Using the provided table interface table.h and the sample linked lis.pdf

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Using the provided table interface table.h and the sample linked list code linkedList.c, complete an implementation of the Table ADT. Make sure that you apply the concepts of design by contract (DbC) to your implementation. Once you have fully implemented the table, create a main.c file that implements a testing framework for your table. Your table implementation must ensure that values inserted are unique, and internally sorted within a linked list. table.h linkedList.c Solution khsdg #include #include typedef enum BOOL { false, true } bool; // Linked list node definition typedef struct Node node; struct Node { int number; node *next; }; static node *top = NULL; // used to track where we are for the list traversal methods static node *traverseNode = NULL; // \"destroy\" will deallocate all nodes in a linked list object // and will set \"top\" to NULL. void destroy() { node *curr = top; node *temp = NULL; while ( curr != NULL ) { // flip order to see it blow up... temp = curr; curr = curr->next; free( temp ); } top = NULL; } // \"build\" will create an ordered linked list consisting // of the first \"size\" even integers. void build( int size ) { node *newNode = NULL; int i = 0; // make sure we don\'t have a list yet destroy(); for ( i=size ; i>0 ; i-- ) { newNode = malloc( sizeof( node ) ); newNode->number = i*2; newNode->next = top; top = newNode; } } // starts a list traversal by getting the data at top. // returns false if top == NULL. bool firstNode( int *item ) { bool result = false; if ( top ) { *item = top->number; traverseNode = top->next; result = true; } return result; } // gets the data at the current traversal node and increments the traversal. // returns false if we\'re at the end of the list. bool nextNode( int *item ) { bool result = false; if ( traverseNode ) { *item = traverseNode->number; traverseNode = traverseNode->next; result = true; } return result; } // \"print\" will output an object\'s entire linked list // to the standard output device -- one \"number\" per line. void print() { int value; if ( firstNode( &value ) ) { do { printf( \"%d\ \", value ); } while ( nextNode( &value ) ); } } int main( int argc, char *argv[] ) { build( 10 ); print(); destroy(); build( 5 ); build( 20 ); print(); destroy(); return 0; }.

// flip order to see it blow up...
temp = curr;
curr = curr->next;
free( temp );
}
top = NULL;
}
// "build" will create an ordered linked list consisting
// of the first "size" even integers.
void build( int size )
{
node *newNode = NULL;
int i = 0;
// make sure we don't have a list yet
destroy();
for ( i=size ; i>0 ; i-- )
{
newNode = malloc( sizeof( node ) );
newNode->number = i*2;
newNode->next = top;
top = newNode;
}
}
// starts a list traversal by getting the data at top.
// returns false if top == NULL.
bool firstNode( int *item )
{
bool result = false;
if ( top )
{
*item = top->number;
traverseNode = top->next;
result = true;
}
return result;
}

// gets the data at the current traversal node and increments the traversal.
// returns false if we're at the end of the list.
bool nextNode( int *item )
{
bool result = false;
if ( traverseNode )
{
*item = traverseNode->number;
traverseNode = traverseNode->next;
result = true;
}
return result;
}
// "print" will output an object's entire linked list
// to the standard output device -- one "number" per line.
void print()
{
int value;
if ( firstNode( &value ) )
{
do
{
printf( "%d ", value );
} while ( nextNode( &value ) );
}
}
int main( int argc, char *argv[] )
{
build( 10 );
print();
destroy();
build( 5 );
build( 20 );
print();
destroy();
return 0;

C++: Doubly-Linked Lists The goal of the exercise is to implement a class List of doubly- linked lists. My goal is to implement the class in a file doubly-linked.cpp. The class List implements lists using the following structures for list elements: struct Node { int val ; Node next; Node prev; }; Each Node contains a value (an integer) and two pointers: one meant to point to the next element of the list and one meant to point to the previous element in the list. The class provides the following methods that you need to implement: • A constructor and a destructor, with no arguments; • void insert(int n): insert an integer at the end of the list; • void reverse(): reverse the list; • void print(): print the list to cout in the same format as the input (i.e. integers separated by spaces); doubly-linked.h #ifndef __dll__ #define __dll__ #include using namespace std; // Basic structure to store elements of a list struct Node { int val; // contains the value Node * next; // pointer to the next element in the list Node * prev; // pointer to the previous element in the list }; // Class List class List { public: List(void); // Constructor ~List(void); // Destructor void insert(int n); // This should insert n in the list void reverse(void); // This should reverse the list void print(void); // This shoiuld print the list private: Node * first; // Pointer to the first (if any) element in the list }; #endif main.cpp #include #include \"doubly-linked.h\" using namespace std; int main(void){ List l; int n; while(cin >> n){ l.insert(n); } // Print list as read from cin l.print(); // Reverse the list and print it l.reverse(); l.print(); // Reverse again and print it l.reverse(); l.print(); return 0; } Solution #include using namespace std; /* Linked list structure */ struct list { struct list *prev; int data; struct list *next; } *node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL; class linkedlist { public: /* Function for create/insert node at the beginning of Linked list */ void insrt_frnt() { list *addBeg = new list; cout << \"Enter value for the node:\" << endl; cin >> addBeg->data; if(first == NULL) { addBeg->prev = NULL; addBeg->next = NULL; first = addBeg; last = addBeg; cout << \"Linked list Created!\" << endl; } else { addBeg->prev = NULL; first->prev = addBeg; addBeg->next = first; first = addBeg; cout << \"Data Inserted at the beginning of the Linked list!\" << endl; } } /* Function for create/insert node at the end of Linked list */ void insrt_end() { list *addEnd = new list; cout << \"Enter value for the node:\" << endl; cin >> addEnd->data; if(first == NULL) { addEnd->prev = NULL; addEnd->next = NULL; first = addEnd; last = addEnd; cout << \"Linked list Created!\" << endl; } else { addEnd->next = NULL; last->next = addEnd; addEnd->prev = last; last = addEnd; cout << \"Data Inserted at the end of the Linked list!\" << endl; } } /* Function for Display Linked list */ void display() { node = first; cout << \"List of data in L.

