Check Leap Year Using Python

A year that occurs every four years is considered a leap year in the calendar. For example, 2024 is divisible by 4 therefore, it is a leap year.

Conditions for a Leap Year

To determine whether a given year is a leap year, the following conditions must be met ?

• The year must be divisible by 4.
• If the year is divisible by 100, it must also be divisible by 400 to qualify as a leap year.
• If the year is divisible by 100 but not by 400, it is not a leap year.

Finding Leap Year in Python

Following are different ways to check whether a given year is a loop year in Python -

• Using if-else Statement
• Using Calendar Module
• Using Custom Function
  

Let us look at these one by one -

Using 'if-else' Statement

We can check if a given year is a leap year using an if-else statement. The conditions are placed in the if statement. If the conditions are satisfied, the program returns "It is a leap year." Otherwise, it returns "It is not a leap year."

Example

In the following example we have checked whether a given year is a leap year or not using an if-else statement ?

Year = 2024
if Year % 4 == 0 and (Year % 100 != 0 or Year % 400 == 0):
    print(Year, "is a leap year")
else:
    print(Year, "is not a leap year")

Following is the output of the above code ?

2024 is a leap year

Using Calendar Module

We can also check whether a year is a leap year by using Python's calendar module. The isleap() function determines if a year is a leap year.

Example

Here's an example of checking if a given year is a leap year using the calendar module ?

import calendar
Year = 2025
if calendar.isleap(Year):
    print(Year, "is a leap year")
else:
    print(Year, "is not a leap year.")

Following is the output of the above code ?

2025 is not a leap year

Using Custom Function

We can also determine whether a given year is a leap year using a function. If the year satisfies the leap year conditions, the function will return True; otherwise, it will return False.

Example

In the following example we have checked if a given year is a leap year or not using a function ?

def Leap_year(Year):
    if Year % 4 == 0 and (Year % 100 != 0 or Year % 400 == 0):
        return True
    else:
        return False

Year = 2026		
Result = Leap_year(Year)
print(Year, "is a Leap Year:", Result)

Following is the output of the above code ?

2026 is a Leap Year: False