
printf(" ");
}
for(c=1; c<=rw; c++)
{
printf("%2d",c);
}
printf("n");
}
getch();
}
Output :

1
1 2 3
1 2 3 4 5
1 2 3 4 5 6 7
1 2 3 4 5 6 7 8 9_
Program :
#include <stdio.h>
#include <conio.h>
void main()
{
int i,j,k;
clrscr();
for(i=1; i<=5; i++)
{
for(j=1; j<=5-i; j++)
{
printf(" ");
}
for(k=1; k<=2*i-1; k++)
{
printf(" %d ",k);
}
printf("n");
}
getch();
}
Output :
A B C D E F G G F E D C B A
A B C D E F F E D C B A
A B C D E E D C B A
A B C D D C B A
A B C C B A
A B B A
A A_
Program :
#include <stdio.h>
#include <conio.h>
void main()

{
int i,j,asci,spc;
clrscr();
for(i=7; i>=1; i--)
{
for(spc=6; spc>=i; spc--)
{
printf(" ");
}
asci=65;
for(j=1; j<=i; j++)
{
printf("%2c",asci++);
}
for(j=i-1; j>=0; j--)
{
printf("%2c",--asci);
}
printf("n");
}
getch();
}
Output :
AAA AAB AAC ABA ABB ABC ACA ACB ACC BAA BAB BAC BBA BBB
BBC BCA BCB BCC CAA CAB CAC CBA CBB CBC CCA CCB CCC_
Program :
/* Program to print all Combinations of characters
A, B, C : Pattern 14
#include <stdio.h>
#include <conio.h>
void main()
{
char ch1, ch2, ch3;
clrscr();
for(ch1='A' ; ch1<='C' ; ++ch1)
{
for(ch2='A' ; ch2<='C' ; ++ch2)
{
for(ch3='A' ; ch3<='C' ; ++ch3)
{
printf(" %c%c%c", ch1, ch2, ch3);
}
}
}
getch();

}
 Write a C program to print the following pattern:
1
0 1
1 0 1
0 1 0 1
1 0 1 0 1
Program:
#include <stdio.h>
int main(void) {
int i, j;
for (i = 0; i < 4; i++) {
for (j = 0; j <= i; j++) {
if (((i + j) % 2) == 0) { // Decides on as to which digit to print.
printf("0");
} else {
printf("1");
}
printf("t");
}
printf("n");
}
return 0;
}
 Write C program to print the following pattern:
0
1 1
2 3 5
8 13 21
Program:
#include <stdio.h>
int main(void) {
int i, j, a = 0, b = 1, temp = 1;
for (i = 1; i <= 4; i++) {
for (j = 1; j <= i; j++) {
if (i == 1 && j == 1) { // Prints the '0' individually first
printf("0");
continue;
}
printf("%d ", temp); // Prints the next digit in the series
//Computes the series
temp = a + b;
a = b;
b = temp;
if (i == 4 && j == 3) { // Skips the 4th character of the base
break;
}
}
printf("n");
}
return 0;
}

 Write C program to print the following pattern:
1
121
12321
1234321
12321
121
1
Program:
#include <stdio.h>
void sequence(int x);
int main() {
/* c taken for columns */
int i, x = 0, num = 7;
for (i = 1; i <= num; i++) {
if (i <= (num / 2) + 1) {
x = i;
} else {
x = 8 - i;
}
sequence(x);
puts("n");
}
return 0;
}
void sequence(int x) {
int j;
for (j = 1; j < x; j++) {
printf("%d", j);
}
for (j = x; j > 0; j--) {
printf("%d", j);
}
}
77777777777
7
7
7
7
7
7
7
7
7
7
Program:
#include <stdio.h>
int main(void) {
int i, j;
for (i = 11; i >= 1; i--) {
for (j = 1; j <= i; j++) {
if (i == 11) {

printf("7"); // Makes sure the base is printed completely
continue;
} else if (j == i) { // Hollows the rest
printf("7");
} else {
printf(" ");
}
}
printf("n");
}
return 0;
}
1
2 4
3 6 9
2 4
1
Program:
#include <stdio.h>
int main(void) {
int i,j;
for (i=1; i<=3 ; i++) {
for (j=1; j<=i; j++) {
printf("%2d", (i*j));
}
printf("n");
}
for (i=2; i>=1; i--) { // As they share the same base
for (j=1; j<=i; j++) {
printf("%2d",i*j);
}
printf("n");
}
return 0;
}
1
1 0
1 0 0
1 0 0 0
1 0 0 0 0
1 0 0 0 0 0
1 0 0 0 0 0 0
1 0 0 0 0 0
1 0 0 0 0
1 0 0 0
1 0 0
1 0
1
Program:
#include <stdio.h>

int main(void) {
int i,j;
for (i=1; i<=7; i++) {
for (j=1; j<=i; j++) {
if (j==1) { // Applying the condition
printf(" 1");
} else {
printf(" 0");
}
}
printf("n");
}
for (i=6; i>=1; i--) { //As it shares the same base i=6
for (j=1; j<=i; j++) {
if (j==1) { // Applying the condition
printf(" 1");
} else {
printf(" 0");
}
}
printf("n");
}
return 0;
}

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