Lab-2.4 101.pdf21E135MAHIESHWARJ

The document contains C program code to implement three data structures using linked lists: 1) A stack using a singly linked list with push, pop, and display functions. 2) A queue using a singly linked list with enqueue, dequeue, and display functions. 3) A program to merge two sorted linked lists by comparing nodes and appending to the merged list. Pseudocode and sample test cases are provided for each problem.

This assignment and the next (#5) involve design and development of a.pdfEricvtJFraserr

This assignment and the next (#5) involve design and development of a sequential non contiguous and dynamic datastructure called LinkedList. A linked list object is a container consisting of connected ListNode objects. As before, we are not going to use pre-fabricated classes from the c++ library, but construct the LinkedList ADT from scratch. The first step is construction and testing of the ListNode class. A ListNode object contains a data field and a pointer to the next ListNode object (note the recursive definition). #This assignment requires you to 1. Read the Assignment 4 Notes 2. Watch the Assignment 4 Support video 3. Implement the following methods of the ListNode class -custom constructor -setters for next pointer and data 4. Implement the insert and remove method in the main program 5. Scan the given template to find the above //TODO and implement the code needed //TODO in ListNodecpp.h file public: ListNode(T idata, ListNode<T> * newNext); public: void setNext(ListNode<T> * newNext); public: void setData(T newData); // TODO in main program void remove(ListNode<int> * &front,int value) void insert(ListNode<int> * &front,int value) # The driver is given ListNodeMain.cpp is given to you that does the following tests 1. Declares a pointer called front to point to a ListNode of datatype integer 2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked list. 3. Inserts ListNode with data 3 to the list 4. Removes node 1 and adds it back to test removing and adding the first element 5. Removes node 3 to test removing a middle node 6. Removes node 4 to test removing the last node 7. Attempt to remove a non existent node 8. Remove all existing nodes to empty the list 9. Insert node 4 and then node 1 to test if insertions preserve order 10.Print the list Main.cpp #include <iostream> #include "ListNodecpp.h" // REMEMBER each ListNode has two parts : a data field // and an address field. The address is either null or points to the next node //in the chain //Requires: integer value for searching, address of front //Effects: traverses the list node chain starting from front until the end comparing search value with listnode getData. Returns the original search value if found, if not adds +1 to indicate not found //Modifies: Nothing int search(ListNode<int> * front, int value); //Requires: integer value for inserting, address of front //Effects: creates a new ListNode with value and inserts in proper position (increasing order)in the chain. If chain is empty, adds to the beginning //Modifies: front, if node is added at the beginning. //Also changes the next pointer of the previous node to point to the //newly inserted list node. the next pointer of the newly inserted pointer //points to what was the next of the previous node. //This way both previous and current links are adjusted //******** NOTE the use of & in passing pointer to front as parameter - // Why do you think this is needed ?********** void insert(ListNode<int> * &fr.

could you implement this function please, im having issues with it..pdfferoz544

could you implement this function please, im having issues with it. void makeList (const ListNode::value_type [],const size_t& count) class ListNode { public: typedef int value_type; ListNode (value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; } //Assessor value_type getDatum () const { return datum; } ListNode const* getNext () const { return next; } //Mutator void setDatum (const value_type& d) {datum = d; } ListNode* getNext () { return next; } void setNext (ListNode* new_link) {next = new_link; } private: value_type datum; ListNode* next; }; class LinkedList { public: LinkedList (); virtual ~LinkedList (); void insertItem (ListNode::value_type); void makeList (const ListNode::value_type [],const size_t& count); void deleteList (); //The following friend function is implemented in lablinklist.cpp friend std::ostream& operator<<(std::ostream&, const LinkedList&); private: ListNode* head; }; This is the pseudocode, but i still have a hard time undertanding it. Creating a List (makeList(const ListNode::value_type [],const size_t& count)) This function receives an array in the order that we want to add it to the linkedlist. Index 0 will be the head node, index n will be the last node. First, create a node initialized with a data value and a NULL pointer. Set the \"head\" to point to the first node. Set up a current-pointer to the first node (or \"head\"). Get a data value for the next node. While more nodes to add { Create a new node initialized with the data value and a NULL pointer. Set the current-pointer link member (\"next\") to the new node. Set the current-pointer to point to the new node. Get a data value for the next node. } Thanks. Solution //linkedList.h #ifndef LINKEDLIST_H #define LINKEDLIST_H #include #include class ListNode { public: typedef int value_type; ListNode(value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; } //Assessor value_type getDatum() const { return datum; } ListNode const* getNext() const { return next; } //Mutator void setDatum(const value_type& d) { datum = d; } ListNode* getNext() { return next; } void setNext(ListNode* new_link) { next = new_link; } private: value_type datum; ListNode* next; }; class LinkedList { public: LinkedList(); virtual ~LinkedList(); void insertItem(ListNode::value_type); void makeList(const ListNode::value_type[], const size_t& count); void deleteList(); //The following friend function is implemented in lablinklist.cpp friend std::ostream& operator<<(std::ostream&, const LinkedList&); private: ListNode* head; }; #endif ------------------------------------------------------------- //linkedList.cpp #include \"linkedlist.h\" LinkedList::LinkedList() { head = NULL; } LinkedList::~LinkedList() { ListNode *tmp = head; while (tmp != NULL) { head = head->getNext(); delete tmp; tmp = head; } } void LinkedList::insertItem(ListNode::value_type item) { ListNode *newNode,*cur = head; newNode = new ListNode; newNode->setDatum(item); newNode->setNext(NULL);.

