Signals and Systems Assignment Help

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Signals and Systems
Problem 1:
(a) Does the Fourier transform of this signal converge?
(b) For which of the following values of a does the Fourier transform of x(t)e -" converge?
(c) Determine the Laplace transform X(s) of x(t). Sketch the location of the poles and zeros of X(s)
and the ROC.
Problem 2:
Determine the Laplace transform, pole and zero locations, and associated ROC for each of the
following time functions.
Problem 3:
Shown in Figures P20.3-1 to P20.3-4 are four pole-zero plots. For each statement in Table P20.3
about the associated time function x(t), fill in the table with the corresponding constraint on the
ROC
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Constraint on ROC for Pole-Zero Pattern
Problem 4:
Determine x(t) for the following conditions if X(s) is given by
(a) x(t) is right-sided
(b) x(t) is left-sided
(c) x(t) is two-sided

Problem 5:
An LTI system has an impulse response h(t) for which the Laplace transform H(s) is
Determine the system output y(t) for all t if the input x(t) is given by
Problem 6:
(a) From the expression for the Laplace transform of x(t), derive the fact that the Laplace transform of
x(t) is the Fourier transform of x(t) weighted by an exponential.
(b) Derive the expression for the inverse Laplace transform using the Fourier transform synthesis
equation.
Problem 7:
Determine the time function x(t) for each Laplace transform X(s).

Problem 8:
The Laplace transform X(s) of a signal x(t) has four poles and an unknown number of zeros. x(t) is
known to have an impulse at t = 0. Determine what information, if any, this provides about the
number of zeros.
Problem 9:
Determine the Laplace transform, pole-zero location, and associated ROC for each of the following
time functions.

Problem 10:
(a) If x(t) is an even time function such that x(t) = x(- t), show that this requires that X(s) = X(-s).
(b) If x(t) is an odd time function such that x(t) = -x(--t), show that X(s) = -X(-s).
(c) Determine which, if any, of the pole-zero plots in Figures P20.10-1 to P20.10-4 could correspond
to an even time function. For those that could, indicate the required ROC.

(d) Determine which, if any, of the pole-zero plots in part (c) could correspond to an odd time
function. For those that could, indicate the required ROC.

Solution
Solution 1:
(a) The Fourier transform of the signal does not exist because of the presence of growing
exponentials. In other words, x(t) is not absolutely integrable.
(b) (i) For the case a = 1, we have that
Although the growth rate has been slowed, the Fourier transform still does not converge.
(ii) For the case a = 2.5, we have that
The first term has now been sufficiently weighted that it decays to 0 as t goes to infinity. However,
since the second term is still growing exponentially, the Fourier transform does not converge.
(iii) For the case a = 3.5, we have that
Both terms do decay as t goes to infinity, and the Fourier transform converges. We note that for any
value of a > 3.0, the signal x(t)e -' decays exponentially, and the Fourier transform converges.
(c) The Laplace transform of x(t) is

and its pole-zero plot and ROC are as shown in Figure S20.1
Note that if a > 3.0, s = a + jw is in the region of convergence because, as we showed in part (b)(iii),
the Fourier transform converges.
Solution 2:

as shown in Figure S20.2-1.
The Laplace transform converges for Re~s) + a > 0, so
as shown in Figure S20.2-2.

Solution 3:
(a) (i) Since the Fourier transform of x(t)e ~'exists, a = 1 must be in the ROC. Therefore only one
possible ROC exists, shown in Figure S20.3-1.
(ii) We are specifying a left-sided signal. The corresponding ROC is as given in Figure S20.3-2.

Solution 4:
(iii) We are specifying a right-sided signal. The corresponding ROC is as given in Figure S20.3-3.
(b) Since there are no poles present, the ROC exists everywhere in the s plane.
(c) (i) a = 1 must be in the ROC. Therefore, the only possible ROC is that shown in Figure S20.3-4.

(ii) We are specifying a left-sided signal. The corresponding ROC is as shown in Figure S20.3-5.

(iii) We are specifying a right-sided signal. The corresponding ROC is as shown in Figure S20.3-9.
Constraint on ROC for Pole-Zero Pattern

Solution 5:
(a) For x(t) right-sided, the ROC is to the right of the rightmost pole, as shown in Figure S20.4-1.
Using partial fractions,
(b) For x(t) left-sided, the ROC is to the left of the leftmost pole, as shown in Figure S20.4-2.

Since
we conclude that
(c) For the two-sided assumption, we know that x(t) will have the form
We know the inverse Laplace transforms of the following:

Which of the combinations should we choose for the two-sided case? Suppose we choose
We ask, For what values of a does x(t)e -0' have a Fourier transform? And we see that there are
no values. That is, suppose we choose a > -1, so that the first term has a Fourier transform. For a
> -1, e - 2 te -'' is a growing exponential as t goes to negative infinity, so the second term does
not have a Fourier transform. If we increase a, the first term decays faster as t goes to infinity,
but the second term grows faster as t goes to negative infinity. Therefore, choosing a > -1 will not
yield a Fourier transform of x(t)e -'. If we choose a 5 -1, we note that the first term will not have
a Fourier transform. Therefore, we conclude that our choice of the two-sided sequence was
wrong. It corresponds to the invalid region of convergence shown in Figure S20.4-3.

If we choose the other possibility,
we see that the valid region of convergence is as given in Figure S20.4-4.
Solution 6:
There are two ways to solve this problem.
Method 1
This method is based on recognizing that the system input is a superposition of eigenfunctions.
Specifically, the eigenfunction property follows from the convolution integral

Now we recognize that
i.e., e a' is an eigenfunction of the system. Using linearity and superposition, we recognize that if
then
so that
Method 2
We consider the solution of this problem as the superposition of the response to two signals x 1(t), x
2(t), where x 1(t) is the noncausal part of x(t) and x 2(t) is the causal part of x(t). That is,

This allows us to use Laplace transforms, but we must be careful about the ROCs. Now consider L{xi(t)},
where C{-} denotes the Laplace transform:
Now since the response to x 1(t) is
The pole-zero plot and associated ROC for Yi(s) is shown in Figure S20.5-1.

Next consider the response y2 (t) to x 2(t):
The pole-zero plot and associated ROC for Y2(s) is shown in Figure S20.5-2.

Solution 7:
We see that the Laplace transform is the Fourier transform of x(t)e -'' from the definition of the
Fourier analysis formula.
This result is the inverse Fourier transform, or synthesis equation. So

Solution 8:

Solution 9:
The Laplace transform of an impulse ab(t) is a.Therefore, if we expand a rational Laplace transform
by dividing the denominator into the numerator, we require a constant term in the expansion. This
will occur only if the numerator has order greater than or equal to the order of the denominator.
Therefore, a necessary condition on the number of zeros is that it be greater than or equal to the
number of poles. This is only a necessary and not a sufficient condition as it is possible to
construct a rational Laplace transform that has a numerator order greater than the denominator
order and that does not yield a constant term in the expansion. For example,
which does not have a constant term. Therefore a necessary condition is that the number of zeros
equal or exceed the number of poles.
Solution 10:

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