C Exam Help Programming Exam Help

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#includeiostream #includecstdio #includecstdlib using na.pdfharihelectronicspune

#include #include #include using namespace std; struct node { int val; struct node *next; }*startNode; // declaring class class LinkedList { public: node* create_node(int); void insert_last(); void sort(); void search(); void reverse(); void display(); LinkedList() { startNode = NULL; } }; // main main() { int userChoice, linkedListNodes, i; LinkedList LinkList; startNode = NULL; while (1) { // displaying menu cout<<\" 1)Insert\"; cout<<\"2) Remove\"; cout<<\"3) Search\"; cout<<\"4) Display\"; cout<<\"5) Reverse\"; cout<<\"6) Exit \"; // reading user choice cout<<\"Enter your userChoice : \"; cin>>userChoice; switch(userChoice) { case 1: cout<<\"Inserting node to linked list: \"; LinkList.insert_begin(); cout; break; case 2: cout<<\"Delete element from linked list: \"; LinkList.delete(); break; case 3: cout<<\"Searching data in linked list: \"; LinkList.search(); cout; break; case 4: cout<<\"Displaying linked list data: \"; LinkList.display(); cout; break; case 5: cout<<\"Linked list reversing: \"; LinkList.reverse(); cout; break; case 6: cout<<\"Exiting...\"; exit(1); break; default: cout<<\"Enter correct userChoice\"; } } } // node creating to store into list node *LinkedList::create_node(int val) { struct node *tempNode, *tempNode; tempNode = new(struct node); if (tempNode == NULL) { cout<<\"No memory allocated \"; return 0; } else { tempNode->val = val; tempNode->next = NULL; return tempNode; } } /* * Inserting Node at last */ void LinkedList::insert_last() { int val; cout<<\"Enter the val to be inserted: \"; cin>>val; struct node *tempNode, *tempNode; tempNode = create_node(val); tempNode = startNode; while (tempNode->next != NULL) { tempNode = tempNode->next; } tempNode->next = NULL; tempNode->next = tempNode; cout<<\"Element Inserted\"; } // deleting element void LinkedList::delete() { int position, i, count = 0; if (startNode == NULL) { cout<<\"Linkedlist empty\"<>position; struct node *tempNode, *ptr; tempNode = startNode; if (position == 1) { startNode = tempNode->next; } else { while (tempNode != NULL) { tempNode = tempNode->next; count++; } if (position > 0 && position <= count) { tempNode = startNode; for (i = 1;i < position;i++) { ptr = tempNode; tempNode = tempNode->next; } ptr->next = tempNode->next; } else { cout<<\"Enter correct position\"; } } } // search data in linked list void LinkedList::search() { int val, position = 0; bool flagValue = false; if (startNode == NULL) { cout<<\"List is empty\"; return; } cout<<\"Enter the val to search: \"; cin>>val; struct node *tempNode; tempNode = startNode; while (tempNode != NULL) { position++; if (tempNode->val == val) { flagValue = true; cout<<\"Data \"<next; } if (!flagValue) cout<<\"data not found\"; } // linkedlist reverese void LinkedList::reverse() { struct node *pointer1, *pointer2, *pointer3; if (startNode == NULL) { cout<<\"List is empty\"<next == NULL) { return; } pointer1 = startNode; pointer2 = pointer1->next; pointer3 = pointer2->next; pointer1->next = NULL; pointer2->.

C code on linked list #include stdio.h #include stdlib.h.pdfdeepua8

TutorialII_Updated____niceupdateprogram.pdfBappyAgarwal

linked List.docx vhjgvjhvgjhjhbbjkhkjhkjhvasavim9

C Homework HelpProgramming Homework Help

How do you stop infinite loop Because I believe that it is making a.pdffeelinggift

How do you stop infinite loop? Because I believe that it is making an infinite circular list. c++ code: Here is the list class: #ifndef LIN_J_LIST #define LIN_J_LIST typedef unsigned int uint; #include #include using namespace std; /** * a simplified generic singly linked list class to illustrate C++ concepts * @author Jerry Lin * @version 2/17/17 */ template< typename Object > class List { private: /** * A class to store data and provide a link to the next node in the list */ class Node { public: /** * The constructor * @param data the data to be stored in this node */ explicit Node( const Object & data ) : data{ data }, next{ nullptr } {} Object data; Node * next; }; public: /** * The constructor for an empty list */ List() : size{ 0 }, first{ nullptr }, last{ nullptr } {} /** * the copy constructor-creates and copy the list */ List( List && rhs ) = delete; List( const List & rhs ) { count = 0; size = 0; if(rhs.size != 0) { push_front(rhs.front()); Node * current = rhs.first; Node * tempNode = first; size++; while(current->next != nullptr) { current = current->next; Node *newNode = new Node(current->data); //transfer the data. basic op. count++; tempNode->next = newNode; last = newNode; tempNode = tempNode->next; size++; } } // you document and implement this method } /** * the operator= method-copies the list */ List & operator=( List && rhs) = delete; List & operator=( const List & rhs ) { count = 0; size = 0; if( size != 0 ) { Node * current = first; Node * temp; while( current != nullptr ) { temp = current; current = current->next; delete temp; } } if(rhs.size!= 0) { push_front(rhs.front()); Node * current = rhs.first; Node * tempNode = first; //create a temporary to store size++; while(current -> next != nullptr) { current = current->next; Node *newNode = new Node(current->data); //transfer the data. basic op count++; tempNode->next = newNode; last = newNode; tempNode = tempNode -> next; size++; } } return *this; // you document and implement this method } /** * accessor * @return count */ int get_count() const { return count; } /** * The destructor that gets rid of everything that\'s in the list and * resets it to empty. If the list is already empty, do nothing. */ ~List() { if( size != 0 ) { Node * current = first; Node * temp; while( current != nullptr ) { temp = current; current = current->next; delete temp; } } } /** * Put a new element onto the beginning of the list * @param item the data the new element will contain */ void push_front( const Object& item ) { Node * new_node = new Node( item );//basic op. if(is_empty()) { last = new_node; } else { new_node->next = first; } first = new_node; size++; /* you complete the rest */ } /** * Remove the element that\'s at the front of the list. Causes an * assertion error if the list is empty. */ void pop_front() { assert( !is_empty() ); Node * temp = first; if( first == last ) { first = last = nullptr; } else { first = first->next; } delete temp; size--; } /** * Accessor to return the da.

A)B) C++ program to create a Complete Binary tree from its Lin.pdfanton291

A) B) // C++ program to create a Complete Binary tree from its Linked List // Representation #include #include #include using namespace std; // Linked list node struct ListNode { int data; ListNode* next; }; // Binary tree node structure struct BinaryTreeNode { int data; BinaryTreeNode *left, *right; }; // Function to insert a node at the beginning of the Linked List void push(struct ListNode** head_ref, int new_data) { // allocate node and assign data struct ListNode* new_node = new ListNode; new_node->data = new_data; // link the old list off the new node new_node->next = (*head_ref); // move the head to point to the new node (*head_ref) = new_node; } // method to create a new binary tree node from the given data BinaryTreeNode* newBinaryTreeNode(int data) { BinaryTreeNode *temp = new BinaryTreeNode; temp->data = data; temp->left = temp->right = NULL; return temp; } // converts a given linked list representing a complete binary tree into the // linked representation of binary tree. void convertList2Binary(ListNode *head, BinaryTreeNode* &root) { // queue to store the parent nodes queue q; // Base Case if (head == NULL) { root = NULL; // Note that root is passed by reference return; } // 1.) The first node is always the root node, and add it to the queue root = newBinaryTreeNode(head->data); q.push(root); // advance the pointer to the next node head = head->next; // until the end of linked list is reached, do the following steps while (head) { // 2.a) take the parent node from the q and remove it from q BinaryTreeNode* parent = q.front(); q.pop(); // 2.c) take next two nodes from the linked list. We will add // them as children of the current parent node in step 2.b. Push them // into the queue so that they will be parents to the future nodes BinaryTreeNode *leftChild = NULL, *rightChild = NULL; leftChild = newBinaryTreeNode(head->data); q.push(leftChild); head = head->next; if (head) { rightChild = newBinaryTreeNode(head->data); q.push(rightChild); head = head->next; } // 2.b) assign the left and right children of parent parent->left = leftChild; parent->right = rightChild; } } // Utility function to traverse the binary tree after conversion void inorderTraversal(BinaryTreeNode* root) { if (root) { inorderTraversal( root->left ); cout << root->data << \" \"; inorderTraversal( root->right ); } } // Driver program to test above functions int main() { // create a linked list shown in above diagram struct ListNode* head = NULL; push(&head, 36); /* Last node of Linked List */ push(&head, 30); push(&head, 25); push(&head, 15); push(&head, 12); push(&head, 10); /* First node of Linked List */ BinaryTreeNode *root; convertList2Binary(head, root); cout << \"Inorder Traversal of the constructed Binary Tree is: \ \"; inorderTraversal(root); return 0; } c) #include #include using namespace std; template class bintree { bintree *left; T data; bintree *right; public : bintree() { left=right=NULL; } void create(); void preorder(); void inorder(); void pos.

THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED .pdffathimahardwareelect

THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED HELP FIXING THIS CODE? THIS IS THE PROBLEM Write a program that allows the user to enter two positive integers and outputs their sum. Sounds simple? Here\'s the catch: The numbers may be any size! They may be way too large to store in a single variable. You may not assume any particular maximum number of digits. HERE IS THE CODE #include #include struct node /* Linked list node*/ { int data; struct node* next; }; struct node *newNode(int data) /* Function to create a new node with giving the data*/ { struct node *new_node = (struct node *) malloc(sizeof(struct node)); new_node->data = data; new_node->next = NULL; return new_node; } void push(struct node** head_ref, int new_data) /* Function to insert a node at the beginning of the Doubly Linked List*/ { struct node* new_node = newNode(new_data); /*allocate a node*/ new_node->next = (*head_ref); /* link the old list off to the new node*/ (*head_ref) = new_node; /*move the head to point to the new node*/ } /* Adding the contents of two linked lists and return the head node of resultant list*/ struct node* addTwoLists (struct node* first, struct node* second) { struct node* res = NULL; /* res is head node of the resultant list*/ struct node *temp, *prev = NULL; int carry = 0, sum; while (first != NULL || second != NULL) /*while both the lists exists*/ { /* Calculate value of next digit in resultant list. // The next digit is sum of following things // (i) Carry // (ii) Next digit of first list (if there is a next digit) // (ii) Next digit of second list (if there is a next digit)*/ sum = carry + (first? first->data: 0) + (second? second->data: 0); carry = (sum >= 10)? 1 : 0; /* update carry for next calulation*/ sum = sum % 10; /*update sum if it is greater than 10*/ temp = newNode(sum); /*Create a new node with sum as data*/ if(res == NULL) /*if this is the first node then set it as head of the resultant list*/ res = temp; else /* If this is not the first node then connect it to the rest.*/ prev->next = temp; prev = temp; /* Set prev for next insertion*/ if (first) first = first->next; /* Move first pointers to next node*/ if (second) second = second->next; /*Move second pointer to the next node*/ } if (carry > 0) temp->next = newNode(carry); return res; /* return head of the resultant list*/ } void printList(struct node *node) /* function to print a linked list*/ { while(node != NULL) { printf(\"%d \", node->data); node = node->next; } printf(\"\ \"); } int main(void) /* program to test above function*/ { struct node* res = NULL; struct node* first = NULL; struct node* second = NULL; printf(\"Enter first positive integer: \"); scanf(\"%d\",&first); printList(first); printf(\"Enter second positive integer: \"); scanf(\"%d\",&second); printList(second); /*Add the two lists and see result*/ res = addTwoLists(first, second); printf(\"Sum is: %d\"); printList(res); return 0; } Solution #include #include typedef struct Node { int da.

Inspect the class declaration for a doubly-linked list node in Node-h-.pdfvishalateen

Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking on the orange arrow next to main.cpp at the top of the coding window. The Node class has three member variables: a double data value, a pointer to the next node, and a pointer to the previous node. Each member variable is protected. So code outside of the class must use the provided getter and setter member functions to get or set a member variable. Node.h is read only, since no changes are required. Step 2: Implement the Insert() member function A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList class's Insert() member function. The function must create a new node with the parameter value, then insert the node into the proper sorted position in the linked list. Ex: Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order and yielding: 23 35.5 47.25 86 Step 3: Test in develop mode Code in main() takes a space- separated list of numbers and inserts each into a SortedNumberList. The list is displayed after each insertion. Ex: If input is 77 15 -42 63.5 then output is: List after inserting 77: 77 List after inserting 15: 15 77 List after inserting -42: -42 15 77 List after inserting 63.5: -42 15 63.5 77 Try various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove() member function Implement the SortedNumberList class's Remove() member function. The function takes a parameter for the number to be removed from the list. If the number does not exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the number is removed from the list and true is returned. Uncomment the commented-out part in main() that reads a second input line and removes numbers from the list. Test in develop mode to ensure that insertion and removal both work properly, then submit code for grading. Ex: If input is 84 72 19 61 19 84 then output is: List after inserting 84: 84 List after inserting 72: 72 84 List after inserting 19: 19 72 84 List after inserting 61: 19 61 72 84 List after removing 19: 61 72 84 List after removing 84: 61 72 main.cpp #include #include #include #include "Node.h" #include "SortedNumberList.h" using namespace std; void PrintList(SortedNumberList& list); vector SpaceSplit(string source); int main(int argc, char *argv[]) { // Read the line of input numbers string inputLine; getline(cin, inputLine); // Split on space character vector terms = SpaceSplit(inputLine); // Insert each value and show the sorted list's contents after each insertion SortedNumberList list; for (auto term : terms) { double number = stod(term); cout << "List after inserting " << number << ": " << endl; list.Insert(number); PrintList(list); } /* // Read the input line with numbers to remove getline(cin, inputLi.

C program to insert a node in doubly linked listSourav Gayen

This C program implements functions to create and manipulate a doubly linked list. It allows the user to choose from a menu to create a list, insert nodes at the beginning, end, or a specified position, and display the list. Functions are defined to create a list by dynamically allocating nodes and linking them together, insert nodes at different positions by updating next and prev pointers, and display the list by traversing from head to tail.

Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdffortmdu

Assignment is: \"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to include comments Use meaningful identifier names (constants where appropriate) Turn in .cpp file AND Turn in a \"print-screen\' of your output (press \"print-screen\' on keyboard, then \'paste\' in MS-Word)\" How do you solve QUESTION #4 in the book data structures using c++ by D.S. Malik in Visiual Studios using the linked list below with what is being asked? Please need help Linked list : #include #include using namespace std; struct nodeType { int info; nodeType *link; }; void createList(nodeType*& first, nodeType*& last); void printList(nodeType*& first); void insertFront(nodeType*& first); void insertBack(nodeType*& last); void deleteFirst(nodeType*& first); void deleteLast(nodeType*& last, nodeType* first); int main() { nodeType *first, *last; int num; createList(first, last); int choice; while(true) { cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\ \"; cout<<\"Enter your choice: \"; cin>>choice; switch(choice) { case 1: insertFront(first); break; case 2: insertBack(last); break; case 3: deleteFirst(first); break; case 4: deleteLast(last, first); break; case 5: printList(first); break; case 6: return 0; default: cout<<\"Invalid menu option. Try again.\"<>number; while (number != -999) { newNode = new nodeType; // create new node newNode->info = number; newNode->link = NULL; if (first == NULL) { first = newNode; last = newNode; } else { last->link = newNode; last = newNode; } cout<<\"Enter an integer (-999 to stop): \"; cin>>number; } // end of while-loop } // end of build list function void deleteFirst(nodeType*& first) { nodeType *temp; temp= first; first= temp->link; delete temp; return; } void deleteLast(nodeType*& last, nodeType* current) { nodeType *temp; while(current->link != NULL) { temp=current; current=current->link; } temp=last; current->link=NULL; delete temp; last = current; return; } void insertFront(nodeType*& front) { int num; cout<<\"\ Enter the number to insert: \"; cin>>num; nodeType *newNode = new nodeType; newNode->info=num; newNode->link= front; front= newNode; return; } void insertBack(nodeType*& last) { int num; cout<<\"\ Enter the number to insert: \"; cin>>num; nodeType *newNode = new nodeType; newNode->info=num; newNode->link= NULL; last->link= newNode; last = newNode; return; } void printList(nodeType*& first) { cout<<\"Inside printList...printing linked list...\ \"<info << \" \"; current = current->link; } cout< #include using namespace std; struct nodeType { int info; nodeType *link; }; void createList(nodeType*& first, nodeType*& last); void printList(nodeType*& first); void insertFront(nodeType*& first); void insertBack(nodeType*& last); void deleteFirst(nodeType*& first); void deleteLast(nodeType*& last, nodeType* first); int main() { nodeType *firs.

Write a program that accepts an arithmetic expression of unsigned in.pdfJUSTSTYLISH3B2MOHALI

Write a program that accepts an arithmetic expression of unsigned integers in postfix notation and builds the arithmetic expression tree that represents that expression. From that tree, the corresponding fully parenthesized infix expression should be displayed and a file should be generated that contains the three address format instructions. This topic is discussed in the week 4 reading in module 2, section II-B. The main class should create the GUI shown below: Pressing the Construct Tree button should cause the tree to be constructed and using that tree, the corresponding infix expression should be displayed and the three address instruction file should be generated. The postfix expression input should not be required to have spaces between every token. Note in the above example that 9+- are not separated by spaces. The above example should produce the following output file containing the three address instructions: Add R0 5 9 Sub R1 3 R0 Mul R2 2 3 Div R3 R1 R2 Inheritance should be used to define the arithmetic expression tree. At a minimum, it should involve three classes: an abstract class for the tree nodes and two derived classes, one for operand nodes and another for operator nodes. Other classes should be included as needed to accomplish good object-oriented design. All instance data must be declared as private. You may assume that the expression is syntactically correct with regard to the order of operators and operands, but you should check for invalid tokens, such as characters that are not valid operators or operands such as 2a, which are not valid integers. If an invalid token is detected a RuntimeException should be thrown and caught by the main class and an appropriate error message should be displayed. Three Adddress Generator Enter Postfix Expression 359 2 3 Construct Tree Infix Expression ((3-(5 9))/ (2* 3 Solution #include #include #include #include #include struct TREE //Structure to represent a tree { char data; struct TREE *right,*left,*root; }; typedef TREE tree; /* Stack Using Linked List */ struct Stack //Structure to represent Stack { struct TREE *data; struct Stack *next,*head,*top; //Pointers to next node,head and top }; typedef struct Stack node; node *Nw; //Global Variable to represent node void initialize(node *&n) { n = new node; n -> next = n -> head = n -> top = NULL; } void create(node *n) { Nw = new node; //Create a new node Nw -> next = NULL; //Initialize next pointer field if(n -> head == NULL) //if first node { n -> head = Nw; //Initialize head n -> top = Nw; //Update top } } void push(node *n,tree *ITEM) { node *temp = n -> head; if(n -> head == NULL) //if First Item is Pushed to Stack { create(n); //Create a Node n -> head -> data = ITEM; //Insert Item to head of List n -> head = Nw; return; //Exit from Function } create(n); //Create a new Node Nw -> data = ITEM; //Insert Item while(temp -> next != NULL) temp = temp -> next; //Go to Last Node temp -> next = Nw; //Point New node n -> top = Nw; //Upda.

Data Structures in C++I am really new to C++, so links are really .pdfrohit219406

Data Structures in C++ I am really new to C++, so links are really hard topic for me. It would be nice if you can provide explanations of what doubly linked lists are and of some of you steps... Thank you In this assignment, you will implement a doubly-linked list class, together with some list operations. To make things easier, you’ll implement a list of int, rather than a template class. Solution A variable helps us to identify the data. For ex: int a = 5; Here 5 is identified through variable a. Now, if we have collection of integers, we need some representation to identify them. We call it array. For ex: int arr[5] This array is nothing but a Data Structure. So, a Data Structure is a way to group the data. There are many Data Structures available like Arrays, Linked List, Doubly-Linked list, Stack, Queue, etc. Doubly-Linked list are the ones where you can traverse from the current node both in left and right directions. Why so many different types of Data Structures are required ? Answer is very simple, grouping of data, storage of data and accessing the data is different. For example, in case of Arrays we store all the data in contiguous locations. What if we are not able to store the data in contiguous locations because we have huge data. Answer is go for Linked List/Doubly-Linked list. Here we can store the data anywhere and link the data through pointers. I will try to provide comments for the code you have given. May be this can help you. #pragma once /* dlist.h Doubly-linked lists of ints */ #include class dlist { public: dlist() { } // Here we are creating a NODE, it has a integer value and two pointers. // One pointer is to move to next node and other to go back to previous node. struct node { int value; node* next; node* prev; }; // To return head pointer, i.e. start of the Doubly-Linked list. node* head() const { return _head; } // To return Tail pointer, i.e. end of the Doubly-Linked list. node* tail() const { return _tail; } // **** Implement ALL the following methods **** // Returns the node at a particular index (0 is the head). node* at(int index){ int cnt = 0; struct node* tmp = head(); while(tmp!=NULL) { if (cnt+1 == index) return tmp; tmp = tmp->next; } } // Insert a new value, after an existing one void insert(node *previous, int value){ // check if the given previous is NULL if (previous == NULL) { printf(\"the given previous node cannot be NULL\"); return; } // allocate new node struct node* new_node =(struct node*) malloc(sizeof(struct node)); // put in the data new_node->data = new_data; // Make next of new node as next of previous new_node->next = previous->next; // Make the next of previous as new_node previous->next = new_node; // Make previous as previous of new_node new_node->prev = previous; // Change previous of new_node\'s next node if (new_node->next != NULL) new_node->next->prev = new_node; } // Delete the given node void del(node* which){ struct node* head_ref = head(); /* base case */ if(*head_ref == NUL.

C++Write a method Node Nodereverse() which reverses a list..pdfarjunenterprises1978

C++ Write a method Node *Node::reverse() which reverses a list. Solution #include #include /* Link list node */ struct node { int data; struct node* next; }; /* Function to reverse the linked list */ static void reverse(struct node** head_ref) { struct node* prev = NULL; struct node* current = *head_ref; struct node* next; while (current != NULL) { next = current->next; current->next = prev; prev = current; current = next; } *head_ref = prev; } /* Function to push a node */ void push(struct node** head_ref, int new_data) { /* allocate node */ struct node* new_node = (struct node*) malloc(sizeof(struct node)); /* put in the data */ new_node->data = new_data; /* link the old list off the new node */ new_node->next = (*head_ref); /* move the head to point to the new node */ (*head_ref) = new_node; } /* Function to print linked list */ void printList(struct node *head) { struct node *temp = head; while(temp != NULL) { printf(\"%d \", temp->data); temp = temp->next; } } /* Driver program to test above function*/ int main() { /* Start with the empty list */ struct node* head = NULL; push(&head, 20); push(&head, 4); push(&head, 15); push(&head, 85); printf(\"Given linked list\ \"); printList(head); reverse(&head); printf(\"\ Reversed Linked list \ \"); printList(head); getchar(); }.

There are a number of errors in the following program- All errors are.docxclarkjanyce

There are a number of errors in the following program. All errors are located in main() and structure definitions. Function declarations and definitions are correct! Locate all errors, fix them (as shown below), run the program and save its output as a comment at the end of the source file. Example: int num = 10; int *ptr; num = &ptr; // <== Error: Comment the line and write the correct line below // Write a short justification where appropriate // num = &ptr; // Error #1 ptr = &num; Name: */ #include <stdio.h> #include <string.h> #include <stdlib.h> #include <time.h> #define DUMMY_TRAILER '\177' // octal ASCII code of the // last character in the ASCII table #define NUM_CITIES 10 typedef struct { char name[12]; int temperature[5]; } CITY; // Stack and Queue Node typedef struct node NODE; struct node { CITY city; node *next; }; // Doubly Linked List Node typedef struct d_node D_NODE; struct d_node { CITY city; NODE *forw; NODE *back; }; // Stack Functions NODE *push(NODE *stack, const CITY *pStu); NODE *pop(NODE **stack); // Queue Functions void enqueue(NODE **queue, NODE **rear, const CITY *pStu); NODE *dequeue(NODE **queue, NODE **rear); // Doubly Linked List Functions D_NODE *init_list(void); int insert(D_NODE *list, const CITY *pStu); void traverse_forw(D_NODE *list); void traverse_back(D_NODE *list); // Other Functions void printCity(const CITY *pCity); int main (void) { CITY cList[NUM_CITIES] = { {"Cupertino", {88, 89, 87, 85, 89}}, {"Flagstaff", {81, 80, 88, 89, 89}}, {"Los Angeles", {87, 88, 89, 89, 90}}, {"Philadelphia", {96, 99, 99, 90, 95}}, {"Phoenix", {106, 109, 109, 100, 105}}, {"Portland", {89, 90, 85, 89, 90}}, {"Reno", {108, 105, 109, 100, 108}}, {"Salem", {85, 90, 85, 89, 90}}, {"Tucson", {107, 100, 109, 100, 108}}, {"Yreka", {101, 109, 100, 108, 109}} }; NODE *stack = NULL; NODE *top = NULL; NODE *queue = NULL, *rear = NULL; NODE *front; D_NODE *list; list = init_list(); // build stack and queue with data from an array of CITY structures srand((unsigned int)time(NULL)); int count = rand() % 10; for ( int n = 0; n < count; n++) { int i = rand() % NUM_CITIES; int duplicate = insert(list, &cList[i]); if(duplicate) { // already in the list! push(stack, &cList[i]); enqueue(&queue, &rear, cList[i]); } } // display list printf("\nLIST contents (forwards):\n"); traverse_forw(list); printf("\nLIST contents (backwards):\n"); traverse_back(list); // display stack if (top) { printf("\nSTACK contents from top to bottom:\n"); while ((top = pop(stack))) { printCity(top->city); } } else printf ("Empty Stack!\n"); // display queue if (front) { printf("\nQUEUE contents from front to rear:\n"); while ((front = dequeue( queue, rear))) { printCity(front->city); } } else printf ("Empty Queue!\n"); return 0; } /*************************************************** Displays the fileds of a CIS_CLASS structure Pre pCls - a pointer to a CIS_CLASS structure Post */ void printCity(const CITY *pCity) { printf("%-20s %3d\n", pCity->name, pCity->temperatur.

take the following code and give details of what each line of code i.pdffastechsrv

take the following code and give details of what each line of code is doing #include #include #include using namespace std; /* * Node Declaration */ struct node { int info; struct node *next; }*start; /* * Class Declaration */ class single_llist { public: node* create_node(int); void insert_begin(); void insert_pos(); void insert_last(); void delete_pos(); void sort(); void search(); void update(); void reverse(); void display(); single_llist() { start = NULL; } }; /* * Main :contains menu */ main() { int choice, nodes, element, position, i; single_llist sl; start = NULL; while (1) { cout<>choice; switch(choice) { case 1: cout<<\"Inserting Node at Beginning: \"<info = value; temp->next = NULL; return temp; } } /* * Inserting element in beginning */ void single_llist::insert_begin() { int value; cout<<\"Enter the value to be inserted: \"; cin>>value; struct node *temp, *p; temp = create_node(value); if (start == NULL) { start = temp; start->next = NULL; } else { p = start; start = temp; start->next = p; } cout<<\"Element Inserted at beginning\"<>value; struct node *temp, *s; temp = create_node(value); s = start; while (s->next != NULL) { s = s->next; } temp->next = NULL; s->next = temp; cout<<\"Element Inserted at last\"<info<<\"->\"; temp = temp->next; } cout<<\"NULL\"< Solution ANSWER :: ASSMUING THE TOTAL LINE IN CODE ARE 158*(INCLUDING COMMENTS) SO... PROGRAM STARTS WITH SPECIFING HEADER FILES AND GLOBAL VARIABLE DECLARATION THEN Node Declaration USING STRUCTURES, THEN WE WANT TO DECLARE THE CLASS USING SINGLE LINKED LIST AND THE PROTOTYPE IS PUBLIC IN THE PUBLIC WE WANT TO CREATE THE NODE AS INTEGER DATATYPE THE NODE CONSIST OF insert_begin(); insert_pos();-> INDICATES THE CURRENT POSSITION insert_last();->INSERT AT LAST delete_pos();->TO DELETE THE NUMBER AT CURRENT POSITION sort();->START THE SORTING search();->USED TO SEARCH update();->UPDATE THE NODE reverse();->REVERSE NUMBERS display();->TO DISPLAY THE NODE single_llist()->FIFO WE ARE STARTING TAKING NULL VALUE AND THEN TAKE USER DEFIND FUNCTION MAIN() CREATE THE DATATYPES choice, nodes, element, position, i OBJECT CREATION OF SLL IS SL USING WHILE LOOP THE NODE INSERT AT THE BEGINING OR ENDING STAGE WE ARE USING SWITCH CASES TO PERFORM SLL ON NODE NODE CREATION AS node *single_llist::create_node(int value) ALSO DECLARE THE TEMP IS TAKEN AS NULL VALUE INSERT THE ELEMENT AT THE BEGINING USING IF CONDITION WE CAN INSERT THE NODE AT THE BEGINING struct node *temp, *p; temp = create_node(value); if (start == NULL) { start = temp; start->next = NULL; } else { p = start; start = temp; start->next = p; AND THEN INSERT THE NODE AT THE LAST struct node *temp, *s; temp = create_node(value); s = start; while (s->next != NULL) { s = s->next; } temp->next = NULL; s->next = temp; USING WHILE LOOP WE ARE INSERTING THE NODE AT LAST USING THIS BELLOW CODE WE CAN SEARCH THE ELEMENTS IN THE NODE struct node *temp; if (start == NULL) { cout<<\"The List is Empty\"<info<<\"->\"; temp = temp->next; } cout.

LinkedlistMasud Parvaze

Linked lists are a data structure where each node contains a pointer to the next node in the list. Each node contains data and a pointer to the next node. The last node's pointer is set to NULL. Linked lists can dynamically grow and shrink during program execution. Nodes are implemented as structs containing data and a pointer. The head pointer points to the first node. Linked lists allow traversing the list by following node pointers until NULL is reached.

Data Structures and Agorithm: DS 05 Doubly Linked List.pptxRashidFaridChishti

#includeiostream#includecstdio#includecstdlibusing names.pdfKUNALHARCHANDANI1

Linked listsGeorge Scott IV

The document contains C++ code for implementing and testing various operations on linked lists, including adding/deleting nodes, sorting, splitting lists, reversing lists, and checking for circularity. It defines a Node struct with data and next pointer, and includes functions for initializing nodes, adding/deleting nodes, sorting, splitting, reversing lists, checking for circularity, and more. It also includes unit tests for various functions using the BOOST test framework.

AnswerNote LinkedList.cpp is written and driver program main.cpp.pdfanwarsadath111

The document provides code for implementing a linked list data structure in C++. It includes class definitions for a ListInterface, Node, and LinkedList class. The Node class represents individual nodes in the linked list. The LinkedList class implements the linked list and inherits from ListInterface. It uses Node objects to store and connect list elements. Helper functions and exceptions are also defined to support linked list operations like insertion, removal and accessing elements.

PROBLEM STATEMENTIn this assignment, you will complete DoubleEnde.pdfclimatecontrolsv

PROBLEM STATEMENT: In this assignment, you will complete DoubleEndedList.java that implements the ListInterface as well as an interface called DoubleEndedInterface which represents the list's entries by using a chain of nodes that has both a head reference and a tail reference. Be sure to read through the code and understand the implementation. WHAT IS PROVIDED: - A driver class to test your code. You should not modify this file! - A list interface (ListInterface.java) - A double ended interface (DoubleEndedInterface.java) - An incomplete DoubleEndedList class (DoubleEndedList.java) WHAT YOU NEED TO DO: 4. Complete the DoubleEndedList class 4. Run the driver and make sure your output is exactly the same as mine (at the bottom of Driver.java) \} // end else numberofEntries--; else throw new IndexOut0fBoundsException("Illegal position given to remove operation."); return result; // Return removed entry }//endreturnreve public T replace(int givenPosition, T newEntry) \{ T replace(int givenPosition, T newEntry) \{ if ((givenPosition >=1)&& (givenPosition <= numberOfEntries)) \{ // Assertion: The list is not empty Node desiredNode = getNodeAt (givenPosition); ToriginalEntry = desiredNode.getData(); desiredNode.setData(newEntry); return originalEntry; f // end if else throw new IndexOut0fBoundsException("Illegal position given to replace operation."); replace if (( givenPosition >=1)&& (givenPosition <= number0fEntries)) \{ // Assertion: The list is not empty Node desiredNode = getNodeAt ( givenPosition); T originalEntry = desiredNode. getData( ); desiredNode.setData(newEntry); return originalentry; \} // end if throw new Index0ut0fBoundsException("Illegal position given to replace operation."); \} // end replace public T getEntry(int givenPosition) \{ if ((givenPosition >=1) \&\& (givenPosition < = number0fEntries ) ) \{ // Assertion: The list is not empty return getNodeAt (givenPosition). getData(); else // end if throw new IndexOut0fBoundsException("Illegal position given to getEntry operation."); \} // end getEntry public boolean contains ( T anEntry) \{ boolean found = false; Node currentNode = firstNode; while (!found && (currentNode != null)) \{ if (anEntry.equals (currentNode.getData())) else found = true; \} // end while currentNode = currentNode. getNextNode () ; return found; \} // end contains public int getLength() \{ return numberofEntries; \} // end getLength public boolean isEmpty() \{ return number0fEntries ==0; \} // end isEmpty public T[] toArray() \{ // The cast is safe because the new array contains null entries aSuppressWarnings ("unchecked") T[] result =(T[]) new 0bject [numberofEntries]; // Unchecked cast int index =0; Node currentNode = firstNode; while ((index < numberOfEntries) \&\& (currentNode != null)) \& result [ index ]= currentNode. getData () ; currentNode = currentNode.getNextNode ( ); index++; 3 // end while return result; 3 // end toArray // Returns a reference to the node at a given position. // Precondition: L.

JAVA ProgrammingDesign a class Message that models an e-mail messa.pdfconnellalykshamesb60

JAVA Programming Design a class Message that models an e-mail message. A message has a recipient, a sender, and a message text. Support the following methods: a. A constructor that takes the sender and recipient b. A method append that appends a line of text to the message body c. A method toString that makes the message into one long string like this: “From: Fname Lname\ To: Some Recipient\ …” Write a driver program that uses this class to make a message and print it. Solution MessageTest.java import java.util.Scanner; public class MessageTest { public static void main(String[] args) { Scanner scan = new Scanner(System.in); System.out.println(\"Enter Recipient Name: \"); String recipientName = scan.nextLine(); System.out.println(\"Enter Sender Name: \"); String senderName = scan.nextLine(); System.out.println(\"Enter the body text: \"); String text = scan.nextLine(); Message m = new Message(recipientName, senderName); m.append(text); System.out.println(m.toString()); } } Message.java public class Message { private String recipient; private String sender; private String text; public Message(String r, String s){ this.recipient = r; this.sender = s; text = \"\"; } public void append(String t){ text = text + t +\"\ \"; } public String toString(){ return \"From: \"+sender+\"\ \ \"+text+\"\ To: \"+recipient+\"\ \"; } }.

In which of the following structures are spores formed (Select all .pdfconnellalykshamesb60

In which of the following structures are spores formed? (Select all that apply.)ovule conespollen conesNone of the answer options is correct.carpelsstamensIn which of the following structures are spores formed? (Select all that apply.)ovule conespollen conesNone of the answer options is correct.carpelsstamens Solution SPORES:it is very light and carried great distances survive in un favourable droughts and temperatures.A spore is a single cell that develop in to exact copy of plant from which it came.it is very small,spores core contain cytoplasm and dna. spores are formed in carpels and stamens.the stamens and carpels of flower contain sprongia,in which spores are developed..

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